SECTION 7.4 THE LAW OF SINES 483. Triangles AjfijC, and A2B2C2 are shown in Figure 9. b = a = EXAMPLE 5 SSA, the No-Solution Case

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SECTION 7.4 THE LAW OF SINES 483 the foothills of the Himalayas. A later expedition, using triangulation, calculated the height of the highest peak of the Himalayas to be 29,002 ft. The peak was named in honor of Sir George Everest. Today, using satellites, the height of Mt. Everest is estimated to be 29,028 ft. The very close agreement of these two estimates shows the great accuracy of the trigonometric method. Triangles AjfijC, and A2B2C2 are shown in Figure 9. C, b = 248.6 a = 186.2 FIGURE 9, «257.8 The next example presents a situation for which no triangle is compatible with the given data. EXAMPLE 5 SSA, the No-Solution Case Solve triangle ABC, where /.A = 42, a = 70, and b = 122. SOLUTION First, let's try to find LB. We have sin A sin B Law of Sines 6 sin A 122 sin 42 Sin B = = = 1.17 Solve for sin B Since the sine of an angle is never greater than 1, we conclude that no triangle satisfies the conditions given in this problem. EXERCISES 1-6 Use the Law of Sines to find the indicated side x or 3. 2. 90 23.1 B 28.1

484 CHAPTER 7 TRIGONOMETRIC FUNCTIONS OF ANGLES.. 5. 6. 28 LBAC = 82 and LABC = 52. Approximate the distance from A to C. 200ft 26. A tree or the angle tal and th height of 7-8 Solve the triangle using the Law of Sines. 7. 8. 65 9-14 Sketch each triangle and then solve the triangle using the Law of Sines. 9. LA = 50, LB = 68, c = 230 10. /.A = 23, LB= 110, c = 50 11. LA = 30, LC = 65, b = 10 12. LA = 22, LB = 95, a = 420 13. LB = 29, LC = 51, b = 44 14. LB = 10, LC= 100, c= 115 15-22 Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. 15. a = 28, b = 15, LA = 110 16. a = 30, c = 40, LA = 37 17. a = 20, c = 45, LA = 125 18. b = 45, c = 42, LC = 38 19. b = 25, c = 30, LB = 25 20. a = 75, b = 100, LA = 30 21. a = 50, b = 100, LA = 50 22. a = 100, b = 80, LA = 135 23. To find the distance across a river, a surveyor chooses points A and B, which are 200 ft apart on one side of the river (see the figure). She then chooses a reference point C on the opposite side of the river and finds that 24. A pilot is flying over a straight highway. He determines the angles of depression to two mileposts, 5 mi apart, to be 32 and 48, as shown in the figure. (a) Find the distance of the plane from point A. (b) Find the elevation of the plane. 25. The path of a satellite orbiting the earth causes it to pass directly over two tracking stations A and B, which are 50 mi apart. When the satellite is on one side of the two stations, the angles of elevation at A and B are measured to be 87.0 and 84.2, respectively. (a) How far is the satellite from station Al (b) How high is the satellite above the ground? mi 27. A commi as shown wire is tc ground, angle a i length of 28. Points A between that La as 527 ft 29. Tocalcu tance d (a) Find (b) Shov form

SECTION 7.4 THE LAW OF SINES 485 late the distance 26. A tree on a hillside casts a shadow 215 ft down the hill. If the angle of inclination of the hillside is 22 to the horizontal and the angle of elevation of the sun is 52, find the height of the tree. (c) Use the formula in part (b) to find the height of a mountain if a = 25, /3 «29, and d = 800 ft. : determines the apart, to be it A. 215 27. A communication tower is located at the top of a steep hill, as shown. The angle of inclination of the hill is 58. A guy wire is to be attached to the top of the tower and to the ground, 100 m downhill from the base of the tower. The angle a in the figure is determined to be 12. Find the length of cable required for the guy wire. < ---- d 30. Observers at P and Q are located on the side of a hill that is inclined 32 to the horizontal, as shown. The observer at P determines the angle of elevation to a hot-air balloon to be 62. At the same instant, the observer at Q measures the angle of elevation to the balloon to be 71. If P is 60 m down the hill from Q, find the distance from Q to the balloon. es it to pass vhich are of the two e measured to d? 28. Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point C on land such that tcab = 48.6. He also measures CA as 312 ft and CB as 527 ft. Find the distance between A and B. 29. To calculate the height of a mountain, angles a, ft, and distance d are determined, as shown. (a) Find the length of BC in terms of a, ft, and d. (b) Show that the height h of the mountain is given by the formula, sin a sin 6 h = d sm(/3 - a) 31. A water tower 30 m tall is located at the top of a hill. From a distance of 120 m down the hill, it is observed that the angle formed between the top and base of the tower is 8. Find the angle of inclination of the hill.

