Chapter 35 &36 Physical Optics
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1 Chapter 35 &36 Physical Optics
2 Physical Optics Phase Difference & Coherence Thin Film Interference 2-Slit Interference Single Slit Interference Diffraction Patterns Diffraction Grating Diffraction & Resolution X-Ray Diffraction MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 2
3 Periodic Waves A periodic wave repeats the same pattern over and over. For periodic waves: v = λf v is the wave s speed f is the wave s frequency λ is the wave s wavelength The period T is measured by the amount of time it takes for a point on the wave to go through one complete cycle of oscillations. The frequency is then f = 1/T. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 3
4 Periodic Waves One way to determine the wavelength is by measuring the distance between two consecutive crests. The maximum displacement from equilibrium is amplitude (A) of a wave. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 4
5 Phase Difference When two waves travel different distances to reach the same point, the phase difference is determined by: d d2 phase difference λ 2π 1 = Note: This is a ratio comparison. λ is not equal to 2π MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 5
6 The Principle of Superposition For small amplitudes, waves will pass through each other and emerge unchanged. Superposition Principle: When two or more waves overlap, the net disturbance at any point is the sum of the individual disturbances due to each wave. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 6
7 Two traveling wave pulses: left pulse travels right; right pulse travels left. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 7
8 Interference Two waves are considered coherent if they have the same frequency and maintain a fixed phase relationship. Two coherent waves. The black wave is π/4 radians behind the orange wave. Two waves are considered incoherent if the phase relationship between them varies randomly. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 8
9 When waves are in phase, their superposition gives constructive interference. When waves are one-half a cycle out of phase, their superposition gives destructive interference. This is referred to as: exactly out of phase or 180 o out of phase. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/2012 9
10 Constructive Interference (Slinky Example) MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
11 Destructive Interference (Slinky Example) MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
12 Constructive Interference. Means that the waves ADD together and their amplitudes are in the same direction Destructive Interference. Means that the waves ADD together and their amplitudes are in the opposite directions. Interference = Bad choice of words The two waves do not interfere with each other. They do not interact with each other. No energy or momentum is exchanged. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
13 Special Condition for a Steady Optical Interference Pattern Same wavelength and frequency Phase difference independent of time Amplitudes approximately equal Same polarization These conditions are most easily achieved by deriving the interfering light from the same source. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
14 Interference Patterns Light from different sources can never yield a stationary interference pattern Different sources are inherently incoherent Successful observation of a stationary interference pattern. Optical Path length is small ~ a few wavelengths MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
15 Reflection and Refraction At an abrupt boundary between two media, a reflection will occur. A portion of the incident wave will be reflected backward from the boundary. A portion of the incident wave will be transmitted through the media. This is the refracted ray. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
16 Reflection and Refraction When a wave is incident on the boundary between two different media, a portion of the wave is reflected, and a portion will be transmitted into the second medium. Reflected ray is 180 o out of phase. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
17 The Frequency is Constant The frequency of the transmitted wave remains the same. However, both the wave s speed and wavelength are changed such that: v λ 1 f = = 1 v2 λ 2 The transmitted wave will also suffer a change in propagation direction (refraction). MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
18 The Reflected Wave & Phase Change When you have a wave that travels from a low density medium to a high density medium, the reflected wave pulse will be inverted. (180 o phase shift.) The frequency of the reflected wave remains the same. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
19 Interference Due to Phase Differences Phase Differences Result from Optical Path Differences Phase Shifting The optical path length in a material of index of refraction n is: d' = d n (Phase) = (Optical Path Length) + (Phase Shift) Constructive Interference: (Phase) = nλ; n = 0, 1, 2,... Destructive Interference: (Phase) = mλ/2; m = 1, 3, 5,... MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
20 Phase Shifting Upon Reflection Ray 1 is phase shifted by λ/2 at the air-film interface Ray 2 is not phase shifted at the film-air interface Extra Conditions: Monochromatic light Nearly normal incidence MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
21 Constructive Interference Ray 1 is phase shifted by λ/2 at the air-film interface The difference in the optical path length is the distance the 2nd ray travels in the soap film. The film distance is 2t. Ray 2 is not phase shifted at the film-air interface Monochromatic light The optical path length is 2t/n soap Looking for constructive interference. This requires that the phase difference of 1 and 2 are an integral number of wavelengths. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
22 Constructive Interference (Phase) = (Optical Path Length)+ (Phase Shift) Constructive interference requires that the phase difference of 1 and 2 be equal to an integral number of wavelengths. Constructive interference requires a minimum phase difference equivalent to one wavelength = λ Phase shifting contributes λ/2 to the total phase difference. The optical path length difference needs to contribute another λ/2. The film distance is 2t. The optical path length difference λ /2 = 2t λ 2n soap = 2t t = λ 4n soap Monochromatic light MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
