REVIEW I MATH 254 Calculus IV. Exam I (Friday, April 29) will cover sections
|
|
- Brook Garrison
- 5 years ago
- Views:
Transcription
1 REVIEW I MATH 254 Calculus IV Exam I (Friday, April 29 will cover sections Functions of multivariables The definition of multivariable functions is similar to that of functions of one variable. For example, a function f of two variables (x, y is a rule that assigns to each point (x, y in a region D in the plane a unique real number f(x, y. The region D is called the domain of f. If the domain of a function f is not specified, then it is understood to be the set of all points (x, y such that f(x, y is well-defined. In what follows below let f(x, y be a function of two variables with domain D. 2. Limits and Continuity. We say the limit of f(x, y exists as (x, y tends to a point (x 0, y 0 if there is a unique real number L such that f(x, y L can be as small as you want as long as (x, y is very close (but not equal to (x 0, y 0. The number L is called the limit of f(x, y as (x, y tends to a point (x 0, y 0. We use the following notation: lim f(x, y = L. (x,y (x 0,y 0 A function f is continuous at (x 0, y 0 if lim f(x, y = f(x 0, y 0. (x,y (x 0,y 0 If f is continuous at every point in its domain we say f is continuous. 3. Partial Derivatives. By definition, f x (x f(x, y 0 f(x 0, y 0 0, y 0 = lim. x x0 x x 0 1
2 2 So when computing the partial derivative of f(x, y with respect to x, the key is to view the other variable y as a constant. The notation f x (x, y is also used very often to denote the partial derivative f. x Just as in the case of functions of one variable, We can define second order partial derivatives: x = ( f = (f 2 x x = f xx, x x y x = ( f = (f x y = f xy, y x and higher order partial derivatives such as 3 f x = (, 3 x x 2 x y = ( f = (f y x = f yx, x y y = ( f = (f 2 y y = f yy, y y 4 f y x = ( 3 f. 3 y x 3 The important Clairaut Theorem says that f xy = f yx as long as both are continuous. This is a very convenient fact to use. The Laplacian of f is defined to be f xx + f yy. 4. Gradient, Differential and Directional Derivatives. The gradient of f is ( f gradf = f = x, f. y which is a vector field (vector valued function of (x, y, that is, at each point (x, y, f is a vector in R 2. The differential of f is df = f f dx + x y dy. This is a very important concept in mathematics. But for our purpose, it is in some sense a linear approximation to the change of function f. The directional derivative of f in direction u = (u 1, u 2 : f D u f(x = u f(x = u 1 x + u f 2 y.
3 Here u = (u 1, u 2 is a unit vector: u = (u u 2 2 1/2 = 1. This represents the rate of change of f in the direction u. We see that D u f = u f u f = f since u = 1. So if D u f 0 at a given point, D u f is maximized for u = f/ f. This says that the function f increases most rapidly in the direction of gradient. For a function f(x, y, z of three variables, the gradient of f is while the differential is f = (f x, f y, f z df = f x dx + f y dy + f z dz. Similarly, the directional derivative D u f for u = (u 1, u 2, u 3 is f D u f = u f(x = u 1 x + u f 2 y + u f Tangent Planes and Linear Approximation. The graph of f is the set of all points (x, y, z in space such that z = f(x, y and (x, y is in D. This is a surface in space. For example, the graph of the function f(x, y = x 2 + y 2 is the elliptic paraboloid z = x 2 + y 2. For function f(x, y of two variables, the tangent plane to the graph of f at a point (x 0, y 0, z 0 (so z 0 = f(x 0, y 0 is given by the equation The linear function z z 0 = f x (x 0, y 0 (x x 0 + f y (x 0, y 0 (y y 0. L(x, y = f(x 0, y 0 + f x (x 0, y 0 (x x 0 + f y (x 0, y 0 (y y 0 is called the linearization or linear approximation function of f at (x 0, y 0. We see that the graph of L is exactly the tangent plane of f at (x 0, y 0, z 0. For (x, y close to (x 0, y 0 we have the approximation f(x, y L(x, y. 3
