ID : aefractions [1] Grade Fractions For more such worksheets visit www.edugain.com Answer the questions (1) Convert 63 13 (2) Convert 6 7 12 into a mixed fraction. to improper fraction. (3) Aleser had to pickup a friend while going to school. Aleser walked 3 of a kilometer to his friend's house. After that he walked of a kilometer to reach the school. How far did he walk in all? () What fraction is represented by shaded portion of these shapes : A) B) C) D) E) F) (5) A 5 kg cauliflower is cut into 5 equal pieces. Find the weight of each piece. (6) Dirran read 6 of a book in two days. If Dirran read the book she read on the second day? 5 of the book on the first day. What fraction of
(7) Shade the images to show the following fraction addition. ID : aefractions [2] 3 6 + 2 6 and makes (8) Shade the images to show the following fraction addition: 2 + 3 + and and makes Choose correct answer(s) from the given choices () The fraction of the shaded part in three of the given figures is equivalent. Find the odd one out. a. b. c. d.
ID : aefractions [3] () The options given below represent a line that has been divided into 16 equal parts. Choose the option which re a. b. 0 13 16 0 c. d. 0 13 16 0 Fill in the blanks (11) Fractions with different denominators are called fractions. (12) Subtract the following fractions A) 12 17 8 17 B) 12 3 12 C) 1 1 D) 5 2 E) 7 5 F) 8 1 (13) In like fractions, the numerator, the smaller the fraction will be. (1) Fill in the blank.. A) 5 2 B) 5 1 7 7 C) 8 2 6
ID : aefractions [] D) 5 6 6 6 E) 1 3 1 7 F) 8 5 13 3 13 (15) Fill in the blank with <,> or sign. 3 6 7 2017 Edugain (www.edugain.com). All Rights Reserved Many more such worksheets can be generated at www.edugain.com
Answers ID : aefractions [5] (1) 11 13 63 is an improper fraction in which the numerator is greater than the denominator. Converting 13 an improper fraction into a mixed fraction implies expressing the improper fraction as the sum of a whole number and a proper fraction. To express the given fraction in the form of a mixed fraction, we will divide 63 by 13. Now, the quotient obtained will represent the whole number while the remainder will become the numerator of the proper fraction. The denominator of the proper fraction part will remain the same as that of the improper fraction, i.e., 13. Step When we divide 63 by 13, we get the quotient as and the remainder as 11. Dividend Divisor 13 ) 6 3 ( Quotient 5 2 Remainder 11 Step 5 Thus 63 13 can be written in the mixed form as 11 13.
ID : aefractions [6] (2) 7 12 A mixed fraction has two parts: a whole number and a proper fraction. In 6 7 12, the whole number is 6 and the proper fraction is 7 12. To convert a mixed fraction into an improper fraction, we need to multiply the denominator of the proper fraction part by the whole number, and add to it the numerator. The resultant number becomes the new numerator for the improper fraction. This means, the new numerator for the improper fraction will be 12 6 + 7 or 7. Step The denominator will remain the same as that of the proper fraction part. This gives us our answer as 7. 12
ID : aefractions [7] (3) 7 Distance covered by Aleser to reach his friend's house Distance covered by Aleser from his friend's to school 3 of a kilometer of a kilometer Total distance covered by Aleser while going to school 3 + 3 + 7 Therefore, he walked 7 kilometer in all.
ID : aefractions [8] () A) 13 We have been asked to find the fraction that represents the shaded portion of the following shape: Total number of equal parts in the image 13 Number of parts that are shaded in the image Fraction of parts of the image that are shaded Number of shaded parts Total number of parts 13 Step Hence, the fraction that is represented by the shaded portion of the shape is 13.
ID : aefractions [] B) 6 We have been asked to find the fraction that represents the shaded portion of the following shape: Total number of equal parts in the image Number of parts that are shaded in the image 6 Fraction of parts of the image that are shaded Number of shaded parts Total number of parts 6 Step Hence, the fraction that is represented by the shaded portion of the shape is 6.
