پوهنتون کابل پوهنځی كمپيوترساینس

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پوهنتون کابل پوهنځی كمپيوترساینس دیپارتمنت سیستم های معلوماتی : : تهیه کننده سال پوهنیار محمد شعیب "زرین خیل" 389

By: M Shuaib Zarinkhail 00

Each column has a unique name which shows one attribute of an entity All values in a column must be of the same type (Data Type) Order of columns and rows is irrelevant Each cell in a relation must be single value No repeating groups or arrays in one cell No two rows can be identical Adjusting Non-Supported Data Type in MySQL By: Zarinkhail 8/5/89

National ID Name Date of Birth 3-45-4567 Saber -03-354 3-45-5678 Maryam 04--358 3-45-6789 Kaihan 06--364 3 By: Zarinkhail 8/5/89 Adjusting Non-Supported Data Type in MySQL

Prior to use, a database must be created Space must be allocated for tables, userdata, indexes, and metadata Metadata tables need to be created and populated Different ways to create the DB structure: GUI (Graphical User Interface) SQL DDL (SQL - Data Definition Language) 4

5

6

CREATE TABLE emp# name address dept dob ); EMPLOYEE( integer varchar(40) varchar(80) varchar(0), date not null, not null, not null, 7

Examples of relational data manipulation languages: Relational Algebra Relational Calculus QBE / QBF Transform-Oriented Languages 8

Procedural Part of Computer Science Part of Relational Model Deals with sets of relations 9

Relevant to Mathematical Logic and Set Theory Relations can be manipulated using operators Relations deal as relvars Topic of much of this and next lectures 0

Non-procedural Can be used for proofs Mainly used by theorists Comes from predicate calculus Example: F = ($Y)(p(X,Y) Ú q(y,z))

Consists of two calculi The tuple relational calculus (TRC) Variables range over tuples The domain relational calculus (DRC) Variables range over domain elements (field values)

RC has variables, constants, comparison operators, logical connectives and quantifiers Expressions in the RC are called formulas RC is contrast to RA 3

RA and RC are logically equivalent For any algebraic expression in RA, there is an equivalent expression in RC and vice versa The difference is known as Dr Codd s Theorem 4

RA might suggest these steps in a query Join books and titles over the BookStoreID Restrict the result of that join to tuples for a sample book Project the result of that over StoreName and StorePhone RC would formulate a descriptive, declarative way: Get StoreName and StorePhone for supplies such that there exists a title BK with the same BookStoreID value and with a BookTitle value of a Sample book 5

Non-procedural languages Produce results as a relation Mostly extracted from SQL SQL stands for Structured Query Language Examples are in the next slide 6

.QL (Dot Quel) CQL (Common Query Language) ERROL (Entity Relationship Role Oriented Language) QUEL QBE (Query By Example) SPARQL (Sparkle) XQuery (XML Query) XSQL (XMLSQL) 7

Is a database query language for relational DBs First developed at IBM in the early 970 s by Moshe M. Zloof QBE is both the name of the DML and an early database system that included this language QBE is the first graphical query language, using visual tables where the user would enter commands, example elements and conditions 8

QBE Has two distinct features:. a two dimensional syntax Queries look like tables 3. queries are expressed by example, Instead of giving procedures for obtaining a desired answer the user gives an example of what is desired 9

3. There are two flavors of QBE GUI based methods of dealing with a DB Graphical version (i.e. Microsoft-Access) 4. By filling in a form or spreadsheet The original text based version Can alter the database or query 0

Major data: methods for manipulating Forms Query languages Stored procedures Application Program Interfaces (API)

Common way to control access in a database Usually custom-built for a table or set of tables Many databases have this type of feature: Oracle (additional package) MS-Access (standard with the database)

3

SQL is the most common query language SQL is non-procedural Lets database determine how to get the data Usually used via a client/server DB Can perform other operations aside from queries: update, insert, and delete data 4

SELECT emp#, name, address FROM EMPLOYEE WHERE dept = Accounting OR dept = Design ; Queries employee number, name and address for those who belong to the Accounting or Design departments UPDATE EMPLOYEE SET salary = salary *.05 WHERE name = Feda ; This query adds a 5% increase to the salaries of Feda 5

