Today. The Memory Hierarchy. Byte Oriented Memory Organization. Simple Memory Addressing Modes

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Today The Memory Hierarchy 15 213 / 18 213: Introduction to Computer Systems 1 th Lecture, Feb 14, 213 DRAM as building block for main memory Locality of reference Caching in the memory hierarchy Storage technologies and trends Instructors: Seth Copen Goldstein, Anthony Rowe, Greg Kesden 1 2 Byte Oriented Memory Organization Programs refer to data by address Conceptually, envision it as a very large array of bytes In reality, it s not, but can think of it that way An address is like an index into that array and, a pointer variable stores an address Note: system provides private address spaces to each process Think of a process as a program being executed So, a program can clobber its own data, but not that of others Simple Memory Addressing Modes Normal (R) Mem[Reg[R]] Register R specifies memory address Aha! Pointer dereferencing in C movl (%ecx),%eax Displacement D(R) Mem[Reg[R]+D] Register R specifies start of memory region Constant displacement D specifies offset movl 8(%ebp),%edx From 2 nd lecture 3 From 5 th lecture 4

Traditional Bus Structure Connecting CPU and Memory A bus is a collection of parallel wires that carry address, data, and control signals. Buses are typically shared by multiple devices. Memory Read Transaction (1) CPU places address A on the memory bus. Load operation: movl A, %eax CPU chip %eax I/O bridge A Main memory x A System bus Memory bus I/O bridge Main memory 5 6 Memory Read Transaction (2) Main memory reads A from the memory bus, retrieves word x, and places it on the bus. Memory Read Transaction (3) CPU read word xfrom the bus and copies it into register %eax. Load operation: movl A, %eax Load operation: movl A, %eax %eax %eax x I/O bridge Main memory x x A I/O bridge Main memory x A 7 8

Memory Write Transaction (1) CPU places address A on bus. Main memory reads it and waits for the corresponding data word to arrive. Memory Write Transaction (2) CPU places data word yon the bus. Store operation: movl %eax, A Store operation: movl %eax, A %eax y %eax y I/O bridge A Main memory A I/O bridge y Main memory A 9 1 Memory Write Transaction (3) Main memory reads data word yfrom the bus and stores it at address A. %eax bus interface register file y I/O bridge Store operation: movl %eax, A main memory y A Dynamic Random Access Memory (DRAM) Key features DRAM is traditionally packaged as a chip Basic storage unit is normally a cell (one bit per cell) Multiple DRAM chips form main memory in most computers Technical characteristics Organized in two dimensions (rows and columns) To access (within a DRAM chip): select row then select column Consequence: 2 nd access to a row faster than different column/row Each cell stores bit with a capacitor; one transistor is used for access Value must be refreshed every 1 1 ms Done within the hardware 11 12

Conventional DRAM Organization dxwdram: dw total bits organized as d supercells of size wbits Reading DRAM Supercell (2,1) Step 1(a): Row access strobe (RAS) selects row 2. Step 1(b): Row 2 copied from DRAM array to row buffer. 16 x 8 DRAM chip 16 x 8 DRAM chip (to/from CPU) Memory 2 bits / addr 8 bits / data rows 1 2 3 cols 1 2 3 supercell (2,1) Memory RAS = 2 2 / addr 8 / data Rows 1 2 3 Cols 1 2 3 Internal row buffer Internal row buffer 13 14 Reading DRAM Supercell (2,1) Step 2(a): Column access strobe (CAS) selects column 1. Step 2(b): Supercell (2,1) copied from buffer to data lines, and eventually back to the CPU. 16 x 8 DRAM chip To CPU supercell (2,1) Memory CAS = 1 2 / addr 8 / data 1 Rows 2 3 Cols 1 2 3 Memory Modules addr (row = i, col = j) DRAM 7 bits 56-63 bits 48-55 bits 4-47 63 56 55 48 47 4 39 bits 32-39 bits 24-31 bits 16-23 DRAM bits 8-15 32 31 24 23 16 15 8 7 64-bit doubleword at main memory address A bits -7 : supercell (i,j) 64 MB memory module consisting of eight 8Mx8 DRAMs Memory supercell (2,1) Internal row buffer 15 64-bit doubleword 16

