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Transcription:

Chapter 2 Elementary Programming 1

Motivations In the preceding chapter, you learned how to create, compile, and run a Java program. Starting from this chapter, you will learn how to solve practical problems programmatically. Through these problems, you will learn Java primitive data types and related subjects, such as variables, constants, data types, operators, expressions, and input and output. 2

Objectives To write Java programs to perform simple calculations ( 2.2). To obtain input from the console using the Scanner class ( 2.3). To use identifiers to name variables, constants, methods, and classes ( 2.4). To use variables to store data ( 2.5-2.6). To program with assignment statements and assignment expressions ( 2.6). To use constants to store permanent data ( 2.7). To declare Java primitive data types: byte, short, int, long, float, double, and char ( 2.8.1). To use Java operators to write numeric expressions ( 2.8.2 2.8.3). To display current time ( 2.9). To use short hand operators ( 2.10). To cast value of one type to another type ( 2.11). To compute loan payment ( 2.12). To represent characters using the char type ( 2.13). To compute monetary changes ( 2.14). To represent a string using the String type ( 2.15). To become familiar with Java documentation, programming style, and naming conventions ( 2.16). To distinguish syntax errors, runtime errors, and logic errors and debug errors ( 2.17). (GUI) To obtain input using the JOptionPane input dialog boxes ( 2.18). 3

Introducing Programming with an Example Listing 2.1 Computing the Area of a Circle This program computes the area of the circle. ComputeArea Run IMPORTANT NOTE: To enable the buttons, you must download the entire slide file slide.zip and unzip the files into a directory (e.g., c:\slide). 4

animation Trace a Program Execution public class ComputeArea { /** Main method */ public static void main(string[] args) { double radius; double area; // Assign a radius radius = 20; // Compute area area = radius * radius * 3.14159; // Display results System.out.println("The area for the circle of radius " + radius + " is " + area); } } radius allocate memory for radius no value 5

animation Trace a Program Execution public class ComputeArea { /** Main method */ public static void main(string[] args) { double radius; double area; // Assign a radius radius = 20; // Compute area area = radius * radius * 3.14159; // Display results System.out.println("The area for the circle of radius " + radius + " is " + area); } } radius area memory no value no value allocate memory for area 6

animation Trace a Program Execution public class ComputeArea { /** Main method */ public static void main(string[] args) { double radius; double area; // Assign a radius radius = 20; // Compute area area = radius * radius * 3.14159; // Display results System.out.println("The area for the circle of radius " + radius + " is " + area); } } radius area assign 20 to radius 20 no value 7

animation Trace a Program Execution public class ComputeArea { /** Main method */ public static void main(string[] args) { double radius; double area; // Assign a radius radius = 20; // Compute area area = radius * radius * 3.14159; radius area memory 20 1256.636 compute area and assign it to variable area // Display results System.out.println("The area for the circle of radius " + radius + " is " + area); } } 8

animation Trace a Program Execution public class ComputeArea { /** Main method */ public static void main(string[] args) { double radius; double area; // Assign a radius radius = 20; radius area memory 20 1256.636 // Compute area area = radius * radius * 3.14159; // Display results System.out.println("The area for the circle of radius " + radius + " is " + area); } } print a message to the console 9

Reading Input from the Console 1. Create a Scanner object Scanner input = new Scanner(System.in); 2. Use the methods next(), nextbyte(), nextshort(), nextint(), nextlong(), nextfloat(), nextdouble(), or nextboolean() to obtain to a string, byte, short, int, long, float, double, or boolean value. For example, System.out.print("Enter a double value: "); Scanner input = new Scanner(System.in); double d = input.nextdouble(); ComputeAreaWithConsoleInput ComputeAverage Run Run 10

Identifiers An identifier is a sequence of characters that consist of letters, digits, underscores (_), and dollar signs ($). An identifier must start with a letter, an underscore (_), or a dollar sign ($). It cannot start with a digit. An identifier cannot be a reserved word. (See Appendix A, Java Keywords, for a list of reserved words). An identifier cannot be true, false, or null. An identifier can be of any length. 11

Variables // Compute the first area radius = 1.0; area = radius * radius * 3.14159; System.out.println("The area is + area + " for radius "+radius); // Compute the second area radius = 2.0; area = radius * radius * 3.14159; System.out.println("The area is + area + " for radius "+radius); 12

int x; Declaring Variables // Declare x to be an // integer variable; double radius; // Declare radius to // be a double variable; char a; // Declare a to be a // character variable; 13

Assignment Statements x = 1; // Assign 1 to x; radius = 1.0; // Assign 1.0 to radius; a = 'A'; // Assign 'A' to a; 14

