Lecture 2: Fun with Search. Rachel Greenstadt CS 510, October 5, 2017

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1 Lecture 2: Fun with Search Rachel Greenstadt CS 510, October 5, 2017

2 Reminder! Project pre-proposals due tonight

3 Overview Uninformed search BFS, DFS, Uniform-Cost, Graph-Search Informed search Heuristics, A*, admissibility, consistency, memory-bounded A* Discussions

4 Why search? Agents with several immediate options of unknown value can choose actions by: examining different sequences of actions choosing the best sequence Examples?

5 Tree Search Explore state space by generating successors of explored states Need Initial State Goal test How Path cost Successor function to get from Arad to Bucharest?

6 Tree Search Initial State : In(Arad) Successor function <action, successor> (Go(Sibiu), In(Sibiu)) Go( Timisoara), In(Timisoara) Go(Zerind), In(Zerind) Goal test: In(Bucharest) Path cost: sum of step costs (in km) How to get from Arad to Bucharest?

7 Class Exercise You have three jugs: 12 gal, 8 gal, and 3 gal and a water faucet. You can fill the jugs up or pour them out from one into another or onto the ground You need to measure out exactly one gal In groups, determine the following precisely enough to implement: Initial state Goal test Successor function Cost function

8 Applications

9 The Mother of All Search Algorithms current_state <= start_state loop: is current_state = goal_state? if yes, output path and terminate generate all next states of current_state and add to fringe set current_state <= choose from fringe set

10 Complications How to choose next state from fringe set? Answer has significant implications on: Time complexity Number of loops Space complexity Size of fringe set Completeness Does loop terminate? Optimality Quality of solution path

11 Measuring complexity b: maximum branching factor (largest number of next states of any state) d: steps to goal m: maximum possible path length not always finite

12 Breadth-first search Expand shallowest unexpanded node Implementation: FIFO queue is data structure for fringe set A B C D E F G

13 Breadth-first search Expand shallowest unexpanded node Implementation: FIFO queue is data structure for fringe set A B C D E F G

14 Breadth-first search Expand shallowest unexpanded node Implementation: FIFO queue is data structure for fringe set A B C D E F G

15 Breadth-first search Expand shallowest unexpanded node Implementation: FIFO queue is data structure for fringe set A B C D E F G

16 Properties of BFS Complete? Optimal? Space? Size of fringe set? O(b d+1 ) Time?

17 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

18 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

19 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

20 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

21 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

22 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

23 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

24 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

25 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

26 Depth-first search Expand deepest unexpanded node Implementation: LIFO (stack) is data structure for fringe set A B C D E F G H I J K L M N O

27 Properties of DFS Space? bm+1 Time? Optimal? Complete? No. Why?

28 Properties of DFS Complete? Spaces with loops Modify to avoid repeated states along path Infinite-depth spaces What if we cut off after depth limit L Depth-Limited DFS

29 Guaranteeing Completeness Idea: Invoke Depth-Limited DFS with iteratively increasing values of L This is called Iterative Deepening Search

30 Iterative Deepening L=0

31 Iterative Deepening L=1

32 Iterative Deepening L=2

33 Iterative Deepening L=3 Etc.

34 Iterative Deepening Search--how efficient? Re-expanding all those nodes seems bad # of nodes in depth-limited search L=d N = b0 + b 1 +b b d-2 +b d-1 +b d # of nodes in iterated deepening search to L=d N = (d+1)b0 + db 1 +(d-1)b b d-2 +2b d-1 +b d For b=10, d=5 N= ,000+10, ,000=111,111 N= ,000+20, ,000=123,456 Overhead = (123, ,111)/111,111=12,345/111,111=11.11%

35 Bi-directional Search Search gets less efficient with depth Minimize depth by doing two searches Forward from the Start State Backward from the Goal Catch: sometimes it s hard to go backward from the goal

36 What if not all paths are equal?

37 Uniform-cost search Expand least-cost unexpanded node Implementation: fringe is priority queue ordered by path cost Same as breath first search if all steps equal A D 3 B 4 E 1 3 F 0 C 4 G

38 Uniform-cost search Expand least-cost unexpanded node Implementation: fringe is priority queue ordered by path cost Same as breath first search if all steps equal A D 3 B 4 E 1 3 F 0 C 4 G

