Geometry Practice Test Unit 8 Name Period: Note: this page will not be available to you for the test. Memorize it! Trigonometric Functions (p. 53 of the Geometry Handbook, version 2.1) SOH CAH TOA sin sin sin cos cos cos tan tan tan Special Triangles (p. 52 of the Geometry Handbook, version 2.1) 45⁰ 45⁰ 90⁰ Triangle 1 1 In a 45⁰ 45⁰ 90⁰ triangle, the congruence of two angles guarantees the congruence of the two legs of the triangle. The proportions of the three sides are:. That is, the two legs have the same length and the hypotenuse is times as long as either leg. 30⁰ 60⁰ 90⁰ Triangle 2 In a 30⁰ 60⁰ 90⁰ triangle, the proportions of the three sides are:. That is, the long leg is times as long as the short leg, and the hypotenuse is times as long as the short leg. 1
Solve each triangle below. Remember, each triangle has three answers. For these problems, we have added names for the angles and the missing sides. We suggest you do the same. 1) A 2) B 6 12 10 45 C B A C The first thing to notice about this right triangle is that the short leg is half the length of the hypotenuse. That makes this a 30 60 90 triangle, which has side proportions: 1 3 2. So, we have: 6 3 The first thing to notice about this right triangle is that it has a 45 angle. That makes this a 45 45 90 triangle, which has side proportions: 1 1 2. So, we have: 3) B This is not a special triangle, so we must use Trig functions to solve it. C 15 9 A First, we have: Then, tan 15 9 sin 15 9 9. tan 15 9. sin 15 Page 2
Tip: When calculating angles in problems where two side lengths are given, base your trig functions on the given lengths, even if you have already calculated the length of the remaining side. This will produce more accurate answers. 4) C 2 B This is not a special triangle, so we must use Trig functions to solve it. A 7 First, we have: Then, 2 7 4 49 45 45 ~. sin 2 7 sin 2. 7.. 5) 12 C 5 Hope you like Trig functions! First, we have: 5 12 25 144 169 169 A B Then, tan 5 12 tan 5. 12.. A Here they are again! 6) First, we have: Then, B 22 10 C tan 22 10 cos 22 10 10 tan 22 ~. 10 cos 22 ~. Page 3
7) A regular octagon has a perimeter of 80 inches and an apothem of 12.07 inches. Find the area of the regular octagon, rounded to one decimal place. The formula for the area of a regular polygon is, where is the length of the apothem and is the perimeter of the polygon. We are given: 80, 12.07 So, 12.07 80. in2 8) Find the area of the regular hexagon shown below. Leave your answer as a radical. Step 1: How many sides? 6 Step 2: Find the perimeter: 6 18 mm 108 mm Step 3: Find the apothem: Create the little guy triangle: Our goal is to find. mm The length of the base of the little guy triangle is: 2 The sum of the angles in the figure (upper right) is: 6 2 180 720 Each angle of the figure measures: 720 6 120 120 260 Then, the little guy triangle is a 30 60 90 triangle. So,. Step 4: Calculate the area: Step 5: (Optional) Compare result to the area of a square with side 2. The area in Step 4 is 486 3 ~. The area of a square with side 2 18 3 should be a little more than this. Square area is: 18 3 18 3 324 3 vs. Page 4
9) A regular pentagon has each side = 8 cm. Find the area of the regular pentagon, rounded to one decimal place. Step 1: How many sides? 5 Step 2: Find the perimeter: 5 8 cm 40 cm Step 3: Find the apothem: Create the little guy triangle: cm Our goal is to find. The length of the base of the little guy triangle is: 2 The sum of the angles in the figure (upper right) is: 5 2 180 540 Each angle of the figure measures: 540 5 108 108 254 Then, tan 54 4tan54 ~.. (keep lots of decimals in your answers until the final calculation) Step 4: Calculate the area:.. Step 5: (Optional) Compare result to the area of a square with side 2. The area in Step 4 is. The area of a square with side 2 ~ 11.01 should be a little more than this. Square area is: 11.01 11.01. vs. Page 5
10) An equilateral triangle has a side of 7 3 inches. Find the area of the equilateral triangle. Leave your answer as a radical. Step 1: How many sides? 3 Step 2: Find the perimeter: 3 mm 21 3 in Step 3: Find the apothem: Create the little guy triangle: in Our goal is to find. The length of the base of the little guy triangle is: 2 The sum of the angles in a triangle is 180 Each angle of the figure measures: 180 3 60 60 230 Then, the little guy triangle is a 30 60 90 triangle. So,. Step 4: Calculate the area: Alternative: Find the height and then use the formula The length of the base of the left triangle is: 2 The sum of the angles in a triangle is 180 Each angle of the figure measures: 180 3 60 Then, the left triangle is a 30 60 90 triangle. So, 3 7 3 3 7 3 3 7 3. in Calculate the area of the entire triangle: Page 6
