Exam (june ) Estimated solving time (10 min) screen shot :- to download the open source click the next url :

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1 Exam (june ) Estimated solving time (10 min) screen shot :- to download the open source click the next url : Page 1

2 code : #include <cstdlib> #include <iostream> using namespace std; struct age_struct int years; int months; int weeks; int days; ; long age_by_days(age_struct); int main(int argc, char *argv[]) char scape; do age_struct newage; cout<<"years :"; cin>>newage.years; cout<<"months :"; cin>>newage.months; cout<<"weeks :"; cin>>newage.weeks; cout<<"days :"; cin>>newage.days; long days = age_by_days(newage); cout<<"your age by days = "<<days<<endl; cout<<"do you want to enter new age"<<endl; cout<<"enter y for new age or any key to exit"<<endl; cout<<"your choice :"; cin>>scape; while(scape =='y' scape=='y'); system("pause"); return EXIT_SUCCESS; long age_by_days(age_struct myage) static int count =0; count++; cout<<"i have been called for "<<count<<" time(s)"<<endl; long days =0; days += myage.years * 365; days += myage.months * 30; days += myage.weeks * 7; days += myage.days; return days; Page 2

3 estimated solving time (5 min) screenshot :- Page 3

4 code : #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) for(int l=1;l <= 4;l++) for(int sp=0;sp<-l+4;sp++) cout<<" "; for(int st=0;st<2*l-1;st++) cout<<"*"; cout<<endl; for(int l=1;l<=3;l++) for(int sp=0;sp<l;sp++) cout<<" "; for(int st=0;st<-2*l+7;st++) cout<<"*"; cout<<endl; system("pause"); return EXIT_SUCCESS; Page 4

5 Estimated solving time (10 min) screenshot :- Page 5

6 code : #include <cstdlib> #include <iostream> using namespace std; long factorial(long); long myfact =1; int main(int argc, char *argv[]) long x=0; char scape; do do cout<<"x ="; cin>>x; while(x <0); if(x==0) cout<<"!"<<x<<" =1"<<endl; else cout<<"!"<<x<<" ="; long f=factorial(x); cout<<"="<<f; myfact =1; cout<<endl<<"do you want to perform new progress"<<endl; cout<<"for new one enter y or any key to exit"<<endl; cout<<"your choice :"; cin>>scape; while(scape =='y' scape=='y'); system("pause"); return EXIT_SUCCESS; long factorial(long x) cout<<x; if(x>1) myfact *=(x--); cout<<"*"; factorial(x); return myfact; Page 6

7 estimated solving time (5 min) screenshot :- code :- for(int o=0;o<4;o++) for(int i=0;i<4;i++) if((o+i)== 3 o==i) sum += x[o][i]; Page 7

8 estimated time (5 min) code :- int m,n,x; cin>>m>>n>>x; switch(x) case 1: case 2: case 3: default: cout<<m-n; break; cout<<m-n; break; cout<<m+n; break; cout<<m*n; Page 8

9 Exam June 2012 Screenshot :- estimated time (10 min) Page 9

10 code :- #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) const int s_count=5; const int g_count=5; int students[s_count][g_count]; for(int s=0;s<s_count;s++) cout<<"enter Grades of Studnet no :"<<s+1<<endl; //clear the total element students[s][4] =0; for(int g=0;g<g_count-1;g++) //be sure that the grade between 0 and 100 do cout<<"subject "<<g+1<<" : "; cin>>students[s][g]; while(students[s][g] >100 students[s][g] <0); students[s][4] +=students[s][g]; cout<<"total grades :"<<students[s][4]<<endl; cout<<"grades average :"<<students[s][4]/4<<endl; cout<<endl; system("pause"); return EXIT_SUCCESS; Page 10

11 Exam Jan 2010 estimated time (5 min) Screenshot :- Page 11

12 Code : #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int x[5][4]; for(int i=0;i<5;i++) for(int j=0;j<4;j++) cout<<"value of "<<i<<" : "<<j<<" = "; cin>>x[i][j]; cout<<endl; int sum =0; for(int i=0;i<5;i++) for(int j=0;j<4;j++) if(i==2 j==2) sum += x[i][j]; cout<<endl; cout<<"sum of selected elements = "<<sum<<endl; system("pause"); return EXIT_SUCCESS; Page 12

