9 abcd = dcba b + 90c = c + 10b b = 10c.

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1 In this session, we ll learn how to solve problems related to place value. This is one of the fundamental concepts in arithmetic, something every elementary and middle school mathematics teacher should understand profoundly. You already know that the digits used to represent a positive integer have different meanings depending on their position. This is commonly called place value. Example 1. Pick a three digit number. Multiply it by 7. Then multiply your answer by 11, and finally multiply by 13. Explain why you got that answer. Example 2. Next, consider the following problem. Find a four-digit number abcd which is reversed when multiplied by 9. In other words, find digits a, b, c, and d such that 9 abcd = dcba. Solution. Our solution method is to reason digit by digit. First note that a = 1 since otherwise 9 abcd = 18000, which is a five-digit number. Since a = 1, it follows that d = 9. Now the equation take the following form: 9 1bc9 = 9cb1. We can express this in decimal notation (in contrast to the underline notation we have been using) as follows: 9 ( b + 10c) = c + 10b. Distributing the 9 across the yields from which it follows that b + 90c = c + 10b b = 10c. Since the right side 10c is at most 90 (c is a digit), we can conclude that b = 0, and hence c = 8. Therefore abcd = 1089 is the only such number. 1

2 In the exercises, you will be asked to investigate larger numbers that reverse when multiplied by 9. Thinking more about the number 1089 enables us to put this phenomenon in perspective. The base b number that looks somewhat like 1089 is N = 10(b 2)(b 1). We use underline so you know we don t mean multiplication. The value of N is b 3 + (b 2)b + b 1. If we multiply this by b 1, we get b 4 2b + 1. On the other hand the base b number that looks like 9801 would be written (b 1)(b 2)01 and its value is (b 1)b 3 + (b 2)b 2 + 1, and this too has value b 4 2b Thus, multiplication by b 1 turns the base b numeral 10(b 2)(b 1) around. In the next example we deal with several digits at once. Example 3. Find a 6-digit number abcdef that becomes 5 times as large when the units digit f is moved to the left end of the number. In other words, solve 5 abcdef = fabcde. Solution. Before we solve this, let s consider how a six-digit number changes when the rightmost digit is moved to the left end. Take as an example. Note that = , whereas = = If we give the name x to 12345, a common technique in algebra, we can write = 10x+6 and = x. What the hypothesis tells us is that 5(10x + 6) = x. Of course does not satisfy the equation, but replacing abcde with x reduces the six variables to just two. Of course we don t know that f = 6 works so we need to solve 5 (10x + f) = f x. Distributing the 5 and migrating we get 50x + 5f = 10 5 f + x which is equivalent to 49x = (10 5 5)f = 99995f. Both sides are multiples of 7 so we can write 7x = f. Now the left side is a multiple of 7, so the right side must also be a multiple of 7. Since is not a multiple of 7, it follows (from the Fundamental Theorem of Arithmetic, which we have yet to prove) that f must be a multiple of 7. Since f is a digit, it must be 7. And x must be This technique is one that you will use repeatedly in the next few weeks. Example 4. The amazing number Start with your favorite 2

3 two-digit number, reverse it and then subtract the smaller from the larger. What can you say about the result? Now pick a three-digit number like 742. Reverse it to get 247 and subtract the smaller of the two from the larger. Here we get = 495. Now take the answer and reverse it to get 594, then add these two to get = What did you get? Finally, compute the product of 1089 and 9. You get = Isn t that odd, multiplying by 9 had the effect of reversing the number. Is there a connection between these two properties? Here s a rationale for always getting First note, assuming a > c that abc cba = 100(a c) + c a = 99(a c) = 99d. Now suppose 99d = u9v. Why is the middle digit of 99d always a 9? Is there a connection between u and v? For d = 1, we have u9v = 099, so u = 0 and v = 9. For d = 2, u9v = 198. Again we see that u + v = 9. Check out what we get for each of d = 3,..., 9. In each case u + v = 9. Thus u9v + v9u = 100(u + v) v + u = = Example 5. Suppose a, b, c and d are digits (ie, in the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}), and the sum of the two four-digit numbers abcd and dabc is Find all four-digit numbers abcd with this property. Note that abcd is a four-digit number only if a 0. Recall the two functions floor ( ) and fractional part ( ), defined by x is the largest integer that is less than or equal to x, and x = x x. For example, π = 3 and π = π 3, π = 4 and π = π ( 4) = 4 π. Also, notice that for any real number x, x = x + x. For example, = = Example 6. Let N be a four-digit number and let N = N/ N/10. Suppose N N = Find all possible values of N. Recall the two functions floor ( ) and fractional part ( ), are defined by x is the largest integer that is less than or equal to x, and x = x x. Solution. Let N = abcd. Then N/10 = abc.d = 0.d, so N/10 could be written as 1000d. On the other hand N/10 = abc.d = abc. In other words, N = dabc, just as in the problem above. The equation 10x + d (1000d + x) = 3105 is equivalent to 9x 999d = 3105, and dividing both 3