ID : aefractions [] C) 8 We have been asked to find the fraction that represents the shaded portion of the following shape: Total number of equal parts in the image Number of parts that are shaded in the image 8 Fraction of parts of the image that are shaded Number of shaded parts Total number of parts 8 Step Hence, the fraction that is represented by the shaded portion of the shape is 8.
ID : aefractions [11] D) 8 13 We have been asked to find the fraction that represents the shaded portion of the following shape: Total number of equal parts in the image 13 Number of parts that are shaded in the image 8 Fraction of parts of the image that are shaded Number of shaded parts Total number of parts 8 13 Step Hence, the fraction that is represented by the shaded portion of the shape is 8 13.
ID : aefractions [12] E) 5 8 We have been asked to find the fraction that represents the shaded portion of the following shape: Total number of equal parts in the image 8 Number of parts that are shaded in the image 5 Fraction of parts of the image that are shaded Number of shaded parts Total number of parts 5 8 Step Hence, the fraction that is represented by the shaded portion of the shape is 5 8.
ID : aefractions [13] F) 2 3 We have been asked to find the fraction that represents the shaded portion of the following shape: Total number of equal parts in the image 3 Number of parts that are shaded in the image 2 Fraction of parts of the image that are shaded Number of shaded parts Total number of parts 2 3 Step Hence, the fraction that is represented by the shaded portion of the shape is 2 3.
ID : aefractions [1] (5) 25 kg According to the question, we have to cut 5 kg cauliflower into 5 equal pieces. For this, we need to divide 5 by 5. To divide 5 by 5, let us multiply 5 by the reciprocal of 5. Reciprocal of 5 1 5 So, 5 5 5 1 5 Multiplying the numerators together and the denominators together, we get, 1 5 5 25 Step To convert the fraction into the simplest form, let us divide the numerator and denominator of the above fraction by their H.C.F, that is 1 25 1 25 25 1 Step 5 Hence, the weight of each piece is 25 kg.
ID : aefractions [15] (6) 1 Fraction of the book read by Dirran in two days 6 Fraction of the book read by Dirran on the first day 5 Fraction of the book read by Dirran on the second day Fraction of the book read by Dirran in two days Fraction of the book read by Dirran on the first day 6 5 6 5 1
ID : aefractions [16] (7) 3 6 + 2 6 5 6 + A proper fraction represents a part of a whole. In the given figures, each circle represents one whole thing, and has been divided into 6 equal parts. The fact that only 3 parts are shaded in the first circle tells us that it represents the fraction 3 6 or â??3 parts out of a thing that has been broken into 6 partsâ??. Similarly the second circle represents â??2 parts of a thing that has been broken into 6 partsâ??. Step 3 parts plus 2 parts of something that has been broken into 6 parts will be same as â??5 parts out of 6 â??, or 5 6. Step 5 So our answer is 5 6 and this can be represented using the third circle by shading 5 parts out of 6.
ID : aefractions [17] (8) 2 + 3 + and and makes A proper fraction represents a part of a whole. In the given figures, each circle represents one whole thing, and has been divided into equal parts. The fact that only 2 parts are shaded in the first circle tells us that it represents the fraction 2 or 2 parts of a thing that has been broken into parts. Similarly, the second circle represents 3 parts of a thing that has been broken into parts. Step Similarly, the third circle represents parts of a thing that has been broken into parts. Step 5 2 parts plus 3 parts plus parts of something that has been broken into parts will be same as parts out of, or. Step 6 So our answer is and this can be represented using the third circle by shading parts out of.
() a. ID : aefractions [18] Let us write the fraction of the shaded part for each of the given figures. Number of shaded parts We know, fraction of the shaded part Number of parts the whole is divided into Option a: Fraction of the shaded part Option b: Fraction of the shaded part Option c: Fraction of the shaded part Option d: Fraction of the shaded part 1 5 16 20 8 12 15 Now, we can see that: 12 15 12 3 15 3 5 16 20 16 20 5 8 8 2 2 5 Hence, we conclude that 12 15, 16 20 and 8 are equivalent fractions. So, 1 5 is the odd one out. Step Therefore, option a is the odd one out.
