CS 179: GPU Programming. Lecture 14: Inter-process Communication
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1 CS 179: GPU Programming Lecture 14: Inter-process Communication
2 The Problem What if we want to use GPUs across a distributed system? GPU cluster, CSIRO
3 Distributed System A collection of computers Each computer has its own local memory! Communication over a network Communication suddenly becomes harder! (and slower!) GPUs can t be trivially used between computers
4 We need some way to communicate between processes
5 Message Passing Interface (MPI) A standard for message-passing Multiple implementations exist Standard functions that allow easy communication of data between processes Works on non-networked systems too! (Equivalent to memory copying on local system)
6 MPI Functions There are seven basic functions: MPI_Init initialize MPI environment MPI_Finalize terminate MPI environment MPI_Comm_size MPI_Comm_rank how many processes we have running the ID of our process MPI_Isend MPI_Irecv send data (nonblocking) receive data (nonblocking) MPI_Wait wait for request to complete
7 MPI Functions Some additional functions: MPI_Barrier wait for all processes to reach a certain point MPI_Bcast MPI_Reduce send data to all other processes receive data from all processes and reduce to a value MPI_Send MPI_Recv send data (blocking) receive data (blocking)
8 The workings of MPI Big idea: We have some process ID We know how many processes there are A send request/receive request pair are necessary to communicate data!
9 MPI Functions Init int MPI_Init( int *argc, char ***argv ) Takes in pointers to command-line parameters (more on this later)
10 MPI Functions Size, Rank int MPI_Comm_size( MPI_Comm comm, int *size ) int MPI_Comm_rank( MPI_Comm comm, int *rank ) Take in a communicator For us, this will be MPI_COMM_WORLD essentially, our communication group contains all processes Take in a pointer to where we will store our size (or rank)
11 MPI Functions Send int MPI_Isend(const void *buf, int count, MPI_Datatype datatype, int dest, int tag, MPI_Comm comm, MPI_Request *request) Non-blocking send Program can proceed without waiting for return! (Can use MPI_Send for blocking send)
12 MPI Functions Send int MPI_Isend(const void *buf, int count, MPI_Datatype datatype, int dest, int tag, MPI_Comm comm, MPI_Request *request) Takes in A pointer to what we send Size of data Type of data (special MPI designations MPI_INT, MPI_FLOAT, etc) Destination process ID
13 MPI Functions Send int MPI_Isend(const void *buf, int count, MPI_Datatype datatype, int dest, int tag, MPI_Comm comm, MPI_Request *request) Takes in (continued) A tag nonnegative integers Uniquely identifies our operation used to identify messages when many are sent simultaneously MPI_ANY_TAG allows all possible incoming messages A communicator (MPI_COMM_WORLD) A request object Holds information about our operation
14 MPI Functions - Recv int MPI_Irecv(void *buf, int count, MPI_Datatype datatype, int source, int tag, MPI_Comm comm, MPI_Request *request) Non-blocking receive (similar idea) (Can use MPI_Irecv for blocking receive)
15 MPI Functions - Recv int MPI_Irecv(void *buf, int count, MPI_Datatype datatype, int source, int tag, MPI_Comm comm, MPI_Request *request) Takes in A buffer (pointer to where received data is placed) Size of incoming data Type of data (special MPI designations MPI_INT, MPI_FLOAT, etc) Sender s process ID
16 MPI Functions - Recv int MPI_Irecv(void *buf, int count, MPI_Datatype datatype, int source, int tag, MPI_Comm comm, MPI_Request *request) Takes in A tag Should be the same tag as the tag used to send message! (assuming MPI_ANY_TAG not in use) A communicator (MPI_COMM_WORLD) A request object
17 Blocking vs. Non-blocking MPI_Isend and MPI_Irecv are non-blocking communications Calling these functions returns immediately Operation may not be finished! Should use MPI_Wait to make sure operations are completed Special request objects for tracking status MPI_Send and MPI_Recv are blocking communications Functions don t return until operation is complete Can cause deadlock! (we won t focus on these)
18 MPI Functions - Wait int MPI_Wait(MPI_Request *request, MPI_Status *status) Takes in A request object corresponding to a previous operation Indicates what we re waiting on A status object Basically, information about incoming data
