GRAPHICAL ALGORITHMS. UNIT _II Lecture-12 Slides No. 3-7 Lecture Slides No Lecture Slides No
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1 GRAPHICAL ALGORITHMS UNIT _II Lecture-12 Slides No. 3-7 Lecture Slides No Lecture Slides No
2 Topics Covered Graphs & Trees ( Some Basic Terminologies) Spanning Trees (BFS & DFS) Disjoint set Operations: Union & Find Algorithms Connected Components Bi-Conncted Components
3 Graphs The diagrammatical representation of a set of Vertices (nodes) and a set of Edges is called a Graph. It is a non-linear data structure. It is hierarchical structure. Examples: In the real world are Airlines, Source-Destination Network, Konigsberg s Bridges, and Flowchart of a Program.
4 Graph Terminology 1. Graph 1. Digraph 2. Weighted Graph 2. Adjacent Vertices 3. Self-loop 3. Parallel Edges 4. Simple Graph 4. Complete Graph 5. Circuit 5. Bipartite Graph 6. Isolated Vertex 6. Degree of Vertex 7. Pendant Vertex 7. Connected Graph 8. Path 8. Tree 9. Sub graph 9. Spanning Tree 10.Isomorphic graphs 10. Biconnected Graphs Height, Level, Parent, Child, Ancestor, leaf etc.
5 A graph is said to be a tree if it is a simple connected graph with no cycles. Directed tree and Non directed tree. In a directed tree there is a specially designated node called the root, remaining nodes are partitioned into n (n>0) disjoint sets T 1, T 2, T 3,,T n, where each T i (i=1,2,3 n) is a tree, T 1, T 2, T 3,,T n are called sub-trees of the root. the path is always fro root to the leaf.
6 Trees A tree is a non-linear data structure. It require two-dimensional representations. Jan Feb Mar Apr Jul May Aug Jun Oct Nov Dec Sep
7 A T1 T2 T3 B C D E F G H I J K Fig A Sample Tree T
8 Representation of Graphs Graph can be represented in many ways: 1. Set representation 2. Linked representation 3. Adjacency Matrix representation 4. Incidence Matrix representation 5. Sparse Matrix representation 6. Multi-lists representation
9 1. Subgraph 1. A subgraph of a graph G is a graph H whose vertices and edges are subsets of the vertices and edges of G. 2. Spanning Subgraph 1. A Spanning Subgraph of G is subgraph of G that contains all the vertices of the graph G. 3. Forest 1. A Forest is a graph without cycles. 4. Tree 1. A Tree is a connected forest, i.e, a connected graph without cycles. 5. Spanning Tree 1. A Spanning tree of a graph is a spanning subgraph that is a tree.
10 Graph Traversal Techniques A traversal is a systematic procedure for exploring a graph by examining all of its vertices and edges. A traversal is efficient if it visits all the vertices and edges in time proportional to their number, i.e., in linear time. There are two methods, called Breadth First Search (BFS) and Depth First Search (DFS).
11 Breadth First Search BFS proceeds in rounds and subdivides the vertices into Levels. BFS can also be thought of as a traversal using a string and paint. With BFS unrolling the string in a more conservative manner. BFS starts at a given vertex s, which is at level-0 and defines the anchor for our string.
12 BFS Algorithm Input: A connected graph G with vertices labeled V 1, V 2,, V n Output: A Spanning tree T for G. Method: Step1: (Start) Let V 1, be the root of T. From the set V= {V 1 }.
13 Step2: (Add new edges) Consider the vertices of V in order consistent with the original labeling. Then for each vertex x V, add the edge {x,v k } to T where k is the minimum index such that adding the edge {x, V k }to T does not produce a cycle. If no edge can be added, then stop; T is a spanning tree for G. After all the vertices of v have been considered in order, go to Step 3.
14 Step3: (Update V) Replace V by all the children Vin T of the vertices x of V where the edges {x, V k } were added in Step2. Go back and repeat Step2 for the new set V.
15 Algorithm BFT (G, n) { //breadth first traversal graph for i=1 to n do //mark all vertices unvisited visited[i]=0; for i=1 to n do if (visited[i] = 0) then BFS(i); }
16 Algorithm BFS (v) // code for Breadth First Search { u = v; //q is a queue of unexplored vertices visited[v] = 1; repeat { for all vertices w adjacent from u do { if (visited[w] = 0) then { add w to q; // w is unexplored visited[w] = 1; } } } If q is empty then return; //no unexplored vertex delete u from q; //get unexplored vertex } until(false)
17 Properties of BFS 1. It is a graph traversal Technique. 2. It is based on visiting FIFO rule. 3. It is based exploring edges. 4. The traversal visits all the vertices in the connected component of s. 5. The discovery edges form a spanning tree T of the connected component of s. 6. For each vertex v at level i, the path of tree T, between s and v has i edges, and any other path of G between s and v has at least i edges. 7. If (u, v) is a cross edge, then the level numbers of u and v differ by at most 1.
18 2. Let G be a graph with n vertices and e edges represented with the adjacency list structure. 3. The time complexity is O (e + n). 4. Problems can be solved based on BFS are 1. Testing whether G is connected. 2. Computing a spanning forest of G. 3. Computing the connected component of G. 4. Computing a cycle in G, or reporting that G has no cycles. 5. Given a start vertex s of G, computing, for every vertex v of G, path with the minimum number of edges between u an v, or reporting that no such path exists.
