State your dream system (use the following materials, if you need) Alliance model character year character 4. A/T description character 51

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1 Final Project report State your dream system (use the following materials, if you need) 1. Meta Data Table Example Fields Type length Alliance model character year character 4 A/T description character litres character 4 L4 engine type character 3 85 cubic inches character 6 Rlink number 4 Table 1 The metadata of radcrx.txt is in Table 2; you should join it with Table 1(for all makers) over Modine parts Type part# Rlink Number 4 A.R.S NS Standard (radiator) 3 characters NS heavy duty 3 characters NS air condition 3 characters NS maximum 3 characters Modine NS Standard (radiator) 3 characters NS heavy duty 3 characters NS air condition 3 characters NS maximum 3 characters Behr NS Standard (radiator) 3 characters NS heavy duty 3 characters

2 NS air condition 3 characters NS maximum 3 characters Daniel NS Standard (radiator) 3 characters NS heavy duty 3 characters NS air condition 3 characters NS maximum 3 characters Table 2 MNO MAK COD 01 AMERICAN MOTORS OR AMC AMC 02 AUDI AUD 03 BMW BMW 04 BUICK BUK 05 CADILLAC CAD 06 CHEVROLET CHE 07 CHRYSLER CRY 08 DODGE DOD 09 DODGE/PLYMOUTH LITE TRK & VAN DOT 10 FORD LIGHT TRUCK AND VAN FDT 11 FORD MEDIUM AND HEAVY TRUCK FDM 12 FIAT FIA 13 FORD FOR 14 CHEVROLET & GMC TRUCK & VAN GMC 15 HONDA HON 16 INTERNATIONAL TRUCK (I.H.C.) INT 17 ISUZU ISU 18 LINCOLN LIN 19 MERCEDES MCS 20 MITSUBISHI MIT 21 MERCURY MRY 22 MAZDA MZD 23 NISSAN / DATSUN NIS 24 OLDSMOBILE OLD 25 PLYMOUTH PLY 26 PORSCHE POR 27 PONTIAC PON 28 RENAULT REN

3 29 SAAB SAB 30 SUBARU SUB 31 TOYOTA TOY 32 UPS UPS 33 VOLKSWAGEN VOL 34 HYUNDAI HUN 35 YUGO YUG 36 GMC TRUCK AND VAN GMM CREATE TABLE RDIMARS (P_NUMBER VARCHAR2(6) NOT NULL, CORE VARCHAR2(32), INHEAD VARCHAR2(17), OUTHEAD VARCHAR2(17), INCON VARCHAR2(14), OUCON VARCHAR2(14), TMOUNT VARCHAR2(24), OILCOOL VARCHAR2(10), PRICE NUMBER(8, 2), AMOUNT NUMBER(10), PRIMARY KEY (P_NUMBER)); You have similar data RDIMOD RDIBEH RDIDAN

4 Part II 1 10 pts pts 3 10 pts 4 30 pts Get manager Lname which has at least one employee who is working on project number 1, or 2 Get LNAME of each employee whose salary more than $ Write a SQL to detect the functional dependency from manager s salary to average salary of the employees (in the department). Use DB2: Write a SQL (in paper) to do the following: For each part time worker (5 pts) find all full time co-worker (5 pts)s; here co-worker means having worked together in at least one project. For every worker please give his ssn and last name

5 CS157A Final Exam (12/18/2012) Name (last name first) then hyphen with Class id II 1 10 pts pts 3 10 pts 4 30 pts Get manager Lname which has at least one employee who is working on project number 1, or 2 Get LNAME of each employee whose salary more than $ Write a SQL to detect the functional dependency from manager s salary to average salary of the employees (in the department). Use DB2: Write a SQL (in paper) to do the following: For each part time worker (5 pts) find all full time co-worker (5 pts)s; here co-worker means having worked together in at least one project. For every worker please give his ssn and last name

6 I. Multiple Choices (2 points) 1 Which of the following SQL represents the notation STUDIONAME ='LUCAS FILMS' AND YEAR = 1980 ( TITLE,LENGTH (MOVIE)) A B C D E SELECT title, length FROM MOVIES WHERE STUDIONAME ='LUCAS FILMS' AND YEAR = 1980; SELECT * FROM (SELECT STUDIONAME, YEAR FROM MOVIES ) WHERE STUDIONAME ='LUCAS FILMS' AND YEAR = 1980; BOTH ARE CORRECT BOTH ARE INCORRECT NONE OF THE ABOVE 2 Which of the following SQL will have the same out puts TITLE,LENGTH ( STUDIONAME ='LUCAS FILMS' AND YEAR = 1980 (MOVIE)) A B C SELECT title, length FROM MOVIES WHERE STUDIONAME ='LUCAS FILMS' AND YEAR = 1980; SELECT title, length FROM ( SELECT * FROM Movies WHERE studioname = 'LUCAS FILMS' AND year = 1990); BOTH ARE CORRECT D* BOTH ARE INCORRECT E NONE OF THE ABOVE 3 SELECT * FROM MovieStar, MovieExec WHERE MovieStar.address = MovieExec.address Select appropriate relational operator for the SQL given above A Projection B Selection C Natural Join D Eqi Join E Cartesian Product A Union B Intersect C Minus 4. SELECT cert# FROM MovieExec INTERSECT SELECT producerc# FROM Movies WHERE(title,year) IN

