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1 Pattern-Oriented Software Design (Fall 2013) Homework #1 (Due: 09/25/2013) 1. Introduction Entity relation (ER) diagrams are graphical representations of data models of relation databases. In the Unified Modeling Language (UML), entity relation diagram can be used to describe a database that contains the entities, and relationships between entities, within an information system in an abstract way. For example, Microsoft Visio (Figure 1) includes an UML modeling tool, which supports the drawing of ER diagrams. In this course, you are required to develop a non-trivial program called Entity Relation Diagramming Tool (ERD), which supports the construction and display of ER diagrams. Figure 1 Microsoft Visio The development of ERD is divided into several iterations. Each iteration is accomplished by a homework assignment. In general, each iteration includes implementing a number of system features, applying one or two design patterns in your design, writing and performing unit testing in your program, and drawing class diagrams for your design. 1

2 2. Text-mode interface In the first homework assignment, you need to implement some basic features and a textmode interface for ERD. The text-mode interface is shown in Table 1. There are 6 functionalities in the command menu. Users can first select "Add a node" command to add a specific node. A node can be an Entity, Attribute, or Relationship in an ER diagram. Examples of adding nodes are showed in Table 2. If the user selects a non-existent node, an error message should be showed: You entered an invalid node. Please enter a valid one again. In the example, the user uses command "E" to add an Entity with name "Engineer", and then uses command "A" to add an attribute with name "Emp_ID". Each time after the user adds a node, ERD shows all the nodes there are in the current diagram. Table 1 shows only part of addition steps. Please refer to Table 4 if you want to know the complete table. After the user adds two or more nodes, the user can use "Connect two nodes" command to connect nodes. An example is shown in Table 3. When the user enters the first node ID "0" and the second node ID "1", ERD connects the two nodes 0 and 1 and shows the connections. Of course, ERD should warn the user if he/she enters an ID that does not exist in the current diagram. In addition, an Attribute cannot connect to an Attribute, an Entity cannot connect to an Entity, and a relation cannot connect to a relation. In other words, it s illegal to connection two nodes of the same types. At any time, a user can select "Display the current diagram" command to view the nodes and connections in the diagram. Table 4 shows a display of ER diagram for Figure 2. Figure 2 An ER diagram sample When an Entity is properly connected to its attribiutes, the user can use "Set a primary key" command to set the primary keys of the Entity. An example is shown in Table 5. When the user enters the first node ID "0", ERD lists all attributes of the entity '0'. The user receives a warning, if he/she enters an ID that does not exist in the table. When the user enters the ID of the Attributes "1, 3", the setting of the primary keys of entity "0" finishes. ERD provides a feature that can display the corresponding database table for an ER diagram. For simplicity, this feature only supports ER diagrams with one-to-one relationships. An example is shown in Table 6. Note that, the table shown in Table 6 not the only legal solution (another solution is possible). In case that the ER diagram has relationships other than one-to-one, the diagram is not converted to tables. An example is shown in Table 7. 2

3 Finally, the user can use the "Exit" option to exit the tool. > Table 1 Text-mode interface Table 2 Add nodes What kind of node do you want to add? [A]Attribute [E]Entity [R]Relation > X You entered an invalid node. Please enter a valid one again. [A]Attribute [E]Entity [R]Relation > E Enter the name of this node: > Engineer A node [Entity] has been added. ID: 0, Name: "Engineer" Components: E 0 Engineer What kind of node do you want to add? [A]Attribute [E]Entity [R]Relation > A Enter the name of this node: > Emp_ID A node [Attribute] has been added. ID: 1, Name: "Emp_ID" Components: E 0 Engineer A 1 Emp_ID 3

4 What kind of node do you want to add? [A]Attribute [E]Entity [R]Relation > R Enter the name of this node: > Has A node [Relation] has been added. ID: 2, Name: "Has" Components: E 0 Engineer A 1 Emp_ID R 2 Has Table 3 Connect nodes > X The node ID you entered does not exist. Please enter a valid one again. The node '0' has been connected to the node '1'. Connections: Connection node node The node '1' cannot be connected to itself. 4

5 > 4 The node '4' cannot be connected by the node '0'. > 3 The node '3' cannot be connected by the node '1'. The node '1' has already been connected to component '0'. Enter the type of the cardinality: [0]1 [1]N The node '2' has been connected to the node '0'. Its cardinality of the relationship is '1'. Table 4 Display current diagram 5

6 > 3 The ER diagram is displayed as follows: Nodes: E 0 Engineer A 1 Emp_ID R 2 Has A 3 Name E 4 PC A 5 PC_ID A 6 Purchase_Date C 7 C 8 C 9 C 10 C 11 1 C 12 1 A 13 Department C Connections: Connection node node > 4 Entities: E 0 Engineer E 4 PC Table 5 Set the primary key Enter the ID of the entity: > 8 The node '8' is not an entity. Please enter a valid one again. 6

