1. [3 pts] What is your section number, the period your discussion meets, and the name of your discussion leader?

Transcription

1 CIS 3022 Prog for CIS Majors I October 4, 2007 Exam I Print Your Name Your Section # Total Score Your work is to be done individually. The exam is worth 104 points (four points of extra credit are available throughout the exam) and it has 16 questions. If you notice an error in any portions of the Java code provided within a question, mark through and correct the error. Unless a question directly instructs you to correct a portion of code, there are no known errors. There are times when errors within a portion of code are unnoticed. We will consider giving extra credit for any errors corrected. However, be aware there must actually be an error in the code (programming conventions do not apply). Be sure of yourself, inaccurate corrections could cause you to lose points. 1. [3 pts] What is your section number, the period your discussion meets, and the name of your discussion leader? 2. [3 pts] Describe an interpreter. interprets for multiple HW/SW interpretation is performed as the results are shown we move directly results, do not have a separate file created usually an intrepreted program executes slower 3. [3 pts] State three aspects of Java as a language. Java as a language - JVM - Java API - Dynamic - Simple - Memory Management - Portable - Relatively speaking slower - Internet programming - Security 4. [2 pts] Java utilizes aspects of both a compiler and an interpreter. True OR False 5. [3 pts] The class Calculator has been created and placed in the file Program.java. Show how to compile Calculator. javac Program.java 6. [3 pts] What is the name of the file created after Calculator has been compiled (include any file extension)? Calculator.class 7. [3 pts] Show how to run the program compiled in Question 5. java Calculator

2 October 4, 2007 CIS 3022 Exam I Page 2 of 6 Score 8. [20 pts] Given this sample computer system, fill in the appropriate portions of each table. The system has a 5-bit program counter, an 8-bit Accumulator, and 32 bytes of addressable memory (we will only use a portion of the memory). The system utilizes the instruction set and initial memory shown here. Instruction Set Memory OPCODE MNEMONIC ADDRESS ORIGINAL NEW CONTENTS CONTENTS 000 HALT STAM LDAM LDAI ADDM ADDI SUBM SUBI Given this structure and starting at 00000, step through and show the execution of the system by filling in the all of the fields within the table below. If there are any changes to the 8 bytes of memory, show what they are here by placing the new contents in the NEW CONTENTS column above, next to the original contents. If the position does not change you do not need to place anything in the NEW CONTENTS column. PC Accumulator (before instruction) Instruction Psuedo Code Accumulator (after instruction) Garbage or??? LDAM 6 A:=Mem[00110] SUBI 5 A:=A STAM 7 Mem[00111]:=A ADDM 0 A:=A+Mem[ ] SUBM 2 A:=A- Mem[00010] STAM 1 Mem[00001]:=A HALT - -

3 October 4, 2007 CIS 3022 Exam I Page 3 of 6 Score 9. [12 pts] What is the value of d after each statement executes? Also, what are the values of a, b, and c after all of the statements have executed? Note that the statements are sequential, the first possibly affecting the second, possibly affecting the third, and so on. int a = 1, b = 8, c = 4, d = 5; d = (++a c) % d / 2; d = a++ % c * 3 b; d = a * 2 + b / ++c; d = -1 d = -2 d = -9 All executions complete: a = 2 b = 8 c = [3 pts] Using a single print statement, show how to print to the console (command prompt) the name of each variable in Question 9, followed by an equal sign and the value of the variable on the same line. System.out.print( a= + a +,b= + b +,c= + c +,d= + d); 11. [3 pts] Using a single print statement, show how to print to the console (command prompt) on separate lines the name of each variable in Question 9, followed by an equal sign and the value of the variable; one line per variable name, =, and value. System.out.print( a= + a + \n b= + b + \n c= + c + \n d= + d); 12. [6 pts] Given the variables x and y as well as their declarations, to what value do the following expressions evaluate? int x = 15, y = 21; x = = 8 y >= x!(x! = 3 && x y < = 0) Evaluation = TRUE Evaluation = FALSE (y x >= 5 && y!= x) Evaluation = TRUE

4 October 4, 2007 CIS 3022 Exam I Page 4 of 6 Score 13. [10 pts] Step through this series of statements and show the output produced. Also, state the final value of x, y, and z after all the statements have executed. int x = 3, y = 6, z = 7; if (y >= x) y += x; System.out.println( First ); else z = z % x; System.out.println( Second ); if (x!= 0 && x < z) x = x 1; System.out.println( Third ); if (z!= x z!= y) z += x * y; System.out.println( Fourth ); Output First Third Fourth Final Values x = 2 y = 9 z = [8 pts] Use a while loop (only the code fragment of the loop and its declarations are needed) and a single print statement within the while loop to print the following pattern to the screen. Value: 15 Value: 12 Value: 9 Value: 6 Value: 3 int i = 15; while( i > 0 ) System.out.println( Value: + i ); i -= 3;

5 October 4, 2007 CIS 3022 Exam I Page 5 of 6 Score 15. [10 pts] Create a class Input. The class will contain the main method. Receive an integer value from the user. When the value is greater than zero, print the value multiplied by 10. When the value is less than zero, print its absolute value. When the value is equal to zero print false. class Input public static void main ( String args[] ) System.out.print( Please enter an integer: ); int input = UserInput.readInt(); if( input > 0 ) System.out.println( input * 10 ); else if( input < 0 ) System.out.println( input * -1 ); else System.out.println( false );

6 October 4, 2007 CIS 3022 Exam I Page 6 of 6 Score 16. [12 pts] Create a class Digits. The class will contain the main method. Ask the user for an integer value. Print to the screen on a separate line each of the single digits from the number one digit at a time. If the number were entered, the output would be: class Digits public static void main ( String args[] ) System.out.print( Please enter an integer: ); int num = UserInput.readInt(); while( num > 0 ) System.out.println( num % 10 ); num /= 10;