Vidyalankar F.Y. Diploma : Sem. II [CD/CM/CO/CW/DE/ED/EE/EI/EJ/EN/EP/ET/EV/EX/IC/IE/IF/IS/IU/MU] Programming in C

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1 F.Y. Diploma : Sem. II [CD/CM/CO/CW/DE/ED/EE/EI/EJ/EN/EP/ET/EV/EX/IC/IE/IF/IS/IU/MU] Programming in C Time : 3 Hrs.] Prelim Question Paper Solution [Marks : 100 Q.1 Attempt any TEN of the following : [20] Q.1(a) Explain with the example the use of Break statement. [2] (A) The break statement in C programming language has the following two usage : 1. When the break statement is encountered inside a loop, the loop is immediately terminated and the program control resumes at the next statement following the loop. 2. It can be used to terminate the case in the switch statement If one is using nested loops, the break statement will stop the execution of the innermost loop and start executing the next line of code after the block. Syntax break; Example : #include <stdio.h> int main() int a = 10; while(a<20) printf( value of a: %d \n, a) a++; if(a > 15) break; return 0; Q.1(b) List and explain types of qualifiers. [2] (A) C type qualifiers : the keywords which are used to modify the properties of a variable are called type qualifiers. Types of C-type qualifiers : There are two types of qualifiers available in C language. They are : (i) const (ii) volatile (i) const keyword : Constants are also like normal variables. But, only difference is, their values cant be modified by the program once they are defined. They refer to fixed values. They are also called as literals. 1

2 F.Y. Diploma Programming in C They may belong to any of the data type. Syntax const datatype variablename; Or const datatype *variablename (ii) volatile keyword : when a variable is defined as volatile, the program may not change the value of the variable explicitly. But, these variable values might keep on changing without any explicit assignments by the program. These types of qualifiers are called volatile. For ex, if global variable s address is passed to clock routine of the operating system to store the system time, the value in this address keep on changing without any assignment by the program. These variables are named as volatile variable. Syntax volatile datatype variablename Or Volatile datatype *variablename Q.1(c) What is an array? How to declare one-dimensional and two dimensional array. [2] (A) C Programming/Arrays. Arrays in C act to store related data under a single variable name with an index, also known as a subscript. It is easiest to think of an array as simply a list or ordered grouping for variables of the same type. Declaration of One Dimensional Array: Syntax: data_type array_name[width]; Example: int roll[8]; In this example, an array of integer type is declared and named it as roll which can store roll numbers of 8 students. C Array Assignment and Initialization: We can assign value to an array at the time of declaration or during runtime. Syntax: data_type array_name[size]=list of values; Example: int arr[5]=1,2,3,4,5; int arr[]=1,2,3,4,5; Declaration of Two Dimensional Array: Syntax: data_type array_name[rows][cols]; Example: int number[3][4]; In this example, an array of integer type is declared and named it as number which can store numbers in 3 rows and 4 columns format. So total 12 numbers are stored. C Array Assignment and Initialization: We can assign value to an array at the time of declaration or during runtime. Syntax: data_type array_name[rows][cols]=list of values; Example: int number[3][4]= 1,2,3,4, 5,6,7,8, 2

3 int number[][]= ; 9,10,11,12 ; 1,2,3,4, 5,6,7,8, 9,10,11,12 Prelim Question Paper Solution Q.1(d) Distinguish between call-by-value and call-by-reference. [2] (A) Call by Value Call by Reference This is the usual method to call a function In this method, the address of the variable in which only the value of the variable is is passed as an argument. passed as an argument. Any alternation in the value of the Any alternation in the value of the argument passed is local to the function argument passed is accepted in the calling and is not accepted in the calling program. program. Memory location occupied by formal and Memory location occupied by formal and actual arguments is different. actual arguments is same and there is a saving of memory location. Since a new location is created, this Since the existing memory location is used method is slow. through its address, this method is fast. There is no possibility of wrong data There is a possibility of wrong data manipulation since the arguments are manipulation since the addresses are used directly used in an application. in an expression. A good skill of programming is required here. Q.1(e) Write a C program to find the factorial of an entered number using recursion. [2] (A) #include <stdio.h> #include <conio.h> void main() int no, factorial; int fact (int no); clrscr(); printf( Enter a number ); scanf( %d, &no); factorial = fact(no); printf( the factorial of a %d is %d, no, factorial); int fact(no1) int c, fact=1; for(c=1; c<=no1; c++); fact = fact * c; return fact; 3