7 The output are CERT# (SELECT movietitle, movieyear FROM StarsIn WHERE starname = 'LEONARDO DICAPRIO' ) ; A B TRUE FAlSE 5.(DB3) To retrieves title of the movies whose length is unknown Which of the following SQL is correct a) SELECT Title FROM Movies WHERE length is null; b) SELECT Title FROM Movies WHERE length = null; c) SELECT Title FROM Movies WHERE length = 0; d) None of the above 6. (DB3) SELECT name FROM MovieExec WHERE cert# in (SELECT producerc# FROM Movies WHERE title NOT IN (SELECT movietitle FROM StarsIN WHERE starname = 'SAMUEL HENRY') ); Who should be NOT in the output: NAME a) JAMES CAMERON b) DANNY BOYLE c) Darren Aronofsky d) CATHERINE WINDER e) None of the above 7 (DB2) SELECT EMPLOYEE.LNAME FROM DEPARTMENT, EMPLOYEE WHERE DEPARTMENT.DNAME = 'ADMINISTRATION' AND EMPLOYEE.DNO = DEPARTMENT.DNUMBER ; (a) Smith Borg Jabbar Zelaya (b) Zelaya Wallace Jabbar Borg (c) Zelaya Wallace Jabbar (d) Zelaya Wallace ( e ) None of the above

8 8. SELECT COUNT (DISTINCT P.PNAME) FROM PARTS P WHERE 0 < (SELECT COUNT(*) FROM SHIPMENTS SP WHERE SP.PNUM=P.PNUM AND SP.SNUM='S2' ); USE MOD 5 : (a) MOD 1 (b) MOD 2 (c) MOD 3 (d) MOD 4 (e) MOD 5 9. (DB2) Get ssn & address of each employee who works with Jennifer Wallace on the same project. SELECT SSN, ADDRESS FROM WORKS_ON, EMPLOYEE WHERE WSSN = SSN AND PNO IN (SELECT PNO FROM WORKS_ON, EMPLOYEE WHERE WSSN = SSN AND LNAME = 'WALLACE' AND FNAME = 'JENNIFER'); The output is VOSS HOUSTON TX CASTLE SPRING TX BERRY BELLAIRE TX BERRY BELLAIRE TX DALLAS HOUSTON TX STONE HOUSTON TX (a) (b) True False 10. (DB2) Which of the following SQL will Get department name which has at least one employee who is working on project number 1, 2 or 30. (a) SELECT DNAME, PROJECT WHERE SSN=ESSN AND PNUMBER IN (1,2,30); (b) SELECT DNAME WHERE EXISTS (SELECT * FROM PROJECT WHERE SSN=WSSN AND PNUMBER IN (1,2,30)); (c) SELECT DNAME WHERE PNUMBER IN ( SELECT PNUMBER FROM PROJECT WHERE PNUMBER =1 OR PNUMBER =2 OR PNUMBER =3); (d) SELECT DISTINCT DNAME, DEPARTMENT WHERE EXISTS (SELECT * FROM WORKS_ON WHERE SSN=WSSN AND

9 PNO IN (1,2,30)); (e) None of the above 11 (DB3) SELECT COUNT (DISTINCT NAME) FROM MOVIEEXEC WHERE CERT# IN (SELECT PRODUCERC# FROM MOVIES WHERE TITLE = 'STAR''s WARS' AND PRODUCERC# > 950); USE MOD 5 : (a) MOD 1 (b) MOD 5 (c) MOD 3 (d) MOD 4 (e) NONE OF THE ABOVE 12. (DB2) SELECT DISTINCT COUNT(DISTINCT MGRSSN),DEPARTMENT GROUP BY SALARY HAVING COUNT(DISTINCT MGRSSN) >1; The output will be Use Mod 5: a ) 1, b) 2, c) 3, d) 4, e) none of the above 13(DB2) (a) (b) (c) List the Last names of employees who work on at least two projects. Which of the following are incorrect SELECT EMPLOYEE.LNAME WHERE 2 <= (SELECT COUNT(*) FROM WORKS_ON WHERE EMPLOYEE.SSN = WORKS_ON.WSSN) ; SELECT EMPLOYEE.LNAME, WORKS_ON WHERE EMPLOYEE.SSN = WORKS_ON.WSSN GROUP BY EMPLOYEE.LNAME, EMPLOYEE.FNAME Having COUNT(*) >=2; SELECT EMPLOYEE.LNAME, EMPLOYEE.FNAME WHERE SSN in (SELECT WSSN FROM WORKS_ON); (d) (e) All are correct None of the above 14 Get the last names of employees who have at least one son. (choose best answer) (a) (b) SELECT FNAME,LNAME FROM DEPENDENT, EMPLOYEE WHERE SSN=DEPSSN AND DEPENDENT.RELATIONSHIP = 'SON' ; SELECT FNAME, LNAME WHERE SSN IN ( SELECT DEPSSN FROM DEPENDENT

