# A complex expression to evaluate we need to reduce it to a series of simple expressions. E.g * 7 =>2+ 35 => 37. E.g.

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1 1.3a Expressions

2 Expressions An Expression is a sequence of operands and operators that reduces to a single value. An operator is a syntactical token that requires an action be taken An operand is an object on which an operation is performed; it receives an operator s action. A simple expression contains only one operator. E.g. 2+5 is a simple expression which gives 7 -a is a simple expression A complex expression to evaluate we need to reduce it to a series of simple expressions. E.g * 7 =>2+ 35 => 37

3 Expression Categories Expression Categories Primary Postfix Prefix Unary Binary Ternary

4 Primary Expressions Most elementary type of expression A primary expression consists of only one operand with no operator Operands can be name, constant, a parenthesized expression Primary expression is evaluated first in case of precedence Name: is any identifier for a variable, function or any other object in the language. E.g.: a b12 int_max SIZE Literal Constants: It is a piece of data whose value can t be changed during the execution of the program E.g.: A Welcome Parenthetical Expressions: Any value enclosed in parenthesis may be reducible to a single value E.g.: (2* 3+4) (a=23 + b * 6)

5 Postfix Expressions Operand Operator Postfix expression consists of one operand followed by one operator Postfix Increment: value is increased by 1.Thus a++ results in the variable a being increased by 1.The effect is the same as a=a+1. a++ has the same effect as a=a+1 The difference is that the value of the postfix increment expression is determined before the variable is increased x++, where ++ appears after its operand, post-increment operator x--, the decrement operator is called the post-decrement operator

6 Postfix Increment and decrement Postfix increment and decrement has a value and a side effect For instance, if a variable contains 4 before the expression is evaluated, the value of the expression is evaluated,i.e, the value of expression a++ is 4.As a result of evaluating the expression and it s side effect, a contains 5 Postfix decrement (a--), the value of the expression is the value of a before the decrement; the side effect is the variable is decremented by 1 y = x++; y is assigned the original value of x first, then x is increased by 1. y = x--; the assignment of y to the value of x takes place first, then x is decremented.

7 Prefix Expressions Operator Operand/ Variable Two prefix operators : Prefix increment and Prefix decrement The operand of a prefix expression must be a variable ++ a has the same effect as a =a+1 ++x, where ++ appears before its operand, pre-increment operator The operator first adds 1 to x, and then yields the new value of x --x;, the pre-decrement operator first subtracts 1 from x and then yields the new value of x

8 Example

9 Example int w, x, y, z, result; w = x = y = z = 1; printf( w = %d, x = %d, y = %d, z = %d,\n, w, x, y, z); result = ++w; printf( ++w evaluates to %d, w is now %d\n, result, w); result = x++; printf( x++ evaluates to %d, x is now %d\n, result, x); Given w = 1, x = 1, y = 1, and z = 1, ++w evaluates to 2 and w is now 2 x++ evaluates to 1 and x is now 2

10 Unary Expression Consist of one operator and one operand Like the prefix expression, the operator comes before the operand But unlike the prefix expression, unary expression can have an expression or variable as the operand Operator Operand

11 sizeof Gives the size in bytes of a type or primary expression By specifying the size of an object during execution, we make our program more portable with other hardware sizeof (int) sizeof sizeof x

12 Unary Plus /Minus If the expression s value is negative, it remains negative If the expression s value is positive, it remains positive Expression Contents of a before and after expression +a a 3-3 +a a Expression Value

13 Cast Operator Cast operator converts one expression type to another (type_name) expression To convert an integer to a real number, float(x) Only the expression value is changed, the integer variable x is unchanged

14 Example :Cast operator #include <stdio.h> main() { int sum = 17, count = 5; double mean; mean = (double) sum / count; printf("value of mean : %f\n", mean ); } When the above code is compiled and executed, it produces the following result Value of mean :

15 BinaryExpressions Operand Operator Operand Binary expressions are formed by an operand-operatoroperand combination Any two numbers added,subtracted,multiplied or divided are usually formed in algebraic notation, which is a binary expression a + b c - d