4 F.Y. Diploma Programming in C Q.1(f) Find the output of the following. void main() int i=1; clrscr(); for(;;) printf("%d ",i); getch(); (A) void main() int i=1; clrscr(); for(;;) printf("%d ",i); getch(); Ans : Output infinite Q.1(g) Write the syntax of whi le and do..while statements. [2] (A) Syntax - while while(condition) Statement; Syntax do while do Statements while (condition) Q.1(h) What is a storage class? Enlist storage classes available in C. [2] (A) A storage class defines the scope and life time of variables and/or functions withing a C program. There are following storage classes which can be used in a C program. auto register static extern [2] 4

5 Prelim Question Paper Solution Q.1(i) What is a meaning of Prototype of a function? [2] (A) Prototype of a function : Declaration of function is known as prototype of a function. Prototype of a function means (1) What is return type of function? (2) What parameters are we passing? For example prototype of print function is: int print(int a, int b); i.e. its return type is int data type, its first parameter is an integer variable and second parameter is also an integer variable. Q.1(j) Find out the error if any, in the program. #include<stdio.h> int main() int i=1; switch(i) case 1: printf("\radioactive cats have 18 half-lives"); break; case 1*2+4: printf("\bottle for rent -inquire within"); break; return 0; (A) #include<stdio.h> int main() int i=1; switch(i) case 1: printf("\radioactive cats have 18 half-lives"); break; case 1*2+4: printf("\bottle for rent -inquire within"); break; return 0; Ans : No error Q.1(k) What will be output when you will execute following c code? #include<stdio.h> void main() int a=100; if(a>10) printf("m.s. Dhoni"); else if(a>20) printf("m.e.k Hussey"); else if(a>30) printf("a.b. de villiers"); 5 [2] [2]

6 F.Y. Diploma Programming in C (A) 6 #include<stdio.h> void main() int a=100; if(a>10) printf("m.s. Dhoni"); else if(a>20) printf("m.e.k Hussey"); else if(a>30) printf("a.b. de villiers"); Ans : M.S.Dhoni Q.1(l) Write a C program to find whether the given year is a leap or not. [2] (A) #include <stdio.h> #include<conio.h> void main() int year; clrscr(); printf( Enter any year ); scanf( %d, &year); if((year%4= =0 && year %100!=0) (year%100= =0 && year%400= =0) printf( Leap year ); else printf( Not a leap year ); getch(); Q.2 Attempt any FOUR of the following : [16] Q.2(a) Write a program for exchanging values of two variables using call by reference. [4] (A) #include <stdio.h> #include <conio.h> void main() int a,b; void swap(int *p1, int *p2) clrscr(); printf( Enter two numbers ); scanf( %d %d, &a, &b); printf( The values of a and b in the main function before calling the swap function are %d and %d \n, a,b); swap(&a,&b); printf( The values of a and b in the main function after calling the swap function are %d and %d \n, a,b); getch(); void swap(int *p1, int *p2)

7 Prelim Question Paper Solution int temp; temp = *p1; *p1 = *p2; *p2 = temp; printf( The values of a and b in the swap function after swapping are %d and %d \n, *p1, *p2); Q.2(b) Explain the use of bitwise operator. [4] (A) Consider A = B = Operator Description Example & Binary AND operator copies a bit to (A & B) will give 12 which is the result if it exists in both operands. Binary OR operator copies a bit if it exists in either operand (A B) will give 61 which is ^ Binary XOR operator copies the (A ^ B) will give 49 which is bit if it is set in one operand but not both. ~ Binary Ones Complement operator (~A) will giove -61 which is is unary and has the effect of in 2 s complement form due to a signed flipping bits. binary number. Q.2(c) Explain break and continue statements with an example of each. [4] (A) continue statement : The continue statement in C programming language forces the next iteration of the loop to take place, skipping any code in between. For the for loop, continue statement causes the conditional test and increment portions of the loop to execute. For the while and do while,continue statement causes the program control to pass the conditional test. Example #include<stdio.h> int main() int a = 10; do if(a= =15) a = a + 1; continue; printf( value of a : %d \n, a); a++; while(a<20); 7