4 4 We say f is differentiable at (x 0, y 0 if this gives a good approximation for (x, y close enough to (x 0, y 0. More precisely, f is differentiable at (x 0, y 0 if f(x, y = f(x 0, y 0 +f x (x 0, y 0 (x x 0 +f y (x 0, y 0 (y y 0 +R 1 (x x 0 +R 2 (y y 0 where R 1, R 2 0 as (x, y (0, 0. Theorem. If f x and f y are continuous then f is differentiable. 6. The Chain Rule. Suppose z = f(x, y and x, y are in turn functions of a variable t: x = g(t, y = h(t. The chain rule states that dz dt f(g(t, h(t = f x(g(t, h(tg (t + f y (g(t, h(th (t, or equivalently, dz dt = dx x dt + dy y dt. Similarly, if x = g(s, t and y = h(s, t, then and s = f g x s + f h y s t = f g x t + f h y t. 7. Level Curves and Implicit Differentiation. For a function f(x, y of two variables, the level curves of f are the curves defined by the equation f(x, y = c where c is constant. For example, the level curves of function f(x, y = x 2 +y 2 are the circles x 2 + y 2 = c of radius c for c > 0. Let (x 0, y 0 be a point on a level curve f(x, y = c (so f(x 0, y 0 = c. The gradient of f at (x 0, y 0 is perpendicular to the tangent line to the level
5 curve at (x 0, y 0. That is f(x 0, y 0 T = 0 where T is a tangent vector to the level curve. If f y (x 0, y 0 0. Then the level curve determines a function y = φ(x near (x 0, y 0. This means f(x, φ(x c. We can find the derivative φ (x of this function by implicit differentiation: d d f(x, φ(x = dx dx c = 0 since c is a constant. By the Chain Rule, So f x (x, φ(x + f y (x, φ(xφ (x = 0. φ (x = f x(x, φ(x f y (x, φ(x. This is also often written in the form dy dx = f x(x, y f y (x, y. For a function f(x, y, z of three variables, a surface defined by the equation f(x, y, z = c is called a level surface of f. At a point (x 0, y 0, z 0 on the surface, the gradient f = (f x, f y, f z is a normal vector to the level surface. So the equation of the tangent plane to the level surface at (x 0, y 0, z 0 is f x (x 0, y 0, z 0 (x x 0 + f y (x 0, y 0, z 0 (y y 0 + f z (x 0, y 0, z 0 (z z 0 = 0. Similarly, the implicit differentiation formula takes the form x = f x(x, y, z f z (x, y, z, Here are some example of level surfaces: y = f y(x, y, z f z (x, y, z. a Sphere: x 2 + y 2 + z 2 = a 2 ; f(x, y, z = x 2 + y 2 + z 2. b Cylinder: x 2 + y 2 = a 2 ; f(x, y, z = x 2 + y 2. c Cone: z 2 = (x 2 + y 2 ; f(x, y, z = x 2 + y 2 z 2. d Paraboloid: z = x 2 + y 2 ; f(x, y, z = x 2 + y 2 z. e Planes: ax + by + cz = d; f(x, y, z = ax + by + cz. 5
6 6 8. Maximum and Minimum Values A point (x 0, y 0 is called a critical point of f(x, y if f x (x 0, y 0 = 0 and f(x 0, y 0 = 0 or one of the partial derivatives does not exist. Theorem. If f has a local maximum or local minimum at a point (x 0, y 0 then (x 0, y 0 is a critical point of f. To determine whether f has a local maximum or local minimum or neither at a critical point, sometimes we can use the Second Derivative Test: Theorem. Suppose f has continuous second partial derivatives and suppose (x 0, y 0 is a critical point of f, that is, f(x 0, y 0 = 0. Let Then D = f xx (x 0, y 0 f yy (x 0, y 0 (f xy (x 0, y 0 2. (a If D > 0 and f xx (x 0, y 0 > 0, then f(x 0, y 0 is a local minimum. (b If D > 0 and f xx (x 0, y 0 < 0, then f(x 0, y 0 is a local maximum. (c If D < 0 then f(x 0, y 0 is not a local maximum or local minimum. 9. Lagrange Multipliers. Let f and g are functions of two variables (x, y. To find the maximum and minimum values of f(x, y subject to the constraint g(x, y = k where k is a constant, we can use the method of Lagrange multipliers: (a Find all values of x, y and λ such that f(x, y = λ g(x, y, and g(x, y = k. (b Evaluate f at all the point (x, y obtained in the previous step (a; the largest of these values is the maximum value of f (on the curve g(x, y = k; the smallest is the minimum value of f.
