Stage Computation: Arith/Log. Ops

Size: px
Start display at page:

Download "Stage Computation: Arith/Log. Ops"

Transcription

1 Stage Computation: Arith/Log. Ops OPl ra, rb Fetch icode:ifun M 1 [PC] ra:rb M 1 [PC+1] Read instruction byte Read register byte back valp PC+2 vala R[rA] valb R[rB] vale valb OP vala Set CC R[rB] vale PC valp Compute next PC Read operand A Read operand B Perform ALU operation Set condition code register back result Update PC Formulate instruction execution as sequence of simple steps Use same general form for all instructions 1 CS:APP

2 Stage Computation: rmmovl Fetch rmmovl ra, D(rB) icode:ifun M 1 [PC] ra:rb M 1 [PC+1] valc M 4 [PC+2] valp PC+6 vala R[rA] valb R[rB] vale valb + valc Read instruction byte Read register byte Read displacement D Compute next PC Read operand A Read operand B Compute effective address back M 4 [vale] vala PC valp value to memory Update PC Use ALU for address computation 2 CS:APP

3 Stage Computation: popl popl ra Fetch icode:ifun M 1 [PC] ra:rb M 1 [PC+1] Read instruction byte Read register byte back valp PC+2 vala R[%esp] valb R [%esp] vale valb + 4 valm M 4 [vala] R[%esp] vale R[rA] valm PC valp Compute next PC Read stack pointer Read stack pointer Increment stack pointer Read from stack Update stack pointer back result Update PC Use ALU to increment stack pointer Must update two registers Popped value New stack pointer 3 CS:APP

4 Stage Computation: Jumps jxx Dest icode:ifun M 1 [PC] Read instruction byte Fetch valc M 4 [PC+1] valp PC+5 Read destination address Fall through address back Bch Cond(CC,ifun) PC Bch? valc : valp Take branch? Update PC Compute both addresses Choose based on setting of condition codes and branch condition 4 CS:APP

5 Stage Computation: call call Dest icode:ifun M 1 [PC] Read instruction byte Fetch back valc M 4 [PC+1] valp PC+5 valb R[%esp] vale valb + 4 M 4 [vale] valp R[%esp] vale PC valc Read destination address Compute return point Read stack pointer Decrement stack pointer return value on stack Update stack pointer Set PC to destination Use ALU to decrement stack pointer Store incremented PC 5 CS:APP

6 Stage Computation: ret ret icode:ifun M 1 [PC] Read instruction byte Fetch back vala R[%esp] valb R[%esp] vale valb + 4 valm M 4 [vala] R[%esp] vale PC valm Read operand stack pointer Read operand stack pointer Increment stack pointer Read return address Update stack pointer Set PC to return address Use ALU to increment stack pointer Read return address from memory 6 CS:APP

7 Computation Steps OPl ra, rb Fetch icode,ifun ra,rb valc valp icode:ifun M 1 [PC] ra:rb M 1 [PC+1] valp PC+2 vala, srca vala R[rA] valb, srcb valb R[rB] vale vale valb OP vala Cond code Set CC valm dste R[rB] vale back dstm PC PC valp Read instruction byte Read register byte [Read constant word] Compute next PC Read operand A Read operand B Perform ALU operation Set condition code register [ read/write] back ALU result [ back memory result] Update PC All instructions follow same general pattern Differ in what gets computed on each step 7 CS:APP

8 Computation Steps call Dest icode,ifun icode:ifun M 1 [PC] Read instruction byte Fetch ra,rb valc valc M 4 [PC+1] [Read register byte] Read constant word valp valp PC+5 Compute next PC vala, srca valb, srcb valb R[%esp] [Read operand A] Read operand B vale Cond code vale valb + 4 Perform ALU operation [Set condition code reg.] valm dste M 4 [vale] valp R[%esp] vale [ read/write] [ back ALU result] back dstm PC PC valc back memory result Update PC All instructions follow same general pattern Differ in what gets computed on each step 8 CS:APP