8 F.Y. Diploma Programming in C return 0; 8 Output : value of a : 10 value of a : 11 value of a : 12 value of a : 13 value of a : 14 value of a : 16 value of a : 17 value of a : 18 value of a : 19 Q.2(d) Explain relational operators supported by C. Write a C program illustrating [4] its use. (A) Operator Description Example = = Checks if the values of two operands are equal or not, if yes, then (A = = B) the condition returns true.!= Checks if the values of two operands are equal or not, if values (A!= B) are not equal, then the condition returns true. > Checks if the value of the left operand is greater than the value of (A > B) the right operand, if yes, then the condition returns true. < Checks if the value of the left operand is less than the value of the (A < B) right operand, if yes, then the condition returns true. >= Checks if the value of the left operand is greater than or equal to the (A >= B) value of the right operand, if yes, then the condition returns true. <= Checks if the value of the left operand is less than or equal to the value of the right operand, if yes, then the condition returns true. (A <= B) Example - #include<stdio.h> int a=21; int b=10; int c; if(a == b) printf( a is equal to b ); else printf( a is not equal to b ); if (a < b) printf( a is less than b ); else

9 printf( a is not less than b ); if (a > b) printf( a is greater than b ); else printf( a is not greater than b ); a=5; b=20; if(a <= b) printf( a is either less than or equal to b ); if(b >= a) printf( b is either greater than or equal to a ); Prelim Question Paper Solution Q.2(e) What is operators precedence and associativity? [4] (A) Operator precedence determines the grouping of terms in an expression. This affects how an expression is evaluated. Certain operators have higher precedence than others; for exthe multiplication operator had higher precedence than the addition operator. For example x = * 2; here x is assigned 13, not 20 because operator * has higher precedence than +. Category Operator Associativity Postfix () [] -> Left to right Unary + -! ~ (type)* &sizeof Right to left Multiplicative */ % Left to right Additive + - Left to right Shift << >> Left to right Relational <<= >>= Left to right Equality ==!= Left to right Bitwise AND & Left to right Bitwise XOR ^ Left to right Bitwise OR Left to right Logical AND && Left to right Logical OR Right to left Conditional?: Right to left Assignment = += -= *= %= >>= <<= &= ^= = Left to right Q.2(f) Write a C program to accept a float number and display its integer part. [4] (A) #include<stdio.h> #include<conio.h> void main() int a; 9

10 F.Y. Diploma Programming in C float b; clrscr(); printf( enter any float number ); scanf( %f, &b); a = (int) b; printf( the integer part of the number is %d, a); getch(); Q.3 Attempt any FOUR of the following : [16] Q.3(a) Explain global and local variable. Write C program to explain global and [4] local variable. (A) Local variables these are the variables declared inside a function in which they are to be utilized. They are created when the function is called and destroyed automatically when the function is exited, hence the name automatic. Automatic variables are therefore private or local to the function in which they are declared. They are also referred to as local or internal variables. A variable declared inside a function without storage class is by default an automatic variable. e.g main() int number;.... We may also use the keyword auto to declare automatic variables explicitly. main auto int number;.. The value of automatic variables can not be changed in other function in the program. We may declare and use the same variable in different functions in the same program. e.g main() int m = 1000; function2(); printf( %d \n, m); function1() int m = 10; printf( %d\n, m); 10

11 function2() int m=1000; function1(); printf( %d\n, m); Output Prelim Question Paper Solution Global variables : Variables that are active throughout the entire program are known as global or external variables. They can be accessed by any function in the program. They are declared outside a function. e.g. int number; float length = 7.5; main() Function1() Function2() The variable numbers and length are available for use in all the three functions e.g int x; main() x=10; printf( x=%d\n, x); printf( x=%d\n, fun1()); printf( x=%d\n, fun2()); printf( x=%d\n, fun3()); fun1() x=x+10; 11

12 F.Y. Diploma Programming in C return(x); 12 fun2() int x; x=1; return(x); fun3() x=x+10; return(x); Output: x=10; x=20 x=1 x=30 Q.3(b) What is the difference between pre-increment and post-increment operators? [4] Explain with the help of an example. (A) As the name says Pre increment means increment first than operate. Post increment means operate than increment. eg for x=7 a=++x x will increase first than a=x will operate while for a=x++ a will be equal x(7) and after than x value will be 8. #include<stdio.h> main() int x = 7; int a; a = ++x; printf( the value of a = %d, a); Output : The value of a = 8 #include<stdio.h> main() int x = 7; int a;