Math 113 Calculus III Final Exam Practice Problems Spring 2003
Math 113 Calculus III Final Exam Practice Problems Spring 23 1. Let g(x, y, z) = 2x 2 + y 2 + 4z 2. (a) Describe the shapes of the level surfaces of g. (b) In three different graphs, sketch the three cross
More informationCurves, Tangent Planes, and Differentials ( ) Feb. 26, 2012 (Sun) Lecture 9. Partial Derivatives: Signs on Level Curves, Tangent
Lecture 9. Partial Derivatives: Signs on Level Curves, Tangent Planes, and Differentials ( 11.3-11.4) Feb. 26, 2012 (Sun) Signs of Partial Derivatives on Level Curves Level curves are shown for a function
More informationx 6 + λ 2 x 6 = for the curve y = 1 2 x3 gives f(1, 1 2 ) = λ actually has another solution besides λ = 1 2 = However, the equation λ
Math 0 Prelim I Solutions Spring 010 1. Let f(x, y) = x3 y for (x, y) (0, 0). x 6 + y (4 pts) (a) Show that the cubic curves y = x 3 are level curves of the function f. Solution. Substituting y = x 3 in
More informationWhat you will learn today
What you will learn today Tangent Planes and Linear Approximation and the Gradient Vector Vector Functions 1/21 Recall in one-variable calculus, as we zoom in toward a point on a curve, the graph becomes
More informationPartial Derivatives. Partial Derivatives. Partial Derivatives. Partial Derivatives. Partial Derivatives. Partial Derivatives
In general, if f is a function of two variables x and y, suppose we let only x vary while keeping y fixed, say y = b, where b is a constant. By the definition of a derivative, we have Then we are really
More informationSurfaces and Integral Curves
MODULE 1: MATHEMATICAL PRELIMINARIES 16 Lecture 3 Surfaces and Integral Curves In Lecture 3, we recall some geometrical concepts that are essential for understanding the nature of solutions of partial
More informationd f(g(t), h(t)) = x dt + f ( y dt = 0. Notice that we can rewrite the relationship on the left hand side of the equality using the dot product: ( f
Gradients and the Directional Derivative In 14.3, we discussed the partial derivatives f f and, which tell us the rate of change of the x y height of the surface defined by f in the x direction and the
More informationLagrange multipliers October 2013
Lagrange multipliers 14.8 14 October 2013 Example: Optimization with constraint. Example: Find the extreme values of f (x, y) = x + 2y on the ellipse 3x 2 + 4y 2 = 3. 3/2 1 1 3/2 Example: Optimization
More informationMultivariate Calculus: Review Problems for Examination Two
Multivariate Calculus: Review Problems for Examination Two Note: Exam Two is on Tuesday, August 16. The coverage is multivariate differential calculus and double integration. You should review the double
More informationMath 213 Calculus III Practice Exam 2 Solutions Fall 2002
Math 13 Calculus III Practice Exam Solutions Fall 00 1. Let g(x, y, z) = e (x+y) + z (x + y). (a) What is the instantaneous rate of change of g at the point (,, 1) in the direction of the origin? We want
More informationLagrange multipliers 14.8
Lagrange multipliers 14.8 14 October 2013 Example: Optimization with constraint. Example: Find the extreme values of f (x, y) = x + 2y on the ellipse 3x 2 + 4y 2 = 3. 3/2 Maximum? 1 1 Minimum? 3/2 Idea:
More informationGradient and Directional Derivatives
Gradient and Directional Derivatives MATH 311, Calculus III J. Robert Buchanan Department of Mathematics Fall 2011 Background Given z = f (x, y) we understand that f : gives the rate of change of z in
More informationf xx (x, y) = 6 + 6x f xy (x, y) = 0 f yy (x, y) = y In general, the quantity that we re interested in is
1. Let f(x, y) = 5 + 3x 2 + 3y 2 + 2y 3 + x 3. (a) Final all critical points of f. (b) Use the second derivatives test to classify the critical points you found in (a) as a local maximum, local minimum,
More informationMath 209, Fall 2009 Homework 3
Math 209, Fall 2009 Homework 3 () Find equations of the tangent plane and the normal line to the given surface at the specified point: x 2 + 2y 2 3z 2 = 3, P (2,, ). Solution Using implicit differentiation
More informationMATH. 2153, Spring 16, MWF 12:40 p.m. QUIZ 1 January 25, 2016 PRINT NAME A. Derdzinski Show all work. No calculators. The problem is worth 10 points.
MATH. 2153, Spring 16, MWF 12:40 p.m. QUIZ 1 January 25, 2016 PRINT NAME A. Derdzinski Show all work. No calculators. The problem is worth 10 points. 1. Evaluate the area A of the triangle with the vertices
More informationCalculus III. Math 233 Spring In-term exam April 11th. Suggested solutions
Calculus III Math Spring 7 In-term exam April th. Suggested solutions This exam contains sixteen problems numbered through 6. Problems 5 are multiple choice problems, which each count 5% of your total
More informationMath 253, Section 102, Fall 2006 Practice Final Solutions
Math 253, Section 102, Fall 2006 Practice Final Solutions 1 2 1. Determine whether the two lines L 1 and L 2 described below intersect. If yes, find the point of intersection. If not, say whether they
More informationMultivariate Calculus Review Problems for Examination Two
Multivariate Calculus Review Problems for Examination Two Note: Exam Two is on Thursday, February 28, class time. The coverage is multivariate differential calculus and double integration: sections 13.3,
More informationMath 213 Exam 2. Each question is followed by a space to write your answer. Please write your answer neatly in the space provided.
