Essar Placement Paper

Transcription

1 Essar Placement Paper Question 1 The fourth proportional to 5, 8, 15 is: A. 18 B. 24 C. 19 D. 20 Let the fourth proportional to 5, 8, 15 be x. Then, 5 : 8 : 15 : x 5x = (8 x 15) x=(8*15)/5=24 Question 2 If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number? A. 2 : 5 B. 3 : 7 C. 5 : 3 D. 7 : 3 Ans. C Let 40% of A=2/3 B Then,40 A/100=2B/3 => 2A/5=2B/3 => A/B-[2/3-5/2]=5/3p A : B = 5 : 3. Question 3 The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?

2 A. 3 : 3 : 10 B. 10 : 11 : 20 C. 23:33:60 D. 32 :43:53 Ans. C Let A = 2k, B = 3k and C = 5k. A's new salary = 115/ 100 of 2k =[115/ 100 x 2k]= 23k/ 10 B's new salary = 110/ 100 of 3k = [110/ 100x 3k] = 33k/ 10 C's new salary = 120/ 100 of 5k = [120/ 100 x 5k] = 6k New ratio = 23k : 33k : 6k = 23 : 33 : 60 Question 4 A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white? A. 3/4 B. 4/7 C. 1/8 D. 3/7 Let number of balls = (6 + 8) = 14. Number of white balls = 8. P (drawing a white ball)=8/14=4/7 Question 5 One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card? A. 1/13 B. 3/13 C. 1/4

3 D. 9/5 Clearly, there are 52 cards, out of which there are 12 face cards. P (getting a face card)=12/52=3/13 Question 6 Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is: A. 3 /20 B. 29/ 34 C. 47/ 100 D. 13 /102 Ans. D Let S be the sample space. Then, n(s) = 52C2 = 52 * 51/ (2*1)= Let E = event of getting 1 spade and 1 heart. n(e) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13 = (13C1 x 13C1) = (13 x 13) = 169. P(E) =n (E)/n(S) = 169/ 1326= 13/102 Question 7 A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is: A. 1/ 22 B. 3/ 22 C. 2/ 91 D. 2/ 81

4 Ans. C Let S be the sample space. Then, n(s)= number of ways of drawing 3 balls out of 15 = 15C3 = (15 x 14 x 13)/ (3 x 2 x 1) = 455. Let E = event of getting all the 3 red balls. n(e) = 5C3 = 5C2 = (5 x 4)/ (2 x 1)= 10. P(E) = n(e) / n(s)= 10/ 455 = 2/ 91 Question 8 A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is: A. 1 /13 B. 2 /13 C. 1 /26 D. 1 /52 Ans. C Here, n(s) = 52. Let E = event of getting a queen of club or a king of heart. Then, n(e) = 2. P(E) =n(e)/ n(s)= 2/ 52= 1/ 26 Question 9 Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is: A. 27 B. 33 C. 49 D. 55

5 Let the numbers be 3x and 5x. Then,(3x-9)/(5x-9)=12/13 23(3x - 9) = 12(5x - 9) 9x = 99 x = 11. The smaller number = (3 x 11) = 33. Question 10 In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there? A. 50 B. 100 C. 150 D. 200 Ans. C Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively. Then, sum of their values=rs[(25x/100)+(10*2x)/100+(5*3x)/100]=rs 60x/100 60x/100=30 =>x=(30*100)/60=50 Hence, the number of 5 p coins = (3 x 50) = 150. Question 11 B2CD,, BCD4, B5CD, BC6D A. B2C2D B. BC3D C. B2C3D D. BCD7

6 Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order. Question 12 DEF, DEF2, DE2F2,, D2E2F3 A. DEF3 B. D3EF3 C. D2E3F D. D2E2F2 Ans. D In this series, the letters remain the same: DEF. The subscript numbers follow this series: 111, 112, 122, 222, 223, 233, 333,... Question women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? A. 3 B. 5 C. 7 D. Cannot be determined Ans. C

7 1 woman's 1 day's work=1/70 1 child's 1 day's work =1/140 (5 women + 10 children)'s day's work =5/70 +10/140=1/14 +1/14=1/7 5 women and 10 children will complete the work in 7 days. Question 14 A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs With the help of C, they completed the work in 3 days. How much is to be paid to C? A. Rs. 375 B. Rs. 400 C. Rs. 600 D. Rs. 800 C's 1 day's work = 1/3 - [1/6 + 1/8]= 1/3-7/24= 1/24 A's wages : B's wages : C's wages = 1/6: 1/8: 1/24= 4 : 3 : 1. C's share (for 3 days) = Rs.[3 x 1/24 x 3200] = Rs Question 15 The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is: A. 380 B. 395 C. 400 D. 425 Ans. C Let the numbers be x and y. Then, xy = 9375 and x/y=15 Xy/(x/y)=9375/15 y2 = 625. y = 25. x = 15y = (15 x 25) = 375. Sum of the numbers = x + y = = 400.

8 Question 16 The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area? A. 25% increase B. 50% increase C. 50% decrease D. 75% decrease Let original length = x and original breadth = y. Original area = xy. New length =x/2 New breadth = 3y. New area=[(x/2)*3y]=(3/2)xy Increase % =[(1/2)xy*(1/xy)*100]%=50% Question 17 The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is: A m2 B m2 C m2 D m2 Ans. D We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103. Solving the two equations, we get: l = 63 and b = 40. Area = (l x b) = (63 x 40) m2 = 2520 m2.