Aside: Nonvolatile Memories DRAM and SRAM (caches, on Tuesday) are volatile memories Lose information if powered off Most common nonvolatile storage is the hard disk Rotating platters (like DVDs) plentiful capacity, but very slow Nonvolatile memories retain value even if powered off Read only memory (ROM): programmed during production Programmable ROM (PROM): can be programmed once Eraseable PROM (EPROM): can be bulk erased (UV, X Ray) Electrically eraseable PROM (EEPROM): electronic erase capability Flash memory: EEPROMs with partial (sector) erase capability Wears out after about 1, erasings Uses for Nonvolatile Memories Firmware programs stored in a ROM (BIOS, s for disks, network cards, graphics accelerators, security subsystems, ) Solid state disks (replace rotating disks in thumb drives, smart phones, mp3 players, tablets, laptops, ) caches 17 Issue: memory access is slow DRAM access is much slower than CPU cycle time A DRAM chip has access times of 3 5ns and, transferring from main memory into register can take 3X or more longer than that With sub nanosecond cycles times, 1s of cycles per memory access and, the gap grows over time Consequence: memory access efficiency crucial to performance approximately 1/3 of instructions are loads or stores both hardware and programmer have to work at it 18 The CPU Memory Gap The gap between DRAM, disk, and CPU speeds. Locality to the Rescue! 1,,. 1,,. 1,,. 1,. SSD The key to bridging this CPU Memory gap is a fundamental property of computer programs known as locality ns 1,. 1,. 1. DRAM seek time Flash SSD access time DRAM access time SRAM access time CPU cycle time Effective CPU cycle time 1. 1..1 CPU. 198 1985 199 1995 2 23 25 21 Year 19 2

Today DRAM as building block for main memory Locality of reference Caching in the memory hierarchy Storage technologies and trends Locality Principle of Locality: Programs tend to use data and instructions with addresses near or equal to those they have used recently Temporal locality: Recently referenced items are likely to be referenced again in the near future Spatial locality: Items with nearby addresses tend to be referenced close together in time 21 22 Locality Example sum = ; for (i = ; i < n; i++) sum += a[i]; return sum; Qualitative Estimates of Locality Claim: Being able to look at code and get a qualitative sense of its locality is a key skill for a professional programmer. Data references Reference array elements in succession (stride 1 reference pattern). Reference variable sum each iteration. Instruction references Reference instructions in sequence. Cycle through loop repeatedly. Spatial locality Temporal locality Spatial locality Temporal locality Question: Does this function have good locality with respect to array a? int sum_array_rows(int a[m][n]) { int i, j, sum = ; } for (i = ; i < M; i++) for (j = ; j < N; j++) sum += a[i][j]; return sum; 23 24

Locality Example Question: Does this function have good locality with respect to array a? int sum_array_cols(int a[m][n]) { int i, j, sum = ; Today DRAM as building block for main memory Locality of reference Caching in the memory hierarchy Storage technologies and trends } for (j = ; j < N; j++) for (i = ; i < M; i++) sum += a[i][j]; return sum; 25 26 Memory Hierarchies An Example Memory Hierarchy Some fundamental and enduring properties of hardware and software: Fast storage technologies cost more per byte, have less capacity, and require more power (heat!) The gap between CPU and main memory speed is widening Well written programs tend to exhibit good locality These fundamental properties complement each other beautifully Smaller, faster, costlier per byte Larger, slower, cheaper per byte L4: L3: L2: L1: L: Registers L1 cache (SRAM) L2 cache (SRAM) Main memory (DRAM) Local secondary storage (local disks) CPU registers hold words retrieved from L1 cache L1 cache holds cache lines retrieved from L2 cache L2 cache holds cache lines retrieved from main memory Main memory holds disk blocks retrieved from local disks Local disks hold files retrieved from disks on remote network servers They suggest an approach for organizing memory and storage systems known as a memory hierarchy L5: Remote secondary storage (tapes, distributed file systems, Web servers) 27 28