Math 213 Exam 2 Name: Section: Do not remove this answer page you will return the whole exam. You will be allowed two hours to complete this test. No books or notes may be used other than a onepage cheat
More informationChapter 5 Partial Differentiation
Chapter 5 Partial Differentiation For functions of one variable, y = f (x), the rate of change of the dependent variable can dy be found unambiguously by differentiation: f x. In this chapter we explore
More informationTangent Planes and Linear Approximations
February 21, 2007 Tangent Planes Tangent Planes Let S be a surface with equation z = f (x, y). Tangent Planes Let S be a surface with equation z = f (x, y). Let P(x 0, y 0, z 0 ) be a point on S. Tangent
More informationTotal. Math 2130 Practice Final (Spring 2017) (1) (2) (3) (4) (5) (6) (7) (8)
Math 130 Practice Final (Spring 017) Before the exam: Do not write anything on this page. Do not open the exam. Turn off your cell phone. Make sure your books, notes, and electronics are not visible during
More informationwe wish to minimize this function; to make life easier, we may minimize
Optimization and Lagrange Multipliers We studied single variable optimization problems in Calculus 1; given a function f(x), we found the extremes of f relative to some constraint. Our ability to find
More informationFunctions of Several Variables
Functions of Several Variables Directional Derivatives and the Gradient Vector Philippe B Laval KSU April 7, 2012 Philippe B Laval (KSU) Functions of Several Variables April 7, 2012 1 / 19 Introduction
More informationIntroduction to PDEs: Notation, Terminology and Key Concepts
Chapter 1 Introduction to PDEs: Notation, Terminology and Key Concepts 1.1 Review 1.1.1 Goal The purpose of this section is to briefly review notation as well as basic concepts from calculus. We will also
More informationSurfaces and Partial Derivatives
Surfaces and Partial Derivatives James K. Peterson Department of Biological Sciences and Department of Mathematical Sciences Clemson University November 9, 2016 Outline Partial Derivatives Tangent Planes
More informationLagrange Multipliers. Lagrange Multipliers. Lagrange Multipliers. Lagrange Multipliers. Lagrange Multipliers. Lagrange Multipliers
In this section we present Lagrange s method for maximizing or minimizing a general function f(x, y, z) subject to a constraint (or side condition) of the form g(x, y, z) = k. Figure 1 shows this curve
More informationFunctions of Two variables.
Functions of Two variables. Ferdinánd Filip filip.ferdinand@bgk.uni-obuda.hu siva.banki.hu/jegyzetek 27 February 217 Ferdinánd Filip 27 February 217 Functions of Two variables. 1 / 36 Table of contents
More information13.1. Functions of Several Variables. Introduction to Functions of Several Variables. Functions of Several Variables. Objectives. Example 1 Solution
13 Functions of Several Variables 13.1 Introduction to Functions of Several Variables Copyright Cengage Learning. All rights reserved. Copyright Cengage Learning. All rights reserved. Objectives Understand
More informationTopic 2.3: Tangent Planes, Differentiability, and Linear Approximations. Textbook: Section 14.4
Topic 2.3: Tangent Planes, Differentiability, and Linear Approximations Textbook: Section 14.4 Warm-Up: Graph the Cone & the Paraboloid paraboloid f (x, y) = x 2 + y 2 cone g(x, y) = x 2 + y 2 Do you notice
More informationExam 2 Preparation Math 2080 (Spring 2011) Exam 2: Thursday, May 12.
Multivariable Calculus Exam 2 Preparation Math 28 (Spring 2) Exam 2: Thursday, May 2. Friday May, is a day off! Instructions: () There are points on the exam and an extra credit problem worth an additional
More information= w. w u. u ; u + w. x x. z z. y y. v + w. . Remark. The formula stated above is very important in the theory of. surface integral.
1 Chain rules 2 Directional derivative 3 Gradient Vector Field 4 Most Rapid Increase 5 Implicit Function Theorem, Implicit Differentiation 6 Lagrange Multiplier 7 Second Derivative Test Theorem Suppose
More information27. Tangent Planes & Approximations
27. Tangent Planes & Approximations If z = f(x, y) is a differentiable surface in R 3 and (x 0, y 0, z 0 ) is a point on this surface, then it is possible to construct a plane passing through this point,
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Calculus III-Final review Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find the corresponding position vector. 1) Define the points P = (-,
More informationMath 241, Final Exam. 12/11/12.
