Database implementation Further SQL

Transcription

1 IRU SEMESTER 2 January 2010 Semester 1 Session 2 Database implementation Further SQL Objectives To be able to use more advanced SQL statements, including Renaming columns Order by clause Aggregate functions Group by and having clauses Table aliases Joins Creating, altering and deleting database objects All the above are required in exercise two! To continue work on the IRU assignment, part one. C:\Allwork\geoff\web stuff\askgeoff\iru\iru session 2 header - SQL 2.doc

2 Information Retrieval and Use (IRU) An Introduction To SQL Part 2 1 SQL Data Retrieval Recap: The SQL Data Manipulation Language (DML)has four commands: SELECT: retrieving data INSERT: creating data UPDATE: altering data DELETE: removing data 2 Select Statement: displaying data You can display data in a different format: Show all the department names found in the dept table but rename the column with the heading diff_dept: SQL> select dname as diff_dept from dept; DIFF_DEPT ACCOUNTING RESEARCH SALES OPERATIONS 3 1

3 The Order By Clause: Key principles Oracle will display your rows of data in an unordered fashion. We use the ORDER BY clause to order the rows that are retrieved. The ORDER BY clause should always be placed last in the query. The default ordering is ascending Numeric ascending by order value Dates chronological order Char alphabetically DESC is used to reverse the order 4 The Order By Clause: Example 1 List all departments in order of their location: SELECT * FROM dept ORDER BY loc; DEPTNO DNAME LOC OPERATIONS BOSTON 30 SALES CHICAGO 20 RESEARCH DALLAS 10 ACCOUNTING NEW YORK 5 The order by Clause: example 2 Show details of employees in department 10 with the earliest hire dates first: SELECT empno, ename, hiredate FROM emp WHERE deptno = 10 ORDER BY hiredate; EMPNO ENAME HIREDATE CLARK 09-JUN KING 17-NOV MILLER 23-JAN

4 The order by Clause: example 3 Show all employees in job order but within each job place in descending order of salary: SELECT ename, job, sal, deptno FROM emp ORDER BY job, sal DESC; 14 rows will be selected. 7 The order by Clause: example 4 SELECT ename,job,sal, comm, comm/sal as ratio,deptno From emp Where deptno = 30 Order by ratio; ENAME JOB SAL COMM RATIO DEPTNO TURNER SALESMAN ALLEN SALESMAN WARD SALESMAN MARTIN SALESMAN BLAKE MANAGER JAMES CLERK (NB: Nulls sort high) 8 Group By Function Results can be grouped according to a common attribute value. We can find the sum of the salaries by department. SELECT deptno, sum(sal) FROM emp GROUP BY deptno; DEPTNO SUM(SAL)

5 Processing Data: Aggregate Functions Some simple functions include: Count: Min: Max: Sum: returns a count of rows returns the lowest value for an attribute returns the highest value for an attribute returns the sum of values Avg: returns the average value SELECT COUNT (*) FROM EMP COUNT(*) RETURNS THE NUMBER OF ROWS IN THE EMP TABLE. 10 Processing Data: min/max 11 You can find the highest salary: Select max(sal) from emp; MAX(SAL) Select min (sal) as min_sal from emp; MIN_SAL Processing Data: sum/average Sum is used on numeric functions to return the sum of all the values: SELECT sum(sal), sum (comm) from emp; SUM(SAL) SUM(COMM) SELECT avg(sal) from emp; AVG(SAL)

6 Having Clause We can constrain the subgroups that appear by using a HAVING CLAUSE. We can find the sum of the salaries of each department, but only request those departments with more than 5 employees. SELECT deptno, sum(sal) FROM emp GROUP BY deptno HAVING count (*) >5; DEPTNO SUM(SAL) The self-join Useful to put more than one aggregate function on the same row of output. E.g. Count the number of people in dept 10 who receive salary, and the number in dept 10 who receive commission SELECT COUNT(A.SAL) AS COUNTSAL, COUNT(B.COM) AS COUNTCOMM FROM EMP A, EMP B WHERE A.EMPNO=B.EMPNO AND A.DEPTNO=10; SQL DATA DEFINITION : DDL Create Table CREATE TABLE customer as follows: CREATE TABLE CUSTOMER (CUSTOMER_ID NUMBER (5), NAME VARCHAR2 (10), HOUSE_NUMBER NUMBER (2), STREET VARCHAR2 (15), TOWN VARCHAR2 (15)); Each column has a name, data type and column width. 15 5

