8.2 Graph and Write Equations of Parabolas

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1 8.2 Graph and Write Equations of Parabolas Where is the focus and directrix compared to the vertex? How do you know what direction a parabola opens? How do you write the equation of a parabola given the focus/directrix? What is the general equation for a parabola?

2 Parabolas A parabola is defined in terms of a fixed point, called the focus, and a fixed line, called the directrix. A parabola is the set of all points P(x,y) in the plane whose distance to the focus equals its distance to the directrix. directrix focus axis of symmetry

3 Horizontal Directrix Standard Equation of a parabola with its vertex at the origin is x 2 = 4py y p > 0: opens upward p < 0: opens downward focus: (0, p) P(x, y) F(0, p) directrix: y = p axis of symmetry: y-axis O D(x, p) y = p x

4 Vertical Directrix Standard Equation of a parabola with its vertex at the origin is y 2 = 4px y p > 0: opens right p < 0: opens left focus: (p, 0) directrix: x = p axis of symmetry: x-axis D(x, p) x = p O P(x, y) F(p, 0) x

5 Example 1 Graph directrix.. Label the vertex, focus, and y 2 = 4px Identify p. y 2 = 4(1)x So, p = Since p > 0, the parabola opens to the right Vertex: (0,0) Focus: (1,0) Directrix: x = -1

6 Example 1 Graph directrix.. Label the vertex, focus, and Y 2 = 4x Use a table to sketch a graph 4 y x

7 Graph x = ⅛y 2. Identify the focus, directrix, and axis of symmetry. SOLUTION STEP 1 Rewrite the equation in standard form. x = 1 y 2 8 Write original equation. 8x = y 2 STEP 2 Multiply each side by 8. Identify the focus, directrix, and axis of symmetry. The equation has the form y 2 = 4px where p = 2. The focus is (p, 0), or ( 2, 0). The directrix is x = p, or x = 2. Because y is squared, the axis of symmetry is the x - axis.

8 STEP 3 8x = y 2 Draw the parabola by making a table of values and plotting points. Because p < 0, the parabola opens to the left. So, use only negative x - values.

9 Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola. 1. Y 2 = 6x SOLUTION STEP 1 Rewrite the equation in standard form. Y 2 = 4 ( 3 2 )x STEP 2 Identify the focus, directrix, and axis of symmetry. The equation has the form y 2 = 4px where p = 3. The focus 2 is (p, 0), or ( 3 3, 0). The directrix is x = p, or x =. 2 2 Because y is squared, the axis of symmetry is the x - axis.

10 STEP 3 Y 2 = 6x Draw the parabola by making a table of values and plotting points. Because p < 0, the parabola opens to the left. So, use only negative x - values

11 Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola y = x 2 4 SOLUTION STEP 1 Rewrite the equation in standard form. y = 1 x 2 Write original equation. 4 Multiply each side by 4. 4y = x 2 STEP 2 equation focus directrix axis of symmetry x 2 = 4y (0, 1) y = 1 Vertical x = 0

12 STEP 3 x 2 = 4y Draw the parabola by making a table of values and plotting points. Because p < 0, the parabola opens to the left. So, use only negative y - values. y x

13 Graph the equation. Identify the focus, directrix, and axis of symmetry of the parabola. 4. x = 1 y 2 3 SOLUTION STEP 1 Rewrite the equation in standard form. 1 x = Y 2 Write original equation. 3 3x = y 2 Multiply each side by 3. STEP 2 equation Y 2 3 = 4 4 x focus directrix axis of symmetry 3,0 x = 3 Horizontal y = 0 4 4

14 STEP 3 3x = y 2 Draw the parabola by making a table of values and plotting points. Because p < 0, the parabola opens to the left. So, use only negative x - values. y x

15 Example 2 Write the standard equation of the parabola with its vertex at the origin and the directrix y = -6. Since the directrix is below the vertex, the parabola opens up Since y = -p and y = -6, p = 6 x 2 =4(6)y x 2 = 24y

16 Write an equation of the parabola shown. SOLUTION The graph shows that the vertex is (0, 0) and the directrix is y = p = 3 for p in the standard form 2 of the equation of a parabola. x 2 = 4py Standard form, vertical axis of symmetry x 2 = 4 ( 3 )y 2 Substitute 3 for p 2 x 2 = 6y Simplify.

17 Write the standard form of the equation of the parabola with vertex at (0, 0) and the given directrix or focus. 5. Directrix: y = 2 SOLUTION x 2 = 4py x 2 = 4 ( 2)y x 2 = 8y Standard form, vertical axis of symmetry Substitute 2 for p Simplify.