Math, Final Exam. //. No notes, calculator, or text. There are points total. Partial credit may be given. ircle or otherwise clearly identify your final answer. Name:. (5 points): Equation of a line. Find
More informationEquation of tangent plane: for implicitly defined surfaces section 12.9
Equation of tangent plane: for implicitly defined surfaces section 12.9 Some surfaces are defined implicitly, such as the sphere x 2 + y 2 + z 2 = 1. In general an implicitly defined surface has the equation
More informationThe Differential df, the Gradient f, & the Directional Derivative Dû f sec 14.4 (cont), Goals. Warm-up: Differentiability. Notes. Notes.
The Differential df, the Gradient f, & the Directional Derivative Dû f sec 14.4 (cont), 14.5 10 March 2014 Goals. We will: Define the differential df and use it to approximate changes in a function s value.
More information1. Show that the rectangle of maximum area that has a given perimeter p is a square.
Constrained Optimization - Examples - 1 Unit #23 : Goals: Lagrange Multipliers To study constrained optimization; that is, the maximizing or minimizing of a function subject to a constraint (or side condition).
More information3.6 Directional Derivatives and the Gradient Vector
288 CHAPTER 3. FUNCTIONS OF SEVERAL VARIABLES 3.6 Directional Derivatives and te Gradient Vector 3.6.1 Functions of two Variables Directional Derivatives Let us first quickly review, one more time, te
More informationName: Class: Date: 1. Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint.
. Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. f (x, y) = x y, x + y = 8. Set up the triple integral of an arbitrary continuous function
More informationCalculus 234. Problems. May 15, 2003
alculus 234 Problems May 15, 23 A book reference marked [TF] indicates this semester s official text; a book reference marked [VPR] indicates the official text for next semester. These are [TF] Thomas
More information18.02 Final Exam. y = 0
No books, notes or calculators. 5 problems, 50 points. 8.0 Final Exam Useful formula: cos (θ) = ( + cos(θ)) Problem. (0 points) a) (5 pts.) Find the equation in the form Ax + By + z = D of the plane P
More informationDaily WeBWorK, #1. This means the two planes normal vectors must be multiples of each other.
Daily WeBWorK, #1 Consider the ellipsoid x 2 + 3y 2 + z 2 = 11. Find all the points where the tangent plane to this ellipsoid is parallel to the plane 2x + 3y + 2z = 0. In order for the plane tangent to
More information14.4: Tangent Planes and Linear Approximations
14.4: Tangent Planes and Linear Approximations Marius Ionescu October 15, 2012 Marius Ionescu () 14.4: Tangent Planes and Linear Approximations October 15, 2012 1 / 13 Tangent Planes Marius Ionescu ()
More informationSecond Midterm Exam Math 212 Fall 2010
Second Midterm Exam Math 22 Fall 2 Instructions: This is a 9 minute exam. You should work alone, without access to any book or notes. No calculators are allowed. Do not discuss this exam with anyone other
More information1. Suppose that the equation F (x, y, z) = 0 implicitly defines each of the three variables x, y, and z as functions of the other two:
Final Solutions. Suppose that the equation F (x, y, z) implicitly defines each of the three variables x, y, and z as functions of the other two: z f(x, y), y g(x, z), x h(y, z). If F is differentiable
More informationCalculus III Meets the Final
Calculus III Meets the Final Peter A. Perry University of Kentucky December 7, 2018 Homework Review for Final Exam on Thursday, December 13, 6:00-8:00 PM Be sure you know which room to go to for the final!