16 Multiplicative Expressions Which take its name from the first opearator,include the multiply, divide and modulus operator These operators have the highest priority among the binary operators and therefore evaluated first among them Result of a multiply operator (*) is the product of the two operands Operands can be any arithmetic type 10 * 3 //evaluates to 30 true * 4 //evaluates to 4 A * 2 //evaluates to * 2 //evaluates to 44.6 (2 + 3 * I) * (1 + 2 * I) //evaluates to * I

17 Divide operator Multiplicative Expressions Result of a divide operator (/) depends on the type of the operands. If one or both operands is a floating point type, the result is a floating point quotient If both operands are integral type, the result is the integral part of the quotient 10 / 3 //evaluates to 3 true / 4 //evaluates to 0 A / 2 //evaluates to / 2 // //evaluates to 11.15

18 Modulus Operator (%) Multiplicative Expressions This operator divides the first operator by second operator and returns the remainder rather than quotient Both operands must be integral type and the operator returns the remainder as an integer type 10 % 3 //evaluates to 1 true % 4 //evaluates to 1 A % 2 //evaluates to % 2 // Error: Modulo cannot be Floating Point Both Operands of the modulo operator (%) must be integral types

19 Division and Modulus Operator The value of an expression with the division operator is the quotient and the value of the expression with the modulus operator is remainder 3 / 5 //evaluates to 0 3 % 5 //evaluates to 3 If the integral operand is smaller than the second integral operand, the result of division is zero and the result of the modulo operator is the first operand 3 / 7 //evaluates to 0 3 % 7 //evaluates to 3

20 Additive Expressions Depending on the operator used, the second operand is added or subtracted from the first operand The operand in an additive expression can be any arithmetic types (integral or floating point) Additive operators have lower precedence than multiplicative operators //evaluates to //evaluates to -4

21 Assignment Expressions Assignment Operator evaluates the operand on the right side of the operator (=) and places it s value in the variable on the left. The assignment expression has a value and a side effect The value of the total expression is the value of the expression on the right of the assignment operator (=) The side effect places the expression value in the variable on the left of the assignment operator The left operand in an assignment expression must be a single variable There are two forms of assignment : simple and compound

22 Simple Assignment Found in algebraic expressions a = 5 b = x + 1 i = i +1 Left variable must be able to receive it, that is, it must be a variable and not a constant If the left operand cannot receive a value and we assign one to it, we get a compile error

23 Compound Assignment A compound assignment requires that the left operand be repeated as part of the right expression Five compound assignment operators are *=,/=,%=,+=,-= To evaluate the compound assignment, first change it to a simple assignment, then perform the operation to determine the value of the expression Compound Expression x *= expression x /= expression x %= expression x += expression x -= expression Equivalent Simple Expression x = x * expression x = x / expression x = x % expression x = x + expression x = x - expression

24 Compound Expression Evaluation x *= y + 3 is evaluated as x = x * (y + 3) which, given the values x is 10 and y is 5, evaluates to 80.

25 Short hand Assignment Operators = Assignment * = Multiply and assign / = Divide and assign % = Modulo and assign + = Add and assign - = Subtract and assign << = Bitwise left shift and assign >> = Bitwise right shift and assign & = Bitwise AND and assign ^ = Bitwise XOR and assign = Bitwise OR and assign

26 = Assignment The left operand is the variable to be assigned The right hand side is evaluated and its type converted to the type of the variable on the left and stored in the variable Assign multiple variables on a single line:this is possible because, assignment operators return the value that was stored in the variable

27 a = c = 5; printf( "a = %dn", a ); c = 5 is done first, then the value of c (which is now 5) is assigned to a a <<= c - 3; printf( "a = %dn", a ); a variable is 5 (101 in binary), which when left shifted by 2 becomes 20 (10100 in binary) a &= c; printf( "a = %dn", a ); a ( 20 decimal, binary ) bitwise and (keeps only the 1 bits that are common to both numbers ) with c ( 5 decimal, 101 binary ) results in 4 ( 100 binary ), which is then stored in a.