SECTION 7.5 THE LAW OF COSINES 491 I?'5 I EXERCISES 1-6 Use the Law of Cosines to determine the indicated side x or angle 6. 1. 2. 13. b = 125, c = 162, /IB = 40 14. a = 65, c = 50, /LC = 52 15. a = 50, b = 65, A4 = 55 20 B 10 4. 16.a = 73.5, /LB = 61, ^C = 83 17-24 Find the indicated side x or angle 0. (Use either the Law of Sines or the Law of Cosines, as appropriate.) C 18. C ending factor in low follows by 60.1/0 154.6 122.5 6. 10 location (see 280, and 315 ft. 20 22. C 7-16 Solve triangle ABC. 7. 8. 9. a = 3.0, b = 4.0, LC = 53 10. b = 60, c = 30, A = 10 11. a = 20, b = 25, c = 22 12. a = 10, b = 12, c = 16 38

492 CHAPTER 7 TRIGONOMETRIC FUNCTIONS OF ANGLES 25. To find the distance across a small lake, a surveyor has taken the measurements shown. Find the distance across the lake using this information. 32. Two tugboats that are 120 ft apart pull a barge, as shown. If the length of one cable is 212 ft and the length of the other is 230 ft, find the angle formed by the two cables. mountain needed. ~ X* -3 L \J 3.56 mi 26. A parallelogram has sides of lengths 3 and 5, and one angle is 50. Find the lengths of the diagonals. 27. Two straight roads diverge at an angle of 65. Two cars leave the intersection at 2:00 P.M., one traveling at 50 mi/h and the other at 30 mi/h. How far apart are the cars at 2:30 P.M.? 28. A car travels along a straight road, heading east for 1 h, then traveling for 30 min on another road that leads northeast. If the car has maintained a constant speed of 40 mi/h, how far is it from its starting position? 29. A pilot flies in a straight path for 1 h 30 min. She then makes a course correction, heading 10 to the right of her original course, and flies 2 h in the new direction. If she maintains a constant speed of 625 mi/h, how far is she from her starting position? 30. Two boats leave the same port at the same time. One travels at a speed of 30 mi/h in the direction N 50 E and the other travels at a speed of 26 mi/h in a direction S 70 E (see the figure). How far apart are the two boats after one hour? Ni N50 E 230ft 33. A boy is flying two kites at the same time. He has 380 ft of line out to one kite and 420 ft to the other. He estimates the angle between the two lines to be 30. Approximate the distance between the kites. 34. A 125-ft tower is located on the side of a mountain that inclined 32 to the horizontal. A guy wire is to be attached to the top of the tower and anchored at a point 55 ft downhill from the base of the tower. Find the shortest length of wire needed. 36. TheCNl the world above the two landr angle forr 43. She and the li the other two landn 37. Three circ Find the s w 50 S70 E 31. A triangular field has sides of lengths 22, 36, and 44 yd. Find the largest angle. 35. A steep mountain is inclined 74 to the horizontal and rises 3400 ft above the surrounding plain. A cable car is to be installed from a point 800 ft from the base to the top of the

SECTION 7.5 THE LAW OF COSINES 493 ;e, as shown. If th of the other ibles. e has 380 ft of 5 estimates the ximate the ^ I mtain that is ' o be attached t 55 ft downest length of mountain, as shown. Find the shortest length of cable needed. 800ft ^74 3400 ft 36. The CN Tower in Toronto, Canada, is the highest tower in the world. A woman on the observation deck, 1150 ft above the ground, wants to determine the distance between two landmarks on the ground below. She observes that the angle formed by the lines of sight to these two landmarks is 43. She also observes that the angle between the vertical and the line of sight to one of the landmarks is 62 and to the other landmark is 54. Find the distance between the two landmarks. 38. Prove that in triangle ABC a = b cos C + c cos B b = c cos A + a cos C c = a cos B + b cos A These are called the Projection Laws. [Hint: To get the first equation, add together the second and third equations in the Law of Cosines and solve for a.] 39. A surveyor wishes to find the distance betwen two points A and B on the opposite side of a river. On her side of the river, she chooses two points C and D that are 20 m apart and measures the angles shown. Find the distance between A and B. 40. Find the area of a triangle with sides of lengths 12, 18, and 24m. 41. Land in downtown Columbia is valued at $20 a square foot. What is the value of a triangular lot with sides of lengths 112, 148, and 190 ft? 42. Find the area of the quadrilateral in the figure, correct to two decimal places. ntal and rises ;ar is to be the top of the 37. Three circles of radii 4, 5, and 6 cm are mutually tangent. Find the shaded area enclosed between the circles. DISCOVERY DISCUSSION 43. Solving for the Angles in a Triangle When we solved for /LB in Example 3 using the Law of Sines, we had to be careful because there were two possibilities, 35.2 and 144.8. That is because these are the two angles between 0 and 180 whose sine is 0.577. What if we use the Law of Cosines to find LB1 Would the problem of two possible measures for LB still arise? Which method do you prefer here: the Law of Sines or the Law of Cosines?