More informationLecture 6: Chain rule, Mean Value Theorem, Tangent Plane
Lecture 6: Chain rule, Mean Value Theorem, Tangent Plane Rafikul Alam Department of Mathematics IIT Guwahati Chain rule Theorem-A: Let x : R R n be differentiable at t 0 and f : R n R be differentiable
More informationUniversity of California, Berkeley
University of California, Berkeley FINAL EXAMINATION, Fall 2012 DURATION: 3 hours Department of Mathematics MATH 53 Multivariable Calculus Examiner: Sean Fitzpatrick Total: 100 points Family Name: Given
More informationMATH 2400, Analytic Geometry and Calculus 3
MATH 2400, Analytic Geometry and Calculus 3 List of important Definitions and Theorems 1 Foundations Definition 1. By a function f one understands a mathematical object consisting of (i) a set X, called
More informationFirst of all, we need to know what it means for a parameterize curve to be differentiable. FACT:
CALCULUS WITH PARAMETERIZED CURVES In calculus I we learned how to differentiate and integrate functions. In the chapter covering the applications of the integral, we learned how to find the length of
More informationWorksheet 2.2: Partial Derivatives
Boise State Math 275 (Ultman) Worksheet 2.2: Partial Derivatives From the Toolbox (what you need from previous classes) Be familiar with the definition of a derivative as the slope of a tangent line (the
More informationDate: 16 July 2016, Saturday Time: 14:00-16:00 STUDENT NO:... Math 102 Calculus II Midterm Exam II Solutions TOTAL. Please Read Carefully:
Date: 16 July 2016, Saturday Time: 14:00-16:00 NAME:... STUDENT NO:... YOUR DEPARTMENT:... Math 102 Calculus II Midterm Exam II Solutions 1 2 3 4 TOTAL 25 25 25 25 100 Please do not write anything inside
More informationMAT175 Overview and Sample Problems
MAT175 Overview and Sample Problems The course begins with a quick review/overview of one-variable integration including the Fundamental Theorem of Calculus, u-substitutions, integration by parts, and
More informationConstrained Optimization and Lagrange Multipliers
Constrained Optimization and Lagrange Multipliers MATH 311, Calculus III J. Robert Buchanan Department of Mathematics Fall 2011 Constrained Optimization In the previous section we found the local or absolute
More informationSurfaces and Partial Derivatives
Surfaces and James K. Peterson Department of Biological Sciences and Department of Mathematical Sciences Clemson University November 15, 2017 Outline 1 2 Tangent Planes Let s go back to our simple surface
More informationContinuity and Tangent Lines for functions of two variables
Continuity and Tangent Lines for functions of two variables James K. Peterson Department of Biological Sciences and Department of Mathematical Sciences Clemson University April 4, 2014 Outline 1 Continuity
More informationMA 243 Calculus III Fall Assignment 1. Reading assignments are found in James Stewart s Calculus (Early Transcendentals)
MA 43 Calculus III Fall 8 Dr. E. Jacobs Assignments Reading assignments are found in James Stewart s Calculus (Early Transcendentals) Assignment. Spheres and Other Surfaces Read. -. and.6 Section./Problems
More informationMATH 2023 Multivariable Calculus
MATH 2023 Multivariable Calculus Problem Sets Note: Problems with asterisks represent supplementary informations. You may want to read their solutions if you like, but you don t need to work on them. Set
More information(c) 0 (d) (a) 27 (b) (e) x 2 3x2
1. Sarah the architect is designing a modern building. The base of the building is the region in the xy-plane bounded by x =, y =, and y = 3 x. The building itself has a height bounded between z = and
More informationMAT203 OVERVIEW OF CONTENTS AND SAMPLE PROBLEMS
MAT203 OVERVIEW OF CONTENTS AND SAMPLE PROBLEMS MAT203 covers essentially the same material as MAT201, but is more in depth and theoretical. Exam problems are often more sophisticated in scope and difficulty
More informationTangent Planes/Critical Points
Tangent Planes/Critical Points Christopher Croke University of Pennsylvania Math 115 UPenn, Fall 2011 Problem: Find the tangent line to the curve of intersection of the surfaces xyz = 1 and x 2 + 2y 2
More informationKevin James. MTHSC 206 Section 14.5 The Chain Rule
MTHSC 206 Section 14.5 The Chain Rule Theorem (Chain Rule - Case 1) Suppose that z = f (x, y) is a differentiable function and that x(t) and y(t) are both differentiable functions as well. Then, dz dt
More informationMATH 116 REVIEW PROBLEMS for the FINAL EXAM
MATH 116 REVIEW PROBLEMS for the FINAL EXAM The following questions are taken from old final exams of various calculus courses taught in Bilkent University 1. onsider the line integral (2xy 2 z + y)dx
More informationSolution 2. ((3)(1) (2)(1), (4 3), (4)(2) (3)(3)) = (1, 1, 1) D u (f) = (6x + 2yz, 2y + 2xz, 2xy) (0,1,1) = = 4 14
Vector and Multivariable Calculus L Marizza A Bailey Practice Trimester Final Exam Name: Problem 1. To prepare for true/false and multiple choice: Compute the following (a) (4, 3) ( 3, 2) Solution 1. (4)(
More information6. Find the equation of the plane that passes through the point (-1,2,1) and contains the line x = y = z.
Week 1 Worksheet Sections from Thomas 13 th edition: 12.4, 12.5, 12.6, 13.1 1. A plane is a set of points that satisfies an equation of the form c 1 x + c 2 y + c 3 z = c 4. (a) Find any three distinct
More information302 CHAPTER 3. FUNCTIONS OF SEVERAL VARIABLES. 4. Function of several variables, their domain. 6. Limit of a function of several variables
302 CHAPTER 3. FUNCTIONS OF SEVERAL VARIABLES 3.8 Chapter Review 3.8.1 Concepts to Know You should have an understanding of, and be able to explain the concepts listed below. 1. Boundary and interior points
More information. Tutorial Class V 3-10/10/2012 First Order Partial Derivatives;...