10 WHERE RELATIONSHIP = 'SON' ); (c) d) (e) (a) (b) SELECT FNAME,LNAME WHERE EXISTS( SELECT * FROM DEPENDENT WHERE SSN=DEPSSN AND RELATIONSHIP = 'SON'); SELECT T.FNAME,T.LNAME FROM DEPENDENT D, (SELECT SSN, FNAME,LNAME )T WHERE D.DEPSSN=T.SSN AND RELATIONSHIP ='SON'; SELECT EMPLOYEE.FNAME, EMPLOYEE.LNAME WHERE EXISTS (SELECT * FROM DEPENDENT WHERE EMPLOYEE.SSN = DEPENDENT.DEPSSN) AND EXISTS (SELECT * FROM DEPARTMENT WHERE EMPLOYEE.SSN = DEPARTMENT.MGRSSN); All are correct None of the above 15 Get SSN of each employee who has a dependent with the same first name as the employee. A B C D SELECT SSN WHERE SSN IN (SELECT DEPSSN FROM DEPENDENT WHERE DEPSSN = SSN AND FNAME = DEPENDENT_NAME); SELECT SSN, DEPENDENT WHERE SSN = DEPSSN AND FNAME = DEPENDENT_NAME; All are correct None of the above 16 Get department name & the average salary of all employees in each department. SELECT DNAME, AVG(SALARY) FROM DEPARTMENT, EMPLOYEE WHERE DNUMBER = DNO

11 GROUP BY DNAME; Has the output: ADMINISTRATION RESEARCH HEADQUARTERS (a) True (b) False 17) When Tuple 5 is deleted, it will cause deletion anomaly, tuple # S # S C 1 S1 20 LONDON 2 S2 10 PARIS 3 S3 10 PARIS 4 S4 20 LONDON 5 S5 30 ATHENS 6 S6 20 LONDON The anomaly is degree a) 0 b) 1 c) 2 d) 3 e) none of the above 18 R B A and A B and B C A B C S1 50 LONDON S2 10 PARIS S3 70 PARIS S4 50 LONDON S5 100 ATHENS R s highest normal form is A 1NF; B 2NF; C 3NF D BCNF; E None of the above 19 S (A, B, C, D) is a relation with functional dependencies [A, B] C C D S s highest normal form is A 1NF; B 2NF; C 3NF D BCNF; E None of the above 20 T(A, B, C) is a relation with functional dependencies [A, B] C C A T s highest normal form is A 1NF; B 2NF; C 3NF D BCNF; E None of the above 21.The following R1 and R2 are good decomposition of W W S J T SMITH MATH Prof. WHITE SMITH PHYSICS Prof. GREEN

12 JONES MATH Prof. WHITE JONES PHYSICS Prof. BROWN R1 S J R2 S T SMITH MATH SMITH Prof. WHITE SMITH PHYSICS SMITH Prof. GREEN JONES MATH JONES Prof. WHITE JONES PHYSICS JONES Prof. BROWN (a) True (b) False 22 The following relation ACP is 4NF, hence it has no anomaly AGENT COMPANY PRODUCT SMITH FORD CAR SMITH FORD TRUCK SMITH GM CAR SMITH GM TRUCK JONES FORD CAR JONES FORD TRUCK BROWN FORD CAR BROWN GM CAR BROWN TOYOTA CAR BROWN TOYOTA BUS A True B False C None of the above 23. How can you prove ACP can be lossless decomposed into three relations AC, CP and AP: AC CP AP Agent Company Company Product Agent Product Smith Ford Ford Car Smith Car Smith GM Ford Truck Smith Truck Jones Ford GM Car Jones Car Brown Ford GM Truck Jones Truck Brown GM TOYOTA Car Brown Car Brown TOYOTA TOYOTA Bus Brown Bus (a) ACP=AC CP AP (b) ACP=(AC CP) AP (c) ACP=AC (CP AP) (d) All are correct (e ) None of the above 24 Given a relation R (a, b, c, d, e) [b, e] is a CK (candidate key) d > a a > b Which are the correct CK A [b, e] B [b, e], [a, e] C [b, e], [a, e], [d, e] D [b, e], [a, e], [c, e], [d, e]

13 25 Given a relation R (a, b, c, d, e) [b, e] is a CK (candidate key) d > a a > b What is the normal form of R A 1NF; B 2NF; C 3NF D BCNF; E None of the above

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