ACP Semester 2 Review Answer Section
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1 P Semester 2 Review nswer Section MULTIPLE HOIE 1. NS: REF: 93d dd-8a f11039 OJ: Problem-Solving pplication NT: NT.SS.MTH SP.6 ST: TEKS.7.6.H TOP: Making Predictions KEY: probability prediction problem solving OK: OK 2 2. NS: REF: fa53f47c-6ff9-11df-9c f0d2ea NT: NT.SS.MTH SP.6 ST: TEKS.7.6.I KEY: probability experimental OK: OK 1 3. NS: The 6 outcomes of the spinner not landing on and rolling a prime number in the format (spinner, number cube) are (, 2), (, 3), (, 5), (, 2), (, 3), and (, 5). Since there are 18 possible outcomes in the sample space, the probability of the spinner not landing on and rolling a prime number is 6 18, or 1 3. The probability of the spinner landing on or rolling a 4 is 4 9, not The probability of the spinner not landing on and rolling a 3 is 1 13, not The probability of the spinner landing on or rolling a number greater than 2 is 7 9, not 2 9. That s correct! NT: NT.SS.MTH SP.8.a NT.SS.MTH SP.8.b NT.SS.MTH.10.K-12.MP.5 ST: TEKS.7.6.I KEY: compound events identifying outcomes probability sample space tree diagram OK: OK 2 4. NS: REF: 9922c dd-8a f11039 OJ: Finding the rea of a omposite Figure NT: NT.SS.MTH G.6 ST: TEKS.7.9. TOP: rea of Irregular Figures KEY: area irregular figure OK: OK 3 5. NS: REF: 940f dd-8a f11039 OJ: Solving Two-Step Equations NT: NT.SS.MTH EE.4 ST: TEKS TOP: Solving Two-Step Equations KEY: solving equation two-step equation OK: OK 2 1
2 6. NS: REF: 94737e8f dd-8a f11039 NT: NT.SS.MTH EE.4 ST: TEKS TOP: Translating Words into Math KEY: multi-step OK: OK 2 7. NS: NT: NT.SS.MTH EE.7 ST: TEKS OK: OK 2 8. NS: ompare the corresponding sides. MN RS = 9 15 = 3 5 MP RU = 6 10 = 3 5 Since the measures of the corresponding angles are equal and the ratios of the corresponding sides are equivalent, the rectangles are similar. The similarity ratio is 3 5. rectangle MNOP ~ rectangle RSTU orrect! ompare the corresponding sides. heck whether the ratios of the corresponding sides are equivalent. heck whether the ratios of the corresponding sides are equivalent. IF: dvanced ST: TEKS.8.3. TOP: Similar Figures and Proportions 2
3 9. NS: height of maple height of pine shadowof maple = shadowof pine Write a proportion using the corresponding sides. x = Substitute. x Use compatible numbers to estimate. x 20 4 Simplify. x 80 Multiply to isolate the variable. The maple tree is about 80 feet tall. Use compatible numbers to estimate. orrect! Set up a proportion and estimate. Set up a proportion and estimate. IF: verage OJ: Estimating with Indirect Measurement ST: TEKS.8.3. TOP: Using Similar Figures KEY: indirect measurement similar 10. NS: Multiply the coordinates by the scale factor to find the vertices of the image. orrect! id you multiply each of the coordinates by the scale factor? id you remember to list the x-coordinates first and the y-coordinates second? id you perform the dilation on each of the vertices? IF: verage REF: Page 245 OJ: Using the Origin as the enter of ilation ST: TEKS.8.3. TOP: 5-6 ilations NT: c KEY: coordinate plane dilation 3
4 11. NS: Under a dilation (x, y) (kx, ky), the lengths of the sides change by a scale factor of k. So, the length of each segment of the figure changes by a scale factor of 2 3. That s correct! The dilation does not preserve the length of the segment. The scale factor of the dilation is not 3 2. The scale factor of the dilation is not 2. NT: NT.SS.MTH G.3 ST: TEKS.8.3. KEY: dilation scale factor length of line segment OK: OK NS: NT: NT.SS.MTH G.3 ST: TEKS.8.3. OK: OK NS: REF: 986ff3b dd-8a f11039 OJ: Using a ilation to Reduce a Figure NT: NT.SS.MTH G.3 ST: TEKS.8.3. TOP: ilations KEY: coordinate plane dilation OK: OK NS: NT: NT.SS.MTH SP.2 ST: TEKS.8.5. OK: OK NS: NT: NT.SS.MTH SP.2 ST: TEKS.8.5. OK: OK NS: NT: NT.SS.MTH F.3 ST: TEKS.8.5.I OK: OK NS: NT: NT.SS.MTH F.3 ST: TEKS.8.5.I OK: OK 1 4
5 18. NS: First, find the function s rate of change using the first two ordered pairs in the table = = 2 Then, find the function s initial value using the equation s = mt + b, the slope, and one ordered pair from the table. 