Tutorial Class V 3-10/10/2012 1 First Order Partial Derivatives; Tutorial Class V 3-10/10/2012 1 First Order Partial Derivatives; 2 Application of Gradient; Tutorial Class V 3-10/10/2012 1 First Order
More information. 1. Chain rules. Directional derivative. Gradient Vector Field. Most Rapid Increase. Implicit Function Theorem, Implicit Differentiation
1 Chain rules 2 Directional derivative 3 Gradient Vector Field 4 Most Rapid Increase 5 Implicit Function Theorem, Implicit Differentiation 6 Lagrange Multiplier 7 Second Derivative Test Theorem Suppose
More informationPractice problems from old exams for math 233 William H. Meeks III December 21, 2009
Practice problems from old exams for math 233 William H. Meeks III December 21, 2009 Disclaimer: Your instructor covers far more materials that we can possibly fit into a four/five questions exams. These
More informationNAME: Section # SSN: X X X X
Math 155 FINAL EXAM A May 5, 2003 NAME: Section # SSN: X X X X Question Grade 1 5 (out of 25) 6 10 (out of 25) 11 (out of 20) 12 (out of 20) 13 (out of 10) 14 (out of 10) 15 (out of 16) 16 (out of 24)
More informationMATH 19520/51 Class 6
MATH 19520/51 Class 6 Minh-Tam Trinh University of Chicago 2017-10-06 1 Review partial derivatives. 2 Review equations of planes. 3 Review tangent lines in single-variable calculus. 4 Tangent planes to
More informationMath Exam III Review
Math 213 - Exam III Review Peter A. Perry University of Kentucky April 10, 2019 Homework Exam III is tonight at 5 PM Exam III will cover 15.1 15.3, 15.6 15.9, 16.1 16.2, and identifying conservative vector
More informationPractice problems. 1. Given a = 3i 2j and b = 2i + j. Write c = i + j in terms of a and b.
Practice problems 1. Given a = 3i 2j and b = 2i + j. Write c = i + j in terms of a and b. 1, 1 = c 1 3, 2 + c 2 2, 1. Solve c 1, c 2. 2. Suppose a is a vector in the plane. If the component of the a in
More informationInverse and Implicit functions
CHAPTER 3 Inverse and Implicit functions. Inverse Functions and Coordinate Changes Let U R d be a domain. Theorem. (Inverse function theorem). If ϕ : U R d is differentiable at a and Dϕ a is invertible,
More information14.5 Directional Derivatives and the Gradient Vector
14.5 Directional Derivatives and the Gradient Vector 1. Directional Derivatives. Recall z = f (x, y) and the partial derivatives f x and f y are defined as f (x 0 + h, y 0 ) f (x 0, y 0 ) f x (x 0, y 0
More informationDirectional Derivatives and the Gradient Vector Part 2
Directional Derivatives and the Gradient Vector Part 2 Lecture 25 February 28, 2007 Recall Fact Recall Fact If f is a dierentiable function of x and y, then f has a directional derivative in the direction
More informationR f da (where da denotes the differential of area dxdy (or dydx)
Math 28H Topics for the second exam (Technically, everything covered on the first exam, plus) Constrained Optimization: Lagrange Multipliers Most optimization problems that arise naturally are not unconstrained;
More informationGrad operator, triple and line integrals. Notice: this material must not be used as a substitute for attending the lectures
Grad operator, triple and line integrals Notice: this material must not be used as a substitute for attending the lectures 1 .1 The grad operator Let f(x 1, x,..., x n ) be a function of the n variables
More informationDirection Fields; Euler s Method
Direction Fields; Euler s Method It frequently happens that we cannot solve first order systems dy (, ) dx = f xy or corresponding initial value problems in terms of formulas. Remarkably, however, this
More informationBackground for Surface Integration
Background for urface Integration 1 urface Integrals We have seen in previous work how to define and compute line integrals in R 2. You should remember the basic surface integrals that we will need to
More informationWithout fully opening the exam, check that you have pages 1 through 11.
Name: Section: Recitation Instructor: INSTRUCTIONS Fill in your name, etc. on this first page. Without fully opening the exam, check that you have pages 1 through 11. Show all your work on the standard
More informationMAC2313 Test 3 A E g(x, y, z) dy dx dz
MAC2313 Test 3 A (5 pts) 1. If the function g(x, y, z) is integrated over the cylindrical solid bounded by x 2 + y 2 = 3, z = 1, and z = 7, the correct integral in Cartesian coordinates is given by: A.
More informationMath 233. Lagrange Multipliers Basics
Math 33. Lagrange Multipliers Basics Optimization problems of the form to optimize a function f(x, y, z) over a constraint g(x, y, z) = k can often be conveniently solved using the method of Lagrange multipliers:
More informationLECTURE 18 - OPTIMIZATION
LECTURE 18 - OPTIMIZATION CHRIS JOHNSON Abstract. In this lecture we ll describe extend the optimization techniques you learned in your first semester calculus class to optimize functions of multiple variables.