13 Prelim Question Paper Solution a = x++; printf( the value of a = %d, a); The value of a = 7 Q.3(c) Write a C program to calculate the value of following series. 1 + ½ + 1/3 + ¼ + 1/5. + 1/n (A) #include <stdio.h> #include<conio.h> void main() int i,n; float sum=0.0; clrscr(); printf( enter a number ); scanf( %d, &n); for(i=1; i<=n; i++) sum=sum+0.1/i; printf( The value of the series is : %f,sum); getch() Q.3(d) Explain declaration and initialization of string variable with example. [4] (A) A group of characters can be stored inn a character array. Character arrays are many a times called strings. A string constant is a one dimensional array of characters terminated by a null ( \0 ). For example : Char name[] = R, O, N, N, Y, \0 ; The terminating null is important, nbecause it is the only way the functions that work with a string can know where the string ends. In fact, a string not terminated by a \ \0 is not really a string, but merely a collection of characters. The string used above can also be initialized as : Char name[] = RONNY ; In this, declaration \0 is not necessary. C inserts the null character automatically. Q.3(e) Describe the string functions strlen() and strcpy() with an example of each. [4] (A) strlen() this function returns length of the string. strcpy this function is used for copying one char array into another. #include<stdio.h> main() char x[50] = hello, char y[50]; int len = 0; len = strlen(x) printf( The length is %d, len); strcpy(y,x); [4] 13

14 F.Y. Diploma Programming in C Q.3(f) Write a program to print first 10 prime numbers. [4] (A) #include<stdio.h> #include<conio.h> main() int count, n, no=1,div,rem,flag=0; clrscr(); for(count=0;count<=10;count++) for(div=2;div<no; div++) rem = no % div; if(rem == 0) flag = 1; break; if(flag= =0) count++; printf( %d, no) Q.4 Attempt any FOUR of the following : [16] Q.4(a) What is a function? Explain the need of function with example. [4] (A) A function is a self-contained block of statements that perform a coherent task of some kind. Every c program can be thought of as a collection of these functions. Need : 1. Writing functions avoids rewriting the same code over and over. Suppose u have a section of code in your program that calculates area of a triangle. If later in the program you want to calculate the area of a different triangle, you wont like it if you required to write the same instructions all over again. Instead, you would prefer to jump to a section of code that calculates area and then jump back to the place from where you left off. This section of code is nothing but a function. 2. Using functions it becomes easier to write programs and keep track of what they are doing. If the operation of a program can be divided into separate activities, and each activity placed in a different function, then each could be written and checked more or less independently. Separating the code into modular functions also makes the program easier to design and understand. 3. Q.4(b) Explain any two storage classes and their characteristics. [4] (A) There are following storage classes which can be used in a C Program. auto register static extern 14

15 Prelim Question Paper Solution (i) auto auto is the default storage class for all local variables. int Count; auto int Month; The example above defines two variables with the same starage class. auto can only be used within functions. i.e. local variables. (ii) register register is used to define local variables that should be stored in a register instead of RAM. This means that the variable has a maximum size equal to the register size9usually one word) and cannot have the unary & operator applied to it. (as it does not have the memory location) Register int miles; Register should only be used for variables that require quick access such as counters. It should also be noted that defining register does not mean that the variable will be stored in a register. It means that it MIGHT be stored in a register depending on hardware and implementation restrictions. Q.4(c) How to define Structure? How to access structure members? Explain it with [4] the help of an example. (A) Defining structure : To define a structure, you must use the struct statement. The struct statement defines the new data type, with more than one member for your program. The format of struct statement is this : struct [structure tag] Member definiation; Member definiation; [one or more structure variables] Example : struct Books char title[50]; char author[50]; char subject[100]; int book_id; book; Accessing structure memners : To access the structure members, member access operator (.) is used. struct keyword is used to define a variable of a structure type. Example struct Books 15

16 F.Y. Diploma Programming in C 16 char title[50]; char author[50]; char subject[100]; int book_id; book; int main() struct Books Book1; strcpy (Book1.title, C Programming ); strcpy(book1.author, Neha ali )l strcpy(book1.subject, C Programming Tutorial ); Book1.id = 3446; /* print book1 info */ printf( Book1 title:, Book1.title); printf( Book1 author:, Book1.author); printf( Book1 subject:, Book1.subject); printf( Book1 book id:, Book1.book_id); return 0; Q.4(d) What is an array? State types of array. Write any one statement to initialize array of 5 elements. (A) An array is a collection of values of same data type. Types of array 1. One dimensional array 2. Two dimensional array 3. Multidimensional array To initialize array of 5 elements in one line int marks[5] = 55,66,77,88,99; Q.4(e) Write a program to find Transpose of any (3 * 3) matrix. [4] (A) #include<stdio,h> #inlcude<conio.h> void main() int m,n, I,j, a[10][10]; void transpose(int a[10][10], int m, int n); clrscr(); printf( Enter the number of rows and columns ); scanf( %d%d, &m,&n); for(i=0;i<m-1;i++) for(j=0;j<=n-1;j++) printf( Enter a value ); scanf( %d, &a[i][j]); [4]