18 Write the standard form of the equation of the parabola with vertex at (0, 0) and the given directrix or focus. 8. Focus: (0, 3) SOLUTION x 2 = 4py x 2 = 4 (3)y x 2 = 12y Standard form, vertical axis of symmetry Substitute 3 for p Simplify.

19 Where is the focus and directrix compared to vertex? The focus is a point on the line of symmetry and the directrix is a line below the vertex. The focus and directrix are equidistance from the vertex. How do you know what direction a parabola opens? x 2, graph opens up or down, y 2, graph opens right or left How do you write the equation of a parabola given the focus/directrix? Find the distance from the focus/directrix to the vertex (p value) and substitute into the equation. What is the general equation for a parabola? x 2 = 4py (opens up [p>0] or down [p<0]), y 2 = 4px (opens right [p>0] or left [p<0])

20 Hw 8.2 p. 499, 3-17 odd, 26-33, NO WORK = NO CREDIT This is a long assignment with 24 problems! Start working on them today!

21 8.2 Graph and Write Equations of Parabolas day 2 What does it mean if a parabola has a translated vertex? What general equations can you use for a parabola when the vertex has been translated?

22 Standard Equation of a Translated Parabola Vertical axis: (x h) 2 = 4p(y k) vertex: (h, k) focus: (h, k + p) directrix: y = k p axis of symmetry: x = h

23 Standard Equation of a Translated Parabola Horizontal axis: (y k) 2 = 4p(x h) vertex: (h, k) focus: (h + p, k) directrix: x = h - p axis of symmetry: y = k

24 Example 3 Write the standard equation of the parabola with a focus at F(-3,2) and directrix y = 4. Sketch the info. The parabola opens downward, so the equation is of the form (x h) 2 = 4p(y k) vertex: (-3,3) h = -3, k = 3 p = -1 (x + 3) 2 = 4( 1)(y 3)

25 SOLUTION STEP 1 STEP 2 Graph (x 2) 2 = 8 (y + 3). Compare the given equation to the standard form of an equation of a parabola. You can see that the graph is a parabola with vertex at (2, 3),focus (2, 1) and directrix y = 5 Draw the parabola by making a table of value and plot y point. Because p > 0, he parabola open to the right. So use only points x- value x y STEP 3 Draw a curve through the points.

26 Example 4 Write an equation of a parabola whose vertex is at ( 2,1) and whose focus is at ( 3, 1). Begin by sketching the parabola. Because the parabola opens to the left, it has the form (y k) 2 = 4p(x h) Find h and k: The vertex is at ( 2,1) so h = 2 and k = 1 Find p: The distance between the vertex ( 2,1) and the focus ( 3,1) by using the distance formula. p = 1 (y 1) 2 = 4(x + 2)

27 Write an equation of the parabola whose vertex is at ( 2, 3) and whose focus is at ( 4, 3). SOLUTION STEP 1 Determine the form of the equation. Begin by making a rough sketch of the parabola. Because the focus is to the left of the vertex, the parabola opens to the left, and its equation has the form (y k) 2 = 4p(x h) where p < 0. STEP 2 Identify h and k. The vertex is at ( 2, 3), so h = 2 and k = 3. STEP 3 Find p. The vertex ( 2, 3) and focus ( 4, 3) both lie on the line y = 3, so the distance between them is p = 4 ( 2) = 2, and thus p = +2. Because p < 0, it follows that p = 2, so 4p = 8. The standard form of the equation is (y 3) 2 = 8(x + 2).

28 Write the standard form of a parabola with vertex at (3, 1) and focus at (3, 2). SOLUTION STEP 1 Determine the form of the equation. Begin by making a rough sketch of the parabola. Because the focus is to the left of the vertex, the parabola opens to the left, and its equation has the form (x h) 2 = 4p(y k) where p > 0. STEP 2 Identify h and k. The vertex is at (3, 1), so h = 3 and k = 1. STEP 3 Find p. The vertex (3, 1) and focus (3, 2) both lie on the line x = 3, so the distance between them is p = 2 ( 1) = 3, and thus p = + 3. Because p > 0, it follows that p = 3, so 4p = 12. The standard form of the equation is (x 3) 2 = 12(y + 1)

29 What does it mean if a parabola has a translated vertex? It means that the vertex of the parabola has been moved from (0,0) to (h,k). What general equations can you use for a parabola when the vertex has been translated? (y-k) 2 =4p(x-h) (x-h) 2 =4p(y-k)

30 Hw 8.2 p. 499, 3-17 odd, 26-33, NO WORK = NO CREDIT This is a long assignment with 24 problems! Start working on them today!

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