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14 Code : #include <cstdlib> #include <iostream> using namespace std; bool iseven(int); int main(int argc, char *argv[]) int arr[10]; char scape; do for(int i=0;i<10;i++) cout<<"number "<<i+1<<" = "; cin>>arr[i]; if(iseven(arr[i])) cout<<"the number "<<arr[i]<<" is even"<<endl; cout<<"do you want to try it again?"<<endl; cout<<"for new progress enter y or any key to exit"<<endl; cout<<"your choice :"; cin>>scape; while(scape == 'y' scape =='Y'); system("pause"); return EXIT_SUCCESS; bool iseven(int num) if(num % 2==0) return true; else return false; Page 14

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16 Code :- #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int item_id =0; char scape; do cout<<"enter Item ID from 1,4"<<endl; cout<<"you selected :"; cin>>item_id; switch(item_id) case 1: cout<<"the price 100"<<endl; break; case 2: cout<<"the price 200"<<endl; break; case 3: cout<<"the price 600"<<endl; break; case 4: cout<<"the price 150"<<endl; break; default : cout<<"invalid Item ID"<<endl; cout<<"do you want to perform new search?"<<endl; cout<<"for new progress enter y or any key to exit"<<endl; cout<<"your choice :"; cin>>scape; while(scape =='y' scape =='Y'); system("pause"); return EXIT_SUCCESS; Page 16

17 estimated time (20~30 min) Screenshot : Page 17

18 Code recursive function :- #include <cstdlib> #include <iostream> using namespace std; /*argumenet details 1-int arr[] the array 2-int* pointer for how many times the target number has been found 3-int the target number which will be searched for in the passed array 4-int index for recursive function which will tell the function when it has to stopped 5-int last index the target number has been found on 6-last argumenet which tells the function the size of the array */ void location_of_target(int arr[],int*,int,int,int*,int); int main(int argc, char *argv[]) const int arr_size = 7; int arr[arr_size]; int target_num =0; for(int i=0;i<arr_size;i++) cout<<"enter Number "<<i+1<<" = "; cin>>arr[i]; cout<<endl<<"enter the Target Number ="; cin>>target_num; int count =0; int res =-1; location_of_target(arr,&count,target_num,0,&res,arr_size); if(res!= -1) cout<<"the number : "<<target_num<<" found "<<count<<" times and lat (largest) index was: "<<res<<endl; else cout<<"the number : "<<target_num<<" does not exist in the passed array"<<endl; system("pause"); return EXIT_SUCCESS; void location_of_target(int arr[],int* count,int target,int index,int* last_index,int size) if(index <size) if(arr[index] == target) *count = *count+1; *last_index = index; index++; location_of_target(arr,count,target,index,last_index,size); Page 18

19 code (2) : #include <cstdlib> #include <iostream> using namespace std; /*arguement details 1-int [] the passed array 2-int* pointer for the count how many times the target number found 3-int the target number 4-the size of array*/ int location_of_target(int[],int*,int,int); int main(int argc, char *argv[]) const int size =7; int arr[size]; int count =0; int target_num; for(int i =0;i< size;i++) cout<<"number "<<i+1<<" = "; cin>>arr[i]; cout<<"target Number ="; cin>>target_num; int res = location_of_target(arr,&count,target_num,size); if(res!= -1) cout<<"the number : "<<target_num<<" found "<<count<<" times and lat (largest) index was: "<<res<<endl; else cout<<"the number : "<<target_num<<" does not exist in the passed array"<<endl; return 0; int location_of_target(int arr[],int* count,int target_num,int size) static int last_index =-1; for(int i=0;i< size;i++) if(arr[i] == target_num) *count = *count +1; last_index =i; return last_index; Page 19