7 > X The node ID you entered does not exist. Please enter a valid one again. Attributes of the entity '0' A 1 Emp_ID A 3 Name A 13 Department Enter the IDs of the attributes (use a comma to separate two attributes):,4 The node '4' does not belong to Entity '0'. Please enter a valid one again.,3 The entity '0' has the primary key (1,3). Table 6 Display the table > 5 Tables: Entity Attribute Engineer PK(Emp_ID, Name), Department PC PK(PC_ID), Purchase_Date, FK(Emp_ID, Name) > 6 Goodbye! > 5 It has no table to display. Table 7 Display the table without an one-to-one relation 7

8 3. Applying MVC pattern Model view controller (MVC) is a software architecture pattern frequently used in software design. The pattern isolates "domain logic" (the application logic for the user) from the user interface (presentation). In this homework, you must apply MVC pattern to ERD (Entity Relation Diagram Drawing Tool). Figure 3 is a reference class diagram, when the MVC pattern is applied. 4. Applying Simple Factory pattern Simple Factory is a simplified variant of Factory Method pattern. It uses a factory class to create objects. Figure 3 shows the class diagram of the Simple factory pattern used in this homework. ComponentFactory is a factory class that offers creation operations. The createcomponent method takes a type parameter to specify the type of the primitive component to be created. After applying this pattern, except for ComponentFactory class, your program must avoid creating concrete devices by using the new keyword. That is, a statement such as "Component* entity = new Entity();" should be replaced by "Component* entity = factory.create(component_entity);" where the factory object is an instance of the ComponentFactory class. TextUI +dispalymenu() +processcommand() ERModel -components +addnode(type : int) +addconnection(node : components*, node : components*) +gettable() Component -id -type -text -connections +getid() +gettype() +gettext() ComponentFactory +createcomponent(type : int):component* Node Connector Entity Attribute Relationship Figure 3 MVC and Simple Factory pattern 5. Grading Please write a C++ program to implement ERD described above. The grading of this homework will be based on the following criteria: 1. Applying MVC pattern in the design of the ERD (20%) 8

9 2. Applying Simple Factory pattern in the design of the ERD (10%) 3. A text-mode interface and simulation program (35%) i. Add a node (5%) ii. Connect two nodes (5%) iii. Display the current diagram (5%) iv. Set Primary keys (5%) v. Display the table (10%) vi. Exit (5%) 4. Draw a class diagram (5%) 5. Time Measurement (0%, but necessary) You are required to record your working time into a time log sheet (reference Table). The following work items should be included: i. Reading the requirement of the homework ii. The design of your implementation, including drawing UML diagrams iii. Coding iv. Testing v. Other work items that spend you a lot of time, e.g., reading GoF book. You must submit your time log; otherwise, your homework will not be graded. 6. Summary (0%, but necessary) Before start doing your homework, please estimate (guess) the time (in hours) that you will need to spend on the homework, and write the estimated hours in the homework summary file. In addition, you are required to turn in your time log (the time in hours that you actually spent on the homework, including documentation, as precisely as possible). Please download the summary file template from the instructor s website. 7. Code Quality (30%) Please write a C++ program to perform the features described above. The efficiency of your program is not of concern in this homework. The grading of code quality will be based on whether your programs have bad smells. 9

10 作業批改原則 A. Crash 程式如果會 Crash 是很嚴重的問題, 因此批改標準比較嚴格 當批改作業時, 對於各個功能, 助教會依照作業題目中所提供的範例至少操作一遍, 此部分佔該功能得分的 60%, 但是, 若操作過程中發生 crash, 使得程式不能依範例執行時, 則這 60% 得 0 分 因此, 交作業前, 請務必針對範例作過詳細測試 此外, 助教也會使用其他的測試案例測試該功能, 此部分佔該功能得分的 40%, 同理, 如果有 crash 發生時, 則這 40% 得 0 分 B. 不能編譯 執行請依規定的環境安裝軟體, 若上傳的原始程式在助教安裝的環境中無法正常編譯 執行, 而在你自己的環境卻可以編譯 執行時, 則酌予扣分 當第一次發生時, 整體作業成績打九折, 第二次發生時, 打八折, 依此類推 C. 每個 class 均應有獨立的檔案, 且應分成.h 和.cpp 檔, 若未分檔案, 則扣該次作業成績 5 分 注意事項 : 1. 如果對作業有疑問, 請於成績出來後的一週內找助教討論, 否則不予以理會 2. 每次作業可申請複查一次, 助教將會對於申請複查之項目重新批閱 例如 : 對於程式碼品質上有扣分錯誤, 則會對整份作業重新批改, 並重新計算該項分數 10

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