Caches General Cache Concepts Cache: A smaller, faster storage device that acts as a staging area for a subset of the data in a larger, slower device. Fundamental idea of a memory hierarchy: For each k, the faster, smaller device at level kserves as a cache for the larger, slower device at level k+1. Why do memory hierarchies work? Because of locality, programs tend to access the data at level kmore often than they access the data at level k+1. Thus, the storage at level k+1 can be slower, and thus larger and cheaper per bit. Big Idea: The memory hierarchy creates a large pool of storage that costs as much as the cheap storage near the bottom, but that serves data to programs at the rate of the fast storage near the top. Cache Memory 84 9 14 1 3 1 4 1 2 3 4 5 6 7 8 9 1 11 12 13 14 15 Data is copied in block sized transfer units Smaller, faster, more expensive memory caches a subset of the blocks Larger, slower, cheaper memory viewed as partitioned into blocks 29 3 General Cache Concepts: Hit How locality induces cache hits Cache Request: 14 8 9 14 3 Data in block b is needed Block b is in cache: Hit! Temporal locality: 2 nd through N th accesses to same location will be hits Memory 1 2 3 4 5 6 7 8 9 1 11 Spatial locality: Cache blocks contains multiple words, so 2 nd to N th word accesses can be hits on cache block loaded for 1 st word Row buffer in DRAM is another example 12 13 14 15 31 32

General Cache Concepts: Miss General Caching Concepts: Types of Cache Misses Cache Memory Request: 12 8 12 9 14 3 12 Request: 12 1 2 3 4 5 6 7 8 9 1 11 12 13 14 15 Data in block b is needed Block b is not in cache: Miss! Block b is fetched from memory Block b is stored in cache Placement policy: determines where b goes Replacement policy: determines which block gets evicted (victim) Cold (compulsory) miss The first access to a block has to be a miss Most cold misses occur at the beginning, because the cache is empty Conflict miss Most caches limit blocks at level k+1 to a small subset (sometimes a singleton) of the block positions at level k E.g., Block iat level k+1 must be placed in block (i mod 4) at level k Conflict misses occur when the level kcache is large enough, but multiple data objects all map to the same level kblock E.g., Referencing blocks, 8,, 8,, 8,... would miss every time Capacity miss Occurs when the set of active cache blocks (working set) is larger than the cache 33 34 Examples of Caching in the Hierarchy Memory hierarchy summary Cache Type Registers What is Cached? 4 8 bytes words Where is it Cached? CPU core Latency (cycles) Managed By Compiler The speed gap between CPU, memory and mass storage continues to widen TLB Address translations On Chip TLB Hardware Well written programs exhibit a property called locality L1 cache 64 bytes block On Chip L1 1 Hardware L2 cache Virtual Memory Buffer cache 64 bytes block 4 KB page Parts of files On/Off Chip L2 Main memory Main memory 1 1 1 Hardware Hardware + OS OS Memory hierarchies based on caching close the gap by exploiting locality cache sectors 1, firmware Network buffer cache Parts of files Local disk 1,, AFS/NFS client Browser cache Web pages Local disk 1,, Web browser Web cache Web pages Remote server disks 1,,, Web proxy server 35 36

Today What s Inside A Drive? DRAM as building block for main memory Locality of reference Caching in the memory hierarchy Storage technologies and trends Actuator Arm Spindle Platters SCSI connector Electronics (including a processor and memory!) Image courtesy of Seagate Technology 37 38 Geometry s consist of platters, each with two surfaces. Each surface consists of concentric rings called tracks. Each track consists of sectors separated by gaps. Tracks Surface Track k Gaps Geometry (Muliple Platter View) Aligned tracks form a cylinder. Surface Surface 1 Surface 2 Surface 3 Surface 4 Surface 5 Cylinder k Platter Platter 1 Platter 2 Spindle Spindle Sectors 39 4

