PH 222-2A Spring 2015 Images Lectures 24-25 Chapter 34 (Halliday/Resnick/Walker, Fundamentals of Physics 9 th edition) 3
Chapter 34 Images One of the most important uses of the basic laws governing light is the production of images. Images are critical to a variety of fields and industries ranging from entertainment, to security, to medicine. In this chapter we define and classify images, and then classify several basic ways in which they can be produced. 4
Two Types of Images object lens real image object mirror virtual image Image: A reproduction derived from light. Real Image: Light rays actually pass through image, really exist in space (or on a screen for example) whether you are looking or not. Virtual Image: No light rays actually pass through image. Only appear to be coming from image. Image only exists when rays are traced back to perceived 5 location of source.
A Common Mirage Light travels faster through warm air warmer air has smaller index of refraction than colder air refraction of light near hot surfaces. For observer in car, light appears to be coming from the road top ahead, but is really coming from the sky. Fig. 34-1 6
Plane Mirrors, Point Object Plane mirror is a flat reflecting surface. Fig. 34-2 Identical triangles Ib Ob Fig. 34-3 Plane Mirror: i p Since I is a virtual image, i < 0. 7
Plane Mirrors, Extended Object Each point source of light in the extended object is mapped to a point in the image. Fig. 34-4 Fig. 34-5 8
Plane Mirrors, Mirror Maze Your eye traces incoming rays straight back, and cannot know that the rays may have actually been reflected many times. 1 2 8 3 9 7 6 4 5 4 2 3 1 6 5 8 7 9 Fig. 34-6 9
plane concave Spherical Mirrors, Making a Spherical Mirror Plane mirror concave mirror 1. Center of curvature C: in front at infinity in front but closer 2. Field of view - the extent of the scene that is reflected to observer wide smaller 3. Image i=p i >p 4. Image height image height = object height image height > object height convex Fig. 34-7 Plane mirror convex mirror 1. Center of curvature C: in front at infinity behind mirror and closer 2. Field of view wide larger 3. Image i=p i <p 4. Image height image height = object height image height < object height 10
Spherical Mirrors, Focal Points of Spherical Mirrors concave convex Fig. 34-8 Spherical Mirror: f r > 0 for concave (real focal point) r < 0 for convex (virtual focal point) 11 1 2 r
Images from Spherical Mirrors Start with rays leaving a point on object, where they intersect, or appear to intersect, marks the corresponding point on the image. Fig. 34-9 Real images form on the side where the object is located (side to which light is going). Virtual images form on the opposite side. Spherical Mirror: 1 1 1 Lateral Magnification: p i f Lateral Magnification: h ' m h i m 12 p
Locating Images by Drawing Rays Fig. 34-10 1. A ray that is parallel to central axis reflects through F. 2. A ray that reflects from mirror after passing through F emerges parallel to central axis. 3. A ray that reflects from mirror after passing through C returns along itself. 4. A ray that reflects from mirror after passing through c is reflected symmetrically about the central axis. 13
Proof of the Magnification Equation Similar triangles (are angles same?) Fig. 34-10 de cd de cd i, ca p, m ab ca ab i m (magnification) p 14
The Spherical Mirror Formula and 2 1 2 2 ac ac ac ac, co p cc r Fig. 34-20 ac ac CI i 1 f r r 2 f 2 ac ac ac 1 1 1 2 p i 2 f p i f 15
Spherical Refracting Surfaces Fig. 34-11 Real images form on the side of a refracting surface that is opposite the object (side to which light is going). Virtual images form on the same side as the object. Spherical Refracting Surface: n n n n p i r 1 2 2 1 When object faces a convex refracting surface r is positive. When it faces a concave surface, r is negative. CAUTION: This is reverse of mirror sign convention! 16
