Cumulative Review Problems Packet # 1
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1 April 15, 009 Cumulative Review Problems Packet #1 page 1 Cumulative Review Problems Packet # 1 This set of review problems will help you prepare for the cumulative test on Friday, April 17. The test will cover the whole course up to the end of the Polynomials unit. For a review outline, see this web page: Here are the directions that will appear on the test. Look them over now. Directions: Time limit: 50 minutes (ecept for those with an individualized plan that says differently). The test has 8 questions that count for 4 points each, so 3 points in total. Graphing calculators are needed for some problems. Show your work. The more you write, the more opportunities you have for partial credit. For all grids shown on this test, the lines are 1 unit apart from each other. Any non-whole numbers may be written as fractions or decimals (if you round off, keep three decimal places). Many calculator difficulties can be fied by doing a reset. Ask your teacher if you don t know how to do it. Resetting is the only calculator help that teachers will give during the test. Don t give up early, work for the full time allowed. If you finish early, check your answers. Your teachers all say: We know you can do it! Practice Problems: 1. Find an equation for each of the lines described below. 1 a. line with a slope of! and passing through the point (, 6) b. line passing through the points (1, 5) and (7, 3) c. line perpendicular to the line y = 4 and passing through (3, 1) d. vertical line passing through (, 5)
2 April 15, 009 Cumulative Review Problems Packet #1 page. a. Fill in the missing output values in these tables, given that f() is a linear function and g() is a quadratic function. b. Write a function formula for the linear function f(). f() g() a. Solve the inequality 5 < b. Graph the solution on the number line below Solve the system of equations + 3y = 14, 4y = 15 by two different methods. a. using the substitution method
3 April 15, 009 Cumulative Review Problems Packet #1 page 3 b. using the elimination method (linear combination method)
4 April 15, 009 Cumulative Review Problems Packet #1 page 4 5. Evaluate and simplify as much as possible, without using your calculator. You must show your steps. a. ( ) 4 3 b. ( )! Simplify these epressions as much as possible. Your answer should have no negative eponents.! 4 a.! 3 b. ( ) 0 c. In each row below, two of the epressions are equal. Circle the equal epressions. An eample is shown. Eample: i ii iii. 1 ( ) iv. ( )
5 April 15, 009 Cumulative Review Problems Packet #1 page 5 7. Multiply ( 5) ( ). Simplify your answer as much as possible. 8. a. Factor b. Using the factors you found in part a, solve the equation = 0. c. Solve the equation = 30.
6 April 15, 009 Cumulative Review Problems Packet #1 page 6 9. Answer these questions about the quadratic function f() = by non-calculator methods. (You can use the calculator to check your answers.) a. Find the y-intercept of f(). b. Find the zeros of f(). c. Find the verte of f(). d. On the grid, sketch the graph of f().
7 April 15, 009 Cumulative Review Problems Packet #1 page Frank and Georgia each have a Myspace account. This problem is about how many friends each of them has on Myspace. a. At the start of the year, Frank has 50 friends. Suppose that his number of friends increases by 10% every month. Let f() stand for how many friends Frank will have after months. Write a function formula for f() and write a NOW NEXT equation. f() = ; Net =, starting from b. At the start of the year, Georgia had 70 friends. Suppose that she gains 0 more friends each month. Let g() stand for how many friends Georgia will have after months. Write a function formula for g() and write a NOW NEXT equation. f() = ; Net =, starting from c. At the end of the year (that is, when = 1), who will have more Myspace friends, Frank or Georgia? Show calculations supporting your answer. 11. Each table below has either a linear function or an eponential function that fits it eactly. Write a y = equation and a NOW-NEXT description for each. a y y =. NEXT =, starting from. b y y =. NEXT =, starting from.
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