Section 1: C Programming Lab
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1 Course Code : MCSL-017 Course Title : C and Assembly Language Programming (Lab Course) Assignment Number : MCA(1)/015/Assignment/17-18 Maximum Marks : 100 Weightage : 25% Last Dates for Submission : 15th October, 2017 (For July 2017 Session) : 15th April, 2018 (For January 2018 Session) Section 1: C Programming Lab 1. Write an interactive program in C language to create an application program for a small office to maintain the employees database. This application should be having menu options like Creating a New Record Reading/Listing of Records Modify the record Delete the record Each employee record should have Employee Name, Employee ID, Department Name, Salary, Position, Date of Joining, etc). The application should be designed user-friendly. Note: You must execute the program and submit the program logic, sample input and output along with the necessary documentation for this question. Assumptions can be made wherever necessary. Ans: Section 1: C Programming Lab Structure is a user-defined data type in C which allows you to combine different data types to store a particular type of record. Structure helps to construct a complex data type in more meaningful way. It is somewhat similar to an Array. The only difference is that array is used to store collection of similar datatypes while structure can store collection of any type of data. Structure is used to represent a record. Suppose you want to store record of Student which consists of student name, address, roll number and age. You can define a structure to hold this information. Array of Structure: We can declare an array of structure. Each element of the array representing a structure variable. Example : struct employee emp[5];
2 #include <stdio.h> #include <stdlib.h> #include <string.h> #define size 200 struct emp int emp_id; char *emp_name; char *Dept_name; float Salary; char *Pos; int Date; *emp1, *emp3; void create(); void display(); void update(); void delete(); FILE *fp, *fp1; int count = 0; void main(int argc, char **argv) int i, n, ch; printf("1] Create a Record\n"); printf("2] Display Records\n"); printf("3] Update Records\n"); printf( 4] Delete Records\n ); printf("4] Exit"); while (1) printf("\nenter your choice : "); scanf("%d", &ch); switch (ch) case 1: fp = fopen(argv[1], "a"); create(); break; case 2: fp1 = fopen(argv[1],"rb"); display();
3 break; case 3: fp1 = fopen(argv[1], "r+"); update(); break; case 4: exit(0); /* To create an employee record */ void create() int i; char *p; emp1 = (struct emp *)malloc(sizeof(struct emp)); emp1->emp_name = (char *)malloc((size)*(sizeof(char))); emp1 = (struct emp *)malloc(sizeof(struct emp)); emp1->dept_name = (char *)malloc((size)*(sizeof(char))); emp1 = (struct emp *)malloc(sizeof(struct emp)); emp1->pos = (char *)malloc((size)*(sizeof(char))); printf("enter name of employee : "); scanf(" %[^\n]s", emp1-> emp_name); printf("enter emp id : "); scanf(" %d", &emp1-> emp_id); printf("enter name of the Department: "); scanf(" %[^\n]s", emp1-> Dept_name); printf("enter Salary : "); scanf(" %d", &emp1-> Salary); printf("enter Position: "); scanf(" %[^\n]s", emp1-> Pos); printf("enter Date of Joining : "); scanf(" %d", &emp1->date); fwrite(&emp1->emp_id, sizeof(emp1->emp_id), 1, fp); fwrite(emp1->emp_name, size, 1, fp); fwrite(&emp1->dept_name, sizeof(emp1-> Dept_name), 1, fp); fwrite(emp1-> Dept_name, size, 1, fp);
