Section 2.2 Mrs. Daniel AP Statistics We abbreviate the Normal distribution with mean µ and standard deviation σ as N(µ,σ). Any particular Normal distribution is completely specified by two numbers: its mean µ and standard deviation σ. The mean of a Normal distribution is the center of the symmetric Normal curve. The standard deviation is the distance from the center to the change of curvature points on either side. Section 2.2 After this section, you should be able to DESCRIBE and APPLY the 68 95 99.7 Rule DESCRIBE the standard Normal Distribution are Useful Normal distributions are good descriptions for some distributions of real data. Normal distributions are good approximations of the results of many kinds of chance outcomes. Many statistical inference procedures are based on Normal distributions. PERFORM Normal distribution calculations ASSESS Normality All Normal curves are symmetric, single peaked, and bellshaped A Specific Normal curve is described by giving its mean µ and standard deviation σ. Two Normal curves, showing the mean µ and standard deviation σ. The 68 95 99.7 Rule Although there are many different sizes and shapes of Normal curves, they all have properties in common. The 68 95 99.7 Rule ( The Empirical Rule ) In the Normal distribution with mean µ and standard deviation σ: Approximately 68% of the observations fall within σ of µ. Approximately 95% of the observations fall within 2σ of µ. Approximately 99.7% of the observations fall within 3σ of µ.
Normal. Suppose the distribution is N(6.84, 1.55). b) Using the Empirical Rule, what percent of ITBS vocabulary scores are less than 3.74? Normal. Suppose the distribution is N(6.84, 1.55) and the range is between 0 and 12. a) Sketch the Normal density curve for this distribution. Normal. Suppose the distribution is N(6.84, 1.55). b) Using the Empirical Rule, what percent of ITBS vocabulary scores are less than 3.74? Normal. Suppose the distribution is N(6.84, 1.55) and the range is between 0 and 12. a) Sketch the Normal density curve for this distribution. Normal. Suppose the distribution is N(6.84, 1.55).? c) Using the Empirical Rule, what percent of the scores are between 5.29 and 9.94?
Normal. Suppose the distribution is N(6.84, 1.55).? c) Using the Empirical Rule, What percent of the scores are between 5.29 and 9.94? How to Standardize a Variable: 1. Draw and label an Normal curve with the mean and standard deviation. 2. Calculate the z score x= variable µ= mean σ= standard deviation 3. Determine the p value by looking up the z score in the Standard Normal table. 4. Conclude in context. Importance of Standardizing There are infinitely many different Normal distributions; all with unique standard deviations and means. In order to more effectively compare different Normal distributions we standardize. Standardizing allows us to compare apples to apples. We can compare SAT and ACT scores by standardizing. The Standardized Normal Distribution All Normal distributions are the same if we measure in units of size σ from the mean µ as center. The standardized Normal distribution is the Normal distribution with mean 0 and standard deviation 1. The Standard Normal Table Because all Normal distributions are the same when we standardize, we can find areas under any Normal curve from a single table. The Standard Normal table is a table of the areas under the standard normal curve. The table entry for each value z is area under the curve to the LEFT of z. The area to left is called the p value Probability Percent
Using the Standard Normal Table Row: Ones and tenths digits Column: Hundredths digit Practice: What is the p value for a z score of 2.33? 1. Draw and label an Normal curve with the mean and standard deviation. 2. Calculate the z score x= variable µ= mean σ= standard deviation Using the Standard Normal Table Using the Standard Normal Table, find the following: 3. Determine the p value by looking up the z score in the Standard Normal table. P(z < 0.81) =.7910 2.23 1.65 Z Score P value Z.00.01.02 0.7.7580.7611.7642 0.8.7881.7910.7939 0.9.8159.8186.8212.52.79.23 Let s Practice In the 2008 Wimbledon tennis tournament, Rafael Nadal averaged 115 miles per hour (mph) on his first serves. Assume that the distribution of his first serve speeds is Normal with a mean of 115 mph and a standard deviation of 6.2 mph. About what proportion of his first serves would you expect to be less than 120 mph? Greater than? 4. Conclude in context. We expect that 79.1% of Nadal s first serves will be less than 120 mph. We expect that 20.9% of Nadal s first serves will be greater than 120 mps.
