Oracle Exam 1z0-808 Java SE 8 Programmer I Version: 6.0 [ Total Questions: 236 ]

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s@lm@n Oracle Exam 1z0-808 Java SE 8 Programmer I Version: 6.0 [ Total Questions: 236 ]

Oracle 1z0-808 : Practice Test Question No : 1 What is the result? A. 10 : 10 B. 5 : 5 C. 5 : 10 D. Compilation fails Answer: A Question No : 2 Given: 2

What is the result? Oracle 1z0-808 : Practice Test A. box B. nbo C. bo D. nb E. An exception is thrown at runtime Answer: E Question No : 3 Which three are advantages of the Java exception mechanism? A. Improves the program structure because the error handling code is separated from the normal program function B. Provides a set of standard exceptions that covers all the possible errors C. Improves the program structure because the programmer can choose where to handle exceptions D. Improves the program structure because exceptions must be handled in the method in which they occurred E. Allows the creation of new exceptions that are tailored to the particular program being created Answer: A,C,E Question No : 4 3

Oracle 1z0-808 : Practice Test What is the result? A. Jesse 25 Walter 52 B. Compilation fails only at line n1 C. Compilation fails only at line n2 D. Compilation fails at both line n1 and line n2 Answer: D Question No : 5 Given: class Mid { public int findmid(int n1, int n2) { return (n1 + n2) / 2; } 4

} Oracle 1z0-808 : Practice Test public class Calc extends Mid { public static void main(string[] args) { int n1 = 22, n2 = 2; // insert code here System.out.print(n3); } } Which two code fragments, when inserted at // insert code here, enable the code to compile and print 12? A. Calc c = new Calc(); int n3 = c.findmid(n1,n2); B. int n3 = super.findmid(n1,n3); C. Calc c = new Mid(); int n3 = c.findmid(n1, n2); D. Mid m1 = new Calc(); int n3 = m1.findmid(n1, n2); E. int n3 = Calc.findMid(n1, n2); Answer: A,D Explanation: Incorrect: Not B: circular definition of n3. Not C: Compilation error. line Calc c = new Mid(); required: Calc found: Mid Not E: Compilation error. line int n3 = Calc.findMid(n1, n2); non-static method findmid(int,int) cannot be referenced from a static context Question No : 6 5

Oracle 1z0-808 : Practice Test Assume that the system date is June 20, 2014. What is the result? A. Option A B. Option B C. Option C D. Option D Answer: A Question No : 7 6

What is the result? Oracle 1z0-808 : Practice Test A. 20 B. 25 C. 29 D. Compilation fails E. AnArrayIndexOutOfBoundsException is thrown at runtime Answer: A Question No : 8 What is the result? A. May 04, 2014T00:00:00.000 B. 2014-05-04T00:00: 00. 000 C. 5/4/14T00:00:00.000 D. An exception is thrown at runtime. Answer: D Explanation: java.time.temporal.unsupportedtemporaltypeexception: Unsupported field: HourOfDay Question No : 9 7

Oracle 1z0-808 : Practice Test And given the requirements: If the value of the qty variable is greater than or equal to 90, discount = 0.5 If the value of the qty variable is between 80 and 90, discount = 0.2 Which two code fragments can be independently placed at line n1 to meet the requirements? A. Option A B. Option B C. Option C D. Option D E. Option E Answer: A,C Question No : 10 8

Given: Oracle 1z0-808 : Practice Test The class is poorly encapsulated. You need to change the circle class to compute and return the area instead. Which two modifications are necessary to ensure that the class is being properly encapsulated? A. Remove the area field. B. Change the getarea( ) method as follows: public double getarea ( ) { return Match.PI * radius * radius; } C. Add the following method: public double getarea ( ) {area = Match.PI * radius * radius; } D. Change the cacess modifier of the SerRadius ( ) method to be protected. Answer: B,D Question No : 11 9

What is the result? Oracle 1z0-808 : Practice Test A. 10 8 6 4 2 0 B. 10 8 6 4 2 C. AnArithmeticException is thrown at runtime D. The program goes into an infinite loop outputting: 10 8 6 4 2 0... E. Compilation fails Answer: B Question No : 12 Given: Which code fragment, when inserted at line 14, enables the code to print Mike Found? A. int f = ps.indexof {new patient ( Mike )}; B. int f = ps.indexof (patient( Mike )); C. patient p = new Patient ( Mike ); int f = pas.indexof(p) D. int f = ps.indexof(p2); Answer: C 10