7 DDL: Creating Tables continued. Here s an example. What s it doing? Create Table account (account_num number (6), Account_name varchar2 (20), Branch_name varchar2(20), Date_opened date, Balance number (10,2)); The Balance column is a decimal number with a maximum Column width of ten digits and a precision of two digits i.e is stored as Simple Constraints: Primary keys A correct definition of the table customer might be: CREATE TABLE CUSTOMER (CUSTOMER_ID NUMBER (5), PRIMARY KEY NOT NULL, NAME VARCHAR2 (10), HOUSE_NUMBER NUMBER (2), STREET VARCHAR2 (15), TOWN VARCHAR2 (15)); 17 Simple Constraints: Primary keys The PRIMARY KEY indicates that all values for these columns must be unique. NOT NULL is used to designate that the column must have a value for all its rows. 18 Therefore in the account table the first two lines should read: Create Table account (account_num number (6) primary key not null, 6

8 Simple Constraints: Customer and account has a many to many relationship, we can resolve this with a table constraint by creating a composite primary key. CREATE table customer_account (CUSTOMER_ID NOT NULL, ACCOUNT_NUM NOT NULL, PRIMARY KEY (CUSTOMER_ID,ACCOUNT_NUM)); 19 Simple Constraints: Foreign keys In the CUSTOMER_ACCOUNT table that we have just created we have two foreign keys CUSTOMER_ID and ACCOUNT_NUM. We can specify these at the time of defining the table as: CREATE table CUSTOMER_ACCOUNT CUSTOMER_ID NOT NULL REFERENCES CUSTOMER, ACCOUNT_NUM NOT NULL REFERENCES ACCOUNT, PRIMARY KEY(REFNO,ACCNO)); (In order to get rid of the old table use the command DROP table customer_account. Take care when using this command because when you have dropped a table it has gone for good!) 20 Simple Constraints: Foreign keys 21 When we have created a table we may find that the original definition of the table is now unsatisfactory. For example we may create another table BANK, and the account table has a foreign key reference to the table Bank in the attribute BRANCHNAME. Therefore we need to create a relation between Account and Bank. We can use the ALTER command to change the original definition of the Account table. ALTER TABLE ACCOUNT ADD(FOREIGN KEY(BRANCHNAME) REFERENCES BANK); 7

9 Dropping & altering objects DROP <object type> <object name DROP TABLE EMP; (NOT undoable!) ALTER <object type> object name> ADD <column name> <data type> /DROP COLUMN <column name> ALTER TABLE EMP ADD NICKNAME VARCHAR(30) 22 Inserting Data Using SQL 23 We use the SQL command INSERT to create rows. INSERT INTO CUSTOMER VALUES(12345, DAWES, 21, BACK LANE, STAFFORD ); Remember non-numerics require quotation marks around their values. These values have been entered into the Customer table in the order in which the columns appeared in the original create table statement. Deleting/UPDATING Data Using SQL Use the DELETE command to remove data from a relation (i.e. table). DELETE FROM CUSTOMER WHERE REFNO = 12345; Use the UPDATE command to alter the data held in the rows. i.e. Change the name in the account table from Dawes to Dalby. UPDATE CUSTOMER SET NAME = DALBY WHERE CUSTOMER_ID = 12345; 24 8

10 25 SQL SUMMARY You have worked through some simple SQL expressions and have learnt how to : Use the SELECT command for retrieving data. Use INSERT, UPDATE, AND DELETE commands to insert, amend and delete data. Use aggregate functions to assist with processing data, i.e. COUNT, MIN, MAX, SUM, AVG. Use DDL to create, alter and drop tables. Create some simple constraints using the WHERE clause. Use the GROUP BY, HAVING and ORDER BY functions to assist with selecting and displaying data. Create simple primary and foreign key constraints. Further Reading Rolland chapter 5 Patrick chapters 1-3, 9-11, 13 SQL at w3schools - click to follow the link 26 9

11 IRU SEMESTER January 2010 Semester 1 Session 2 Database implementation Further SQL Tutorial work A. Complete SQL exercise two (attached). B. Continue work on IRU assignment part one (if available). Be ready to demonstrate your solutions during next week s tutorial session. C:\Allwork\geoff\web stuff\askgeoff\iru\iru session 2 tutorial - SQL 2.doc

12 IRU SEMESTER 2 January 2010 SQL Exercise 2: 1: Find out how many managers there are without listing them. Display as below: COUNT(JOB) : Compute the average annual salary plus commission for all salesmen: COMPENSATION : Find the highest and lowest paid employees and the difference between them display as below: RICH POOR DIFFERENCE : Find the number of characters in the longest department name: LONGEST : Count the number of people in department 30 who receive a salary and the number of people who receive a commission: SALARIES COMMMISSION : List the average commission of employees who receive a commission and the average commission of all employees (treating employees who do not receive a commission as receiving a zero commission): AVECOMM AVEALL : List the average salary of employees that receive a salary, the average commission of employees that receive a commission, the average salary plus commission of only those employees that receive a commission, and the average salary plus commission of all employees including those who do not receive a commission. AVESAL AVECOMM AVETOTAL AVETOTALALLL C:\Allwork\geoff\web stuff\askgeoff\iru\iru session 2 tutorial - SQL 2.doc