4 sides by 9 yields x 111d = 345. There are six solutions for x 100: d = 0 x = 345, N = 3450 d = 1 x = 456, N = 4561 d = 2 x = 567, N = 5672 d = 3 x = 678, N = 6783 d = 4 x = 789, N = 7894 d = 5 x = 900, N =

5 Example 7. Consider the equations = = = = 9876 Find the next few equations in the list and prove that each one follows from the one above it. During the rest of the session, please work on the following problems. You cannot finish them, but perhaps you will have time to work on them later. 1. X ing digits. Consider the number N = , obtained by writing the numbers from 1 to 60 in order next to one another. What is the largest number that can be produced by crossing out 100 digits of N? What is the smallest number that can be produced by crossing out 100 digits of N? 2. Use each of the five digits 1, 3, 5, 7 and 9 exactly once to build two numbers A and B such that A B is as large as possible. Then build two numbers C and D such that C D is as small as possible. 3. For each of the following problems, let S(n) = n in case n is a single digit integer. If n 10 is an integer, S(n) is the sum of the digits of n. Similarly P (n) is n if n is a positive single digit integer and the product of the digits of n otherwise. If there is no solution, prove it. (a) What is the smallest solution to S(n) = Express your answer in exponential notation. (b) How many five-digit numbers n satisfy S(S(n)) + S(n) = 50. (c) Find all solutions to S(S(S(n))) + S(S(n)) + S(n) =

6 (d) Find all solutions to S(S(n)) + S(n) + n = (e) When the decimal point of a certain positive decimal number is moved four places to the right, the new number is four times as big and the reciprocal of the original number. What is the number? (f) (2007 North Carolina High School Math Contest) Find the sum S(1) + S(2) + + S(2007). (g) Can both S(a) and S(a + 1) be multiples of 49? (h) Find a number n such that S(n) = 2S(n + 1). For what values of k does there exist n such that S(n) = ks(n + 1)? (i) Find, with proof, the largest n for which n = 7s(n). (j) Find the smallest positive integer n satisfying S(S(n)) 10. (k) Find the smallest positive integer n satisfying S(S(n)) 100. (l) Find the smallest positive integer n such that S(n 2 ) = Recall the two functions floor ( ) and fractional part ( ), defined by x is the largest integer that is less than or equal to x, and x = x x. (a) For each member x of the set S, S = {π, 1.234, 1.234, 7 3, 7 3 }, evaluate x and x. (b) Define another function f by f(x) = x 10 x. Find f(x) and 10 f( x ) for each x in S. (c) Let g(x) = x x 10. Evaluate g at each of the members of S. (d) Prove that for any number x = 100a + 10b + c + f, where a is a positive integer, b is a digit, c is a digit, and 0 f < 1, g(x) = b. In other words, g(x) is the tens digit of x. 5. Take the first three digits of your phone number (NOT the Area code...) Then multiply by 80. Next add 1. Multiply by 250. Then add to this the last 4 digits of your phone number. Then add to this the last 4 digits of your phone number again. Subtract 250. Finally divide 6

7 number by 2. What do you get and why does this work? Explain why you get such an interesting answer. 6. The numbers 1, 2, 3, 6, 7, 8 are arranged in a multiplication table, with three along the top and the other three down the column. The multiplication table is completed and the sum of the nine entries is tabulated. What is the largest possible sum obtainable. a b c d e f 7. A special-8 number is one whose decimal representation consists entirely of 0 s and 8 s. For example and 0.08 are special numbers. What is the fewest special numbers whose sum is A special-3 number is one whose decimal representation consists entirely of 0 s and 3 s. For example and 0.03 are special numbers. What is the fewest special numbers whose sum is A special-7 number is one whose decimal representation consists entirely of 0 s and 7 s. For example and 0.07 are special numbers. What is the fewest special numbers whose sum is What is the largest 5-digit multiple of 11 that has exactly 3 different digits? 11. A two-digit integer N that is not a multiple of 10 is k times the sum of its digits. The number formed by interchanging the digits is m times the sum of the digits. What is the relationship between m and k? 12. A check is written for x dollars and y cents, both x and y two-digit numbers. In error it is cashed for y dollars and x cents, the incorrect amount exceeding the correct amount by $ Find a possible value for x and y. 13. Solve the alpha-numeric problem abcd 4 = dcba, where a, b, c and d are decimal digits. 7

