GG450 4/5/2010. Today s material comes from p and in the text book. Please read and understand all of this material!

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GG450 April 6, 2010 Seismic Reflection I Today s material comes from p. 32-33 and 81-116 in the text book. Please read and understand all of this material! Back to seismic waves Last week we talked about rays that are critically refracted and travel along subsurface interfaces. We will now talk about the region where rays are reflected. In terms of our acquisition parameters, what determines whether we receive mostly reflected or mostly refracted waves? Seismic waves spread out from their origin Geometrical Spreading As waves radiate away from the source, the energy spreads out. The energy of a wave is proportional to the square of the amplitude, so as the energy spreads out, the amplitude decreases, although the total energy remains constant. For body waves (P and S), the waves spread out in spherical shells. Since the surface area of a sphere is proportional to the square of the radius, the energy per unit area (energy density) decreases as r 2, E=E 0 /r 2, and the amplitude decreases as r, A=A 0 /r (note: the book uses H instead of A) Absorption Attenuation is the result of absorption of energy. A small amount of energy is lost from seismic waves to heat as the wave moves through a material. Absorption takes the form: where I is a measure of energy called the intensity, q is the absorption coefficient, and r is distance. q has units of db/wavelength. So, at a given frequency, the energy decreases with distance at a certain number of db/wavelength. Note that even if q is constant, the energy in a high frequency wave will decrease faster than the energy in a low frequency wave. 1

An attenuation of 0.6 db/ implies that a signal with a ten km wavelength will decrease in size by a factor of 2 in 100 km. If the material loses one tenth of its amplitude every wavelength, what will its amplitude be after ten wavelengths? Attenuation by a constant db/ implies that waves with short wavelengths will decrease in size faster than those with long wavelengths. What does this imply about the frequencies of seismic waves as they travel into the earth? This means that if we want to use seismic waves to see deep into the earth, we need to use either long wavelength waves, or very high amplitude sources. V = λf λ = V/f So, if V generally increases with depth, and if f generally decreases with depth, what happens to seismic wavelengths with depth? Energy Partitioning When a seismic wave hits an interface, it splits into different waves, both reflected and refracted. In the most general case an incident P wave will split into reflected P and S waves and refracted P and S waves. The energy of the incident wave is partitioned among the resulting waves. Reflection Method V 1 How long does it take a ray to travel from E to A to G? Basic formula: The reflection path E-A-G, is symmetric, thus the time it takes to travel from the surface to the reflector and back is: 2

Since x and t can be measured directly, there are two unknowns in the above equation the layer thickness and the layer velocity. Thus we need more information to solve for thickness and velocity. We can plot distance vs. time to see how the reflection arrival time changes with distance: T 0 The direct arrival (green) is exactly as in refraction, so the slope of the line is 1/V 1. The reflection (red) is a hyperbola with an asymptote (blue) that can be found by looking at the limit as x gets very large: t=x/v 1. Note that this is actually the same as the equation for the direct arrival. T 0 is the time at x = 0 (also called zero offset). Direct arrival This is a standard reflection plot, with time positive downwards, since the later arrivals are coming from deeper in the earth. Reflected arrivals This is called a split spread, with the shot in the middle and geophones spread out to either side. It is typical for land acquisition. Graphical demonstration of NMO The hyperolic shape is called Normal Move-Out (NMO) and is the time difference between the arrival at x=0 and the arrival at x. The hyperolic shape is called Normal Move-Out (NMO) and is the time difference between the arrival at x=0 and the arrival at x. where h 1 is the layer depth, V 1 is the layer velocity, and x is the distance from the source to the geophone. 2h 1 /V 1 = T 0 (time at zero offset). Note that NMO decreases with depth. Since 2h 1 /v 1 is the time required for a normal incidence reflection, T NMO is the EXTRA time needed if the receiver is not directly over the reflection point. If we subtract T NMO from each trace, the time of arrival at each distance should be the same at each geophone, and is what it would be if each geophone were at the shot point. 3