19 = 2 ( 3) + b 19 = 6 + b 13 = b So, the function represented by the table is s = 2t The rate of change is not negative. The initial value is not 2. The initial value is not 0. That s correct! NT: NT.SS.MTH F.4 NT.SS.MTH.10.K-12.MP.4 ST: TEKS.8.5.I KEY: constructing linear functions analyzing tables OK: OK NS: REF: 911ba69b-6ab2-11e0-9c f0d2ea OJ: Identifying Similarity Transformations NT: NT.SS.MTH G.4 ST: TEKS TOP: Similarity and ongruence Transformations KEY: dilation transformation similarity congruence OK: OK NS: Two figures are congruent if there exists a sequence of translations, reflections, and/or rotations that maps one figure to the other. Two figures are similar if there exists a sequence of translations, reflections, rotations, and/or dilations that maps one figure to the other. So, if the sequence of transformations includes a dilation, the figures are similar but not congruent. The figure with the vertices ( 6, 6), ( 2, 2), (2, 2), (6, 6) is the image of the given figure after a dilation with respect to the origin by a scale factor of 2. So, this figure is similar but not congruent to the given figure. This figure is the image of the given figure after a rotation 90 clockwise about the origin. That s correct! This figure is the image of the given figure after a translation right 1 unit and down 3 units. This figure is the image of the given figure after a reflection across the x-axis. NT: NT.SS.MTH G.4 NT.SS.MTH G.2 ST: TEKS KEY: similar figures congruent figures translation reflection rotation dilation sequence of transformations OK: OK 2 5
6 21. NS: REF: 9d5d10e dd-8a f11039 NT: NT.SS.MTH G.3 ST: TEKS TOP: Transformations KEY: transformation reflection coordinate plane OK: OK NS: NT: NT.SS.MTH G.3 ST: TEKS OK: OK NS: REF: ML10917 NT: NT.SS.MTH G.3 ST: TEKS TOP: Translations in a oordinate Plane KEY: translation OK: OK NS: NT: NT.SS.MTH G.3 ST: TEKS OK: OK NS: When the dimensions of a triangle are increased by a factor of x, the perimeter is increased by a factor of x, and the area is increased by a factor of x 2. orrect! heck the change in the area. heck the change in the perimeter. ompare the perimeter and area of the original figure with the perimeter and area of the enlarged figure. IF: verage REF: Page 548 OJ: omparing Perimeters and reas ST: TEKS TOP: 10-4 hanging imensions KEY: length width perimeter area change 6
7 26. NS: Ê The vertices of figure and figure are shown in the table below. Since the dilation (x, y) 1 3 x, 1 ˆ 3 y ËÁ transforms figure to figure, the scale factor is 1 3. Preimage Image ( 3, 3) ( 1, 1) ( 3, 9) ( 1, 3) (3, 6) (1, 2) (3, 6) (1, 2) That s correct! The distance from the origin to a vertex of figure is not half of the distance from the origin to the corresponding vertex of figure. Figure is not the same size figure. Figure is not larger than figure. NT: NT.SS.MTH G.3 ST: TEKS KEY: dilation scale factor OK: OK NS: NT: NT.SS.MTH SP.1 ST: TEKS OK: OK NS: REF: f9e15b9c-6ff9-11df-9c f0d2ea NT: NT.SS.MTH SP.1 ST: TEKS KEY: association relationship scatter plot OK: OK NS: REF: f9e182ac-6ff9-11df-9c f0d2ea NT: NT.SS.MTH SP.1 ST: TEKS KEY: association relationship scatter plot OK: OK NS: NT: NT.SS.MTH SP.5.c ST: TEKS OK: OK NS: NT: TEKS ST: TEKS OK: OK NS: NT: TEKS ST: TEKS OK: OK NS: REF: 96da7a3b dd-8a f11039 OJ: Problem-Solving pplication NT: NT.SS.MTH RP.3 ST: TEKS TOP: Simple Interest KEY: interest simple interest OK: OK NS: NT: NT.SS.MTH RP.3 ST: TEKS OK: OK 2 7
8 35. NS: The formula for the surface area of a rectangular prism is S = 2 w + 2 h + 2wh, where is the length, w is the width, and h is the height. S = 2 ( 9) ( 7) + 2 ( 9) ( 5) + 2 ( 7) ( 5) = = 286 Thus, the surface area of the prism is 286 m 2. The prism has 6 faces, not just 3 faces. That s correct! 315 m 3 is the volume of the prism. This is the surface area of a cube with side length 9 m. NT: NT.SS.MTH G.6 ST: TEKS.8.7. KEY: rectangular prism surface area OK: OK NS: NT: NT.SS.MTH G.4 ST: TEKS.8.7. OK: OK NS: NT: NT.SS.MTH EE.7 ST: TEKS.8.8. OK: OK NS: REF: 9f83fac dd-8a f11039 OJ: pplication NT: NT.SS.MTH EE.7 NT.SS.MTH EE.7.b ST: TEKS.8.8. TOP: Solving Equations with Variables on oth Sides KEY: multi-step equation solve OK: OK NS: NT: NT.SS.MTH EE.7 NT.SS.MTH EE.7.b ST: TEKS.8.8. OK: OK NS: NT: NT.SS.MTH EE.7 NT.SS.MTH EE.7.b ST: TEKS.8.8. OK: OK 2 NUMERI RESPONSE 1. NS: 299 REF: 99e6204d dd-8a f11039 OJ: pplication NT: NT.SS.MTH SP.6 ST: TEKS.7.6.H TOP: Making Predictions KEY: multi-step OK: OK 2 2. NS: REF: 92f83f1d dd-8a f11039 NT: NT.SS.MTH G.1 ST: TEKS.7.9. TOP: rea of omposite Figures OK: OK 3 8
9 3. NS: REF: fa136d67-6ff9-11df-9c f0d2ea NT: NT.SS.MTH SP.5.c ST: TEKS KEY: residual linear least-squares regression absolute deviation goodness of fit OK: OK 2 SHORT NSWER 1. NS: ) Sample answer: ustin and erenice are riding a train. ustin is in the sixth train car from the end of the train and is walking towards the end at a rate of half a car per minute. erenice is at the end of the train and is walking forward at a rate of two and a half cars per minute. t what time will they meet? ) x = 2; Sample answer: They will meet after 2 minutes. NT: TEKS.8.8. ST: TEKS.8.8. OK: OK 2 9
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