Intro Right Triangle Trig

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Ch. Y Intro Right Triangle Trig In our work with similar polygons, we learned that, by definition, the angles of similar polygons were congruent and their sides were in proportion - which means their ratios are the same. We also learned the ngle-ngle Postulate. That is, if two angles of one triangle were congruent to two angles of another triangle, the triangles were similar. s we look at the ratios of the sides of similar triangles, we are going to use that information and name some of those ratios - an introduction to right triangle trigonometry. Look at the three triangles below - BC, MN and XY. They are similar because of the Postulate. Each triangle has a right angle and each triangle contains. B M X Y N C That means BC:MN have the same ratio as MN:XY. In fact, I could continue the relationships by saying BC:B as MN:M as XY:X. Let me write some of those relationships in words: the side to the of each of the triangles, BC, MN and XY have the same ratio. This is kind of important, so we are going to name that ratio. The side an angle over the will be called the sine ratio, abbreviated sin, of that angle. So sin is equal to any of those ratios; " BC B = MN M = XY X BC B = MN M = XY X

If we were to look at other ratios based on the above triangles, we would also C realize because of similar triangles, these ratios are also equal; ". B = N M = Y X Putting that ratio in words, the side to the angle over the will be called the cosine, abbreviated cos, of that angle. So the cos is equal to any of those ratios; " nd one more set of ratios that would be equal are the ratio of the side that angle over that side. That ratio is called the tangent, abbreviated tan. Summarizing those names, we have BC B = MN M = XY X sin = " cos = " tan = " popular way to remember those ratios is by memorizing SOHCHTO. The S stands for sine, O for side, H for, C for cosine, for side and T for tangent. Example Using a 0-60-90 special right triangle, find the sine, cosine and tangent of 0 B 0 Using SOHCHTO 2 sin0 = " ; " cos0 = " ; " 2 2 60 C tan0 = " ; " = " 2

Example 2 Using the same 0-60-90 special right triangle, find the tan60 and the cos60. Using SOHCHTO tan60 = " ; " cos60 = " ; " Using your knowledge of special right triangles, you should be able to find the sine, cosine and tangent ratios for 0, 45 and 60 angles. The ratios frothier angles would have to be looked up in your book or found on your calculator. 2 We just said, based on our knowledge of special right triangles, the cos60 = /2. If you were to use a table or your calculator, you would find the cos60 =.500. To find the tan42, use either your calculator or book and you will find that ratio is always 0.9004. Because of similar triangles and the sides being in proportion, the ratio of the side : side is called the tangent and the tangent of 42 will always be equal to 0.9004. Example Use the tables in your calculator or in your book to find the sine, cosine and tangent of the following angles.. 0 2. 60. 40 4. 6 Find the measure of the angle with the following values (ratios). 5. Sin =.550 6. CosB =.707 7, tanc =.270

Example 4 Let s find the sin B, cos B, and the tan B 5 B 4 C Remember SOHCHTO. sinb = /5 cosb = 4/5 tan B = /4 Was that hard? Of course not. Using the same triangle, find the sin, cos, and tan. sin = 4/5 cos = /5 tan = 4/ Example 5 Find the sin, cos, and tan for angles Q and R. Q 2 R S 5 Using SOHCHTO sin Q = 5/ sin R = 2/ cos Q = 2/ cos R = 5/5 tan Q = 5/2 tan R = 2/5 In these examples, we have just asked you to find the ratios given a specific angle. To solve problems, you will have to determine which trig ratio is most appropriate based on the information provided. 4

Example 6 boy standing on level ground notices (or can measure) that the angle he has to look up (angle of elevation) to see the top of a flagpole is 42 degrees. He can also measure the distance he is from the pole and finds it to be 20 feet. How high is the flagpole? We ll call the height of the flagpole h. Let s look at a picture and fill in any information we have h 42 20 ft Now, how can we determine the height? Well, since we are studying trig, let s hope we use one of the trig ratios. Which one do we use? That s the question. The sine is the over the ; we don t know the or the. So we won t use the sine. Cosine is the over the ; that does not give the height. So I won t use that. Tangent is the, which is h, over the. There, I know the is 20 and I m looking for the (height). Therefore, I will use the tangent ratio. I will have to look up the tan 42 on my trig table. The tan 42 =.9004 tan42 = = h 20.9004 = h 20 08 h So the height of the flagpole is approximately 08 feet. 5

In a number of applications, professionals use terms like angle of elevation or angle of depression angle of depression B angle of elevation Line segment B is the line of sight, the other two lines are horizontals. Notice how those two angles are defined with the horizontals. If you are looking up, that s an angle of elevation. Looking down is an angle of depression. To solve problems involving the trigonometric ratios, it s always wise to think first, then set up a ratio. s we have said before, the choices we make can either make math easier or more cumbersome. So, we have to ask, given certain information, am I going to use the sine cosine or tangent ratios and from what angle? So thinking first is important. Example 7 Find the measure of DE in the diagram. F D 2 x 200 E Using the trig ratios, we are working with 2 sides and an angle. To solve problems, we need to know 2 of those and find the unknown. 6

" " In this problem, we have 2 sides and an angle. Notice that the is NOT one of the sides given. For me, that eliminates using the sine or cosine ratios. So, that leaves me with the tangent ratio, do I want to use angle D or F? Remember, if D = 2, then F = 58. The sum must be 90. So now decide, which is an easier equation to solve, or B?. tan 2 = 200 x or B. tan58 = x 200 In either case, I have to use a table or calculator to find the respective tangent values. However, since x is in the numerator of the B, I would choose to multiply, rather then divide. tan58 = x 200 tan 58.600.600 x 200 x 200(.600) 20 Example 8 The length of a kite string is 00 feet long. How high is the kite if the kite make a 0 angle with the round? The first best thing to do is draw a picture and label what we can. 00 feet h 0 7

Drawing the picture, you can see I straightened out the string and the height of anything is always denoted by perpendicular lines to form a right triangle. Now, the question is; which trig ratio is best to use? To solve a problem with a trig ratio, I need to know 2 of things; sides and angles. In this case, the sin 0 is something I know from applications of special triangles or I could look it up. sin0 = " Substituting sin 0 = /2 and the is 00 ft 2 = h 00 2h = 00 h = 50 The tip of the kite string is 50 feet above the ground. Let s examine what we know. ll trig is in the study of the ratios of the sides of the right triangle. Those ratios are given names; sine, cosine, tangent, cosecant, secant, and cotangent. To know which ratio we are talking about, we stand on the vertex of the angle and use the acronym SOHCHTO. By looking at different right triangles and knowing the ratios are the same for equal angles (using SIMILR TRINGLES) we are able to create trig tables for all the angles that will give us the ratio of those sides. Don t you just love this stuff? You are probably thinking trig is my life. 8

Try these next two problems. In the first problem, the angle of depression is given. You need to know how to draw that - see page 6. We should not need tables because we are working with a 60 angle - use the special right triangle relationships.. From the top of a building 00 feet high, you see a parked car on a bridge, if the angle of depression is 60, how far is the car from the building? In this problem, we don t know the ratio of sides for an angle measuring 20, s we will have to use the book or calculator to determine that value based on the trig ratio you chose. 2. pilot reads the angle of depression from his position 5000 feet in the air is 20, how far is the plane from the airport? 9