20 Exam june 2007 Estimated time (15~20 min) screenshot Page 20

21 code (2) #include <cstdlib> #include <iostream> using namespace std; int fib(int); int main(int argc, char *argv[]) int max=0; cout<<"enter your last elemet of fibonacci series"<<endl; cout<<"last element :"; cin>>max; for(int i=0;i<=max;i++) cout<<fib(i)<<" "; cout<<endl; system("pause"); return EXIT_SUCCESS; int fib(int n) if(n==1 n==0) return n; else return fib(n-1)+fib(n-2); Page 21

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23 code :- #include <cstdlib> #include <iostream> using namespace std; void reverser(char*); void copy_reverser(char*,char*); int main(int argc, char *argv[]) const int size =20; char word[size]; char word_copy[size]; char scape; do cout<<"enter your word :"; cin>>word; copy_reverser(word,word_copy); cout<<"the Original String :"<<word<<endl; cout<<"the Revered Copy :"<<word_copy<<endl; reverser(word); cout<<"the Original Reversed String :"<<word<<endl; cout<<endl<<"do you want to enter new word?"<<endl; cout<<"for new word enter y or any key to exit"<<endl; cout<<"your choice :"; cin>>scape; while(scape == 'y' scape =='Y'); return (0); void reverser(char* ptr) for(;*ptr!='\0';ptr++) for(char* ptr2=ptr+1;*ptr2!= '\0';ptr2++) char temp = *ptr2; *ptr2 = *ptr; *ptr = temp; void copy_reverser(char *ptr,char* copy) int size=0; for(;*ptr!='\0';ptr++,copy++) *copy = *ptr; size++; *copy='\0'; copy -=size; for(;*copy!='\0';copy++) for(char* ptr2=copy+1;*ptr2!= '\0';ptr2++) char temp = *ptr2; *ptr2 = *copy; *copy = temp; Page 23

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25 code : #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int a,b,c,d=0;int a1,b1=0; char dummy_opera1,dummy_opera2;char operation; char scape; do cout<<"enter your Operation like"<<endl; cout<<"\t a \t \t b"<<endl; cout<<"\t \toperator\t"<<endl; cout<<"\t-----\t \t-----"<<endl; cout<<"\t b\t \t d"<<endl; cout<<"the Operation :"; cin>>a>>dummy_opera1>>b>>operation>>c>>dummy_opera2>>d; switch(operation) case '+': a1 = (a*d)+(b*c); b1=(b*d); break; case'-': a1=(a*d)-(b*c); b1=(b*d); break; case'*': a1=(a*c); b1=(b*d); break; case '/': a1=a*d; b1=b*c; break; default: cout<<"invalid operator"<<endl; cout<<"you entered :"<<endl; cout<<"\t "<<a<<" \t \t "<<c<<"\t\t "<<a1<<endl; cout<<"\t \t "<<operation<<endl; cout<<"\t-----\t \t-----\t=\t----"<<endl; cout<<"\t "<<b<<"\t \t "<<d<<"\t\t "<<b1<<endl; cout<<endl<<"do you want to perform new calculation?"<<endl; cout<<"for new calculation enter y or any key to exit"<<endl; cout<<"your choice:"; cin>>scape; while(scape =='y' scape=='y'); system("pause");return EXIT_SUCCESS; Page 25

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27 Code :- #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) const int size=20; int num,first_index,last_index,count =0; int arr[size]; for(int i=0;i<size;i++) cout<<"number "<<i+1<<" = "; cin>>arr[i]; //start sorting the array for(int i=0;i<size;i++) //bool issorted = true; for(int n=i+1;n<size;n++) if(arr[i] > arr[n]) //issorted = false; int temp = arr[i]; arr[i] = arr[n]; arr[n] = temp; /*if(issorted) break; */ cout<<endl<<"your array sorted ascending"<<endl; cout<<"do you want to extract your sorted array?"<<endl; char dic; cout<<"enter y for extracting your sorted array or any key to continue"<<endl; cout<<"your choice :"; cin>>dic; if(dic =='y' dic=='y') for(int i=0;i<size;i++) if(i % 10!=0) cout<<arr[i]<<" "; else cout<<endl<<arr[i]<<" "; Page 27