Declaring and Initializing in One Step int x = 1; double d = 1.4; 15

Constants final datatype CONSTANTNAME = VALUE; final double PI = 3.14159; final int SIZE = 3; 16

Numerical Data Types Name Range Storage Size byte 2 7 (-128) to 2 7 1 (127) 8-bit signed short 2 15 (-32768) to 2 15 1 (32767) 16-bit signed int 2 31 (-2147483648) to 2 31 1 (2147483647) 32-bit signed long 2 63 to 2 63 1 64-bit signed (i.e., -9223372036854775808 to 9223372036854775807) float Negative range: 32-bit IEEE 754-3.4028235E+38 to -1.4E-45 Positive range: 1.4E-45 to 3.4028235E+38 double Negative range: 64-bit IEEE 754-1.7976931348623157E+308 to -4.9E-324 Positive range: 4.9E-324 to 1.7976931348623157E+308 17

Numeric Operators Name Meaning Example Result + Addition 34 + 1 35 - Subtraction 34.0 0.1 33.9 * Multiplication 300 * 30 9000 / Division 1.0 / 2.0 0.5 % Remainder 20 % 3 2 18

Integer Division +, -, *, /, and % 5 / 2 yields an integer 2. 5.0 / 2 yields a double value 2.5 5 % 2 yields 1 (the remainder of the division) 19

Remainder Operator Remainder is very useful in programming. For example, an even number % 2 is always 0 and an odd number % 2 is always 1. So you can use this property to determine whether a number is even or odd. Suppose today is Saturday and you and your friends are going to meet in 10 days. What day is in 10 days? You can find that day is Tuesday using the following expression: Saturday is the 6 th day in a week (6 + 10) % 7 is 2 After 10 days A week has 7 days The 2 nd day in a week is Tuesday 20

Problem: Displaying Time Write a program that obtains hours and minutes from seconds. DisplayTime Run 21

NOTE Calculations involving floating-point numbers are approximated because these numbers are not stored with complete accuracy. For example, System.out.println(1.0-0.1-0.1-0.1-0.1-0.1); displays 0.5000000000000001, not 0.5, and System.out.println(1.0-0.9); displays 0.09999999999999998, not 0.1. Integers are stored precisely. Therefore, calculations with integers yield a precise integer result. 22

Number Literals A literal is a constant value that appears directly in the program. For example, 34, 1,000,000, and 5.0 are literals in the following statements: int i = 34; long x = 1000000; double d = 5.0; 23

Integer Literals An integer literal can be assigned to an integer variable as long as it can fit into the variable. A compilation error would occur if the literal were too large for the variable to hold. For example, the statement byte b = 1000 would cause a compilation error, because 1000 cannot be stored in a variable of the byte type. An integer literal is assumed to be of the int type, whose value is between -2 31 (-2147483648) to 2 31 1 (2147483647). To denote an integer literal of the long type, append it with the letter L or l. L is preferred because l (lowercase L) can easily be confused with 1 (the digit one). 24

Floating-Point Literals Floating-point literals are written with a decimal point. By default, a floating-point literal is treated as a double type value. For example, 5.0 is considered a double value, not a float value. You can make a number a float by appending the letter f or F, and make a number a double by appending the letter d or D. For example, you can use 100.2f or 100.2F for a float number, and 100.2d or 100.2D for a double number. 25

Scientific Notation Floating-point literals can also be specified in scientific notation, for example, 1.23456e+2, same as 1.23456e2, is equivalent to 123.456, and 1.23456e-2 is equivalent to 0.0123456. E (or e) represents an exponent and it can be either in lowercase or uppercase. 26

Arithmetic Expressions 3 4x 5 10( y 5)( a x b c) 4 9( x 9 y x ) is translated to (3+4*x)/5 10*(y-5)*(a+b+c)/x + 9*(4/x + (9+x)/y) 27

How to Evaluate an Expression Though Java has its own way to evaluate an expression behind the scene, the result of a Java expression and its corresponding arithmetic expression are the same. Therefore, you can safely apply the arithmetic rule for evaluating a Java expression. 3 + 4 * 4 + 5 * (4 + 3) - 1 (1) inside parentheses first 3 + 4 * 4 + 5 * 7 1 (2) multiplication 3 + 16 + 5 * 7 1 (3) multiplication 3 + 16 + 35 1 (4) addition 19 + 35 1 (5) addition 54-1 (6) subtraction 53 28

Problem: Converting Temperatures Write a program that converts a Fahrenheit degree to Celsius using the formula: celsius 5 ( 9 )( fahrenheit 32) FahrenheitToCelsius Run 29