4 fwrite(&emp1-> salary, sizeof(emp1-> salary), 1, fp); fwrite(emp1-> salary, size, 1, fp); fwrite(&emp1->pos, sizeof(emp1-> Pos), 1, fp); fwrite(emp1-> Pos, size, 1, fp); fwrite(&emp1->date, sizeof(emp1-> Date), 1, fp); fwrite(emp1-> Date, size, 1, fp); count++; // count to number of entries of records fclose(fp); /* Display the records in the file */ void display() emp3=(struct emp *)malloc(1*sizeof(struct emp)); emp3->emp_name=(char *)malloc(size*sizeof(char)); int i = 1; if (fp1 == NULL) printf("\nfile not opened for reading"); while (i <= count) fread(&emp3->emp_id, sizeof(emp3->emp_id), 1, fp1); fread(emp3->emp_name, size, 1, fp1); printf("\n%d %s",emp3->emp_id,emp3->emp_name); i++; fclose(fp1); free(emp3->emp_name); free(emp3); void update() int id, flag = 0, i = 1; char s[size]; if (fp1 == NULL) printf("file cant be opened"); return; printf("enter employee id to update : "); scanf("%d", &id); emp3 = (struct emp *)malloc(1*sizeof(struct emp)); emp3->emp_name=(char *)malloc(size*sizeof(char));
5 while(i<=count) fread(&emp3->id, sizeof(emp3->emp_id), 1, fp1); fread(emp3->emp_name,size,1,fp1); if (id == emp3->emp_id) printf("enter new name of emplyee to update : "); scanf(" %[^\n]s", s); fseek(fp1, -204L, SEEK_CUR); fwrite(&emp3->emp_id, sizeof(emp3->id), 1, fp1); fwrite(s, size, 1, fp1); flag = 1; break; i++; if (flag!= 1) printf("no employee record found"); flag = 0; fclose(fp1); free(emp3->name); /* to free allocated memory */ free(emp3); $ a.out emprec1 1] Create a Record 2] Display Records 3] Update Records 4] Delete Record 5] Exit Enter your choice : 1 Enter name of employee : aaa Enter emp id : 100 Enter the name of the Department : Accounting Enter Salary : Enter Position: Audit manager Enter Date of Joining: 10/3/2015 Enter your choice : 1 Enter name of employee : Ram Enter emp id : 101 Enter the name of the Department : Management
6 Enter Salary : Enter Position: Manager Enter Date of Joining: 12/3/2015 Enter Your Choice : 1 Enter name of employee : Shyam Enter emp id : 105 Enter the name of the Department : Management Enter Salary : Enter Position: Junior Manager Enter Date of Joining: 10/4/2015 Enter your choice : 4 Section 2: Assembly Language Programming Lab 1. a) Write a program in assembly language to swap two numbers. Ans: DATA SEGMENT A DB 50H B DB 60H DATA ENDS CODE SEGMENT ASSUME DS:DATA,CS:CODE START: MOV AX,DATA MOV DS,AX MOV AL,A MOV AH,B MOV BL,AL MOV AL,AH MOV AH,BL MOV A,AL MOV B,AH MOV AX,4C00H INT 21H
7 CODE ENDS END START OUTPUT *********** BEFOR ax 0000 bx 0000 AFTER ax 06C1 bx CD36 b) Write a program in assembly language to check whether a number is even or odd. Ans: DATA SEGMENT X DW 27H MSG1 DB 19,13,'NUMBER IS EVEN$' MSG2 DB 10,13,'NUMBER IS ODD$' DATA ENDS CODE SEGMENT ASSUME CS:CODE,DS:DATA START: MOV AX,DATA MOV DS,AX MOV AX,X TEST AX,01H JNZ EXIT LEA DX,MSG1 MOV AH,09H INT 21H JMP LAST ;Test for Even/Odd number. ;If it is Even go to Exit label.
8 c) Write a program in assembly language to load a byte in memory location 8000H and increment the contents of the memory location. Ans: Program 1: MVI A, 32H : Store 32H in the accumulator STA 4000H : Copy accumulator contents at address 4000H HLT : Terminate program execution Program 2: LXI H : Load HL with 4000H MVI M : Store 32H in memory location pointed by HL register pair (4000H) HLT : Terminate program execution d) Write a program in assembly language to reverse a given number. Ans: INCLUDE io.h Cr EQU 0ah Lf EQU 0dh data SEGMENT p_num DB cr, lf, 'Enter a number: ',0 p_rev DB cr, lf,'the reverse is: ',0 ten DW? tmpstr DW 40 DUP (?) data ENDS code SEGMENT ASSUME cs:code, ds:data start: mov ax, data mov ds, ax ;input the number output p_num inputs tmpstr, 10 atoi tmpstr ;initialize mov cx, 00h;stores the reverse number mov ten, 10
9 ;iterate to reverse digits next: cmp ax, 0 jz op_rev;exit the loop if number=0 cwd idiv ten;to extract units digit mov bx, dx;to save contents of dx xchg ax, cx;to perform multiplication imul ten;to insert units digit add ax, bx;add the acutal units digit xchg ax, cx;save the reverse number back jmp next ;output the reverse op_rev: output p_rev itoa tmpstr, cx output tmpstr quit: mov al, 00h mov ah, 4ch int 21h code ENDS END start
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