17 Prelim Question Paper Solution printf( Then original matrix is ); for(i=0;i<m-1;i++) for(j=0;j<=n-1;j++) printf( %d\t, a[i[][j]); printf( \n ); transpose(a,m,n); getch(); void transpose(int a[10][10], int m, int n) int b[10][10], I, j; for (i=0;i<=m-1;i++) for(j=0;j<=n-1;j++) b[i][j] = a[i][j]; printf( the transpose of this matrix is : \n ); for (i=0;i<=m-1;i++) for(j=0;j<=n-1;j++) printf( %d\t, b[i][j]; Q.4(f) Write a program to accept a string and display the length of it without using standard library functions. (A) #include<stdio,h> #include<conio.h> void main() char a[100]; int len=0; clrscr(); printf( Enter any string ); gets(a); while(a[len]!= \0 ) len ++; printf( the length of the string is %d, len); [4] 17

18 F.Y. Diploma Programming in C Q.5 Attempt any FOUR of the following : [16] Q.5(a) What will be output of following c code? [4] #include<stdio.h> int main() int i=1; for(i=0;i=-1;i=1) printf("%d ",i); if(i!=1) break; return 0; (A) 1 Q.5(b) Explain Static variable with the help of an example. [4] (A) Q.5(c) Write a C program to convert lower case to upper case. [4] (A) #include<stdio.h> int main() char str[20]; int i; printf("enter any string: "); scanf("%s",str); printf("the string is: %s",str); for(i=0;i<=strlen(str);i++) if(str[i]>=97&&str[i]<=122) 18

19 Prelim Question Paper Solution str[i]=str[i]-32; printf("\nthe string in lowercase is: %s",str); return 0; Q.5(d) Write the meaning of declaration: int * ptr; [4] (A) main() int i = 3; printf( \n address of i = %u, &i); printf( \n Value of i = %d, i); The o/p Address of i = Value of i = 3 In the first printf statement & is used which is C s Address of operator. The expression &i returns the address of the variable i. which in this case happens to be Since this number represents an address, there is no question of a sign being associated with it. Hence it is printed out using %u, which is a format specifier for printing an unsigned integer. The other pointer operator available in C is *, called value at address operator. It gives the value stored at a particular address. The value at address operator is also called as indirection operator. Q.5(e) Write a program for addition of two 3 * 3 matrix. [4] (A) #include<stdio.h> #incluse<conio.h> void main() int m,n,i,j,a[3][3],b[3][3],c[3][3]; printf( Enter the number of rows and columns: ); scanf( %d %d, &m, &n); printf( Enter the elements of Matrix 1\n ); for(i=0;i<=m-1;i++) for(j=0;j<=n-1;j++) printf( enter a value: ); scanf( %d, &a[i][j]); printf( Enter the elements of Matrix 2\n ); for(i=0;i<=m-1;i++) for(j=0;j<=n-1;j++) 19

20 F.Y. Diploma Programming in C printf( enter a value: ); scanf( %d, &b[i][j]); for(i=0;i<=m-1;i++) for(j=0;j<=n-1;j++) c[i][j] = a[i][j] + b[i][j]; printf( the sum of two matrices is :\n ); for(i=0;i<=m-1;i++) for(j=0;j<=n-1;j++) printf( %d \t, c[i][j]; printf( \n ); getch(); Q.5(f) Write a C program to find GCD/LCM of given number. [4] (A) #include<stdio.h> #include<conio.h> void main() int n01, no2, gcd; int GCD(int no1, int no2); clrscr(); printf( Enter two numbers ); scanf( %d%d, &no1, &no2); gcd=gcd(no1, no2); if(gcd==1) printf( GCD doesn t exist ); else printf( GCD = %d, gcd); getch(); int GCD(int no1, int no2) int gcd; if(no1<no2) gcd=no1; else gcd=no2; while(no1%gcd!= 0 noo2%gcd!=0) 20

