Stack Frames. Compilers use the stack: to store the to to a subroutine for storage of declared in the subroutine and a place to
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1 Stack Frames EE 357 Unit 8 Stack Frames Compilers use the stack: to store the to to a subroutine for storage of declared in the subroutine and a place to Every call to a subroutine will create a data structure called a on the stack to store this information To access this data structure on the stack an address register pointer called is used in addition to the normal stack pointer () Stack Frames Accessing Values on the Stack Caller s code pushes parameters (arguments) Call to subroutine pushes Callee saves registers it will overwrite (including ) Callee allocates space for l variables Caller llee Ca ans = avg(param1, param2); Subroutines Stack Frame Callee callee s Main Routine s int avg(int a, int b) { Stack Frame int temp=1; // var s Caller Stack Frame Organization Stack pointer () is usually used to access only the top value on the stack To access parameters / arguments, we need to access values We could try to use a displacement from, but other by the callee may change the requiring Need a better solution Saved Regs. Saved (its s, To access parameters we could try to use some displacement [i.e. ]
2 Frame Pointer Frame Pointer and Subroutines Use a new pointer called Frame Pointer () to point to the base of the current routines frame is used as will during the course of subroutine execution Can use constant displacements from to access parameters or variables Key 1: doesn t change during subroutine execution Key 2: Number of parameters and variables is a known value Locals disp. from Arguments disp. from - disp. Saved Regs. Saved (its s, Problem is that each executing subroutine needs its The called subroutine must and setup its own as the first thing it does when it is called. The called subroutine must restore the before it returns and instructions are used to save/restore old and allocate space for s - disp. Callers (its s, LINK Instruction LINK Instruction Example LINK should be of a subroutine Pushes on top of stack and can also allocates space for that routines stack frame ( var s, saved reg s, etc.) LINK An, #imm An should be the, imm = # of bytes for s and other saved values Saves current An () onto the stack Sets to current (top of stack) Adds imm. to to allocate space on the stack for l variables imm. should be negative to allocate space old new old Before LINK old stack frame After LINK 1.) Before LINK 1 2.) old is 2 pushed onto stack 3.) is copied into so now points at old 3 4.) negative 4 immediate value old is added d to to allocate var. old space
3 UNLK Instruction UNLK should be used just before RTS Restores old by popping it off the stack as well as deallocating variable space on the stack. UNLK An Copies An (i.e. ) to so that now points at old. Pops old into An new old old Before UNLK After UNLK 1 old 3 UNLK Instruction Example 1.) Before UNLK 2.) is copied to so that now points below the s 3.) old on the stack is copied into restoring the callers value 4.) is incremented to now point at 2 old 4 LINK & UNLK LINK and UNLK are the single instruction equivalent to the following sequences: LINK An,#imm => MOVE.L An,-() MOVEA.L,An ADDA.L #imm, UNLK => MOVEA.L An, MOVEA.L ()+,An Building a Stack Frame Caller s code pushes parameters (arguments) Parameters pushed in reverse order (param. n first) Call to subroutine pushes First instruction of subroutine is LINK Saves old on the stack and allocates space for variables Last instruction of subroutine is UNLK Deallocates variables and restores old RTS pops Caller s code pops parameters int ans; ans = avg(1,5); int avg(int a, int b) { int temp = 1; return a + b >> temp;
4 &Summary Summary is used as always points at old Local variables are at lower addresses (above) where points [i.e. -4(), -8(), ] is directly below old [i.e. 4()] Parameters are below [i.e. 8(), 12(), 16() ] is always pointing at current top of stack (above ) old Stack Frame Example int ans; ANS:.space 4 MAIN: ans = avg(1,5); MOVE.L #5,-() MOVE.L #1,-() int avg(int a, int b) { BSR.W AVG int temp = 1; 0x052C ADDA.L #8, return a + b >> temp; 3558 MOVE.L D0,ANS 355c.org 0x AVG: LINK,#-4 MOVE.L #1, -4() 3568 MOVE.L 8(),D0 ADD.L 12(),D0 356c MOVE.L -4(),D LSR.L L D1,D0D0 UNLK RTS Assume for MAIN that points to 0x and points to 0x3570 Example 2 Subroutine to sum an array of integers int sumit(int dat[], int length) { int sum, i; sum = 0; for(i=0; i < length; i++) sum = sum + data[i]; return sum; Example 2.data DAT:.space 400.text MAIN: MOVE.L #100,-() MOVE.L #DATA,-() 0x50c BSR.W SUMDAT ADDA.L #8,.org 0x SUMIT: LINK,#-8 CLR.L -4() 355c MOVE.L -4(),D0 ; move sum to D MOVE.L 8(),A0 ; move pointer MOVE.L 12(),-8() ; init i=length MOVE.L -8(),D1 ; move i to D LOOP: ADD.L (A0)+,D0 SUBI.L #1,D1 356c MOVE.L D0,-4() UNLK BNE LOOP DONE: MOVE.L #100,-8() RTS Main s 357c Stack Frame Originally for MAIN, points to 0x and points to 0x
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