Lecture 5 / Chapter 6 (CPU Scheduling) Basic Concepts. Scheduling Criteria Scheduling Algorithms

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Operating System Lecture 5 / Chapter 6 (CPU Scheduling) Basic Concepts Scheduling Criteria Scheduling Algorithms

OS Process Review Multicore Programming Multithreading Models Thread Libraries Implicit Threading Threading Issues

Objectives To introduce CPU scheduling, which is the basis for multi-programmed operating systems. By switching the CPU among processes, the operating system can make the computer more productive. (In fact the kernel-level threads are being scheduled not the user-level threads) To describe various CPU-scheduling algorithms

Basic Concepts Maximum CPU utilization obtained with multiprogramming CPU I/O Burst Cycle Process execution consists of a cycle of CPU execution and I/O wait Start CPU burst followed by I/O burst CPU burst distribution is of main concern

Basic Concepts Scheduling of this kind is a fundamental operating-system function. Almost all computer resources are scheduled before use. The CPU is, of course, one of the primary computer resources. Thus, its scheduling is central to operating-system design. Process execution begins with a CPU burst. That is followed by an I/O burst, which is followed by another CPU burst, then another I/O burst, and so on. Eventually, the final CPU burst ends with a system request to terminate execution. CPU burst distribution is of main concern The durations of CPU bursts have been measured extensively. Although they vary greatly from process to process and from computer to computer, they tend to have a frequency curve similar.

CPU Scheduler Short-term scheduler selects from among the processes in ready queue, and allocates the CPU to one of them Queue may be ordered in various ways CPU scheduling decisions may take place when a process: 1. Switches from running to waiting state (result of an I/O request) 2. Switches from running to ready state (when an interrupt occurs) 3. Switches from waiting to ready (at completion of I/O) 4. Terminates Scheduling under 1 and 4 is non-preemptive (cooperative) All other scheduling is preemptive Consider access to shared data Consider preemption while in kernel mode Consider interrupts occurring during crucial OS activities

Dispatcher Another component involved in the CPU-scheduling function Dispatcher module gives control of the CPU to the process selected by the short-term scheduler; this involves: switching context switching to user mode jumping to the proper location in the user program to restart that program The dispatcher should be as fast as possible, since it is invoked during every process switch. Dispatch latency time it takes for the dispatcher to stop one process and start another running

Scheduling Criteria CPU utilization keep the CPU as busy as possible Throughput # of processes that complete their execution per time unit Turnaround time amount of time to execute a particular process (from start to complete finishing sum of waiting to get into memory, waiting in the ready queue, executing on the CPU, and doing I/O) Waiting time amount of time a process has been waiting in the ready queue (The CPU-scheduling algorithm does not affect the amount of time during which a process executes or does I/O.) Response time amount of time it takes from when a request was submitted until the first response is produced, not output (for time-sharing environment)

Scheduling Algorithm Optimization Criteria Max CPU utilization Max throughput Min turnaround time Min waiting time Min response time

First- Come, First-Served (FCFS) Scheduling Process Burst Time P 1 24 P 2 3 P 3 3 Suppose that the processes arrive in the order: P 1, P 2, P 3 The Gantt Chart for the schedule is: Non-preemptive process keeps the CPU until it releases the CPU, either by terminating or by requesting I/O Thus: particularly troublesome for time-sharing systems Waiting time for P 1 = 0; P 2 = 24; P 3 = 27 Average waiting time: (0 + 24 + 27)/3 = 17 P P P 1 2 3 0 24 27 30

FCFS Scheduling (Cont.) Suppose that the processes arrive in the order: P 2, P 3, P 1 The Gantt chart for the schedule is: There is a convoy effect as all P 2 P 3 P 1 the other processes wait for the one big process to get off the CPU. This effect results in lower CPU and device utilization than might be possible if the shorter processes were allowed to go first. 0 3 6 30 Waiting time for P 1 = 6; P 2 = 0 ; P 3 = 3 Average waiting time: (6 + 0 + 3)/3 = 3 Much better than previous case Convoy effect - short process behind long process Consider one CPU-bound and many I/O-bound processes

Shortest-Job-First (SJF) Scheduling Associate with each process the length of its next CPU burst Use these lengths to schedule the process with the shortest time SJF is optimal gives minimum average waiting time for a given set of processes The difficulty is knowing the length of the next CPU request Could ask the user

Example of SJF Processme Burst Time P 1 6 P 2 2.0 8 P 3 4.0 7 P 4 5.0 3 P 4 P 1 0 3 9 16 24 P 3 P 2 (P1+P2+P3+P4) Average waiting time = (3 + 16 + 9 + 0) / 4 = 7

Determining Length of Next CPU Burst The real difficulty with the SJF algorithm is knowing the length of the next CPU request. For long-term (job) scheduling in a batch system, we can use the process time limit that a user specifies when he submits the job. In this situation, users are motivated to estimate the process time limit accurately, since a lower value may mean faster response but too low a value will cause a time-limitexceeded error and require resubmission. SJF scheduling is used frequently in long-term scheduling.