Most DBs provide a way to store commonly used SQL statements Analogous to the idea of a function or method in a programming language Can pass in arguments to fill in parameters within the stored procedure Could contain multiple SQL statements 6

Many DBs have APIs available that allow developers to write programs that will connect up to the DB Example: Java s JDBC APIs allow developers to: Issue SQL commands Work with the results that are returned by the DB 7

Often have an underlying set of methods that are actually used Methods and usage documents are included A pre-compiler is used to convert the SQL statements in the appropriate method calls 8

9

By: M Shuaib Zarinkhail 00

Received little attention until the publication of Codd s Relational Model Theory in 970 Codd proposed such an algebra as a basis for DB Query Languages The first query language based on Codd s algebra was ISBL (Information Systems Base Language) 3

Provides a way to construct new relations from existing relations Query languages are based on RA Deals as Read-Only to the relations Some operations are similar to the corresponding set operations 3

Consists of: variables represent relations Operators represent the actions we can take with these relations 33

Three classes of operators: Set based: - Union - Intersection - Difference Operations to remove parts of relations: - Selection: eliminates some rows - Projection: eliminates some columns Operations that join tuples in two relations: - Product - Join - Divide 34

Union Intersection Selection Difference Divide Projection a b c a a a b c b b b b b b3 c c c3 x y a Product (Natural) Join a a a3 x y x x y a a a3 b b b c c c a b c x y a a b b c c x y x y x y 35

The union of two relations produces a new relation with the all of the rows from either relation No duplicates are allowed (duplicates are removed) Common notations: R S R+S R UNION S 36

37

To create a union of two relations, they must be Union Compatible : Each relation has the same number of attributes The attributes must be in the same order in both relations corresponding attributes must come from the same domain 38

EMP(Emp#, Name, Salary) DEPT(Dept#, Name, Income) Does EMP + DEPT make sense? Note: Most databases would let you do this! 39

The union operation is commutative R S=S R Note: All RA operations are not commutative! 40

BuildEmployees EMP # 4 5 7 8 Name Address DoB NID Bahadur Kabir Wasil Edris Laila Chamtal Dis Dis4 Dis6 Dis Dis9 Dis 345 3456 34567 45678 56789 67890 /3/54 3//49 4/7/53 9/6/45 //39 4/9/55 4

DesignEmployees EMP # 3 5 7 9 Name Address DoB NID Bahadur Adalat Edris Laila Jaihona Dis Dis Dis Dis9 Dis 345 98765 45678 56789 87654 /3/54 5//44 9/6/45 //39 6/7/4 4

What is the result of BuildEmployees UNION DesignEmployees? 43

Result: EMP# Name Address DoB NID Bahadur Dis /3/54 345 Kabir Dis4 3//49 3456 3 Adalat Dis 5//44 98765 4 Wasil Dis6 4/7/53 34567 5 Edris Dis 9/6/45 45678 7 Laila Dis9 //39 56789 8 Chamtal Dis 4/9/55 67890 9 Jaihona Dis 6/7/4 87654 44

The intersection of two relations is a new relation that contains the rows that appear in both relations The relations must be union compatible Notation: R S R INTERSECT S 45

46

Order of relations in the operation is irrelevant the result will be the same as R S=S R 47

BuildEmployees EMP # 4 5 7 8 Name Address DoB NID Bahadur Kabir Wasil Edris Laila Chamtal Dis Dis4 Dis6 Dis Dis9 Dis 345 3456 34567 45678 56789 67890 /3/54 3//49 4/7/53 9/6/45 //39 4/9/55 48

DesignEmployees EMP # 3 5 7 9 Name Address DoB NID Bahadur Adalat Edris Laila Jaihona Dis Dis Dis Dis9 Dis 345 98765 45678 56789 87654 /3/54 5//44 9/6/45 //39 6/7/4 49

What is the result of BuildEmployees INTERSECT DesignEmployees? 50

Results: EMP # 5 7 Name Addre ss Bahadur Dis Edris Dis Laila Dis9 DoB NID /3/54 9/6/45 //39 345 45678 56789 5

Difference gives all of the rows from the first relation that do not appear in the second relation Relations must be union compatible Notations: R S R DIFFERENCE S 5

53

Order does change the resulting relation, just as order is important in subtraction operation in math: R S S R 54