Without NMO With NMO Notice the big assumptions here: To correctly apply a normal move-out correction we need to know both the layer thickness and the velocity of the layer above. When we apply the correct values for normal move-out, subtracting the travel times from those observed, our reflection gather will no longer be curved, but will be a horizontal straight line. This is fine as long as we know the velocity and depth to the layer. What if the move-out velocity we use for the correction is too high or too low? This is fine as long as we know the velocity and depth to the layer. What if the move-out velocity we use for the correction is too high or too low? Another fact to keep in mind is that the velocity between two layers does not need to change to observe a reflection. The reflection amplitude is a function of acoustic impedance: velocity times the density. Thus, a reflection can be observed even if only the density changes from one layer to another. But, we need the velocities between each layer boundary to get accurate estimates of depths to those boundaries. There are several ways to estimate the propagation velocities, each with its own advantages and problems. We ll work with some of these methods in next week s lab. What about dipping layers? Previously we worked with a single layer over a half space. Now we will look at many layers of different velocities. Unlike refraction, the velocities won t be directly obtained from the slopes of travel time curves, since we don t have the advantage of head waves and the knowledge that our ray is horizontal in the deepest layer. We also need to deal with the fact that the rays aren t straight as we go to deeper layers, but they bend (refract) as velocities change at and (in between) each layer boundary. We will have to make approximations to deal with these complexities. E G N Reflections from a single dipping layer We can model reflections from a flat layer using the image source geometry. How does this geometry change if the layer is dipping? Q For a dipping layer, the image source is placed at twice the depth to the layer along the perpendicular to the boundary, Notice that the travel times of reflections from the dipping layer will be identical to the case where the shot is above the image source and the layer is horizontal, i.e. the reflections are symmetric around the minimum time. 4

E G E G N N Q There are several important observations to be made: The angle of incidence equals the angle of reflection from the layer, so Snell's law is obeyed, The length QN equals the length EN, so that the length of ray ENQ is identical to the length QG Q The shortest reflected ray (least-time) is the one that hits the surface directly above the image source, The shape of the travel time curve for the reflections is independent of the dip - but the location of t min changes with dip. The reflection arrival is no longer asymptotic to the direct arrival. We need to look at the effects of dip on normal move-out. Recall that our desire is to be able to apply the NMO correction to our data so that we can later add together seismograms at various x distances to emphasize reflection arrivals. It's clear that if we apply normal move-out to dipping reflectors, the result will NOT be the horizontal line required if we want to preserve this reflection when we stack. The indication that dip is present in travel time data is the offset of the shortest reflection time from directly below the shot point. If we look at NMO again, we can re-write T NMO as: We can then define a Dip Move-Out (DMO) as: Eqn. 33, 34 We use velocities very often in seismic reflection work: Velocity controls travel times Velocity controls impedance contrasts Velocities are necessary for NMO corrections Velocities are needed for conversion from time to depth Where α is the dip of the reflecting horizon. DMO is the difference in travel time between the plus and minus x (equal distances from the source). 5

There are many different kinds of seismic velocities: Interval velocity Stacking (NMO) velocity RMS velocity Average velocity Layer 1 Layer 2 Layer 3 h 1 = 500 m t 1 = 0.333 s h 2 = 400 m t 2 = 0.222 s h 3 = 600 m t 3 = 0.300 s V 1 = V 2 = V 3 = V ave0,2 = V ave0,3 = Layer 1 Layer 2 Layer 3 h 1 = 500 m t 1 = 0.333 s h 2 = 400 m t 2 = 0.222 s h 3 = 600 m t 3 = 0.300 s Another velocity valid for zero-offset is the NMO velocity. This is simply the velocity that aligns the reflections horizontally for stacking (so this is also called the stacking velocity). Generally we deal with receivers that are offset from the source, so we get non-vertical travel paths. 1 Interval velocities from RMS or stacking velocities Interval velocities from RMS or stacking velocities Dix (1955) showed that a sequence of constantvelocity layers will have reflections such that: V n is the INTERVAL velocity between the n-1 and n th reflector. This is the Dix Equation, and it turns out to be a considerably better approximation for interval velocities than the no-refraction assumption, although it still works best for short spread lengths relative to the reflector depth. 6

Multiple reflections Layer 1 Once we have velocities, thicknesses are easy to obtain by: Layer 2 Layer 3 Primaries 1 st multiples Peg leg multiples Interbed multiples Our interpretations of reflection data are often made more difficult when energy is reflected back into the earth from shallow horizons (or the sea surface). What is the characteristic of primary multiples that allows us to quickly recognize them? 7