Roadmap. Handling large amount of data efficiently. Stable storage. Parallel dataflow. External memory algorithms and data structures

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Roadmap Handling large amount of data efficiently Stable storage External memory algorithms and data structures Implementing relational operators Parallel dataflow Algorithms for MapReduce Implementing concurrency Implementing resilience coping with system failures Introduction to query optimization

Lecture 2.3 Data transfer between disk and RAM Buffer management in DBMS By Marina Barsky Winter 27, University of Toronto

Data must be in RAM to operate on it!

Buffering disk blocks in main memory In order to provide efficient access to disk block data, every DBMS implements a large shared buffer pool in its own memory space The buffer pool is organized as an array of, each frame size corresponds precisely to a size of a single database disk block. Blocks are copied in native format from disk directly into, manipulated in memory in native format, and written back.

Buffer pool Page Requests from Higher Levels BUFFER POOL MAIN MEMORY disk page free frame DB DISK choice of frame dictated by replacement policy Table of <frame#,pageid> pairs is maintained.

Page table Associated with the array of is an array of metadata called a page table The page table contains for each frame: the disk location for the corresponding page a dirty bit to indicate whether the page has changed since it was read from disk any information needed by the page replacement policy used for choosing pages to evict on overflow. a pin count for the page in the frame

Pinning and unpinning pages Each frame with a page in it has an associated pin count The task requests the page and pins it by incrementing the pin count before manipulating the page, and decrementing it thereafter (unpins) The same page in pool may be requested many times, and pin count changes accordingly When requestor of a page unpins it, it sets a dirty bit to indicate that this page has been modified. A page is a candidate for replacement iff pin count = Concurrency & recovery may entail additional I/O when a frame is chosen for replacement (Write-Ahead Log protocol) Buffer manager tries to not replace dirty pages it may be expensive

Algorithm for loading pages into buffer if requested page is not in pool choose a frame for the page: if there are no free : choose the frame for replacement if frame is dirty: write it to disk read requested page into chosen frame pin the page and return its address. If requests can be predicted (e.g., sequential scans) pages can be pre fetched several pages at a time

Page faults A page fault occurs when a program requests data from a disk block and the corresponding page is not in buffer pool The thread is put into a wait state while the operating system finds the page on disk and loads it into a memory frame The goal is to have the least number of page faults possible to always keep necessary pages in buffer This is not possible with very large databases. We need to be able to replace pages in the buffer pool

Page replacement policy Frame is chosen for replacement by a replacement policy First-in-first-out (FIFO) Least-recently-used (LRU) Clock Most-recently-used (MRU) etc. We evaluate an algorithm by running it on a particular string of page requests and computing the number of page faults,

Least Recently Used (LRU) Replace the page that has not been referenced for the longest time Maintain a stack (queue?) of recently used pages

LRU page replacement algorithm: sample run Req. c a d b e b a b c d 4 RAM c c c c a a a d d b F F F F

LRU page replacement algorithm: sample run c a d b Req. c a d b e b a b c d 4 RAM c c c c e a a a a d d d b b F F F F F

LRU page replacement algorithm: sample run Req. c a d b e b a b c d 4 RAM c c c c e e e e a a a a a a a d d d d d d b b b b b F F F F F

LRU page replacement algorithm: sample run d e a b Req. c a d b e b a b c d 4 RAM c c c c e e e e a a a a a a a d d d d d d b b b b b F F F F F F

LRU page replacement algorithm: sample run d e a b Req. c a d b e b a b c d 4 RAM c c c c e e e e e a a a a a a a a d d d d d d c b b b b b b F F F F F F

LRU page replacement algorithm: sample run Which page is evicted next? Req. c a d b e b a b c d 4 RAM c c c c e e e e e a a a a a a a a d d d d d d c b b b b b b F F F F F F

LRU page replacement algorithm: sample run e a b c Req. c a d b e b a b c d 4 RAM c c c c e e e e e d a a a a a a a a a d d d d d d c c b b b b b b b F F F F F F F 7 page faults for requests

Approximate LRU: the Clock algorithm Maintain a circular list of pages Use a clock bit (used) to track accessed page The bit is set to whenever a page is referenced Clock hand sweeps over pages looking for one with used bit= Replace pages that haven t been referenced for one complete revolution of the clock

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f f2 f3 f4 Resident bit f Used (clock) bit f4 f2 f3

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c f2 f3 f4 F f:c f4 f2 f3

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c f2 a f3 f4 F F f:c f4 f2:a f3

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c f2 a a f3 d f4 F F F f:c f4 f2:a f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c f2 a a a f3 d d f4 b F F F F f:c f4:b f2:a f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c f2 a a a f3 d d f4 b F F F F f:c f4:b f2:a Searching for page to evict f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c f2 a a a f3 d d f4 b F F F F f:c f4:b f2:a f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c f2 a a a f3 d d f4 b F F F F f:c f4:b f2:a f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c f2 a a a f3 d d f4 b F F F F f:c f4:b f2:a f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c e f2 a a a a f3 d d d f4 b b F F F F F f:e f4:b f2:a Evicted page c f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c e e f2 a a a a c f3 d d d d f4 b b b F F F F F F f:e f4:b f2:c Evicted page a its clock bit was f3:d

