A non-partitionable CM simplicial complex

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Transcription:

A non-partitionable Cohen-Macaulay simplicial complex Art M. Duval (University of Texas, El Paso) Bennet Goeckner (University of Kansas) Caroline J. Klivans (Brown University) Jeremy L. Martin (University of Kansas) Midwest Combinatorics Conference University of Minnesota, May 19, 2015 Preprint: arxiv:1504.04279

Overview: The Partitionability Conjecture The focus of this talk is the following conjecture, described in Stanley s Green Book as a central combinatorial conjecture on Cohen-Macaulay complexes. Partitionability Conjecture (Stanley 1979) Every Cohen-Macaulay simplicial complex is partitionable.

Overview: The Partitionability Conjecture The focus of this talk is the following conjecture, described in Stanley s Green Book as a central combinatorial conjecture on Cohen-Macaulay complexes. Partitionability Conjecture (Stanley 1979) Every Cohen-Macaulay simplicial complex is partitionable. Theorem (DGKM 15+) The Partitionability Conjecture is false. We construct an explicit counterexample and describe a general method to construct more.

Partitionable Complexes X d = pure simplicial complex of dimension d A partitioning of X is a decomposition X = [R(F ), F ] where [R, F ] facets F def = {σ R σ F }. X shellable = X partitionable X partitionable = h i (X ) = #{F : R(F ) = i} 0

Cohen-Macaulay and Constructible Complexes X d is Cohen-Macaulay iff its Stanley-Reisner ring (face ring) is Cohen-Macaulay, i.e., dim k[x ] = depth k[x ]. (Combinatorial/topological condition: Reisner s criterion.) X d is constructible iff either it is a simplex, or the union of two constructible d-dimensional complexes whose intersection is constructible of dimension d 1. shellable = constructible = CM = h(x ) 0 partitionable

Stanley Depth Definition Let S = k[x 1,..., x n ]; µ S a monomial; and A {x 1,..., x n }. The corresponding Stanley space in S is the vector space µ k[a] = k- span{µν supp(ν) A}. Let I S be a monomial ideal. A Stanley decomposition of S/I is a family of Stanley spaces D = {µ 1 k[a 1 ],..., µ r k[a r ]} such that S/I = r µ i k[a i ]. i=1

Stanley Depth Definition The Stanley depth of S/I is sdepth S/I = max min{ A i }. D where D runs over all Stanley decompositions of S/I. For a nice introduction, see M. Pournaki, S. Fakhari, M. Tousi and S. Yassemi, What is Stanley depth?, Notices AMS 2009

Stanley s Depth Conjecture Depth Conjecture (Stanley 1982) Let S = k[x 1,..., x n ] and I S be any monomial ideal. Then sdepth S/I depth S/I. Theorem (Herzog, Jahan and Tassemi 08) The Depth Conjecture implies the Partitionability Conjecture Corollary (DGKM 15+) The Depth Conjecture is false.

Relative Simplicial Complexes Definition A relative simplicial complex Q on vertex set [n] is a convex subset of the Boolean algebra 2 [n]. That is, σ, τ Q, σ ρ τ = ρ Q. Every relative complex can be written as (X, A) = X \ A, where A X are simplicial complexes. Combinatorics 1 3 2 A Q = (X, A) X Geometry Q A 1 2 3 X

Reducing to the Relative Case X = CM complex A X : induced, CM, codim 0 or 1 Q = (X, A) N > # faces of A Idea: Construct Ω by gluing N copies of X together along A. Ω is CM by Mayer-Vietoris. On the level of face posets, Ω = Q 1 Q N A, Q i = Q i. If Ω has a partitioning P, then by pigeonhole i such that i [n] : F Q i : R(F ) A. Therefore, the partitioning of Ω induces a partitioning of Q. Problem: Find a suitable Q.

Background: Unshellable Balls Mary Ellen Rudin (1958) constructed a simplicial 3-ball that is not shellable, with f -vector (1, 14, 66, 94, 41) and h-vector (1, 10, 30). Günter Ziegler (1998) constructed a smaller non-shellable simplicial 3-ball with f -vector (1, 10, 38, 50, 21) and h-vector (1, 6, 14). Its facets are 0123 0125 0237 0256 0267 1234 1249 1256 1269 1347 1457 1458 1489 1569 1589 2348 2367 2368 3478 3678 4578

Our Counterexample Theorem (DGKM 2015+) Let Z be Ziegler s ball, and let B = Z 0,2,3,4,6,7,8. 1. B is a shellable, hence CM, simplicial 3-ball. 2. Q = (Z, B) is not partitionable. Its minimal faces are the three vertices 1, 5, 9. 3. Therefore, the simplicial complex obtained by gluing B + 1 = 53 copies of Z together along B is not partitionable. Assertion (2) can be proved by elementary methods.

A Smaller Counterexample Let X be the smallest simplicial complex containing Q. Then Q = (Z, B) = (X, A), where f (X ) = (1, 10, 31, 36, 14), f (A) = (1, 7, 11, 5). So a much smaller counterexample can be constructed by gluing together (1 + 7 + 11 + 5) + 1 = 25 copies of X along A. In fact, gluing three copies of X along A produces a CM nonpartitionable complex Ω, with f(ω) = 3f(X) 2f(A) = (1, 16, 71, 98, 42). This is the smallest such complex we know, but there may well be smaller ones.

A Much Smaller Relative Counterexample There is a much smaller non-partitionable CM relative complex Q inside Ziegler s ball Z, with face poset 1345 1346 3456 2356 2456 135 134 345 136 346 356 236 456 256 246 13 34 36 56 26 A partitioning of Q would correspond to a decomposition of this poset into five pairwise-disjoint diamonds. It is not hard to check by hand that no such decomposition exists.

A Much Smaller Relative Counterexample Construction: Q = (X, A ), where X = 1589, 1489, 1458, 1457, 4578 = Z 145789, A = 489, 589, 578, 157. Q is CM (since X, A are shellable and A X ) f (Q ) = (0, 0, 5, 10, 5) Minimal faces are edges rather than vertices, so Q cannot be expressed as (X, A) where A is an induced subcomplex. k[q ] is a small counterexample to the Depth Conjecture [computation by Lukas Katthän]

Open Questions Is there a smaller counterexample, perhaps in dimension 2? What is the right strengthening of constructibility that implies partitionability? ( Strongly constructible complexes, as studied by Hachimori, are partitionable.) Is there a better combinatorial interpretation of the h-vectors of Cohen-Macaulay complexes? (Duval Zhang) Are all simplicial balls partitionable? (Yes if convex.) Does the Partitionability Conjecture still hold for balanced simplicial complexes (as conjectured by Garsia)? What are the consequences for Stanley depth? Does sdepth M depth M 1 (as conjectured by Lukas Katthän)?

Thanks for listening!