28 char scape; do cout<<"search for :"; cin>>num; first_index =0; last_index =0; count =0; for(int i=0;i<size;i++) if(num >= arr[i]) if(num == arr[i]) if(count ==0) first_index =i; else last_index =i; count++; else break; if(count > 0) cout<<"your number ("<<num<<") is found "<<count<<" times"<<endl; cout<<"first time was at "<<first_index<<" and last time was at "<<last_index<<endl; else cout<<"the entered element is not found"<<endl; cout<<"do you want to peform a new search?"<<endl; cout<<"for new search enter y or any key to exit"<<endl; cout<<"your choice :"; cin>>scape; while(scape =='y' scape=='y'); system("pause"); return EXIT_SUCCESS; Page 28

29 Extra Practice :- 1)Write a full program (starting from #include) that counts the number of character doubles in a phrase entered by the user. The output should look like the example below. Note there are 3 character doubles in this example input: "bb", "oo", and "!!" Enter phrase: Hobbits love cookies!! There are 3 character doubles. You do not have to worry about detecting upper vs. lower-case letters, nor do you have to handle the case when a character occurs three times or more in a row ) Write a program (starting from #include) that repeatedly collects positive integers from the user, stopping when the user enters a negative number or zero. After that, output the product of all positive entries. A sample run should appear on the screen like the text below. Enter a number: 3 Enter a number: 10 Enter a number: 2 Enter a number: -213 The product of all your positive numbers is ) Write a full program (starting from #include) that reads in an input phrase and removes all occurrences of the word "the" (all lower-case). You do not need to worry about words that contain the letters in "the", such as the word "theory". Page 29

30 A sample run is shown below. Enter a phrase: The light of the moon on the ring by the volcano. The light of moon on ring by volcano ) In Old English, the letter "s" was stylized so that it looked more like the letter "f". Write a program (starting from #include) that takes an input phrase from the user and changes every s to an f. Your result should preserve case, so that a lower-cases becomes f and a capital S becomes F. Furthermore, report the total number of letters you changed. Your program should make only one pass through the input phrase. A sample run is shown below. Enter your phrase: Some say Samwise is short for a hobbit. In Old English: Fome fay Famwife is fhort for a hobbit. Changed 5 letters )Create the equivalent of a four-function calculator. The program should ask the user to enter a number, an operator, and another number. (Use floating point.) It should then carry out the specified arithmetical operation: adding, subtracting, multiplying, or dividing the two numbers. Use a switch statement to select the operation. Finally, display the result. When it finishes the calculation, the program should ask whether the user wants to do another calculation. The response can be y or n. Some sample interaction with the program might look like this: Enter first number, operator, and second number: 10 / 3 Answer = Do another (y/n)? y )Write a C++ program that accepts a number and displays its factorial (factorial (x)=(x-1)*(x- 2)*(x-3) *3*2*1). Interaction with the program might look like this: Enter a number: 5 Page 30

31 The factorial is: )Write a program that counts the words with size greater than two characters and the number of all characters (ignore spaces) in a phrase typed in by the user. The program accepts the phrase character by character using the function getche() until press the enter key. Interaction with the program might look like this: Enter the text: welcome to c++ Count of words is: 2 Count of characters is: )Write a program that accepts an array of string then copies that string in another array in a reverse order. Then display both of the original string and its reverse. For example, if you entered "hallo" in the first array, the program will reverse it to be "ollah" in the second array 9) write an a program that accepts 100 decimal number then compute the average of the entered numbers. Attempt to put the numbers less than the average in another array lessavg[] and the numbers greater than the average in a third array greateravg[]. Finally, display the two averages of the numbers in both of lessavg[] and greateravg[] ) An integer is said to be prime if it is divisible by only 1 and itself. For example, 2, 3 and 5 are prime, but 4, 6 and 8 are not. Response to the following requirements: a) Write a function that determines whether a number is prime. b) Use this function in a program to determine and print all the prime numbers between 1 and ) Raising a number n to a power p is the same as multiplying n by itself p times. Write a function called power() that takes a double value for n and an int value for p, and returns the result as a double value. Use a default argument of 2 for p, so that if this argument is omitted, Page 31