23 Destructive Interference (Phase) = (Optical Path Length)+ (Phase Shift) Destructive interference requires that the phase difference of 1 and 2 be equal to an odd multiple of half wavelengths. Denstructive interference requires a minimum phase difference equivalent to one-half wavelength = λ/2 Phase shifting contributes λ/2 to the total phase difference. The optical path length difference needs to contribute λ. The film distance is 2t. The optical path length difference λ = 2t λ n soap = 2t t = λ 2n soap Monochromatic light MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
24 Destructive Interference (Phase) = (Optical Path Length)+ (Phase Shift) Ray 1 is phase shifted by λ/2 at the air-film interface Ray 2 is also phase shifted by λ/2 at the filmglass interface MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
25 Destructive Interference (Phase) = (Optical Path Length)+ (Phase Shift) Destructive interference requires that the phase difference of 1 and 2 be equal to a half-integral number of wavelengths. Destructive interference requires a minimum phase difference equivalent to one wavelength = λ/2 Phase shifting contributes 0 to the total phase difference. The optical path length difference needs to contribute the λ/2. The film distance is 2t. The optical path length difference λ /2 = 2t λ 2n film = 2t t = λ 4n film MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
26 Newton s Rings Illuminated from above by monochromatic light Dark rings - destructive interference Bright rings - constructive interference MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
27 Newton s Rings Center spot is dark because difference in optical path length is zero MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
28 Newton s Rings Ray 1 is NOT phase shifted at the glassair interface Ray 2 is phase shifted by λ/2 at the airglass interface Dark rings - destructive interference Bright rings - constructive interference For the first rings Dark => 2t = λ Bright => 2t = λ/2 MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
29 Newton s Rings As one moves outward from the center from one dark ring to the next the path difference increases by the same amount λ, a corresponding increase occurs in the thickness of the air layer λ /2. The bottom surface of the lens is curved and the slope of the lens surface increases. Therefore the separation of the rings gets smaller for the outer rings. The radius of the Nth bright ring is given by 1 r = N - N λr MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
30 Measurement Using Interference Normal incidence of monochromatic light light. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
31 What happens on either side of the air Ray 1 is not phase shifted at the glass-air interface Ray 2 is phase shifted at the air-glass interface wedge is what counts Dark band MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
32 First Bright and Dark Lines 1st Bright Line Phase shift already contributes λ /2. Path length delta needs to contribute another λ /2. λ λ 2t = ; t = 2 4 1st Dark Line Phase shift already contributes λ /2. Path length delta needs to contribute λ. λ 2t = λ; t = 2 What happens on either side of the air wedge is what counts Ray 1 is not phase shifted at the top glass-air interface Ray 2 is phase shifted at the bottom air-glass interface MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
33 2t = nλ =λ Small triangle t = λ 2 Large triangle t sinθ = = s T sinθ = L λ 2s θ T L θ t θ T MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
34 θ T 2t = nλ =λ λ t = 2 s θ t L θ L T Small triangle Large triangle t sinθ = = s T sinθ = L λ 2s λ T = 2s L 2 L T = = N D = #Dark lines λ s λ T = N D 2 MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
35 Young s Experiment Double Slit Interference MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
36 Double Slit Interference Pattern MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
37 Double Slit Interference Pattern The intensity equation implies that the bright peaks should all be of equal amplitudes. The decrease in intensity is due to the single slit diffraction pattern of each slit. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
38 Double Slit Calculation ym tanθ m = L -1 ym θ m = tan L Location of the bright lines dsinθ m = mλ; m = 0,1,2,... MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
39 Double Slit Calculation MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
40 Both slits need to be open to observe the interference pattern MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
41 Diffraction Diffraction is the spreading of a wave around an obstacle in its path and it is common to all types of waves. The size of the obstacle must be similar to the wavelength of the wave for the diffraction to be observed. Larger by 10x is too big and smaller by (1/10)x is too small. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
42 Poisson Spot - Arago Spot MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
43 Arago Spot An Arago spot is a bright point that appears at the center of the shadow of a circular object in light from a point source. The spot occurs within the geometrical shadow and no particle theory of light could account for it. Its discovery provided strong evidence for the wave nature of light, In 1818, Siméon Poisson deduced from Augustin Fresnel's theory, the necessity of a bright spot at the centre of the shadow of a circular opaque obstacle. With his counterintuitive result Poisson hoped to disprove the wave theory. Much to Poisson s embarrassment Dominique Arago experimentally verifed the prediction. Dominique Arago supported Jean-Augustin Fresnel's optical theories, and his observation of what is now known as the spot of Arago helped to confirm Fresnel's wave theory of light. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
44 Single Slit Diffraction Pattern MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
45 Single Slit Interference Pattern MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
46 Single Slit - Minimum (Dark) Imagine a number of equally separated points on the wavefront in the single slit opening. Each point is a source of a spherical wavelet. The angle is chosen such that the difference in pathlength from each wavelet source is as shown in the diagram. The waves from points a half slit width apart are 180 o out of phase and cancel. Moving to the next pair, a half slit width apart, they also cancel and so on... The result is a minimum at this special angle 1st Min 1st Min MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