More informationThere are 10 problems, with a total of 150 points possible. (a) Find the tangent plane to the surface S at the point ( 2, 1, 2).
Instructions Answer each of the questions on your own paper, and be sure to show your work so that partial credit can be adequately assessed. Put your name on each page of your paper. You may use a scientific
More informationAnswer sheet: Second Midterm for Math 2339
Answer sheet: Second Midterm for Math 2339 October 26, 2010 Problem 1. True or false: (check one of the box, and briefly explain why) (1) If a twice differentiable f(x,y) satisfies f x (a,b) = f y (a,b)
More informationMAC2313 Final A. a. The vector r u r v lies in the tangent plane of S at a given point. b. S f(x, y, z) ds = R f(r(u, v)) r u r v du dv.
MAC2313 Final A (5 pts) 1. Let f(x, y, z) be a function continuous in R 3 and let S be a surface parameterized by r(u, v) with the domain of the parameterization given by R; how many of the following are
More informationMath 5BI: Problem Set 2 The Chain Rule
Math 5BI: Problem Set 2 The Chain Rule April 5, 2010 A Functions of two variables Suppose that γ(t) = (x(t), y(t), z(t)) is a differentiable parametrized curve in R 3 which lies on the surface S defined
More informationDifferentiability and Tangent Planes October 2013
Differentiability and Tangent Planes 14.4 04 October 2013 Differentiability in one variable. Recall for a function of one variable, f is differentiable at a f (a + h) f (a) lim exists and = f (a) h 0 h
More informationPURE MATHEMATICS 212 Multivariable Calculus CONTENTS. Page. 1. Assignment Summary... i 2. Summary Assignments...2
PURE MATHEMATICS 212 Multivariable Calculus CONTENTS Page 1. Assignment Summary... i 2. Summary...1 3. Assignments...2 i PMTH212, Multivariable Calculus Assignment Summary 2010 Assignment Date to be Posted
More informationExam 1 Review. MATH Intuitive Calculus Fall Name:. Show your reasoning. Use standard notation correctly.
MATH 11012 Intuitive Calculus Fall 2012 Name:. Exam 1 Review Show your reasoning. Use standard notation correctly. 1. Consider the function f depicted below. y 1 1 x (a) Find each of the following (or
More informationCoordinate Transformations in Advanced Calculus
Coordinate Transformations in Advanced Calculus by Sacha Nandlall T.A. for MATH 264, McGill University Email: sacha.nandlall@mail.mcgill.ca Website: http://www.resanova.com/teaching/calculus/ Fall 2006,
More informationFinal Exam - Review. Cumulative Final Review covers sections and Chapter 12
Final Exam - eview Cumulative Final eview covers sections 11.4-11.8 and Chapter 12 The following is a list of important concepts from each section that will be tested on the Final Exam, but were not covered
More informationMATH 2400: CALCULUS 3 MAY 9, 2007 FINAL EXAM
MATH 4: CALCULUS 3 MAY 9, 7 FINAL EXAM I have neither given nor received aid on this exam. Name: 1 E. Kim................ (9am) E. Angel.............(1am) 3 I. Mishev............ (11am) 4 M. Daniel...........
More informationReview 1. Richard Koch. April 23, 2005
Review Richard Koch April 3, 5 Curves From the chapter on curves, you should know. the formula for arc length in section.;. the definition of T (s), κ(s), N(s), B(s) in section.4. 3. the fact that κ =
More information1 Vector Functions and Space Curves
ontents 1 Vector Functions and pace urves 2 1.1 Limits, Derivatives, and Integrals of Vector Functions...................... 2 1.2 Arc Length and urvature..................................... 2 1.3 Motion
More informationDirectional Derivatives and the Gradient Vector Part 2
Directional Derivatives and the Gradient Vector Part 2 Marius Ionescu October 26, 2012 Marius Ionescu () Directional Derivatives and the Gradient Vector Part October 2 26, 2012 1 / 12 Recall Fact Marius
More informationMATH Lagrange multipliers in 3 variables Fall 2016
MATH 20550 Lagrange multipliers in 3 variables Fall 2016 1. The one constraint they The problem is to find the extrema of a function f(x, y, z) subject to the constraint g(x, y, z) = c. The book gives
More informationWorkbook. MAT 397: Calculus III
Workbook MAT 397: Calculus III Instructor: Caleb McWhorter Name: Summer 2017 Contents Preface..................................................... 2 1 Spatial Geometry & Vectors 3 1.1 Basic n Euclidean
More information