Distances in power-law random graphs
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1 Distances in power-law random graphs Sander Dommers Supervisor: Remco van der Hofstad February 2, 2009 Where innovation starts
2 Introduction There are many complex real-world networks, e.g. Social networks (friendships, business relationships, sexual contacts,... ) Information networks (World Wide Web, citations,... ) Technological networks (Internet, airline routes,... ) Biological networks (protein interactions, neural networks,... ) 2/16 Sexual network Colorado Springs, USA (Potterat, et al., 2002)
3 Introduction There are many complex real-world networks, e.g. Social networks (friendships, business relationships, sexual contacts,... ) Information networks (World Wide Web, citations,... ) Technological networks (Internet, airline routes,... ) Biological networks (protein interactions, neural networks,... ) 2/16 Small part of the Internet steve/stuff/ipmap/
4 Introduction 2/16 There are many complex real-world networks, e.g. I Social networks (friendships, business relationships, sexual contacts,... ) I Information networks (World Wide Web, citations,... ) I Technological networks (Internet, airline routes,... ) I Biological networks (protein interactions, neural networks,... ) Yeast protein interaction network (Jeong, et al., 2001) / department of mathematics and computer science
5 Properties of complex networks Power law behavior Number of vertices with degree k is proportional to k τ 3/16 Small worlds Distances in the network are small
6 Random graph models Erdős-Rényi random graph Start with n vertices Draw edges between each pair of vertices with probability p Exponential tails, so no power-law distribution 4/16
7 Random graph models Erdős-Rényi random graph Start with n vertices Draw edges between each pair of vertices with probability p Exponential tails, so no power-law distribution 4/16 Configuration model Start with n vertices Let vertex i have Di half-edges D i has power-law distribution with exponent τ Connect the half-edges uniformly at random Power-law because of Strong Law of Large Numbers
8 Random graph models (continued) Preferential attachment (PA) Networks are growing Popular vertices are more likely to get more edges than unpopular vertices 5/16
9 Random graph models (continued) Preferential attachment (PA) Networks are growing Popular vertices are more likely to get more edges than unpopular vertices 5/16 PA model Choose integer m, and parameter δ > m Start at time t = 2 with 2 vertices connected with 2m edges At each time step, say t + 1, add a new vertex with m edges Connect its m edges independently according to P [ edge of t + 1 i PA m,δ (t) ] = D i (t) + δ t(2m + δ), for i [t].
10 Properties of PA model 6/16 Power law with exponent So any exponent τ > 2 possible τ = 3 + δ m
11 Properties of PA model 6/16 Power law with exponent So any exponent τ > 2 possible τ = 3 + δ m The diameter of a graph at time t, diam(t), is the largest distance present in the graph at time t
12 Properties of PA model Power law with exponent 6/16 So any exponent τ > 2 possible τ = 3 + δ m The diameter of a graph at time t, diam(t), is the largest distance present in the graph at time t τ = 3 (Bollobás and Riordan, 2004) For m 2 and δ = 0, with high probability, log t (1 ε) log log t log t diam(t) (1 + ε) log log t for all ε > 0
13 Properties of PA model (continued) 7/16 τ > 3 (Van der Hofstad and Hooghiemstra, 2008) For m 2 and δ > 0, with high probability, for some c 1, c 2 > 0 c 1 log t diam(t) c 2 log t τ (2, 3) (Van der Hofstad and Hooghiemstra, 2008) For m 2 and δ ( m, 0), with high probability, diam(t) c log log t for some c > 0
14 log log lowerbound for τ > 2 8/16 Theorem Consider preferential attachment with m 2 and δ > m (i.e. τ > 2) Let k = ε log log t, with 0 < ε < 1 log m Then, with high probability, diam(2t) k
15 Proper k-exploration trees Construction of k-exploration tree of a vertex i Start from vertex i Connect its m edges vertices at distance 1 from vertex i Connect the m edges of vertices at distance 1,... Continue in same fashion, up to distance k 9/16 Example for m = 2, k = 3 and i = 30
16 Proper k-exploration trees Construction of k-exploration tree of a vertex i Start from vertex i Connect its m edges vertices at distance 1 from vertex i Connect the m edges of vertices at distance 1,... Continue in same fashion, up to distance k 9/16 Example for m = 2, k = 3 and i = 30