28 int a = 8.3; float b = 1.343f; int c; a = 8, b = printf( "a = %d, b = %fn", a, b ); a += 2; b *= a; printf( "a = %d, b = %fn", a, b ); a %= 4; b -= 0.43; printf( "a = %d, b = %fn", a, b ); a = 10, b = a = 2, b =

29 int i; i = 10; /* Assignment */ printf("i = 10 : %d\n",i); i++; /* i = i + 1 */ printf ("i++ : %d\n",i); i += 5; /* i = i + 5 */ printf ("i += 5 : %d\n",i); i--; /* i = i = 1 */ printf ("i-- : %d\n",i); i -= 2; /* i = i - 2 */ printf ("i -= 2 : %d\n",i); i *= 5; /* i = i * 5 */ printf ("i *= 5 :%d\n",i); i /= 2; /* i = i / 2 */ printf ("i /= 2 : %d\n",i); i %= 3; %d\n",i); /* i = i % 3 */ printf ("i %= 3 : Assignment Operators i = 10 : 10 i++ : 11 i += 5 : 16 i-- : 15 i -= 2 : 13 i *= 5 :65 i /= 2 : 32 i %= 3 : 2

30

31

32 Associativity Associativity can be from left to right or right to left. Left to right associativity evaluates the expression by starting on the left and moving to the right Right to left associativity evaluates the expression by starting on the right and moving to the left Associativity is used only when the operators have same precedence.

33 Left to Right Associativity (* / % ) all have the same precedence 3 * 8 / 4 % 4 * 5 Associativity determines how the sub expressions are grouped together.thier associativity is from left to right

34 Right to Left Associativity E.g.- a += b *= c -= 5 here more than one assignment operator occurs (a += (b *= (c -= 5))) which may be expanded to (a = a+ (b= b* (c =c-5))) (a = 3 + (b = (5 * (c = 8 5) ) ) The value of complete expression is 18 If we need to do a simple initializing then a=b=c=d=0

35 Example If a programmer wishes to perform: z = a + b / c; it may be interpreted as??????? z=(a+b)/c or z=a+(b/c) if a=3,b=6,c=2 then z=4.5 or z=6 In arithmetic expressions scanning is always done from left to right Priority of operations : First Second Third Parenthesis or brackets() Multiplication & Division Addition & Subtraction Fourth Assignment i.e, = Now what is the value of Z? 6 An expression always reduces to a single value

36 Associativity: left-to-right Parentheses (function call) () Brackets (array subscript) [] Member selection via object name. Member selection via pointer -> Postfix increment/decrement ++ --

37 Associativity: right-to-left Prefix increment/decrement Unary plus/minus + - Logical negation/bitwise complement! ~ Cast (change type) (type) Dereference * Address & Determine size in bytes sizeof

38 Associativity: left-to-right * / % + - << >> < <= > >= ==!= & ^ &&,

39 Associativity: right-to-left?: = += -= *= /= %= &= ^= = <<= >>=

40 Example * 2 is calculated as???????? 5 + (3 * 2), giving 11, and not as (5 + 3) * 2, giving 16 :has higher "precedence" than + so the multiplication must be performed first PRECEDENCE/PRIORITY is calculated as???????? (8-3) - 2, giving 3, and not as 8 - (3-2), giving 7: - is "left associative", so the left subtraction must be performed first ASSOCIATIVITY

41 Example result=10+20%5-15*5/2 1. % is evaluated first The remainder is 0 when 5 divides result= *5/2 Multiplication is performed 15*5=75 3. result= /2 Division is performed 75/2 results in 37 instead of result= Addition is performed because it comes before minus 5. result= Finally subtraction is performed and 27 is stored in the variable result

42 Example i= 2*3/4+4/ /8 i is????????????? i=6/ /8 i=1+4/ /8 i= /8 i= i= i= i=8+0 i=8

43 Example Add parentheses to the following expression to make the order of evaluation more clear: year % 4 == 0 && year % 100!= 0 year % 400 == 0 ((year % 4 == 0) && (year % 100!= 0)) (year % 400 == 0)

44 Precedence and Associativity Precedence is used to determine the order in which different operators in a complex expression are evaluated. Associativity is used to determine the order in which operators with the same precedence are evaluated in a complex expression Associativity determines how operators of same preference group together to form complex expression are Precedence is applied before associativity to determine the order in which expressions are evalaued,associativity is then applied, if necessary

45 Hierarchy of operations The preference in which arithmetic operations are performed in an arithmetic expression is called as Hierarchy of operations Operator Precedence Chart- Highest to Lowest Operators Type! Logical NOT * / % Arithmetic and modulus + - Arithmetic ==!= Relational && Logical AND Logical OR = Assignment Operators higher in the chart have a higher precedence,meaning that the C compiler evaluates them first. Operators on the same line in the chart have the same precedence.