39 Uniform-cost search Expand least-cost unexpanded node Implementation: fringe is priority queue ordered by path cost Same as breath first search if all steps equal A D 3 B 4 E 1 3 F 0 C 4 G

40 Uniform-cost search Expand least-cost unexpanded node Implementation: fringe is priority queue ordered by path cost Same as breath first search if all steps equal A D 3 B 4 E 1 3 F 0 C 4 G

41 Notation: g(n) g(n) : cost of path from start to node n Fringe is priority queue ordered by g(n) Goal test when expanded rather than generated (avoid suboptimal path) D 3 B 4 E 1 A g=1 g=3 g=4 g=5 g=3 g=7 3 F 0 C 4 G

42 Uniform-cost Search Complete? If step cost >= Epsilon Time and Space? Cost of Optimal Soln = C* Cost = O(b 1+floor(C*/E) )

43 Graph Search Remove repeated states

44 Summary of algorithms Note: should be floor not ceiling in Uniform-Cost search

45 What about complexity?

46 What about complexity? Or, hey these AI algorithms don t seem so smart!

47 Heuristics NP-Complete problems: impossible to guarantee optimality and sub-exponential run-time A heuristic algorithm gives up one or both Gives good average run-time or good (but not guaranteed optimal) solutions

48 Heuristic in Search Heuristic: a rule of thumb Formally: function that maps a state onto an estimate of the cost to the goal from that state Define h(n) = estimated cost of path from node n to goal if n is goal then h(n)=0. h(a)=10 g(n ) a h(b)=18 h(g)=0 S n b G c h(c)=7

49 Using Heuristics in Informed Search Assume h(n) is given. How can we use it to do search? Data structure for the fringe set? h(a)=10 g(n ) a h(b)=18 h(g)=0 S n b G c h(c)=7

50 Greedy Best-First Search Priority queue using h(n) Pick the node closest to the goal Example fringe (b,18) (a,10) (c,7) h(a)=10 g(n ) a h(b)=18 h(g)=0 S n b G c h(c)=7

51 When Greedy Search Goes Bad h(a)=1 g(n ) 100 a 1 h(g)=0 S Expand successors of n n b f e G h(b)=3 h(e)=2 h(f)=1 Fringe set [(b,h(b)=3), (a, h(a)=1)] Expand successors of a Fringe set [(b, h(b)=3), (G,h(G)=0)] Expand G...found goal...solution path: S...n ->a->g cost = g(n ) Not optimal, g(n ) + 4 exists

52 How to fix? So we have g(n) : Cost from start to n uniform-cost search h(n) : Estimated cost from n to goal greedy best-first search Ideas?

53 A* Search h(a)=1 g(n ) = a 1 h(g)=0 S n b f e G h(b)=3 h(e)=2 h(f)=1 Take into account total path cost Fringe set as a priority queue ordered by f(n) = g(n) + h(n) f(b) =? f(a) =? A* is really important

54 A* Search Example h(a)=1 g(n ) = a 1 h(g)=0 S In state n n b f e G h(b)=3 h(e)=2 h(f)=1 Two successors, a and b f(a) = g(a) + h(a) = = 111 f(b) = g(b) + h(b) = = 14 Fringe set ={(b,14), (a,111)} Choose to expand b Next fringe = {(f,14),(a,111)}

55 Is A* Guaranteed Optimal? h(a)=1 g(n ) = a 1 h(g)=0 S n b f e G h(b)=200 h(e)=2 h(f)=1 Nope, see h(b) A* will return S...n -> a -> G Heuristics can be wrong

56 Good Heuristics : Admissibility h(a)=1 g(n ) = a 1 h(g)=0 S n b f e G h(b)=200 h(e)=2 h(f)=1 Let h*(n) be the real cost of cheapest path from n to goal Definition: h(n) is admissible iff for all n, h(n) is less than or equal h*(n) Is h(n ) = 99 admissible? Is h(n ) = 4 admissible? Is h(b) = 4 admissible? Is h(b) = 0 admissible? Straight line distance on a map?

57 Theorem: If h(n) is admissible, A* is optimal (if no repeated states) Optimal Soln G1 n S G2 Suppose G 2 is suboptimal and path (S...n...G2) is returned by A* Let n be the first unexpanded node in the optimal path to G1 In A*, the only way G2 is expanded before n is if f(n) > f(g2) This is how priority queues work Assume f(n) > f(g 2) : This is a contradiction, why?