17 Proper k-exploration trees Construction of k-exploration tree of a vertex i Start from vertex i Connect its m edges vertices at distance 1 from vertex i Connect the m edges of vertices at distance 1,... Continue in same fashion, up to distance k 9/16 Example for m = 2, k = 3 and i = 30
18 Proper k-exploration trees Construction of k-exploration tree of a vertex i Start from vertex i Connect its m edges vertices at distance 1 from vertex i Connect the m edges of vertices at distance 1,... Continue in same fashion, up to distance k 9/16 Example for m = 2, k = 3 and i = 30
19 Proper k-exploration trees Construction of k-exploration tree of a vertex i Start from vertex i Connect its m edges vertices at distance 1 from vertex i Connect the m edges of vertices at distance 1,... Continue in same fashion, up to distance k 9/16 Example for m = 2, k = 3 and i = 30
20 Proper k-exploration trees Construction of k-exploration tree of a vertex i Start from vertex i Connect its m edges vertices at distance 1 from vertex i Connect the m edges of vertices at distance 1,... Continue in same fashion, up to distance k 9/16 Example for m = 2, k = 3 and i = 30
21 Proper k-exploration trees (continued) 10/16 A k-exploration tree is proper when The k-exploration tree has no collisions No other vertex connects to a vertex in the tree All vertices of the tree are in [2t]\[t] Example for m = 2, k = 3 and i = 30
22 Proper k-exploration trees (continued) 10/16 A k-exploration tree is proper when The k-exploration tree has no collisions No other vertex connects to a vertex in the tree All vertices of the tree are in [2t]\[t] Example for m = 2, k = 3 and i = 30
23 Proper k-exploration trees (continued) 10/16 A k-exploration tree is proper when The k-exploration tree has no collisions No other vertex connects to a vertex in the tree All vertices of the tree are in [2t]\[t] Example for m = 2, k = 3 and i = 30
24 Proper k-exploration trees (continued) 10/16 A k-exploration tree is proper when The k-exploration tree has no collisions No other vertex connects to a vertex in the tree All vertices of the tree are in [2t]\[t] Example for m = 2, k = 3 and i = 30
25 Number of proper k-exploration trees Let Z k (2t) = # proper k-exploration trees at time 2t 11/16
26 Number of proper k-exploration trees Let Z k (2t) = # proper k-exploration trees at time 2t 11/16 Then P [diam(2t) < k] P [Z k (2t) = 0]
27 Number of proper k-exploration trees Let Z k (2t) = # proper k-exploration trees at time 2t 11/16 Then P [diam(2t) < k] P [Z k (2t) = 0] Using Chebychev inequality gives P [Z k (2t) = 0] Var [Z k (2t)] E [Z k (2t)] 2? 0
28 Number of proper k-exploration trees Let Z k (2t) = # proper k-exploration trees at time 2t 11/16 Then P [diam(2t) < k] P [Z k (2t) = 0] Using Chebychev inequality gives We need P [Z k (2t) = 0] Var [Z k (2t)] E [Z k (2t)] 2? 0 E [Z k (2t)] and Var [Z k (2t)] E [Z k (2t)] 2
29 E [Z k (2t)] 12/16 Let B T = no other vertex connects to a vertex in the tree T Then E [Z k (2t)] = E = T possible T possible = T possible I{T PA m,δ (2t) and T is proper} P [T PA m,δ (2t) and T is proper] P [T PA m,δ (2t)] P [B T T PA m,δ (2t)]
30 E [Z k (2t)] (continued) 13/16 E [Z k (2t)] = P [T PA m,δ (2t)] P [B T T PA m,δ (2t)] T possible
31 E [Z k (2t)] (continued) 13/16 E [Z k (2t)] = P [T PA m,δ (2t)] P [B T T PA m,δ (2t)] T possible ( ) 1 T 1 t
32 E [Z k (2t)] (continued) 13/16 E [Z k (2t)] = P [T PA m,δ (2t)] P [B T T PA m,δ (2t)] T possible ( ) 1 T 1 ( 1 T ) mt t t
33 E [Z k (2t)] (continued) 13/16 E [Z k (2t)] = P [T PA m,δ (2t)] P [B T T PA m,δ (2t)] T possible ( ) t T ( ) 1 T 1 ( 1 T ) mt T t t
34 E [Z k (2t)] (continued) 13/16 E [Z k (2t)] = P [T PA m,δ (2t)] P [B T T PA m,δ (2t)] T possible ( ) t T ( ) 1 T 1 ( 1 T ) mt T t t ( 1 t (log t) ε ) (log t) ε m(log t)ε e
35 Var [Z k (2t)] E [Z k (2t)] 2 14/16 Study covariance of two different possible trees being formed in the graph and being proper Take exact look at probabilities involved Conclusion Var [Z k (2t)] c (log t)2 E [Z k (2t)] 2 + E [Z k (2t)] E [Z k (2t)] 2 t
36 log log lowerbound for τ > 2 15/16 Theorem Consider preferential attachment with m 2 and δ > m (i.e. τ > 2) Let k = ε log log t, with 0 < ε < 1 log m Then, with high probability, diam(2t) k Proof P[diam(2t) k] 1 P [Z k (2t) = 0] 1 Var [Z k (2t)] E [Z k (2t)] 2 1
37 Conclusion Small world property holds in preferential attachment model 16/16 Future research Better bounds on distances Distances in other extended PA models Processes on random graphs
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