46 Examples E.g.1: * 4 This is actually 2 binary expressions with one addition and one Multiplication operator Multiplication is done first, followed by addition.the value of the complete expression is 14 (2 + (3 * 4) ) 14 E.g.2:- -b++ First operation is unary minus followed by postfix increment where postfix increment has the highest precedence and is evaluated first followed by unary minus (- (b++) ) Assuming the value of b is 5 initially, the expression is evaluated to -5.

47 Side Effects A side Effect is an action that results from the evaluation of an expression. C first evaluates the expression on the right of the assignment operator and then places the value in the left variable. Changing the value of the left variable is a side effect. x = 4; Expression has 3 parts: first,on the right of the assignment operator is a primary expression that has the value 4 second,the whole expression(x=4) has a value of 4 third, as a side effect, x receives the value 4

48 Example x = x + 4 Assuming that x has the initial value of 3, the value of the expression on the right of the assignment operator has a value 7.The whole expression also has the value of 7.And as a side effect,x receives the value of 7 int x =3; printf( step 1 Value of x: %d\n, x) printf(( step 2 -Value of x =x + 4: %d\n,x=x+4); printf(( step 2 -Value of x now:%d\n,x);

49 Evaluating Expressions Divided into Expression with side effects and Expressions without side effects Expressions without side effects: The first expression has no side effects, so the values of all of it s variables are unchanged a * 4 + b / 2 c * b Assume that all the variables are a b c

50 Evaluation of Expressions without side effects 1. Replace the variables by their values 3 * / 2 5 * 4 2. Evaluate the highest precedence operators and replace them with the resulting value (3 * 4) + (4/2) (5* 4) Repeat step 2 until the result is a single value

51 Expression with Side Effects --a * (3 + b) / 2 c++ * b 1. Calculate the value of the parenthesized expression (3 + b) first --a * 7 / 2 c++ * b 2. Evaluate the postfix expression ( c++) next --a * 7 / 2 5 * b 3. Evaluate the prefix expression (--a) 2 * 7 / 2 5 * b 4. The multiply and division are now evaluated using their associativity rule, left to right 14 /2-5 * b -> 7 5 * 4 -> The last step is to evaluate the subtraction. The final expression value is > -13 After the side effects: a b c

52 Remember. In C,if a single variable is modified more than once in an expression, the result is undefined

53 Statements A statement causes an action to be performed by the program It translates directly into one or more executable computer instructions. Most statements need a semicolon at the end Types of statements are as follows: Statement Null Expression Return Compound Conditional Labeled switch iterative Break Continue Goto

54 Null statement It is just a semicolon (;) It can appear wherever a statement is expected. Nothing happens when a null statement is executed. ; //null statement for ( i = 0; i < 10; line[i++] = 0 ) ;

55 Expression Statement An expression is turned into a statement by placing a semicolon(;) after it expression; //expression statement a = 2; The effect of the expression statement is to store the value 2 in the variable a. The value of the expression is 2.After the value has been stored, the expression is terminated and the value is discarded. continues with the next statement.

56 Expression Statement a = b = 3; The statement actually has two expressions. a = (b =3) The (b =3) has a side effect of assigning the value 3 to the variable b.the value of this expression is 3.Since the expression is terminated by the semicolon, it s value 3, is discarded. The effect of the expression statement, is that 3 has been stored in both a and b.

57 Return Statement A return statement terminates a function. All functions, including main, must have a return statement. When there is no statement at the end of the function, the system inserts one with a void return value. return statement ; \\return statement return statement can return a value to the calling function In case of main, it returns a value to the operating system rather than to another function A return value of 0 tells the operating systems that the program executed successfully

58 Compound statements A compound statement is a unit of code consisting of zero or more statements. It is known as a block. The compound statement allows a group of statements to become one single entity All C functions contain a compound statement known as a function body.

59 Compound Statement A compound statement consists of an opening brace, an optional declaration and definition section and an optional statement section, followed by a closing brace Compound statement does not need a semicolon. Both opening and closing brace acts as the delimiters If we put a semicolon, compiler thinks that it is an extra null statement. Every declaration in C is terminated by a semicolon Most statements in C are terminated by a semicolon

60 Any queries????

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