BuildEmployees EMP # 4 5 7 8 Name Address DoB NID Bahadur Kabir Wasil Edris Laila Chamtal Dis Dis4 Dis6 Dis Dis9 Dis 345 3456 34567 45678 56789 67890 /3/54 3//49 4/7/53 9/6/45 //39 4/9/55 55

DesignEmployees EMP # 3 5 7 9 Name Address DoB NID Bahadur Adalat Edris Laila Jaihona Dis Dis Dis Dis9 Dis 345 98765 45678 56789 87654 /3/54 5//44 9/6/45 //39 6/7/4 56

What is the result of: DesignEmployees BuildEmployees? 57

Results: EMP Name # 3 Adalat 9 Jaihona Addres DoB NID s Dis 5//44 98765 Dis 6/7/4 87654 58

Selection produces a new relation with a subset of the original relation rows Notation: RELATION WHERE condition EMP WHERE Dept# = 3 Condition can be: =, >, <,,, OR: V, AND 59

Dep# DepName Sys Admin Programming 3 Finance 4 Management 5 Planning DEPT WHERE Dep# = OR Dep# = 3 OR Dep# = 5 What result is expected? Next Slide 60

Results: Dep# DepName Sys Admin 3 Finance 5 Planning 6

The project of a relation produces a new relation with selected columns from the original relation (i.e. limits the attributes that will appear in the new relation) Can also use to rearrange the order of columns in a relation Duplicate rows are removed during a projection Notation: RELATION[attr, attr, attr4] 6

BuildEmployees EMP # 4 5 Name Address DoB NID Bahadur Kabir Wasil Edris Dis Dis4 Dis6 Dis 345 3456 34567 45678 /3/54 3//49 4/7/53 9/6/45 What is the result of: BuildEployees [Emp#, Name, DoB] 63

Results: BuildEmployee [EMP#, Name, DoB] EMP# 4 5 Name Bahadur Kabir Wasil Edris DoB /3/54 3//49 4/7/53 9/6/45 64

By: M Shuaib Zarinkhail 00

The set of rows formed by combining each row in one relation with each of the rows in another relation Also called: Cartesian product or Cross product Notations: A x B, A PRODUCT B 66

EMP DEP EMP# Name Dept# Dep# DepName Bahadur Sys Admin Kabir Programming 3 Adalat 3 Finance 4 Management 4 Wasil 3 5 Planning 5 Edris What is the result of EMP X DEP? 67

EMP# Name EMP.Dept# DEPT. Dept# DeptName Bahadur Sys Admin Bahadur Programming Bahadur 3 Finance Bahadur 4 Management Bahadur 5 Planning 5 Rows removed for readability 5 Edris Sys Admin 5 Edris Programming 5 Edris 3 Finance 5 Edris 4 Management 5 Edris 5 Planning 68

The division is a binary operation The result consists of the restrictions of tuples in R to the attribute names unique to R i.e. in the header of R but not in the header of S, for which it holds that all their combinations with tuples in S are present in R For an example see the tables: Completed, DBProject and their division in NEXT SLIDE 69

Notation: R S Note: Attributes of S should be a subset of R, if not, the result will be an empty set 70

Completed Student Farid Farid Farid Fawad Fawad Sara Sara 7 Task Database Database Compiler Database Compiler Database Database DBProject Task Database Database Completed DBProject Student Farid Sara

Need a way to connect two or more relations with each other The general term used for this operation is a join To join two relations, we need attributes in each relation that have the same domain A join can return an empty relation 7

STUDENT (NID, Name, Major, LocalAddress, GPA) DB409 (NID, Section, FinalGrade) In this case, the NID (National Identification) uses the same domain in each relation, so these two relations could be joined 73

Inner joins Equijoin Natural join Outer joins Left outer join Right outer join Full outer join 74

In an equijoin, two attributes are joined using an equality test Both attributes appear in final result Example: STUDENT JOIN (SID = StudentNumber) ENROLLMENT 75

Similar to an equijoin Two attributes are joined using an equality test Only one of the joining attributes appears in final result 76

EMP Emp# Name Dept# Bahadur DEP Dept# DeptName Sys Admin Kabir Programming 3 Adalat 3 Finance 4 Wasil 3 4 Management 5 Edris 5 Planning Emp# Name EMP.Dept# DEP.Dept# Bahadur Sys Admin Kabir Programming 3 Adalat Programming 4 Wasil 3 3 Finance 5 Edris Sys Admin EMP JOIN (EMP.Dept# = DEPT.Dept#) DEPT 77