Capacity Capacity: maximum number of bits that can be stored. Vendors express capacity in units of gigabytes (GB), where 1 GB = 1 9 Bytes (Lawsuit claims deceptive advertising). Capacity is determined by these technology factors: Recording density (bits/in): number of bits that can be squeezed into a 1 inch segment of a track. Track density (tracks/in): number of tracks that can be squeezed into a 1 inch radial segment. Areal density (bits/in2): product of recording and track density. Modern disks partition tracks into disjoint subsets called recording zones Each track in a zone has the same number of sectors, determined by the circumference of innermost track. Each zone has a different number of sectors/track Computing Capacity Capacity = (# bytes/sector) x(avg. # sectors/track) x (# tracks/surface) x(# surfaces/platter) x (# platters/disk) Example: 512 bytes/sector 3 sectors/track (on average) 2, tracks/surface 2 surfaces/platter 5 platters/disk Capacity = 512 x 3 x 2 x2 x5 = 3,72,, = 3.72 GB 41 42 Operation (Single Platter View) Operation (Multi Platter View) The disk surface spins at a fixed rotational rate The read/write head is attached to the end of the arm and flies over the disk surface on a thin cushion of air. Read/write heads move in unison from cylinder to cylinder Arm spindle spindle spindle spindle Spindle By moving radially, the arm can position the read/write head over any track. 43 44

Structure top view of single platter Access Surface organized into tracks Tracks divided into sectors Head in position above a track 45 46 Access Access Read Rotation is counter-clockwise About to read blue sector 47 48

Access Read Access Read After BLUE read After BLUE read After reading blue sector Red request scheduled next 49 5 Access Seek Access Rotational Latency After BLUE read Seek for RED After BLUE read Seek for RED Rotational latency Seek to red s track Wait for red sector to rotate around 51 52

Access Read Access Service Time Components After BLUE read Seek for RED Rotational latency After RED read After BLUE read Seek for RED Rotational latency After RED read Complete read of red Data transfer Seek Rotational latency Data transfer 53 54 Access Time Access Time Example Average time to access some target sector approximated by : Taccess = Tavg seek + Tavg rotation + Tavg transfer Seek time (Tavg seek) Time to position heads over cylinder containing target sector. Typical Tavg seek is 3 9 ms Rotational latency (Tavg rotation) Time waiting for first bit of target sector to pass under r/w head. Tavg rotation = 1/2 x1/rpms x6 sec/1 min Typical Tavg rotation = 72 RPMs Transfer time (Tavg transfer) Time to read the bits in the target sector. Tavg transfer = 1/RPM x1/(avg # sectors/track) x6 secs/1 min. 55 Given: Rotational rate = 7,2 RPM Average seek time = 9 ms. Avg # sectors/track = 4. Derived: Tavg rotation = 1/2 x(6 secs/72 RPM) x 1 ms/sec = 4 ms. Tavg transfer = 6/72 RPM x 1/4 secs/track x 1 ms/sec =.2 ms Taccess = 9 ms + 4 ms +.2 ms Important points: Access time dominated by seek time and rotational latency. First bit in a sector is the most expensive, the rest are free. SRAM access time is about 4 ns/doubleword, DRAM about 6 ns is about 4, times slower than SRAM, 2,5 times slower then DRAM. 56

Logical Blocks Modern disks present a simpler abstract view of the complex sector geometry: The set of available sectors is modeled as a sequence of b sized logical blocks (, 1, 2,...) Mapping between logical blocks and actual (physical) sectors Maintained by hardware/firmware device called disk. Converts requests for logical blocks into (surface,track,sector) triples. Allows to set aside spare cylinders for each zone. Accounts for the difference in formatted capacity and maximum capacity. I/O Bus CPU chip USB Graphics adapter Mouse Keyboard Monitor System bus I/O bridge I/O bus Memory bus Main memory Expansion slots for other devices such as network adapters. 57 58 Reading a Sector (1) CPU chip CPU initiates a disk read by writing a command, logical block number, and destination memory address to a port (address) associated with disk. Reading a Sector (2) CPU chip reads the sector and performs a direct memory access (DMA) transfer into main memory. Main memory Main memory I/O bus I/O bus USB Graphics adapter USB Graphics adapter mouse keyboard Monitor 59 Mouse Keyboard Monitor 6