21 Prelim Question Paper Solution gcd--; return gcd; Q.6 Attempt any FOUR of the following : [16] Q.6(a) Explain with examples different pointer arithmetic operations. [4] (A) Only limited number of arithmetic operations can be performed on pointers. These operations are : Increment and decrement An integer quantity can be added to or subtracted from a pointer variable int *pw; pw++; pw+3; Addition and subtraction One pointer variable can be subtracted from another. It makes sense only if both points tp elements in the same array. int *pw, *pv, A[100]; pv = & A[51]; pw = &A[75]; printf( %d, pw-pv); printf( %d, pv-pw); Comparison Two pinter variables can be compared if they point to objects to the same type. Int *pw, *pv Pw < pv ; pw >=pv; pw<=pv; pw==pv; pw!=pv Pw==NULL char c[4]; if(pw < c).; Gives a warning Pw < (int *) c passes (char *) pw < c also passes Assignment e.g. x=3 the value 3 is assigned to variable x. Q.6(b) How pointers are declared, initialized and accessed? [4] (A) **** How to Declare a Pointer? A pointer is declared as : <pointer type> *<pointer-name> In the above declaration : 1. pointer-type : It specifies the type of pointer. It can be int,char, float etc. This type specifies the type of variable whose address this pointer can store. 2. pointer-name : It can be any name specified by the user. Professionally, there are some coding styles which every code follows. The pointer names commonly start with p or end with ptr An example of a pointer declaration can be : char *chptr; In the above declaration, char signifies the pointer type, chptr is the name of the pointer while the asterisk * signifies that chptr is a pointer variable. 21

22 F.Y. Diploma Programming in C How to initialize a Pointer? A pointer is initialized in the following way : <pointer declaration(except semicolon)> = <address of a variable> OR <pointer declaration> <name-of-pointer> = <address of a variable> Note that the type of variable above should be same as the pointer type.(though this is not a strict rule but for beginners this should be kept in mind). For example : char ch = 'c'; char *chptr = &ch; //initialize OR char ch = 'c'; char *chptr; chptr = &ch //initialize In the code above, we declared a character variable ch which stores the value c. Now, we declared a character pointer chptr and initialized it with the address of variable ch. How to Use a Pointer? A pointer can be used in two contexts. Context 1: For accessing the address of the variable whose memory address the pointer stores. Again consider the following code : char ch = 'c'; char *chptr = &ch; Now, whenever we refer the name chptr in the code after the above two lines, then compiler would try to fetch the value contained by this pointer variable, which is the address of the variable (ch) to which the pointer points. i.e. the value given by chptr would be equal to &ch. For example : char *ptr = chptr; The value held by chptr (which in this case is the address of the variable ch ) is assigned to the new pointer ptr. Context 2: For accessing the value of the variable whose memory address the pointer stores. Continuing with the piece of code used above : char ch = 'c'; char t; char *chptr = &ch; t = *chptr; 22

23 Prelim Question Paper Solution Q.6(c) Predict the output. [4] (A) Compiler error : Cannot modify a constant value. Explanation : p is a pointer to a constant integer. But we tried to change the value of the constant integer. Q.6(d) Write a program to accept 5 integer numbers and display them using Array. [4] (A) #include<stdio.h> #include<conio.h> main() int no[5]; int i; printf( Enter any 5 numbers ); for(i=0;i<5;i++) scanf( %d, &a[i]); printf( the entered numbers are ); for(i=0;i<5;i++) printf( %d \t, a[i]); Q.6(e) Define Pointer. Describe &(ampersand) and * (asterisk) operators in pointers. [4] (A) # include <stdio.h> void fun(int x) x = 30; int main() int y = 20; fun(y); printf("%d", y); return 0; Ans : 20 Q.6(f) Write a C Program to Add Two Distances (in inch-feet) System Using Structures [4] (A) Source code to add two distance using structure #include <stdio.h> struct Distance 23

24 F.Y. Diploma Programming in C int feet; float inch; d1,d2,sum; int main() printf("enter information for 1st distance\n"); printf("enter feet: "); scanf("%d",&d1.feet); printf("enter inch: "); scanf("%f",&d1.inch); printf("\nenter information for 2nd distance\n"); printf("enter feet: "); scanf("%d",&d2.feet); printf("enter inch: "); scanf("%f",&d2.inch); sum.feet=d1.feet+d2.feet; sum.inch=d1.inch+d2.inch; /* If inch is greater than 12, changing it to feet. */ if (sum.inch>12.0) sum.inch=sum.inch-12.0; ++sum.feet; printf("\nsum of distances=%d\'-%.1f\"",sum.feet,sum.inch); return 0; Output Enter information for 1st distance Enter feet: 12 Enter inch: 3.45 Enter information for 1st distance Enter feet: 12 Enter inch: 9.2 Sum of distances=25'-0.6" 24