Problem: Displaying Current Time Write a program that displays current time in GMT in the format hour:minute:second such as 1:45:19. The currenttimemillis method in the System class returns the current time in milliseconds since the midnight, January 1, 1970 GMT. (1970 was the year when the Unix operating system was formally introduced.) You can use this method to obtain the current time, and then compute the current second, minute, and hour as follows. Unix Epoch 01-01-1970 00:00:00 GMT Elapsed time Current Time System.currentTimeMills() Time ShowCurrentTime Run 30

Shortcut Assignment Operators Operator Example Equivalent += i += 8 i = i + 8 -= f -= 8.0 f = f - 8.0 *= i *= 8 i = i * 8 /= i /= 8 i = i / 8 %= i %= 8 i = i % 8 31

Increment and Decrement Operators Operator Name Description ++var preincrement The expression (++var) increments var by 1 and evaluates to the new value in var after the increment. var++ postincrement The expression (var++) evaluates to the original value in var and increments var by 1. --var predecrement The expression (--var) decrements var by 1 and evaluates to the new value in var after the decrement. var-- postdecrement The expression (var--) evaluates to the original value in var and decrements var by 1. 32

Increment and Decrement Operators, cont. int i = 10; Same effect as int newnum = 10 * i++; int newnum = 10 * i; i = i + 1; int i = 10; Same effect as int newnum = 10 * (++i); i = i + 1; int newnum = 10 * i; 33

Increment and Decrement Operators, cont. Using increment and decrement operators makes expressions short, but it also makes them complex and difficult to read. Avoid using these operators in expressions that modify multiple variables, or the same variable for multiple times such as this: int k = ++i + i. 34

Assignment Expressions and Assignment Statements Prior to Java 2, all the expressions can be used as statements. Since Java 2, only the following types of expressions can be statements: variable op= expression; // Where op is +, -, *, /, or % ++variable; variable++; --variable; variable--; 35

Numeric Type Conversion Consider the following statements: byte i = 100; long k = i * 3 + 4; double d = i * 3.1 + k / 2; 36

Conversion Rules When performing a binary operation involving two operands of different types, Java automatically converts the operand based on the following rules: 1. If one of the operands is double, the other is converted into double. 2. Otherwise, if one of the operands is float, the other is converted into float. 3. Otherwise, if one of the operands is long, the other is converted into long. 4. Otherwise, both operands are converted into int. 37

Type Casting Implicit casting double d = 3; (type widening) Explicit casting int i = (int)3.0; (type narrowing) int i = (int)3.9; (Fraction part is truncated) What is wrong? int x = 5 / 2.0; range increases byte, short, int, long, float, double 38

Problem: Keeping Two Digits After Decimal Points Write a program that displays the sales tax with two digits after the decimal point. SalesTax Run 39

Problem: Computing Loan Payments This program lets the user enter the interest rate, number of years, and loan amount and computes monthly payment and total payment. monthlypayment loanamount monthlyinterestrate 1 (1 monthlyinterestrate ) 1 numberofyears 12 ComputeLoan Run 40

char letter = 'A'; (ASCII) Character Data Type char numchar = '4'; (ASCII) char letter = '\u0041'; (Unicode) char numchar = '\u0034'; (Unicode) Four hexadecimal digits. NOTE: The increment and decrement operators can also be used on char variables to get the next or preceding Unicode character. For example, the following statements display character b. char ch = 'a'; System.out.println(++ch); 41

Unicode Format Java characters use Unicode, a 16-bit encoding scheme established by the Unicode Consortium to support the interchange, processing, and display of written texts in the world s diverse languages. Unicode takes two bytes, preceded by \u, expressed in four hexadecimal numbers that run from '\u0000' to '\uffff'. So, Unicode can represent 65535 + 1 characters. Unicode \u03b1 \u03b2 \u03b3 for three Greek letters 42

Problem: Displaying Unicodes Write a program that displays two Chinese characters and three Greek letters. DisplayUnicode Run 43

Escape Sequences for Special Characters Description Escape Sequence Unicode Backspace \b \u0008 Tab \t \u0009 Linefeed \n \u000a Carriage return \r \u000d Backslash \\ \u005c Single Quote \' \u0027 Double Quote \" \u0022 44

Appendix B: ASCII Character Set ASCII Character Set is a subset of the Unicode from \u0000 to \u007f 45

ASCII Character Set, cont. ASCII Character Set is a subset of the Unicode from \u0000 to \u007f 46

Casting between char and Numeric Types int i = 'a'; // Same as int i = (int)'a'; char c = 97; // Same as char c = (char)97; 47

