Standard Equation of a Circle

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Math 335 Trigonometry Conics We will study all 4 types of conic sections, which are curves that result from the intersection of a right circular cone and a plane that does not contain the vertex. (If the plane contains the vertex, the intersection of the plane and the cone is a point, line, or a pair of intersection lines. These are usually called degenerate conics.) Circles Defn A circle is a set of points in the xy-plane that is a fixed distance r from a fixed point (h, k). The fixed distance r is called the radius, and the fixed point (h, k) is called the center. Standard Equation of a Circle (x h) 2 + (y k) 2 = r 2 Note: The equation x 2 + y 2 + ax + by + c = 0 is that of a circle, a point, or has no graph at all. If it s the graph of a circle, it is referred to as the general form of the equation of a circle. Ex 1 (#8) Find the center and radius of the circle. Write the standard form of the equation. (1,2) (1,0) Ex 2 (#30) (a) Find the center, (h, k), and the radius, r. (b) Graph the circle. (c) Find the intercepts, if any. x 2 + y 2 + x + y 1 = 0 2 Page 1 of 13

Ex 3 (#38) Find the standard form of the equation of the circle. Center ( 3, 1) and tangent to the y-axis The Ellipse Defn An ellipse is the collection of all points in the plane, the sum of whose distances from two fixed points, called the foci, is a constant. Note: The constant is 2a. The line containing the foci is called the major axis. The midpoint of the line segment joining the foci is the center of the ellipse. The line through the center and perpendicular to the major axis is the minor axis. The vertices are the two points of intersection of the ellipse and major axis. Equation of Ellipse with Center at (h, k); Major Axis Along x-axis Equation of Ellipse with Center at (h, k); Major Axis Along y-axis (x h) 2 a 2 (y k)2 + b 2 = 1, a > b > 0 (x h) 2 b 2 (y k)2 + a 2 = 1, a > b > 0 Vertices: Foci: a 2 = b 2 + c 2 (h ± a, k) (h ± c, k) (a > c) Vertices: Foci: a 2 = b 2 + c 2 (h, k ± a) (h, k ± c) (a > c) Ex 4 (#24) Find the vertices and foci of the ellipse. Graph the equation. 4y 2 + 9x 2 = 36 Page 2 of 13

Ex 5 Find an equation for each ellipse. Graph each equation. (#27) Center at (0,0); focus at (3,0); vertex at (5,0) (#32) Foci at (0, ±2); length of major axis is 8 Ex 6 (#40) Write an equation for the ellipse. Ex 7 (#50) Analyze the equation; that is, find the center, foci, and vertices of the ellipse. Graph the equation. 4x 2 + 3y 2 + 8x 6y = 5 Page 3 of 13

Ex 8 (#72) If a source of light or sound is placed at one focus of an ellipse, the waves transmitted by the source will reflect off the ellipse and concentrate at the other focus. This is the principle behind whispering galleries, which are rooms designed with elliptical ceilings. Jim, standing at one focus of a whispering gallery, is 6 feet from the nearest wall. His friend is standing at the other focus, 100 feet away. What is the length of this whispering gallery? How high is its elliptical ceiling at the center? 112 ft; 25.2 ft The Hyperbola Defn A hyperbola is the collection of points in the plane, the difference of whose distances from two fixed points, called the foci, is a constant. Note: The constant is 2a. The line containing the foci is called the transverse axis. The midpoint of the line segment joining the foci is the center of the hyperbola. The line through the center and perpendicular to the transverse axis is the conjugate axis. The hyperbola consists of two separate curves, called branches. Equation of Hyperbola with Center at (h, k); Transverse Axis Parallel to the x-axis Equation of Hyperbola with Center at (h, k); Transverse Axis Parallel to the y-axis (x h) 2 a 2 (y k)2 b 2 = 1 c 2 = a 2 + b 2 c > a Vertices: (h ± a, k) Foci: (h ± c, k) Asymptotes: y k = ± b (x h) a (y k) 2 (x h)2 a 2 b 2 = 1 c 2 = a 2 + b 2 c > a Vertices: (h, k ± a) Foci: (h, k ± c) Asymptotes: y k = ± a (x h) b Ex 9 Find an equation for the hyperbola described. Graph the equation. (#20) Center at (0,0); focus at ( 3,0); vertex at (2,0) Page 4 of 13