Thin Lenses Converging lens Diverging lens Fig. 34-13 Thin Lens: 1 1 1 f p i 1 1 1 f r1 r2 Thin Lens in Air: n 1 Lens only can function if the index of the lens is different from that of its surrounding medium. 17
Images from Thin Lenses Fig. 34-14 Real images form on the side of a lens that is opposite the object (side to which light is going). Virtual images form on the same side as the object. 18
Locating Images of Extended Objects by Drawing Rays Fig. 34-15 1. A ray initially parallel to central axis will pass through F 2. 2. A ray that initially passes through F 1, will emerge parallel to central axis. 3. A ray that initially is directed toward the center of the lens will emerge from the lens with no change in its direction (the two sides of the lens at the center are almost parallel). 19
Image formation by a converging lens 20
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Two-Lens System O p 1 i 1 I 1 p 2 i 2 I 2 O 2 Lens 1 Lens 2 1. Let p 1 be the distance of object O from Lens 1. Use equation and/or principle rays to determine the distance to the image of Lens 1, i 1. 2. Ignore Lens 1, and use I 1 as the object O 2. If O 2 is located beyond Lens 2, then use a negative object distance p 2. Determine i 2 using the equation and/or principle rays to locate the final image I 2. The net magnification is: M mm 1 2 24
Two converging lenses, each with a focal length of 0.12 m, are used in combination to form an image of an object located 0.36 m to the left of the left lens in the pair. The distance between the lenses is 0.24 m. (a)where is the final image located relative to the lens on the right? (b) What is the total magnification of the lens combination? 0.24m i 2 p 2 p 1 i 1 a) find image distance i of the first object 1 1 1 1 1 1 p f p i f i f p p f 1 1 1 1 1 1 1 1 1 1 1 p 1 1 i1 p1 f1 0.36 0.12 0.18 2 1 f 0.36 0.12 0.36 0.12 p 0.24 i 0.24 0.18 0.06m find image distance i of the second object 1 0.18m 1 1 1 p f 0.06 0.12 0.06 0.12 i p i f p f 2 2 2 2 2 2 2 2 0.06 0.12 0.06 image is located 0.12 m to the left of the right lens i i 0.18 0.12 0.12m 1 2 b) M m1 m 2 1 p1 p2 0.36 0.06 The size of the final image =size of the object, but the image is inverted.
The human eye 27
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The refractive power of a lens. The diopter. 30
Focal point of contact lens Contact lens should bring the image of the object positioned at the near point of normal eye (0.25m) to the near point of farsighted eye (0.80m). =+0.36 m; refractive power = 1/0.36 m = 2.75 Diopters 31
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Optical Instruments, Simple Magnifying Lens You can make an object appear larger (greater angular magnification) by simply bringing it closer to your eye. However, the eye cannot focus on objects closer than the near point: p n ~25 cmbig & BLURRY IMAGE A simple magnifying lens allows the object to be placed close by making a large virtual image that is far away. Simple Magnifier: m 25 cm f Fig. 34-17 ' m h 25 cm Object at F 1 and ' h f 33
Problem 93. Someone with a near point P n of 25 cm views a thimble through a simple magnifying lens of focal lengths 10 cm by placing the lens near the eye. What is the angular magnification of the thimble if it is positioned so that its image appears at: a) P n; b)infinity? a) Without the magnifier, q = h/p n. With the magnifier, letting i = i = P n, and we obtain 1 1 1 1 1 1 1. p f i f i f P n Consequently, m 1 1 1 1 1 1 1. p f i f i f P n h p f P / 1/ 1/ h/ P 1/ P n n n Pn 25 cm 1 1. f f i i 1/ p1/ i1/ p1/ f In the case where the image appears at infinity, let so that we have m h/ p 1/ f Pn 25cm. With f = 10 cm, 25 cm m h/ Pn 1/ Pn f f 2.5. 10 cm 34
Optical Instruments, Compound Microscope O close to F 1 I close to F 1 Mag. Lens Fig. 34-18 i s m since i s and p f p f M mm ob ob ey ob s 25 cm magnification compounded (microscope) f f 35
Optical Instruments, Refracting Telescope I close to F 2 and F 1 Mag. Lens Fig. 34-19 m ey, ob, ey ob fob fey m f f ob ey h' (telescope) h' 36