Problem: Monetary Units This program lets the user enter the amount in decimal representing dollars and cents and output a report listing the monetary equivalent in single dollars, quarters, dimes, nickels, and pennies. Your program should report maximum number of dollars, then the maximum number of quarters, and so on, in this order. ComputeChange Run 48

Trace ComputeChange int remainingamount = (int)(amount * 100); Suppose amount is 11.56 remainingamount 1156 // Find the number of one dollars int numberofonedollars = remainingamount / 100; remainingamount = remainingamount % 100; // Find the number of quarters in the remaining amount int numberofquarters = remainingamount / 25; remainingamount = remainingamount % 25; remainingamount initialized // Find the number of dimes in the remaining amount int numberofdimes = remainingamount / 10; remainingamount = remainingamount % 10; // Find the number of nickels in the remaining amount int numberofnickels = remainingamount / 5; remainingamount = remainingamount % 5; // Find the number of pennies in the remaining amount int numberofpennies = remainingamount; 49

animation Trace ComputeChange int remainingamount = (int)(amount * 100); Suppose amount is 11.56 // Find the number of one dollars int numberofonedollars = remainingamount / 100; remainingamount = remainingamount % 100; remainingamount numberofonedollars 1156 11 // Find the number of quarters in the remaining amount int numberofquarters = remainingamount / 25; remainingamount = remainingamount % 25; numberofonedollars assigned // Find the number of dimes in the remaining amount int numberofdimes = remainingamount / 10; remainingamount = remainingamount % 10; // Find the number of nickels in the remaining amount int numberofnickels = remainingamount / 5; remainingamount = remainingamount % 5; // Find the number of pennies in the remaining amount int numberofpennies = remainingamount; 50

animation Trace ComputeChange int remainingamount = (int)(amount * 100); Suppose amount is 11.56 // Find the number of one dollars int numberofonedollars = remainingamount / 100; remainingamount = remainingamount % 100; // Find the number of quarters in the remaining amount int numberofquarters = remainingamount / 25; remainingamount = remainingamount % 25; // Find the number of dimes in the remaining amount int numberofdimes = remainingamount / 10; remainingamount = remainingamount % 10; // Find the number of nickels in the remaining amount int numberofnickels = remainingamount / 5; remainingamount = remainingamount % 5; // Find the number of pennies in the remaining amount int numberofpennies = remainingamount; remainingamount numberofonedollars remainingamount updated 56 11 51

animation Trace ComputeChange int remainingamount = (int)(amount * 100); Suppose amount is 11.56 // Find the number of one dollars int numberofonedollars = remainingamount / 100; remainingamount = remainingamount % 100; // Find the number of quarters in the remaining amount int numberofquarters = remainingamount / 25; remainingamount = remainingamount % 25; remainingamount numberofonedollars numberofonequarters 56 11 2 // Find the number of dimes in the remaining amount int numberofdimes = remainingamount / 10; remainingamount = remainingamount % 10; numberofonequarters assigned // Find the number of nickels in the remaining amount int numberofnickels = remainingamount / 5; remainingamount = remainingamount % 5; // Find the number of pennies in the remaining amount int numberofpennies = remainingamount; 52

animation Trace ComputeChange int remainingamount = (int)(amount * 100); Suppose amount is 11.56 // Find the number of one dollars int numberofonedollars = remainingamount / 100; remainingamount = remainingamount % 100; // Find the number of quarters in the remaining amount int numberofquarters = remainingamount / 25; remainingamount = remainingamount % 25; // Find the number of dimes in the remaining amount int numberofdimes = remainingamount / 10; remainingamount = remainingamount % 10; // Find the number of nickels in the remaining amount int numberofnickels = remainingamount / 5; remainingamount = remainingamount % 5; // Find the number of pennies in the remaining amount int numberofpennies = remainingamount; remainingamount numberofonedollars numberofquarters remainingamount updated 6 11 2 53

The String Type The char type only represents one character. To represent a string of characters, use the data type called String. For example, String message = "Welcome to Java"; String is actually a predefined class in the Java library just like the System class and JOptionPane class. The String type is not a primitive type. It is known as a reference type. Any Java class can be used as a reference type for a variable. Reference data types will be thoroughly discussed in Chapter 7, Objects and Classes. For the time being, you just need to know how to declare a String variable, how to assign a string to the variable, and how to concatenate strings. 54

String Concatenation // Three strings are concatenated String message = "Welcome " + "to " + "Java"; // String Chapter is concatenated with number 2 String s = "Chapter" + 2; // s becomes Chapter2 // String Supplement is concatenated with character B String s1 = "Supplement" + 'B'; // s1 becomes SupplementB 55