(#23) Vertices at (0, ±6); asymptote the line y = 2x Ex 10 (#36) Write an equation for the hyperbola. Ex 11 Find the center, transverse axis, vertices, foci, and asymptotes. Graph the equation. (#47) (x 2) 2 (y + 3)2 = 1 4 9 (#49) (y 2) 2 4(x + 2) 2 = 4 Page 5 of 13

(#58) 2y 2 x 2 + 2x + 8y + 3 = 0 Ex 12 Graph (x + 2) 2 (y 3)2 + = 1 9 25 Ex 13 Write an equation of the ellipse with foci at (1, 4) and (5, 4) and with one vertex at (8, 4). Page 6 of 13

The Parabola Defn A parabola is a collection of points P in the plane that are the same distance from a fixed point F as they are from a fixed line D. The point F is called the focus of the parabola, and the line D is called the directrix. As a result, a parabola is the set of points P for which d(p, F) = d(p, D). The line through the focus and perpendicular to the directrix is called the axis of symmetry. The point of intersection of the parabola with its axis of symmetry is called the vertex V. The line segment joining the points on the parabola "above/below" or to the "left/right" of the focus is called the latus rectum. Use the distance formula to derive the equation of a parabola. Shortcut to find points on LR: Distance 2a from focus Page 7 of 13

Equation of Parabola with Vertex (h, k); Opens Left/Right Equation of Parabola with Vertex (h, k); Opens Up/Down (y k) 2 = ±4a(x h) or x = ± 1 (y 4a k)2 + h (x h) 2 = ±4a(y k) or y = ± 1 (x 4a h)2 + k Focus: Directrix: (h ± a, k) x = h ± a Focus: Directrix: (h, k ± a) y = k ± a Ex 14 Find the equation of the parabola described. Find the two points that define the latus rectum, and graph the equation. (#22) Focus at ( 4,0); vertex at (0,0) (#30) Vertex at (4, 2); focus at (6, 2) Page 8 of 13

(#36) Focus at ( 4,4); directrix the line y = 2 Ex 15 Find the vertex, focus, and directrix of each parabola. Graph the equation. (#39) y 2 = 16x (#45) (y + 3) 2 = 8(x 2) (#50) y 2 2y = 8x 1 Page 9 of 13

Ex 16 (#64) Prac Prob A cable TV receiving dish is in the shape of a paraboloid of revolution. Find the location of the receiver, which is placed at the focus, if the dish is 6 feet across at its opening and 2 feet deep. 1.125 ft or 13.5 in from the base of dish along axis of symm Ex 17 Systems of Nonlinear Equations Graph each equation of the system. Then solve the system to find the points of intersection. (#8) { y = 4 x2 y = 2x + 4 y = 3x 5 (#15) { x 2 + y 2 = 5 Ex 18 Solve each system. Use any method you wish. xy = 4 (#19) { x 2 + y 2 = 8 (#20) Prac Prob { x2 = y xy = 1 (1, 1) Page 10 of 13

(#26) { x2 y 2 = 21 x + y = 7 (#36) { x2 3y 2 + 1 = 0 2x 2 7y 2 + 5 = 0 Ex 19 (#86) Prac Prob A rectangular piece of cardboard, whose area is 216 square centimeters, is made into a cylindrical tube by joining together two sides of the rectangle. See the figure. If the tube is to have a volume of 224 cubic centimeters, what size cardboard should you start with? 16.57 cm by 13.03 cm Page 11 of 13

Systems of Inequalities Ex 20 Graph each inequality. x 2 + y 2 < 4 y > x 2 + 4 (#22) xy 1 Ex 21 (#31 ) 2x + y 2 Graph the system of linear inequalities. { 2x + y > 2 Ex 22 Graph each system of inequalities. (#36) { x2 + y 2 9 x + y 3 Page 12 of 13

(#39) { x2 + y 2 16 y x 2 4 (#42) { y + x2 1 y x 2 1 Page 13 of 13