ID : aefractions [1] 0 13 16 () d. According to the question, we have to represent the fraction 13 16 on a number line. As the denominator of the fraction is 16, we will divide the space between every two consecutive numbers into 16 equal parts. To mark 13 16 Hence, 13 16, we need to move 13 parts on the right side of 0. is represented on the number line as follows: 0 13 16 Comparing the number line drawn in step 2 with those given in the options, we conclude that option d is the correct representation of the given fraction on the number line. (11) unlike The fractions who have different denominators are called unlike fractions.
ID : aefractions [20] (12) A) 12 17 8 17 17 The given fractions are like fractions as their denominators are same. We know that we can directly add/subtract the numerators of like fractions and the denominator will remain the same. This means the new fraction will be: 12 8 12 8, or 17 17 17 17 B) 12 3 12 7 12 The given fractions are like fractions as their denominators are same. We know that we can directly add/subtract the numerators of like fractions and the denominator will remain the same. This means the new fraction will be: 3 3 7, or 12 12 12 12
ID : aefractions [21] C) 1 1 6 1 The given fractions are like fractions as their denominators are same. We know that we can directly add/subtract the numerators of like fractions and the denominator will remain the same. This means the new fraction will be: 6, or 1 1 1 1 D) 5 2 3 The given fractions are like fractions as their denominators are same. We know that we can directly add/subtract the numerators of like fractions and the denominator will remain the same. This means the new fraction will be: 5 2 5 2, or 3
ID : aefractions [22] E) 7 5 2 The given fractions are like fractions as their denominators are same. We know that we can directly add/subtract the numerators of like fractions and the denominator will remain the same. This means the new fraction will be: 7 5 7 5 2, or F) 8 1 7 The given fractions are like fractions as their denominators are same. We know that we can directly add/subtract the numerators of like fractions and the denominator will remain the same. This means the new fraction will be: 8 1 8 1, or 7 (13) smaller Like fractions are those who have the same denominator. For such fractions the value of the overall fraction depends directly on the value of their numerator. Therefore, in like fractions, smaller the numerator, smaller is the fraction.
ID : aefractions [23] (1) A) 7 We can see that the denominators are the same for all the fractions. So the resultant numerator depends on the subtraction of first two numerators. The difference between the numerators is 2 and the smaller one of them is 5, which means the larger one will be the sum of the difference and the smaller numerator: 2 + 5 7. The missing number is 7. B) 7 The resultant fraction has the numerator equal to the difference of numerators of the given two fractions. So the denominators of all the given fractions have to be the same. The missing number is 7. C) The resultant fraction has the numerator equal to the difference of numerators of the given two fractions. So the denominators of all the given fractions have to be the same. The missing number is. D) 1 We can see that the denominators are the same for all the fractions. So the resultant difference depends on the subtraction of numerators. The resultant difference: 5 1. The missing number is 1.
ID : aefractions [2] E) 1 The resultant fraction has the numerator equal to the difference of numerators of the given two fractions. So the denominators of all the given fractions have to be the same. The missing number is 1. F) 13 The resultant fraction has the numerator equal to the difference of numerators of the given two fractions. So the denominators of all the given fractions have to be the same. The missing number is 13.
ID : aefractions [25] (15) < The above question is about comparing two unlike fractions. Fractions having different denominators are called unlike fractions. Let us understand the comparison of two unlike fractions (i.e. 3 and 6 7 ) through a simple illustration using a circle. Let us take a circle and divide the circle into equal parts. The shaded region in the circle represents 3 of a circle. Step Similarly, let us divide the same circle into 7 equal parts. The shaded region in the circle represents 6 7 of a circle. Step 5 Thus, from the above illustrations we can infer that 3 is smaller than 6 7.