Programming Style and Documentation Appropriate Comments Naming Conventions Proper Indentation and Spacing Lines Block Styles 56

Appropriate Comments Include a summary at the beginning of the program to explain what the program does, its key features, its supporting data structures, and any unique techniques it uses. Include your name, class section, instructor, date, and a brief description at the beginning of the program. 57

Naming Conventions Choose meaningful and descriptive names. Variables and method names: Use lowercase. If the name consists of several words, concatenate all in one, use lowercase for the first word, and capitalize the first letter of each subsequent word in the name. For example, the variables radius and area, and the method computearea. 58

Naming Conventions, cont. Class names: Capitalize the first letter of each word in the name. For example, the class name ComputeArea. Constants: Capitalize all letters in constants, and use underscores to connect words. For example, the constant PI and MAX_VALUE 59

Proper Indentation and Spacing Indentation Indent two spaces. Spacing Use blank line to separate segments of the code. 60

Block Styles Use end-of-line style for braces. Next-line style public class Test { public static void main(string[] args) { System.out.println("Block Styles"); } } public class Test { public static void main(string[] args) { System.out.println("Block Styles"); } } End-of-line style 61

Syntax Errors Programming Errors Detected by the compiler Runtime Errors Causes the program to abort Logic Errors Produces incorrect result 62

Syntax Errors public class ShowSyntaxErrors { public static void main(string[] args) { i = 30; System.out.println(i + 4); } } 63

Runtime Errors public class ShowRuntimeErrors { public static void main(string[] args) { int i = 1 / 0; } } 64

Logic Errors public class ShowLogicErrors { // Determine if a number is between 1 and 100 inclusively public static void main(string[] args) { // Prompt the user to enter a number String input = JOptionPane.showInputDialog(null, "Please enter an integer:", "ShowLogicErrors", JOptionPane.QUESTION_MESSAGE); int number = Integer.parseInt(input); // Display the result System.out.println("The number is between 1 and 100, " + "inclusively? " + ((1 < number) && (number < 100))); } } System.exit(0); 65

Debugging Logic errors are called bugs. The process of finding and correcting errors is called debugging. A common approach to debugging is to use a combination of methods to narrow down to the part of the program where the bug is located. You can hand-trace the program (i.e., catch errors by reading the program), or you can insert print statements in order to show the values of the variables or the execution flow of the program. This approach might work for a short, simple program. But for a large, complex program, the most effective approach for debugging is to use a debugger utility. 66

Debugger Debugger is a program that facilitates debugging. You can use a debugger to Execute a single statement at a time. Trace into or stepping over a method. Set breakpoints. Display variables. Display call stack. Modify variables. 67

JOptionPane Input This book provides two ways of obtaining input. 1. Using the Scanner class (console input) 2. Using JOptionPane input dialogs 68

Getting Input from Input Dialog Boxes String input = JOptionPane.showInputDialog( "Enter an input"); 69

Getting Input from Input Dialog Boxes String string = JOptionPane.showInputDialog( null, Prompting Message, Dialog Title, JOptionPane.QUESTION_MESSAGE); 70

Two Ways to Invoke the Method There are several ways to use the showinputdialog method. For the time being, you only need to know two ways to invoke it. One is to use a statement as shown in the example: String string = JOptionPane.showInputDialog(null, x, y, JOptionPane.QUESTION_MESSAGE); where x is a string for the prompting message, and y is a string for the title of the input dialog box. The other is to use a statement like this: JOptionPane.showInputDialog(x); where x is a string for the prompting message. 71

Converting Strings to Integers The input returned from the input dialog box is a string. If you enter a numeric value such as 123, it returns 123. To obtain the input as a number, you have to convert a string into a number. To convert a string into an int value, you can use the static parseint method in the Integer class as follows: int intvalue = Integer.parseInt(intString); where intstring is a numeric string such as 123. 72

Converting Strings to Doubles To convert a string into a double value, you can use the static parsedouble method in the Double class as follows: double doublevalue =Double.parseDouble(doubleString); where doublestring is a numeric string such as 123.45. 73

Problem: Computing Loan Payments Using Input Dialogs Same as the preceding program for computing loan payments, except that the input is entered from the input dialogs and the output is displayed in an output dialog. loanamount monthlyinterestrate 1 1 (1 monthlyinterestrate ) numberofyears 12 ComputeLoanUsingInputDialog Run 74

Companion Website Debugging in NetBeans Supplement II.E, Learning Java Effectively with NetBeans 75

Companion Website Debugging in Eclipse Supplement II.G, Learning Java Effectively with NetBeans 76