8 14. The rightmost digit of a six-digit number N is moved to the left end. The new number obtained is five times N. What is N? 15. Repeat the same problem with the 5 changed to a 4. That is 4(abcdef) = fabcde 16. Let N = be the integer obtained by appending the decimal representations of the numbers from 1 to 2000 together in order. What is the remainder when N is divided by 9? 17. Ashley, Chris and Elizabeth have a large supply of identical cubical dice. Each one builds a pile of them directly upon one another. When they are done, they notice that: (a) When they read the tops of the three columns from left to right as one number, the number is exactly the total number of dots showing on all the dice. And (b) When the top numbers are multiplied together, the product is exactly the number of dice used to build the three columns. For example, if the top three dice looked like we would be interpreted as the number 142. How many dice are there among the three piles? 18. Find all three-digit numbers whose squares end with the digits A six-digit number N = abcdef has the property that 7(abcdef) = 6(defabc), where both digits a and d are non-zero. What is N? 20. Let a, b, c, d, and e be digits satisfying 4 abcde4 = 4abcde. Find all five of the digits. 8

9 21. Let a, b, c, d, e be digits satisfying abc a = bda and bda a = cdde. What is cdde a? A reminder about notation: the string of digits abc can be interpreted two ways, first as a b c and secondly as 100a + 10b + c. To distinguish these two interpretations, we use the underline notation abc for the latter of these. 22. Let N = abcdef be a six-digit number such that defabc is six times the value of abcdef. What is the sum of the digits of N? 23. Maximizing Products (a) Using all nonzero digits each once, build two numbers A and B so that A B is as large as possible. (b) Using all nonzero digits each once, build three numbers A, B and C so that A B C is as large as possible. (c) Using all nonzero digits each once, build four numbers A, B, C and D so that A B C D is as large as possible. (d) If we build five two-digit numbers using each of the digits 0 through 9 exactly once, and the product of the five numbers is maximized, find the greatest number among them. (e) Suppose we want to use each non-zero digit once to create three integers whose product is as large as possible but unlike part (b) or numbers are required to have 1, 3 and 5 digits. 24. Calling All Digits (a) Using each nonzero digit exactly once, create three 3-digit numbers A, B, and C, such that A + B = C. (b) Again using each nonzero digit exactly once, create three 3-digit numbers A, B, and C that are in the ratio 1 : 3 : 5. (c) Again using each nonzero digit exactly once, create three 3-digit numbers A, B, and C that are in the ratio 1 : 2 : 3. (d) Again using each nonzero digit exactly once, create three 3-digit numbers A, B, and C that are in the ratio 4 : 5 : 6. 9

10 (e) Again using each nonzero digit exactly once, create three 3-digit numbers A, B, and C that are in the ratio 3 : 7 : 8. (f) Are there any more single digit ratios a : b : c for which the nine nonzero digits can be used to build three numbers A, B, and C in the ratio a : b : c. (g) Using the ten digits each exactly once, create three numbers A, B, and C, such that A + B = C. (h) Use each of the nine nonzero digits exactly once to construct three prime numbers A, B and C such that the sum A + B + C is as small as possible. (i) Now use each of the ten digits exactly once to construct three prime numbers A, B and C such that the sum A + B + C is as small as possible. 25. The number N = is formed stringing together all the numbers from 1 to 999. What is the product of the 2007 th and 2008 th digits of N? 26. The number N = 37! = is a 44-digit number. The first 33 digits are K = In fact, N = K L 10 8, where L is less than Find the number L. 27. Find the smallest integer multiple of 84 and whose decimal representation uses just the two digits 6 and (Mathcounts 2009) Find a six-digit number abcdef such that 4 abcdef = 3 defabc. 29. Find the greatest 9-digit number whose digits product is 9!. 30. Find values for each of the digits A, B and C. 10 BA AB +AB

11 CAA 11