19 DFS DFS is an Non-directed graph. DFS is useful for performing a number of computations on graphs. It also calculates the path from one vertex to another. It determines a graph is connected or not. And computing a spanning tree for a connected graph. It applies Backtracking technique.
20 DFS Algorithm Input: A connected graph G with vertices labeled V 1, V 2,, V n Output: A Spanning tree T for G. Method: Step1: (Start) Let V 1, be the root of T. And set L=V 1. L stands for the vertex last visited.
21 Step2: (Find unexamined edge and unvisited vertex adjacent to L) For all vertices adjacent to L, choose the edge {L, V k }, where k is the minimum index such that adding {L, V k } to T does not create a cycle. I f no such edge exists, go to Step 3, otherwise, add edge {L, V k } to T and set L= V k ; repeat Step 2 at the new value for L.
22 Step3: (Backtrack or terminate) If x is the parent of L in T, set L= x and apply Step2 at the new value of L. If, on the other hand L has no parent in T (so that L=V 1 ) then the depth First Search terminates and T is a spanning tree for G.
23 Construct Spanning tree using BFS and DFS.
24 Algorithm DFS(v) { visited[v] = 1; for each vertex w adjacent from v do { if (visited[w] = 0) then DFS(w); } }
25 Backtracking Algorithm genbacktrack(n) { k = 1; while (k 0) do { if (there remains an untried x[k] T(x[1], x[2],, x[k-1] and B k (x[1], x[2], x[k]) is true) then { if(x[1], x[k] is a path to an answer node) then write (x[1..k]); } else k=k-1; //backtrack to the previous set } }
26 Algorithm recurbacktrack(k) { for (each x[k] T(x[1], x[2],,x[k-1]) do { if (Bk (x[1], x[2],,x[k]) 0) then { if (x[1], x[2],, x[k]) is a path to an answer node then write (x[1..k]); if (k < n) then backtrack(k+1); } } }
27 Applications of Graphs 1. Transportation problem 2. Map Coloring 3. Shortest Path Problem 1. Warshall s algorithm 2. Floyd s algorithm 3. Dijkstra s algorithm 4. Topological Sorting algorithm 5. Minimum Spanning Tree 1. Kruskal s algorithm 2. Prim s algorithm 6. Connectivity in Graph 1. Strongly connectivity 2. Bi-connectivity 7. Euler s path and Hamiltonian Circuits 8. Binary Decision Diagram
28 Let us suppose that we have some finite Universe of n elements, out of which sets will be constructed. These sets may be empty or contain any subsets of the elements of Universe. A common way to represent such sets is to allocate a bit vector of length n, SET(1:n). For example, SET(i) = 1 if the i th element of U is in this set = 0 otherwise.
29 Let us assume that the elements of the sets are the numbers 1,2,3, n. These numbers are the indices into a symbol table where actual names of elements are stored. Assume that the sets are represented pair wise disjoint. Example: S 1 = {1, 7, 8, 9}; S 2 = {2,5,10}; S 3 = {3,4,6}.
30 Operations on Disjoint Sets 1. Disjoint set Union: Combining the sets S i U S j = { All elements x such that x is in Si or Sj}. 2. Find(i): Finding the set containing element i.
31 Simple Union and Find Algorithm Let i and j be the roots of two disjoint sets. Algorithm to Union of two disjoint sets Integer i, j Parent(i) j end of U Algorithm to Find the i th root of the tree containing element i Integer i, j j i While Parent(j)>0 do j Parent(j) repeat return(j) end F
32 Count(i) = number of nodes in that tree. The count can be maintained in the Parent field as a negative number. Parent(i) = -count(i) If Parent (i)= 0 if this is a root node. Weighting rule for Union (I,j). If the number of nodes in tree I is less than the number in tree j, then make j the parent of I, other wise make I the parent of j.
33 Weighting Rule for UNION Weighting rule for Union (i, j): If the number of nodes in tree i is less than the number in tree j, then make j the parent of i, other wise make i the parent of j.
34 UNION Algorithm integer i, j, x x Parent(i) + Parent(j) If Parent(i) > Parent(j) then Parent(i) j Parent (j) x else Parent of (j) i Parent (i) x End if.
35 Find Algorithm j I While Parent(j) > 0 do j parent(j) Repeat k I While k j do t parent(k) Parent(k) j k t Repeat Return(j) End Find. Note: Using the collapsing rule to collapse all nodes from I to the root j.
36 Example on Union operation
37 Let T be a tree with n nodes created as aresult of algorithm Union. No node in T has level greater Floor(logn)+1
38 A vertex v in a connected graph G is an articulation point iff the deletion of vertex v together with all edges incident to v disconnects the graph into two or more non empty components.
39 Example
40 A graph G is bi-connected if and only if it contains no articulation point. G is a maximal bi-connected sub-graph of G if and only if G has no bi connected sub-graph G such that V and E are subsets of V and E
41 Construction of Bi-Connected Graph Step-1: for each articulation point a do Step-2: let B 1, B 2, B k be the bi-connected components containing vertex a Step-3: let vi, vi a be a vertex in B i, 1 i k Step-4: add to G the edges (v i, v i+1 ) 1 i < k Step-5: repeat Note: The step4 is repeated a is no longer an articulation point.
42 Finding DFN and L Procedure ART(u,v) Global DFN(n), L(n), num, n DFN(u) num; L(u) num; num num+1 for each vertex w adjacent from u do if DFN(w) = 0 then call ART(w,u) L(u) min(l(u), L(w)) else if w v then L(u) min (L(u), DFN(w)) End if Repeat end ART End if
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