Let s Practice When Tiger Woods hits his driver, the distance the ball travels can be described by N(304, 8). What percent of Tiger s drives travel between 305 and 325 yards? Normal Calculations on Calculator NormalCDF NormalPDF InvNorm Calculates Probability of obtaining a value BETWEEN two values Probability of obtaining PRECISELY or EXACTLY a specific x value X value given probability or percentile Example What percent of students scored between 70 and 95 on the test? What is the probability that Suzy scored a 75 on the test? Tommy scored a 92 on the test; what proportion of students did he score better than? When Tiger Woods hits his driver, the distance the ball travels can be described by N(304, 8). What percent of Tiger s drives travel between 305 and 325 yards? Step 1: Draw Distribution Step 2: Z Scores When x = 325, z = When x = 305, z = 325-304 8 305-304 8 2.63 0.13 TI Nspire: NormalCDF Normalcdf Area under the curve between two points 1. Select Calculator (on home screen), press center button. 2. Press menu, press enter. 3. Select 6: Statistics, press enter. 4. Select 5: Distributions, press enter. 5. Select 2: Normal Cdf, press enter. 6. Enter the following information: 1. Lower: (the lower bound of the region OR 1^ 99) 2. Upper: (the upper band of the region OR 1,000,000) 3. µ: (mean) 4. Ơ: (standard deviation) 7. Press enter, number that appears is the p value Step 3: P values TI Nspire: NormalPDF Normalpdf Exact percentile/probability of a specific event occurring Using Table A, we can find the area to the left of z=2.63 and the area to the left of z=0.13. 0.9957 0.5517 = 0.4440. Step 4: Conclude In Context 1. Select Calculator (on home screen), press center button. 2. Press menu, press enter. 3. Select 6: Statistics, press enter. 4. Select 5: Distributions, press enter. 5. Select 1: Normal Pdf press enter. 6. Enter the following information: 1. Xvalue (not a percent) 2. µ: (mean) 3. Ơ: (standard deviation) 7. Press enter, number that appears is the p value About 44% of Tiger s drives travel between 305 and 325 yards.
TI Nspire: InvNorm invnorm Exact x value at which something occurred 1. Select Calculator (on home screen), press center button. 2. Press menu, press enter. 3. Select 6: Statistics, press enter. 4. Select 5: Distributions, press enter. 5. Select 3: Inverse Norm press enter. 6. Enter the following information: 1. Area (enter as a decimal) 2. µ: (mean) 3. Ơ: (standard deviation) 7. Press enter, number that appears is the p value Suzy bombed her recent AP Stats exam; she scored at the 25 th percentile. The class average was a 170 with a standard deviation of 30. Assuming the scores are normally distributed, what score did Suzy earn of the exam? When Tiger Woods hits his driver, the distance the ball travels can be described by N(304, 8). What percent of Tiger s drives travel between 305 and 325 yards? Suzy bombed her recent AP Stats exam; she scored at the 25 th percentile. The class average was a 170 with a standard deviation of 30. Assuming the scores are normally distributed, what score did Suzy earn of the exam? When Tiger Woods hits his driver, the distance the ball travels can be described by N(304, 8). What percent of Tiger s drives travel between 305 and 325 yards? When Can I Use Normal Calculations?! Whenever the distribution is Normal. Ways to Assess Normality: Plot the data. Make a dotplot, stemplot, or histogram and see if the graph is approximately symmetric and bell shaped. Check whether the data follow the 68 95 99.7 rule. Construct a Normal probability plot.
Normal Probability Plot These plots are constructed by plotting each observation in a data set against its corresponding percentile s z score. Additional Help Interpreting Normal Probability Plot If the points on a Normal probability plot lie close to a straight line, the plot indicates that the data are Normal. Systematic deviations from a straight line indicate a non Normal distribution. Outliers appear as points that are far away from the overall pattern of the plot. Finding Areas Under the Standard Normal Curve Find the proportion of observations from the standard Normal distribution that are between 1.25 and 0.81. Step 1: Look up area to the left of 0.81 using table A. Step 2: Find the area to the left of 1.25 Summary: The are described by a special family of bell shaped, symmetric density curves called Normal curves. The mean µ and standard deviation σ completely specify a Normal distribution N(µ,σ). The mean is the center of the curve, and σ is the distance from µ to the change ofcurvature points on either side. All Normal distributions obey the 68 95 99.7 Rule, which describes what percent of observations lie within one, two, and three standard deviations of the mean. All Normal distributions are the same when measurements are standardized. The standard Normal distribution has mean µ=0 and standard deviation σ=1. Table A gives percentiles for the standard Normal curve. By standardizing, we can use Table A to determine the percentile for a given z score or the z score corresponding to a given percentile in any Normal distribution. To assess Normality for a given set of data, we first observe its shape. We then check how well the data fits the 68 95 99.7 rule. Finding Areas Under the Standard Normal Curve Find the proportion of observations from the standard Normal distribution that are between 1.25 and 0.81. Step 3: Subtract.