Doing Math: Scientific Notation Scientific notation is a way to show (and do math with) very small or very large numbers b 10 c

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Doing Math: Scientific Notation Scientific notation is a way to show (and do math with) very small or very large numbers b 10 c b = a decimal number between 1.0 and 9.99... c =anexponentof10 Example: 1.53 10 3 = 1530.4 10 =0.04 To convert from scientific notation to standard notation, move the decimal c places to the right. (This is c places to the right if c>0 and c places to the left if c<0). 1

Doing Math: Scientific Notation b 10 c Multiplying numbers in scientific notation: Multiply the b s Add the c s Round to the same or fewer decimal places than the least precise factor Example: (1.76 10 8 ) (3. 10 1 )=(1.76 3.) 10 (1 8) =5.63 10 4 3. is least precise factor, so round to 5.6 10 4

Doing Math: Scientific Notation b 10 c Dividing Numbers in Scientific Notation: Divide the b s Subtract the c s Round to the same or fewer decimal places than the least precise factor Example: (3.000 10 9 )/(.1065 10 13 )= 3.000.1065 10(9 13) =1.441... 10 4 3.000 is least precise factor, so round to 1.44 10 4 3

Doing Math: Scientific Notation b 10 c Adding and Subtracting in Scientific Notation: If the c s are the same: Add or subtract the b s Keep the same c Round to the same or fewer decimal places than the least precise factor Rescale if b is less than 1.0 or greater than or equal to 10.0 What if the c s are not the same? Realign to get the same c s, then add or subtract Use a calculator 4

Doing Math: Scientific Notation b 10 c Examples: 1.53 10 3 +.4 10 3 =(1.53 +.4) 10 3 =3.95 10 3.4 10 +.8 10 =5. 10 Round to number of digits in least precise number = 5. 10 4.78 10 5 +8.4 10 5 =13. 10 5 Keep b between 1.0 and 9.99...,so = 1.3 10 6 5

Example: Calculating the Standard Deviation of n BMI s Standard deviation: a measure of how widely scattered values are (More on this in your first stats class...). n=howmany To compute: 1. Compute the average. Subtract the average from each BMI 3. Square the differences 4. Sum the squared differences 5. Divide by n-1 6. Compute the square root 6

Example: Standard Deviation BMI Avg Diff Sq Diff. - 6.76 = -4.56 0.79 3.1-6.76 = -3.66 13.40 35.0-6.76 = 8.4 67.90 8.3-6.76 = 1.54.37 19.5-6.76 = -7.6 5.71.5-6.76 = -4.6 18.15 37.4-6.76 = 10.64 113.1 30.0-6.76 = 3.4 10.50 9.1-6.76 =.34 5.48 0.5-6.76 = -6.6 39.19 7

Example: Standard Deviation Sum of squared differences = 343.70 Divide by n-1 = 10-1 = 9 to get 38.18888 Take the square root = 6.18, or 6. Later we will use a statistical software package to calculate means (averages) and standard deviations. 8

Algebraic Expressions: Order of Operations Order is important! Recall BMI = Ht Wt For example, BMI = 67.5 1.7 =3.4 We squared Ht before dividing Wt by the denominator. What if we divided and then squared? BMI ( ) Wt = Ht ( ) 67.5 = 1576.3 1.7 Not the same! 9

Algebraic Expressions: Order of Operations Solution: Paul and Judi s Rules of Order 1. Do operations in Parentheses first, starting with the innermost brackets.. Simplify Exponential expressions. 3. Multiply and Divide from left to right. 4. Add and Subtract from left to right. Please Excuse My Dear Aunt Sally 10

Algebraic Expressions: Order of Operations Example: (3 + 1) [5+ ] 1 +1 [ ] 1. Innermost bracket 5+ 4 1 +1. Exponents inside bracket [ 5+ 16 1 +1] 3. Multiplications and divisions inside bracket [5 + 8 +1] [5 + 16 +1] 4. Additions and subtractions inside bracket, left to right [0] 5. Exponents outside bracket = 400 11

Practice: Order of Operations [ + (7 3) + 0 4 ] 7 +3 3+ [ + (4) + 0 4 3+ 8 ] [ + 16 + 0 4 3+ 8 ] [ + 16 + 5 3 + 14] 1

Practice: Order of Operations [ + 16 + 15 + 14] [67] 4489 44.5 13

Order of Operations You can use brackets and parentheses to add clarity to formulas, even if the formula is correct without them. They can help you remember which operations to do first. Be liberal with brackets and parentheses! 14

Order of Operations: Practice with a Calculator [ + (7 3) + 0 4 ] 7 +3 3+ (( + (7 3) +(0/4) 3 + ((7 +3)/)) )/ 15

Variable Expressions When we use letters as placeholders for unknown quantities, the letters are called variables. We saw b 10 c when we discussed scientific notation. We could write BMI = w h Sometimes we write xy to mean x times y. If x = 3 and y = then xy = 6 (not 3) 16

Evaluating Variable Expressions Substitute for each variable the number it represents. Let w =67.5 kgandh =1.7 m. BMI = w h BMI = 67.5 kg 1.7 m =3.4 17

Evaluating Variable Expressions Ideal body weight (IBW) for males, where h = height in inches: IBW (lbs) = 106 + 6(h 60) = 106 + (6 (h 60)) Let h = 68 inches. IBW (lbs) = 106 + (6 (68 60)) = 106 + (6 8) = 106 + 48 = 154 lbs 18

Simplifying Variable Expressions If two terms have the same variables, they can be combined. These can be combined: 3x y +x y = 5x y a b +ba = 4a b (commutative law) These cannot be combined: 3x y +x a b +ab 19

Practice Simplifying Variable Expressions 3a +4b +7 a +8+6b +3b = a +7b +15+6b 0

Evaluating Variable Expressions We can use regression to predict the length of a newborn baby, given two factors we know about the baby s birth: Did the mother experience toxemia during pregnancy? What was the baby s gestational age? Let l = length in centimeters Let g = gestational age in weeks Let t = toxemia (where 0 = no toxemia and 1 = toxemia) l =6.61 + 1.05g 3.48t +0.06gt 1

Evaluating Variable Expressions What if toxemia = yes? Then t = 1 and: Simplifying: l =6.61 + 1.05g 3.48 + 0.06g l =(6.61 3.48) + (1.05 + 0.06)g l =3.13 + 1.11g

Evaluating Variable Expressions What if toxemia = no? Then t = 0 and: l =6.61 + 1.05g 3.48(0) + 0.06(0)g l =6.61 + 1.05g So, for toxemia = 1 (yes), l =3.13 + 1.11g. For toxemia = 0 (no), l =6.61 + 1.05g. 3

Evaluating Variable Expressions l =6.61 + 1.05g 3.48t +0.06gt If gestational age = 3 weeks and toxemia = yes, then what is the infant s predicted length? We can substitute: l =6.61 + 1.05(3) 3.48(1) + 0.06(3)(1) Simplifying (first multiply, then add and subtract): l =6.61 + 33.6 3.48 + 1.9 l =38.65 cm 4