9 Question 18 In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years age which is 48. What is the total number of students in the school? A. 72 B. 80 C. 120 D. 100 Ans. D Question 19 Point out the error in the program? struct emp char name[20]; float sal; ; struct emp e[10]; int i; for(i=0; i<=9; i++) scanf("%s %f", e[i].name, &e[i].sal); A. Error: invalid structure member B. Error: Floating point formats not linked C. No error

10 D. None of above At run time it will show an error then program will be terminated. Sample output: Turbo C (Windwos) Sample scanf : floating point formats not linked Abnormal program termination Question 20 Point out the error in the program? struct emp char name[20]; float sal; ; struct emp e[10]; int i; for(i=0; i<=9; i++) scanf("%s %f", e[i].name, &e[i].sal); A. Error: invalid structure member B. Error: Floating point formats not linked C. No error D. None of above At run time it will show an error then program will be terminated. Sample output: Turbo C (Windwos) c:\>myprogram Sample scanf : floating point formats not linked Abnormal program termination

11 Question 21 What will be the output of the program? char p[] = "%d\n"; p[1] = 'c'; printf(p, 65); A. A B. a C. c D. 65 Ans. A Step 1: char p[] = "%d\n"; The variable p is declared as an array of characters and initialized with string "%d" Step 2: p[1] = 'c'; Here, we overwrite the second element of array p by 'c'. So array p becomes "%c". Step 3: printf(p, 65); becomes printf("%c", 65); Therefore it prints the ASCII value of 65. The output is 'A'. Question 22 What will be the output of the program?

12 char str1[20] = "Hello", str2[20] = " World"; printf("%s\n", strcpy(str2, strcat(str1, str2))); A. Hello B. World C. Hello World D. WorldHello Ans. C Step 1: char str1[20] = "Hello", str2[20] = " World"; The variable str1and str2 is declared as an array of characters and initialized with value "Hello" and " World" respectively. Step 2: printf("%s\n", strcpy(str2, strcat(str1, str2))); => strcat(str1, str2)) it append the string str2 to str1. The result will be stored in str1. Therefore str1 contains "Hello World". => strcpy(str2, "Hello World") it copies the "Hello World" to the variablestr2. Hence it prints "Hello World". Question 23 Point out the error in the program int i; #if A printf("enter any number:"); scanf("%d", &i); #elif B printf("the number is odd"); A. Error: unexpected end of file because there is no matching #endif B. The number is odd

13 C. Garbage values D. None of above Ans. A The conditional macro #if must have an #endif. In this program there is no#endif statement written. Question 24 Point out the error in the program #define SI(p, n, r) float si; si=p*n*r/100; float p=2500, r=3.5; int n=3; SI(p, n, r); SI(1500, 2, 2.5); A B. Nothing will print C. Error: Multiple declaration of si D. Garbage values Ans. C The macro #define SI(p, n, r) float si; si=p*n*r/100; contains the error. To remove this error, we have to modify this macro to #define SI(p,n,r) p*n*r/100

14 Question 25 What will be the output of the program? float d=2.25; printf("%e,", d); printf("%f,", d); printf("%g,", d); printf("%lf", d); A. 2.2, 2.50, 2.50, 2.5 B. 2.2e, 2.25f, 2.00, 2.25 C e+000, , 2.25, D. error Ans. C printf("%e,", d); Here '%e' specifies the "Scientific Notation" format. So, it prints the 2.25 as e+000. printf("%f,", d); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 2.25 as printf("%g,", d); Here '%g' "Use the shorter of %e or %f". So, it prints the 2.25 as printf("%lf,", d); Here '%lf' specifies the "Long Double" format. So, it prints the 2.25 as Question 26 What will be the output of the program?

15 float n=1.54; printf("%f, %f\n", ceil(n), floor(n)); A , B , C , D , Ans. A ceil(x) round up the given value. It finds the smallest integer not < x. floor(x) round down the given value. It finds the smallest integer not > x. printf("%f, %f\n", ceil(n), floor(n)); In this line ceil(1.54) round up the 1.54 to 2 and floor(1.54) round down the 1.54 to 1. In the printf("%f, %f\n", ceil(n), floor(n)); statement, the format specifier "%f %f" tells output to be float value. Hence it prints and Question 27 What will be the output of the program? float a=0.7; if(a < 0.7f) printf("c\n"); else printf("c++\n"); A. C B. C++

16 C. Compiler error D. Non of above if(a < 0.7f) here a is a float variable and 0.7f is a float constant. The float variable a is not less than 0.7f float constant. But both are equal. Hence the ifcondition is failed and it goes to else it prints 'C++' Question 28 What will be the output of the program? float f=43.20; printf("%e, ", f); printf("%f, ", f); printf("%g", f); A e+01, , 43.2 B. 4.3, 43.22, C. 4.3e, 43.20f, D. Error Ans. A printf("%e, ", f); Here '%e' specifies the "Scientific Notation" format. So, it prints the as e+01. printf("%f, ", f); Here '%f' specifies the "Decimal Floating Point" format. So, it prints

17 the as printf("%g, ", f); Here '%g' "Use the shorter of %e or %f". So, it prints the as Question 29 If the size of an integer is 4 bytes, What will be the output of the program? printf("%d\n", strlen("123456")); A. 6 B. 12 C. 7 D. 2 Ans. A The function strlen returns the number of characters int the given string. Therefore, strlen("123456") contains 6 characters. The output of the program is "6". Question 30 What will be the output of the program?

18 int arr[5], i=0; while(i<5) arr[i]=++i; for(i=0; i<5; i++) printf("%d, ", arr[i]); A. 1, 2, 3, 4, 5, B. Garbage value, 1, 2, 3, 4, C. 0, 1, 2, 3, 4, D. 2, 3, 4, 5, 6, Since C is a compiler dependent language, it may give different outputs at different platforms. We have given the TurboC Compiler (Windows) output. Please try the above programs in Windows (Turbo-C Compiler) and Linux (GCC Compiler), you will understand the difference better.