Reading a Sector (3) CPU chip When the DMA transfer completes, the disk notifies the CPU with an interrupt (i.e., asserts a special interrupt pin on the CPU) I/O bus Main memory Solid State s (SSDs) Solid State (SSD) I/O bus Flash memory Block Page Page 1 Page P-1 Flash translation layer Requests to read and write logical disk blocks Block B-1 Page Page 1 Page P-1 Pages: 512KB to 4KB, Blocks: 32 to 128 pages USB Graphics adapter Mouse Keyboard Monitor 61 Data read/written in units of pages. Page can be written only after its block has been erased A block wears out after 1, repeated writes. 62 SSD Performance Characteristics SSD Tradeoffs vs Rotating s Sequential read tput 25 MB/s Sequential write tput 17 MB/s Random read tput 14 MB/s Random write tput 14 MB/s Rand read access 3 us Random write access 3 us Why are random writes so slow? Erasing a block is slow (around 1 ms) Write to a page triggers a copy of all useful pages in the block Find an used block (new block) and erase it Write the page into the new block Copy other pages from old block to the new block Advantages No moving parts faster, less power, more rugged Disadvantages Have the potential to wear out Mitigated by wear leveling logic in flash translation layer E.g. Intel X25 guarantees 1 petabyte (1 15 bytes) of random writes before they wear out In 21, about 1 times more expensive per byte (Now more like 1 15x) Applications MP3 players, smart phones, laptops Beginning to appear in desktops and servers 63 64

SRAM Storage Trends Metric 198 1985 199 1995 2 25 21 21:198 $/MB 19,2 2,9 32 256 1 75 6 32 access (ns) 3 15 35 15 3 2 1.5 2 CPU Clock Rates Inflection point in computer history when designers hit the Power Wall 198 199 1995 2 23 25 21 21:198 CPU 88 386 Pentium P-III P-4 Core 2 Core i7 --- DRAM Metric 198 1985 199 1995 2 25 21 21:198 $/MB 8, 88 1 3 1.1.6 13, access (ns) 375 2 1 7 6 5 4 9 typical size (MB).64.256 4 16 64 2, 8, 125, Metric 198 1985 199 1995 2 25 21 21:198 $/MB 5 1 8.3.1.5.3 1,6, access (ms) 87 75 28 1 8 4 3 29 typical size (MB) 1 1 16 1, 2, 16, 1,5,1,5, 65 Clock rate (MHz) 1 2 15 6 33 2 25 25 Cycle time (ns) 1 5 6 1.6.3.5.4 25 Cores 1 1 1 1 1 2 4 4 Effective cycle 1 5 6 1.6.3.25.1 1, time (ns) 66 Random Access Memory (RAM) SRAM vs DRAM Summary Key features RAM is traditionally packaged as a chip. Basic storage unit is normally a cell (one bit per cell). Multiple RAM chips form a memory. Static RAM (SRAM) Each cell stores a bit with a four or six transistor circuit. Retains value indefinitely, as long as it is kept powered. Relatively insensitive to electrical noise (EMI), radiation, etc. Faster and more expensive than DRAM. Dynamic RAM (DRAM) Each cell stores bit with a capacitor. One transistor is used for access Value must be refreshed every 1 1 ms. More sensitive to disturbances (EMI, radiation, ) than SRAM. Slower and cheaper than SRAM. 67 Trans. Access Needs Needs per bit time refresh? EDC? Cost Applications SRAM 4 or 6 1X No Maybe 1x Cache memories DRAM 1 1X Yes Yes 1X Main memories, frame buffers 68

Enhanced DRAMs Basic DRAM cell has not changed since its invention in 1966. Commercialized by Intel in 197. DRAM cores with better interface logic and faster I/O : Synchronous DRAM (SDRAM) Uses a conventional clock signal instead of asynchronous control Allows reuse of the row addresses (e.g., RAS, CAS, CAS, CAS) Locality Example Question: Can you permute the loops so that the function scans the 3 d array a with a stride 1 reference pattern (and thus has good spatial locality)? int sum_array_3d(int a[m][n][n]) { int i, j, k, sum = ; Double data rate synchronous DRAM (DDR SDRAM) Double edge clocking sends two bits per cycle per pin Different types distinguished by size of small prefetch buffer: DDR (2 bits), DDR2 (4 bits), DDR4 (8 bits) By 21, standard for most server and desktop systems Intel Core i7 supports only DDR3 SDRAM } for (i = ; i < M; i++) for (j = ; j < N; j++) for (k = ; k < N; k++) sum += a[k][i][j]; return sum; 69 7