CSE 373 APRIL 3 RD ALGORITHM ANALYSIS

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Transcription:

CSE 373 APRIL 3 RD ALGORITHM ANALYSIS

ASSORTED MINUTIAE HW1P1 due tonight at midnight HW1P2 due Friday at midnight HW2 out tonight Second Java review session: Friday 10:30 ARC 147

TODAY S SCHEDULE Algorithm Analysis, cont. Floyd s algorithm

REVIEW FROM LAST WEEK Algorithm Analysis Testing is for implementations Analysis is for algorithms Runtime, memory and correctness Best case, average case, worst case Over groups of inputs, not just one

ALGORITHM ANALYSIS Principles of analysis Determining performance behavior How does an algorithm react to new data or changes? Independent of language or implementation

ALGORITHM ANALYSIS Example: find() Sorted v Unsorted How is insert impacted? A sorted array gives us faster find because we can use binary search Can we prove that this is the case?

BINARY SEARCH Analyzing binary search. What is the worst case? When the item is not in the list How long does this take to run?

BINARY SEARCH Consider the algorithm public int binarysearch(int[] data, int tofind){ int low = 0; int high = data.length-1; while(low <= high){ int mid = (low+high)/2; if(tofind>mid) low = mid+1; continue; else if(tofind<mid) high = mid-1; continue; else return mid; } return -1; }

BINARY SEARCH What is important here? At each iteration, we eliminate half of the remaining elements. How long will it take to reach the end? At first iteration, N/2 elements remain At second, N/4 elements remain At the kth iteration?

BINARY SEARCH At the kth iteration: N/2 k elements remain. When does this terminate? When N/2 k = 1 How many iterations then? Solve for k.

BINARY SEARCH Solve for k. N / 2 k = 1 N = 2 k log 2 N = k Is this exact? Where was the error introduced? N can be things other than powers of two Ceiling and floor rounding

ANALYSIS If this isn t exact, is it still correct? Yes. We care about asymptotic growth. How a the runtime of an algorithm grows with big data To incorporate this perspective, we use bigo notation

BIG-O NOTATION Informally: bigo notation denotes an upper bound for an algorithms asymptotic runtime For example, if an algorithm A is O(log n), that means some logarithmic function upper bounds A.

BIG-O NOTATION Formally, a function f(n) is O(g(n)) if there exists a c and n 0 such that: For all n > n 0, f(n) < c*g(n) To prove a function is O(g(n)), simply find the c and n 0

BIG-O NOTATION Example: is 5n 3 + 2n in O(n 4 )? Can we find a c, n 0 such that: 5n 3 + 2n < c*n 4 for all n > n 0 Let c = 7; 5n 3 + 2n < 7n 4 5n 3 + 2n < 5n 4 + 2n 4 Since n 4 > n 3 and n 4 > n for n > 1 5n 3 + 2n < 7n 4 for all n > 1 Therefore, 5n 3 + 2n is O(n 4 )

BIG-O NOTATION This is an upper bound, so if 5n 3 + 2n is in O(n 4 ), then 5n 3 + 2n is in O(n 5 ) and O(n n ) Is 5n 3 + 2n in O(n3)? Yes, let c be 7 and n > 1

BIG-O NOTATION Big-O is for upper bounds. It s equivalent for lower bounds is big Omega Formally, a function f(n) is Ω(g(n)) if there exists a c and n 0 > 0 such that: For all n > n 0, f(n) > c*g(n) If a function f(n) is in O(g(n)) and Ω(g(n))

BIG-O NOTATION If a function f(n) is in O(g(n)) and Ω(g(n)), then g(n) is a tight bound on f(n), we call this big theta. Formally, if f(n) is in O(g(n)) and Ω(g(n)), then f(n) is in θ(g(n)) Note that the two will have different c and n 0

BIG O NOTATION What does this help us with? Sort algorithms into families O(1): constant O(log n): logarithmic O(n) : linear O(n 2 ): quadratic O(n k ): polynomial O(k n ): exponential

BIG O NOTATION What does this help us with? The constant multiple c lets us organize similar algorithms together. Remember that log a k and log b k differ by a constant factor? That makes all logs in the same family

CORRECTNESS ANALYSIS How do we show an algorithm is correct? Need to look at the approach

BINARY SEARCH (AGAIN) public int binarysearch(int[] data, int tofind){ int low = 0; int high = data.length-1; while(low <= high){ int mid = (low+high)/2; if(tofind>mid) low = mid+1; continue; else if(tofind<mid) high = mid-1; continue; else return mid; } return -1; }

BINARY SEARCH CORRECTNESS Prove binary search returns the correct answer Need property of sortedness For all pairs i,j in the array: If A[i] < A[j], then i < j Binary search always chooses the correct side End case: low = high

ANALYSIS Let s find an interesting algorithm to analyze Given an array of length n, how do we make that array into a heap? Naïve approach? Make a new heap and add each element of the array into the heap How long to finish?

ANALYSIS Naïve approach: Must add n items Each add takes how long? log(n) Whole operation is O(n log(n)) Can we do better? What is better? O(n)

NEXT CLASS Analyzing buildheap Function tradeoffs Precomputation