Determining Length of Next CPU Burst Can only estimate the length should be similar to the previous one Then pick process with shortest predicted next CPU burst Can be done by using the length of previous CPU bursts, using exponential averaging 1. 2. 3. t n = actual length of n τ n+ 1 = predicted value for α, 0 α 1 th CPU burst the next CPU burst 4. Define : Commonly, α set to ½ Preemptive version called shortest-remaining-time-first

Example of Shortest-remaining-time-first Now we add the concepts of varying arrival times and preemption to the analysis ProcessAarri Arrival TimeT Burst Time P 1 0 8 P 2 1 4 P 3 2 9 P 4 3 5 Preemptive SJF Gantt Chart P 1 P 2 P 4 P 1 P 3 0 1 5 10 17 26 Average waiting time = [(10-1)+(1-1)+(17-2)+5-3)]/4 = 26/4 = 6.5 msec

Priority Scheduling A priority number (integer) is associated with each process The CPU is allocated to the process with the highest priority (smallest integer highest priority) Preemptive Nonpreemptive SJF is priority scheduling where priority is the inverse of predicted next CPU burst time Problem Starvation (indefinite blocking) low priority processes may never execute Solution Aging as time progresses increase the priority of the process

Priority Scheduling A major problem with priority scheduling algorithms is indefinite blocking, or starvation. A process that is ready to run but waiting for the CPU can be considered blocked. A priority scheduling algorithm can leave some low priority processes waiting indefinitely. In a heavily loaded computer system, a steady stream of higher-priority processes can prevent a low-priority process from ever getting the CPU. Generally, one of two things will happen. Either the process will eventually be run (at 2 A.M. Sunday, when the system is finally lightly loaded), or the computer system will eventually crash and lose all unfinished low-priority processes. (Rumor has it that when they shut down the IBM 7094 at MIT in 1973, they found a low-priority process that had been submitted in 1967 and had not yet been run.) Asolution to the problem of indefinite blockage of low-priority processes is aging. Aging involves gradually increasing the priority of processes that wait in the system for a long time.

Example of Priority Scheduling ProcessAarri Burst TimeT Priority P 1 10 3 P 2 1 1 P 3 2 4 P 4 1 5 P 5 5 2 Priority scheduling Gantt Chart Average waiting time = (6+0+16+18+1)/5 = 8.2 msec

Round Robin (RR) Each process gets a small unit of CPU time (time quantum q), usually 10-100 milliseconds. After this time has elapsed, the process is preempted and added to the end of the ready queue. If there are n processes in the ready queue and the time quantum is q, then each process gets 1/n of the CPU time in chunks of at most q time units at once. No process waits more than (n-1)q time units. Timer interrupts every quantum to schedule next process Performance q large FIFO q small q must be large with respect to context switch, otherwise overhead is too high

Example of RR with Time Quantum = 4 Process Burst Time The Gantt chart is: P 1 24 P 2 3 P 3 3 Waiting : (6+4+7)/ 3 = 5.66 msec P P 2 P 3 P 1 P 1 P 1 P P 1 1 1 0 4 7 10 14 18 22 26 30 Typically, higher average turnaround than SJF, but better response q should be large compared to context switch time q usually 10ms to 100ms, context switch < 10 usec (micro second)

Time Quantum and Context Switch Time

Multilevel Queue Ready queue is partitioned into separate queues, eg: foreground (interactive) background (batch) Process permanently in a given queue Each queue has its own scheduling algorithm: foreground RR background FCFS Scheduling must be done between the queues: Fixed priority scheduling; (i.e., serve all from foreground then from background). Possibility of starvation. Time slice each queue gets a certain amount of CPU time which it can schedule amongst its processes; i.e., 80% to foreground in RR 20% to background in FCFS

Multilevel Queue Scheduling

Multilevel Feedback Queue A process can move between the various queues; aging can be implemented this way Multilevel-feedback-queue scheduler defined by the following parameters: number of queues scheduling algorithms for each queue method used to determine when to upgrade a process method used to determine when to demote a process method used to determine which queue a process will enter when that process needs service

Example of Multilevel Feedback Queue Three queues: Q 0 RR with time quantum 8 milliseconds Q 1 RR time quantum 16 milliseconds Q 2 FCFS Scheduling A new job enters queue Q 0 which is served FCFS When it gains CPU, job receives 8 milliseconds If it does not finish in 8 milliseconds, job is moved to queue Q 1 At Q 1 job is again served FCFS and receives 16 additional milliseconds If it still does not complete, it is preempted and moved to queue Q 2

OS Next Lecture Chapter 5 Process Synchronization