32 the number n will be squared. Write a main() function that gets values from the user to test this function ) Write a function multiple that determines for a pair of integers whether the second integer is a multiple of the first. The function should take two integer arguments and return true if the second is a multiple of the first, false otherwise. Use this function in a program that inputs a series of pairs of integers ) Write a function called swap() that interchanges two int values passed to it by the calling program. (Note that this function swaps the values of the variables in the calling program, not those in the function.) You ll need to decide how to pass the arguments. Create a main() program to exercise the function )Write a program that accepts array of 10 integers and print to as a reversed array so, the reversed one will have the first in reverse. get the average for the even numbers )Write a C++ program that displays a menu for the user: Enter a number x and display it's square Enter a number x check if it is greater than or less than or equal to 1 Enter number x and check if it is multiple of 7 or not )Write a program that calculate the following S= n )Write a program that calculate the following sequence Page 32

33 S= n )Write a program that asks the user to enter an array of 10 integers. The program must count the number of integers greater or equal to 10 and compute their summation and average )Write a program that asks the user to enter an array of 10 integers. The program must count the number of integers that are divisible by5 and compute their summation and average ) Write a program that sorts the array s elements in an ascending order ) Convert the following code by using for loop and switch statement : int x; cin >> x; do if(x % 2 == 0) cout << 2 << endl; else if (x % 3 == 0) cout << 3 << endl; else if(x % 4 == 0) cout << 4 << endl; else cout << "unknown"; while(++x <= 30); Page 33

34 2-OutPut Practice : # include <iostream.h> int main() int x[4] = 4,3, 2 ; int* ptr; ptr=x; for(int j=0; j<4; j++) cout << " " <<++*(x+j) * x[j] << endl; return 0; #include<iostream.h> void sp(float* j,float* i, int* count) static int c=0; float n; c++; *count=c; n=*j*2; *j=*i*2; *i=n; int main() float x=5, y=10; char ch; int c; sp(&x, &y, &c); cout<<"\n x and y become : "<<x<<" and " <<y; cout<<"\n the value of c is: "<<c; sp(&x,&y, &c); cout<<"\n x and y become : "<<x<<" and " <<y; cout<<"\n the value of c is: "<<c; return 0; #include <iostream.h> #include <cstring> int main() char str1[] = "Good luck"; int MAX = strlen(str1); char str2[100]; for(int j=1; j<=max; j++) str2[max-j] = str1[j-1]; str2[max]='\0'; cout << str2 << endl; return 0; #include<iostream.h> int main() int x =8; do x+=2; cout<<"\n "<<x; while(x<20); return 0; #include<iostream.h> int main() int x=3, y=2, z=1; bool b, c=0; b=x<y==++z>y; cout<<"\n "<<b; b=z<-1==x++>--y; cout<<"\t "<<b; c= 100*-30/2; cout<<"\t "<<c; x=++x+x--; cout<<"\t "<<x; return 0; #include<iostream.h> void repchar() for(int j=0; j<4; j++) cout << '*'; cout << endl; void repchar(char ch) for(int j=0; j<4; j++) cout << ch; cout << endl; void repchar(char ch, int n) for(int j=0; j<n; j++) cout << ch; cout << endl; int main() repchar(); repchar('+',7); repchar('='); return 0; hint(overloading) Page 34

35 char y = 'a'; int x = 30; int z = 10; y = y + (x++ % z) +3 ; cout<<x++; cout<<++y<<endl; z = x z; z = z++ * ++x; cout<<z<<endl; #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) char ch; char title[] = "Titanic"; ch = title[1]; title[3] = ch; cout << title << endl; cout << ch << endl; return 0; #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int n; float x = 3.8; n = int(x); cout << "n = " << n << endl; return 0; #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int i = 5, j = 6, k = 7, n = 3; cout << i + j * k - k % n << endl; cout << i / n << endl; int found = 0, count = 5; if (!found --count == 0) cout << "danger" << endl; cout << "count = " << count << endl; return 0; #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) const int LENGTH = 21; char message[length]; cout << "Enter a sentence on the line below." << endl; cin >> message; cout << message << endl; /* Suppose that in response to the prompt, the interactive user types the following line and presses Enter: Please go away. What will the output of the code fragment look like?*/ return 0; #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int x=1, y=2; x++; x+=2; x%=3; y*=2; y/=2; if( ( y < x ) ( x >= 3) ) cout <<y; else cout <<x; return 0; Page 35