58 Proof: f(n) > f(g 2) f(g 2) = g(g2) + h(g2) f(g 2) = g(g2) f(g 2) > g(g1) f(g 2) > g(n) + h*(n) f(g 2) > g(n) + h(n) f(g 2) > f(n) (Contradiction) Assumption def of f def of h (G 2 is a goal state) G 2 is suboptimal n is on opt path to G 1 h is admissible def of f

59 When Admissibility Fails a h(a)=5 g(n ) = h(g)=0 S n h(n)=7 4 b h(b)=1 4 G Is h admissible?

60 When Admissibility Fails a h(a)=5 g(n ) = h(g)=0 S n h(n)=7 4 b h(b)=1 4 G Expand node n: f(a) = = 17 f(b) = = 15 Fringe set {(a,17), (b,15)} Expand b: f(g) = 14+4 = 18 Fringe set {(G,18),(a,17)} Expand a : Ignore b since b already visited Expand G : test for goal, done. But suboptimal

61 Still not optimal using Graph-Search Graph-Search avoids repeated states by ignoring previously seen states What if the second path to the state is optimal? Graph-Search discards it This is why the proof breaks down if repeated states Need yet another requirement...

62 Consistency a h(a)=5 g(n ) = h(g)=0 S n h(n)=7 4 b h(b)=1 4 G What is wrong with h?

63 Consistency a h(a)=5 g(n ) = h(g)=0 S n h(n)=7 4 b h(b)=1 4 G Require that h(a) <= h(b) + cost(a,b) Make the heuristic obey the triangle inequality

64 Consistent Heuristics A heuristic is consistent if For every node n And every successor n of n Generated by any action a cost(n,a,n ) + h(n ) >= h(n)

65 Consistent heuristics If h is consistent, f(n) is nondecreasing along any path c(n,a,n ) n h(n) f(n ) = g(n ) + h(n ) n = g(n) + c(n,a,n ) + h(n ) h(n ) G >= g(n) + h(n) f(n ) >= f(n)

66 Consistent Implies Admissible Thm: h(n) <= h*(n) for all n Proof by induction: Base case: h*(n) = 0 ; n is a goal state so h(n) = 0 by definition Assume h(n ) <= h*(n ) Lemma: h(n) <= h*(n) h(n) <= c(n,n ) + h(n ) by consistency <= c(n,n ) + h*(n ) by inductive hypothesis h(n) <= h*(n) by definition Inductive hypothesis: For all n after n on shortest path to Goal

67 Properties of A* Complete: yes (unless infinite nodes where f<=f(g) ) Time: exponential Space: All nodes in memory Optimal: Yes (if using consistent heuristic and Graph-Search)

68 Time: find a good admissible heuristic What kind of heuristics?

69 Time: find a good admissible heuristic h1(n) = # of misplaced tiles h2(n) = manhattan distance to goal (total number of squares from goal state) h1(s) = 8 h2(s) = =18

70 Dominance if h2(n) >= h1(n) for all n (both admissible) then h2 dominates h1 h2 is better for search IDS A*(h1) A*(h2) 8-puzzle puzzle puzzle too big

71 Complexity So time might be manageable with good heuristics, but space? Memory-bounded A*

72 Simplified Memory- Bounded A* Use all available memory Expand best leaves until you can t Remove worst leaf (highest f-value) Solve ties by expanding newest best leaf and removing oldest worst leaf Complete if soln reachable, optimal if optimal soln reachable

73 Iterative Deepening A* (IDA*) Use iterative deepening to progressively expand the memory usage based on f-cost Runs into the same problems as Uniform- Cost if paths/heuristics are real-valued

74 Recursive Best First Search (RBFS) Keep track of the best alternative path (f-limit) When current f-values exceed f-limit Backtrack and Store best f-value of children at backtracked nodes

75 Readings this week: Lawrence Page, Sergey Brin, Rajeev Motwani, Terry Winograd, The PageRank Citation Ranking: Bringing Order to the Web, Stanford University, SIDL- WP , November Katia Sycara. Multiagent Systems. AAAI Magazine, 1999 Remember: Discussion points by Tuesday at 6 pm, online replies by Thursday at 3 pm.

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