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c e e e f2 a a a a c c f3 d d d d a f4 b b b b F F F F F F F f:e f4:b f2:c Evicted page d f3:a

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c e e e e f2 a a a a c c c f3 d d d d a a f4 b b b b b F F F F F F F f:e f4:b f3:a f2:c We know that b is in buffer set its bit to used this would be our clock start

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c e e e e e f2 a a a a c c c c f3 d d d d a a a f4 b b b b b b F F F F F F F f:e f4:b f2:c We know that c is in buffer our clock start moves to c f3:a

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c e e e e e f2 a a a a c c c c f3 d d d d a a a f4 b b b b b b F F F F F F F f4:b f:e f3:a f2:c Where does d go: A: frame B: frame 2 C: frame 3 D: frame 4

The Clock replacement algorithm 4 RAM Req. c a d b e c a b c d f c c c c e e e e e f2 a a a a c c c c f3 d d d d a a a f4 b b b b b b F F F F F F F f4:b f:e f3:a f2:c Where does d go: A: frame B: frame 2 C: frame 3 D: frame 4 With LRU it would have been frame : e

Optimizing Clock: The Second Chance algorithm There is a significant cost to replacing dirty pages Modified Clock algorithm allows dirty pages to always survive one sweep of the clock hand Assuming there are 4 classes of pages: Used bit Class Class 2 Class 3 Class 4 Dirty bit During the first revolution of the clock unset the used bit as before, and evict page of Class if found If no pages of Class found during the entire revolution, in the next revolution evict page of Class 2, writing its dirty content to disk

Replacement policy depends on data access pattern Policy can have big impact on # of I/O s; depends on the access pattern. Sequential flooding: Nasty situation caused by LRU + repeated sequential scans. # buffer < # pages in file In this case each page request causes an I/O. MRU much better in this situation (but not in other situations)

Sequential flooding example: nested loop A: a, b B: c, d, e, f 3 for A - enough for each record i in A for each record j in B do something with i and j req. a a a a b b b b 3 for B < B req. c d e f c d e f

Sequential flooding example: nested loop A: a, b B: c, d, e, f for each record i in A for each record j in B do something with i and j 3 for A - enough 3 for B < B req. a a a a b b b b a a a F req. c d e f c d e f c c c d d e F F F

Sequential flooding example: nested loop A: a, b B: c, d, e, f for each record i in A for each record j in B do something with i and j 3 for A - enough 3 for B < B req. a a a a b b b b a a a a F req. c d e f c d e f c c c f d d d e e F F F F f evicts c

Sequential flooding example: nested loop A: a, b B: c, d, e, f for each record i in A for each record j in B do something with i and j 3 for A - enough 3 for B < B req. a a a a b b b b a a a a a b F req. c d e f c d e f c c c f f d d d c e e e F F F F F F c evicts d

Sequential flooding example: nested loop A: a, b B: c, d, e, f for each record i in A for each record j in B do something with i and j 3 for A - enough 3 for B < B req. a a a a b b b b a a a a a a b b F req. c d e f c d e f c c c f f f d d d c c e e e d F F F F F F F d evicts e

Sequential flooding example: nested loop A: a, b B: c, d, e, f for each record i in A for each record j in B do something with i and j 3 for A - enough 3 for B < B req. a a a a b b b b a a a a a a a b b b F req. c d e f c d e f c c c f f f e d d d c c c e e e d d F F F F F F F F e evicts f

Sequential flooding example: nested loop A: a, b B: c, d, e, f for each record i in A for each record j in B do something with i and j 3 for A - enough 3 for B < B req. a a a a b b b b a a a a a a a a b b b b F req. c d e f c d e f c c c f f f e e d d d c c c f e e e d d d F F F F F F F F F f evicts c

Sequential flooding example: nested loop A: a, b B: c, d, e, f for each record i in A for each record j in B do something with i and j 3 for A - enough 3 for B < B req. a a a a b b b b a a a a a a a a b b b b F req. c d e f c d e f c c c f f f e e d d d c c c f e e e d d d F F F F F F F F F Sequential flooding each request page fault LRU happens to evict exactly the page which we will need next!

Sequential flooding The LRU page which we evict is always exactly the page we are going to want to read next! We end up having to read a page from disk for every page we read from the buffer This seems like an incredibly pointless use of a buffer!

Solutions General idea: to tune the replacement strategy via query plan information Most systems use simple enhancements to LRU schemes to account for the case of nested loops; Implemented in commercial systems - LRU-2 (evicts second to last frame) The replacement policy depending on the page type: e.g. the root of a B+-tree might be replaced with a different strategy than a page in a heap file, nested loops use MRU etc.

DBMS vs OS buffer management DBMS is better at predicting the data access patterns Buffer management in DBMS is able to: Pin a page in buffer pool Force a page to disk (required to implement CC & recovery) Adjust replacement policy Pre-fetch pages based on predictable access patterns This allows DBMS to Amortize rotational and seek costs Better control the overlap of I/O with computation (double-buffering) Leverage multiple disks

Think about Think about how would you implement LRU replacement policy? Clock algorithm? LRU-2? What is the difference between FIFO and LRU? Show on an example how MRU can be used to prevent sequential flooding Example of a computation where LRU is efficient Similar questions could be on the third quiz and on the exam