EMP Emp# Name Dept# Bahadur DEP Dept# DeptName Sys Admin Kabir Programming 3 Adalat 3 Finance 4 Wasil 3 4 Management 5 Edris 5 Planning Emp# Name Dept# Bahadur Sys Admin Kabir Programming 3 Adalat Programming 4 Wasil 3 Finance 5 Edris Sys Admin EMP JOIN (EMP.Dept# = DEPT.Dept#) DEPT 78

You can use other comparisons aside from equality when doing joins Example: EMP JOIN (EMP.Dept# < DEPT.Dept#) DEPT What results would you expect? 79

Emp# Name EMP.Dept# DEP.Dept# Bahadur Programming Bahadur 3 Finance Bahadur 4 Management Bahadur 5 Planning Kabir 3 Finance Kabir 4 Management Kabir 5 Planning 3 Adalat 3 Finance 3 Adalat 4 Management 3 Adalat 5 Planning 4 Wasil 3 4 Management 4 Wasil 3 5 Planning 5 Edris Sys Admin 5 Edris Programming 5 Edris 4 Management 5 Edris 5 Planning 80

There are cases where you want All entries in one table Any matching entries in the other table Outer-joins allow you to do this Similar notation: EMP LEFT OUTER JOIN (EMP.dept# = DEPT.Dept#) DEPT 8

Gets All rows from the left hand relation Any matching rows from the right hand relation In case of no matching rows, leave columns as NULL 8

DEP EMP Dept# DeptName Emp# Name Dept# Sys Admin Bahadur Programming Kabir 3 Finance 3 Adalat 4 Management 4 Wasil 3 5 Planning 5 Edris

DEPT LEFT OUTER JOIN (DEPT.Dept# = EMP.Dept#) EMP Dept# DeptName Emp# Name Dept# Sys Admin Bahadur Sys Admin 5 Edris Programming Kabir Programming 3 Adalat 3 Finance 4 Wasil 3 4 Management Null Null Null 5 Planning Null Null Null 84

Null means that there is no data stored in the database for that particular instance Null is not equal to zero Null 0 Null is not equal to empty string Null (Empty string) Null is equal to unknown data value Null = Unknown 85

Gets All rows from the right hand relation Any matching rows from the left hand relation In case of no matching rows, leave columns as NULL 86

STUDENT DEPT Stude Name ntid Major Dept Location Students 3 Billal IT IT Bldg 70 50 34 Samira CS CS Bldg 0 700 345 Timor SE SE Bldg 09 500 456 Adel BUS HIS Bldg 3 67 ART Bldg 56 70 STUDENT RIGHT OUTER JOIN (Major = Dept) DEPT What is the result of this join? 87

StudentID Name Major Dept Location Students 3 Billal IT IT Bldg 70 50 34 Samira CS CS Bldg 0 700 345 Timor SE SE Bldg 09 500 Null Null Null HIS Bldg 3 67 Null Null Null ART Bldg 56 70 88

Combines joins the left and right outer You see all rows from both relations Where the rows match the join criteria, both row s values will appear in the new row Nulls will appear in case where the join criteria are not met 89

STUDENT DEPT Stude Name ntid Major Dept Location Students 3 Billal IT IT Bldg 70 50 34 Samira CS CS Bldg 0 700 345 Timor SE SE Bldg 09 500 456 Adel BUS HIS Bldg 3 67 ART Bldg 56 70 90

StudentID Name Major Dept Location Students 3 Billal IT IT Bldg 70 50 34 Samira CS CS Bldg 0 700 345 Timor SE SE Bldg 09 500 Null Null Null HIS Bldg 3 67 Null Null Null ART Bldg 56 70 456 Adel Bus Null Null Null 9

Different operations can be combined in an expression Example: Get the names of all departments with no student records What operations do you need to get the results? 9

Join DEPT LEFT OUTER JOIN(Dept = Major) STUDENT WHERE StudentID = Null [Dept] Selection Projection 93

Structured Query Language (SQL) is based on relational algebra Queries will use combinations of the operations we saw in the last two lectures 94

Installing MySQL DBMS to the lab machines or your own PCs 95