19 MPI Functions - Reduce int MPI_Reduce(const void *sendbuf, void *recvbuf, int count, MPI_Datatype datatype, MPI_Op op, int root, MPI_Comm comm) Takes in A send buffer (data obtained from every process) A receive buffer (where our final result will be placed) Number of elements in send buffer Can reduce element-wise array -> array Type of data (MPI label, as before)
20 MPI Functions - Reduce int MPI_Reduce(const void *sendbuf, void *recvbuf, int count, MPI_Datatype datatype, MPI_Op op, int root, MPI_Comm comm) Takes in (continued) Reducing operation (special MPI labels, e.g. MPI_SUM, MPI_MIN) ID of process that obtains result MPI communication object (as before)
21 int main(int argc, char **argv) { int rank, numprocs; MPI_Status status; MPI_Request request; MPI_Init(&argc,&argv); MPI_Comm_size(MPI_COMM_WORLD,&numprocs); MPI_Comm_rank(MPI_COMM_WORLD,&rank); MPI Example Two processes Sends a number from process 0 to process 1 Note: Both processes are running this code! } int tag=1234; int source=0; int destination=1; int count=1; int send_buffer; int recv_buffer; if(rank == source){ send_buffer=5678; MPI_Isend(&send_buffer,count,MPI_INT,destination,tag, MPI_COMM_WORLD,&request); } if(rank == destination){ MPI_Irecv(&recv_buffer,count,MPI_INT,source,tag, MPI_COMM_WORLD,&request); } MPI_Wait(&request,&status); if(rank == source){ printf("processor %d sent %d\n",rank,recv_buffer); } if(rank == destination){ printf("processor %d got %d\n",rank,recv_buffer); } MPI_Finalize(); return 0;
22 Solving Problems Goal: To use GPUs across multiple computers! Two levels of division: Divide work between processes (using MPI) Divide work among a GPU (using CUDA, as usual) Important note: Single-program, multiple-data (SPMD) for our purposes i.e. running multiple copies of the same program!
23 Multiple Computers, Multiple GPUs Can combine MPI, CUDA streams/device selection, and single-gpu CUDA!
24 MPI/CUDA Example Suppose we have our polynomial problem again Suppose we have n processes for n computers Each with one GPU (Suppose array of data is obtained through process 0) Every process will run the following:
25 MPI/CUDA Example MPI_Init declare rank, numberofprocesses set rank with MPI_Comm_rank set numberofprocesses with MPI_Comm_size if process rank is 0: array <- (Obtain our raw data) for all processes idx = 0 through numberofprocesses - 1: Send fragment idx of the array to process ID idx using MPI_Isend This fragment will have the size (size of array) / numberofprocesses) declare local_data Read into local_data for our process using MPI_Irecv MPI_Wait for our process to finish receive request local_sum <-... Process local_data with CUDA and obtain a sum declare global_sum set global_sum on process 0 with MPI_reduce (use global_sum somehow) MPI_Finalize
26 MPI/CUDA Wave Equation Recall our calculation: y x,t+1 = 2y x,t y x,t 1 + c t x 2 (y x+1,t 2y x,t + y x 1,t )
27 MPI/CUDA Wave Equation Big idea: Divide our data array between n processes!
28 MPI/CUDA Wave Equation In reality: We have three regions of data at a time (old, current, new)
29 MPI/CUDA Wave Equation Calculation for timestep t+1 uses the following data: y x,t+1 = 2y x,t y x,t 1 + c t x 2 (y x+1,t 2y x,t + y x 1,t ) t+1 t t-1
30 MPI/CUDA Wave Equation Problem if we re at the boundary of a process! y x,t+1 = 2y x,t y x,t 1 + c t x 2 (y x+1,t 2y x,t + y x 1,t ) t+1 t t-1 x Where do we get y x 1,t? (It s outside our process!)
31 Wave Equation Simple Solution After every time-step, each process gives its leftmost and rightmost piece of current data to neighbor processes! Proc0 Proc1 Proc2 Proc3 Proc4
32 Wave Equation Simple Solution Pieces of data to communicate: Proc0 Proc1 Proc2 Proc3 Proc4
33 Wave Equation Simple Solution Can do this with MPI_Irecv, MPI_Isend, MPI_Wait: Suppose process has rank r: If we re not the rightmost process: Send data to process r+1 Receive data from process r+1 If we re not the leftmost process: Send data to process r-1 Receive data from process r-1 Wait on requests
34 Wave Equation Simple Solution Boundary conditions: Use MPI_Comm_rank and MPI_Comm_size Rank 0 process will set leftmost condition Rank (size-1) process will set rightmost condition
35 Simple Solution Problems Communication can be expensive! Expensive to communicate every timestep to send 1 value! Better solution: Send some m values every m timesteps!
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