11) A regular hexagon has an apothem of 15 inches. Each side is 10 3. Find the area. We are given: 15 10 3 Perimeter 66 10 3 60 3 So, 15 60 3 in2 in 12) A regular octagon has a perimeter of 8 cm. Find the area of the regular octagon. Round your answer to the nearest tenth. Step 1: How many sides? 8 (note also that we are given ) Step 2: Find the length of a side: 8 1 Step 3: Find the apothem: Create the little guy triangle: Our goal is to find.. The length of the base of the little guy triangle is: 1 2. The sum of the angles in the figure upper right is: 8 2 180 1,080 Each angle of the figure measures: 1,080 8 135 135 267.5 Then, tan 67.5. So,. tan67.5. Step 4: Calculate the area:.. Step 5: (Optional) Compare result to the area of a square with side 2. The area in Step 4 is. The area of a square with side 2 ~ 2.4142 should be a little more than this. Square area is: 2.4142 2.4142. vs. Page 7
Find the surface area for each solid. 13) 4 ft. The two main options to deal with this problem are to use a formula, which works if you have it available, or to deconstruct the shape. We will illustrate the deconstruction method in Problems 13 and 14. 9 ft 3 ft Front and Back Two Sides Top and Bottom 9 ft 9 4 36 ft 2 4 ft 3 ft 4 ft 3 4 12 ft 2 9 ft 9 3 27 ft 2 3 ft Total Surface Area 2 36 2 12 2 27 ft 2 14) c Front and Back Triangular Faces 16 ft 1 2 16 7 7 ft 56 cm 2 Find length of hypotenuse: 7 16 305 ~ 17.46425 7 cm Left Rectangular Face Right Rectangular Face Bottom Rectangle 16 cm 17.46425 cm 7 cm 40 cm 40 cm 40 cm 40 16 640 cm 2 40 17.46425 698.57 cm 2 40 7 280 cm 2 Total Surface Area 2 56 640 698.57 280,. cm 2 Page 8
We will use formulas to calculate the surface area in the balance of these exercises. Find the surface area in terms of x. Leave pi in the answer. 15) 7 in 9x in The formula for the surface area of a cylinder is 2 2, where is the radius of the circular faces and is the height of the cylinder. For this problem, 7 and 9. So, 2 2 279 27 16) 13 in For this problem, 6.5 and 10. So, 10 in 2 2 26.510 26.5. 17) Find the surface area given the square base of side equal to 16m, and height of 10m. m Find the Slant Height Note that the length of the base of the triangular semi cross section if the pyramid is 16 28. Then, 10 m 8 m 8 10 164 ~. m The formula for the surface area of a pyramid is, where is the perimeter of the base, is the slant height of a face, and is the area of the base. For this problem, 4 1664, 12.80625 (see box at left), and 16 256 1 2 1 6412.80625 256. 2 Page 9
Find the surface area for the following solids. Leave pi in the answer. 18) 16 mm 5mm The formula for the surface area of a cone is, where is the radius of the circular base and is the height of the cone. For this problem, 5 and 5 16 16.763. So, 516.763 5. 19) 10 cm 13cm For this problem, 513 5 5 and 13. So, 20) Find the surface area of the cone in terms of x. l = 26x For this problem, 10 and 26. So, 1026 10 r = 10x Page 10
Find the surface area of the solids. Leave pi in the answer. 21) radius = 14 in The formula for the surface area of a sphere is 4, where is the radius of the sphere. For this problem, 14. So, 4 414 22) diameter = 14 cm For this problem, 4 47 7. So, Find the Surface Area of the solid. 23) 2.7 m 2.6 m 3.1 m The formula for the surface area of a rectangular prism is 2, where, and are the dimensions of the prism. For this problem, 2.7, 3.1, 2.6. So, 2 2 2 2 2.73.1 2.72.6 3.12.6. 24) radius = 6 mm 10 mm The formula for the surface area of a cylinder is 2 2, where is the radius of the circular faces and is the height of the cylinder. For this problem, 6 and 10. So, 2 2 2610 26 Page 11
25) Find the surface area of both the right hexagonal prism and the cylinder whose bases are drawn below. Notice that both figures have the same radius. Assume the hexagon is regular and that the height of both solids is 10 m. Surface Area of the Cylinder: 2 2 16 m For this problem, 16 and 10. So, 2 2 2 21610 216 2 ~,. Surface Area of the Hexagonal Prism First, find the area of the Hexagonal Base Step 1: How many sides? 6 Step 2: Find the perimeter: Note that the length of a side of a hexagon is the same as its radius. So, 6 16 mm 96 m Step 3: Find the apothem: Create the little guy triangle: m m Our goal is to find. The length of the base of the little guy triangle is: 2 hypotenuse Therefore, the little guy triangle is a 30 60 90 triangle. So, 3. Step 4: Calculate the area of each hexagonal base: ~. Next, find the area of each rectangular face: 16 10 Then, find the surface area of the regular hexagonal prism: The prism has 2 bases and 6 faces, so 2 6, where is the area of a hexagonal base and is the area of a rectangular face. Page 12 2. 6,.