36 True or false An array can store many different types of values If three are fewer initializers than the number of elements in the array, the remaining elements are automatically initialized to the last value in the list of initializers "\n " Position the screen cursor to the beginning of the current line "\a " Position the screen cursor to the beginning of the new line When arguments are passed by value, the function works with the original arguments in the calling program Data items in a structure are public by default (False) (False) (False) (False) (False) (True) Page 36

37 Choices : 1. Answer the following multiple-choice questions: I. How many times is a do while loop guaranteed to loop? II. III. A. 0 B. Infinitely C. 1 D. Variable What is required to avoid falling through from one case to the next? A. end; B. break; C. Stop; D. A semicolon. What keyword covers unhandled possibilities in a switch statement? A. all B. contingency C. default D. other IV. What is the final value of x when the code int x; for(x=1; x<10; x+=2.7) is run? A. 10 B. 9 C. 0 D. 11 V. The library function exit() causes an exit from A. the loop in which it occurs. B. the block in which it occurs. c. the program in which it occurs. VI. A variable defined within a block is visible A. from the point of definition onward in the program. B. from the point of definition onward in the function. C. from the point of definition onward in the block. D. throughout the function. VII. Assuming a nested loop with a switch statement in the inner loop, a break statement in a switch case causes an exit : A. only from the innermost loop. B. only from the switch statement. c. from all loops and switches. d. from the innermost loop or switch. VIII. How many times the loop body will be executed when running the code for(;;)? A. 0 B. 1 C. Infinitely D. Variable Page 37

38 shapes :- 1- Code : #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) for(int l=1;l<=6;l++) int r_astrisk_cond=7-l; int l_astrisk_cond=7-l; int mid_space_cond=2*l-2; for(;r_astrisk_cond>0;r_astrisk_cond--) cout<<"*"; for(;mid_space_cond >0;mid_space_cond--) cout<<" "; for(;l_astrisk_cond>0;l_astrisk_cond--) cout<<"*"; cout<<endl; system("pause"); return EXIT_SUCCESS; Page 38

39 2- Write a program to solve this shape by coding code : #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int i=1; for(int l=1;l<=5;l++,i+=2) for(int n=0;n<11-2*l;n++) cout<<i; cout<<endl; system("pause"); return EXIT_SUCCESS; Page 39

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41 code : #include <cstdlib> #include <iostream> using namespace std; int main(int argc, char *argv[]) int choice = 0; do cout<<"if you want to exit press 0."<<endl; cout<<"please select shape from 1-4."<<endl; cin>>choice; switch (choice) case 1: for(int line =1;line <=10;line++) for(int star=1;star <= 1+(line -1)*1;star++) cout<<"*"; cout<<endl; break; case 2: for(int line =1;line <= 10;line++) for(int star = 1;star <= 10+(line-1)*-1;star++) cout<<"*"; cout<<endl; break; case 3: for(int line=1;line<=10;line++) for(int space =1;space <= 0+(line-1)*1;space++) cout<<" "; for(int star =1;star <= 10+(line -1)*-1;star++) Page 41

42 cout<<"*"; cout<<endl; break; case 4: for(int line =1;line<=10;line++) for(int space=1;space <= 9+(line-1)*-1;space++) cout<<" "; for(int star=1;star<=1+(line-1)*1;star++) cout<<"*"; cout<<endl; default: cout<<"please insert correct choice between 1-4"; while(choice!=0); system("pause"); return EXIT_SUCCESS; نسأ لمك صاحل ادلعاء Page 42