47 Single Slit - Bright Line 2nd Max 2nd Max Imagine 5 equally separated points on the wavefront in the single slit opening. Each point is a source of a spherical wavelet. The angle is chosen such that the difference in path length from each wavelet source is as shown in the diagram. Following the same argument as in the case of the minimum, these waves reinforce in pairs and result in a bright spot on the screen. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
48 Single Slit Interference Pattern y 2 ym tanθ m = L -1 ym θ m = tan L Location of the minima w λ sinθ m = m 2 2 wsinθ = m λ; m = 1,2,... m MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
49 Single Slit Modulates the Double Slit Pattern You see both interference patterns at the same time. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
50 Interference & Diffraction Demos MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
51 Interference & Diffraction Demos MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
52 Diffraction Gratings MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
53 Grating Information Lab gratings: 100, 300 and 600 lines/mm ( 0.100, and.600 lines/µm) These correspond to slit spacings of : 10.0, 3.33 and 1.67 µm Visible light spectrum 400nm nm µm µm Human Hair Diam ~ µm MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
54 Transmission Diffraction Grating MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
55 Diffraction Grating Location of diffraction maxima dsinθ m = mλ; m = 0,1,2,... At the location of a diffraction maximum the differences in the pathlengths from the adjacent slits are equal to a wavelength ym tanθ m = L -1 ym θ m = tan L MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
56 Diffraction Grating - Line Width N is the total number of slits. Nd is the total length of the grating Ndsinθ =λ θ = min min λ Nd This argument is exactly the same as the single slit case. The minimum value of the central peak occurs at θ min. The width of the peak is 2 θ min. As the number of slits increases the peaks become narrower. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
57 Optical Spectroscopy Transmission diffraction grating illuminated with white light In the lab we used a HeNe laser of wavelength 632.8nm so we did not observed this rainbow effect. The observational technique displayed above is not recommended for use with a laser source MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
58 Diffraction Grating Resolving Power The resolving power (R) of a grating is a measure of its ability to separate the light of two very close wavelengths R λ λ = mn λ N = m λ R is defined as the average of the two wavelengths divided by the absolute value of the difference in the two wavelengths. The second equation, a rearrangement of the first, gives the number of slits needed for a given m, λ, and λ. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
59 Diffraction Limited Optics MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
60 Optical Limits Due to Diffraction Question: How close together can two objects be located and still be resolved by an observer as two distinct objects? An image formed on the retina, on photographic film (or CCD) or viewed through a microscope or telescope passes through at least one circular aperture. This aperature acts as a single slit and causes light from an object to spread out in a single slit diffraction pattern. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
61 Diffraction Limited Optics Overlapping single slit diffraction patterns. As the two point sources move closer together, the angle α decreases and the overlap of the diffraction patterns increases. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
62 Limits of Resolution - Rayleigh s Criterion Overlapping single slit diffraction patterns. Question: How much overlap is possible in the diffraction patterns if the observer is to still be able to resolve the patterns as due to two distinct objects? Rayleigh s Criterion - The limit for resolving two objects as being distinct occurs when the maximum of one diffraction pattern is at the location of the first minimum of the other diffraction pattern. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
63 Limits of Resolution - Rayleigh s Criterion Overlapping single slit diffraction patterns. Rayleigh s criterion λ α c = 1.22 D This angular separation represents the Rayleigh criterion. This is similar to the result for the first minimum of the single slit diffraction pattern: sinθ = λ/a. The 1.22 factor is due to the difference between a linear slit and a circular aperture. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
64 Limits of Resolution - Rayleigh s Criterion The illustration below is for 2 objects separated by the Rayleigh criterion. The illustration above is for objects separated by 0.8, 1.0 and 1.2 times the Rayleigh criterion. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
65 X-Ray Scattering MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
66 X-Ray Crystal Scattering Geometry Diffraction occurs when each object in a periodic array scatters radiation coherently, producing concerted constructive interference at specific angles. Basics of X-Ray Diffraction, Scott A Speakman, Ph.D., MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
67 Bragg's Law 2dsinΘ = nλ Diffraction occurs when each object in a periodic array scatters radiation coherently, producing concerted constructive interference at specific angles. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
68 X-Ray Scattering Geometry ( i k iρ F e ) o ikr e r The incident beam amplitude and phase is represented by the first factor. The second factor represents the the spatial variation of the radiation scattered from the atom at ρ. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
69 X-Ray Scattering Wave Vectors ddsfgddg ' k = k - k k = 2ksinΘ = 4π / λ sinθ ( ) MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
70 Ewald Sphere The discrete points represent the lattice points of the reciprocal lattice of the crystal. The Bragg condition is shown here as a requirement that the difference of the incident and scattered wavevectors be a reciprocal lattice vector. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
71 X-Ray Diffraction Pattern - Positive Every point in the reciprocal lattice corresponds to a possible reflection from the crystal lattice. X-ray diffraction experiments provide the reciprocal lattice points and these allow the reconstruction of the crystal lattice. MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
72 X-Ray Powder Diffraction Camera `~ MFMcGraw-PHY 2426 Chap35 & 36-Physical Optics - Revised 7/31/
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