9 Computed Values Fetch icode ifun ra rb valc valp srca srcb dste dstm vala valb Instruction code Instruction function Instr. Register A Instr. Register B Instruction constant Incremented PC Register ID A Register ID B Destination Register E Destination Register M Register value A Register value B vale Bch ALU result Branch flag valm Value from memory 9 CS:APP

10 Logic Register File Read ports A, B ports E, M Addresses are register IDs or 8 (no access) vala valb A B M Register file E dste dstm srca srcb dste dstm srca srcb valm vale Control Logic srca, srcb: read port addresses dsta, dstb: write port addresses icode ra rb 10 CS:APP

11 A Source OPl ra, rb vala R[rA] rmmovl ra, D(rB) vala R[rA] popl ra vala R[%esp] jxx Dest call Dest ret vala R[%esp] Read operand A Read operand A Read stack pointer No operand No operand Read stack pointer int srca = [ icode in { IRRMOVL, IRMMOVL, IOPL, IPUSHL } : ra; icode in { IPOPL, IRET } : RESP; 1 : RNONE; # Don't need register ]; 11 CS:APP

12 E Destination -back -back -back -back -back -back OPl ra, rb R[rB] vale rmmovl ra, D(rB) popl ra R[%esp] vale jxx Dest call Dest R[%esp] vale ret R[%esp] vale back result None Update stack pointer None Update stack pointer Update stack pointer int dste = [ icode in { IRRMOVL, IIRMOVL, IOPL} : rb; icode in { IPUSHL, IPOPL, ICALL, IRET } : RESP; 1 : RNONE; # Don't need register ]; 12 CS:APP

13 Logic Units ALU Implements 4 required functions Generates condition code values CC Register with 3 condition code bits bcond Computes branch flag Control Logic Set CC: Should condition code register be loaded? ALU A: Input A to ALU ALU B: Input B to ALU ALU fun: What function should ALU compute? Bch bcond CC Set CC ALU A vale ALU ALU B icode ifun valc vala valb ALU fun. 13 CS:APP

14 ALU A Input OPl ra, rb vale valb OP vala rmmovl ra, D(rB) vale valb + valc popl ra vale valb + 4 jxx Dest call Dest vale valb + 4 Perform ALU operation Compute effective address Increment stack pointer No operation Decrement stack pointer ret vale valb + 4 Increment stack pointer int alua = [ icode in { IRRMOVL, IOPL } : vala; icode in { IIRMOVL, IRMMOVL, IMRMOVL } : valc; icode in { ICALL, IPUSHL } : -4; icode in { IRET, IPOPL } : 4; # Other instructions don't need ALU ]; 14 CS:APP

15 ALU Operation OPl ra, rb vale valb OP vala Perform ALU operation rmmovl ra, D(rB) vale valb + valc popl ra vale valb + 4 jxx Dest call Dest vale valb + 4 Compute effective address Increment stack pointer No operation Decrement stack pointer ret vale valb + 4 Increment stack pointer int alufun = [ icode == IOPL : ifun; 1 : ALUADD; ]; 15 CS:APP

16 Logic valm Reads or writes memory word Control Logic Mem. read: should word be read? Mem. write: should word be written? Mem. addr.: Select address icode Mem. read Mem. write read write Data memory Mem addr vale data out Mem data data in vala valp Mem. data.: Select data 16 CS:APP

17 Address OPl ra, rb No operation rmmovl ra, D(rB) M 4 [vale] vala popl ra valm M 4 [vala] value to memory Read from stack jxx Dest No operation call Dest M 4 [vale] valp ret valm M 4 [vala] return value on stack Read return address int mem_addr = [ icode in { IRMMOVL, IPUSHL, ICALL, IMRMOVL } : vale; icode in { IPOPL, IRET } : vala; # Other instructions don't need address ]; 17 CS:APP

18 Read OPl ra, rb rmmovl ra, D(rB) M 4 [vale] vala popl ra valm M 4 [vala] No operation value to memory Read from stack jxx Dest No operation call Dest M 4 [vale] valp ret valm M 4 [vala] return value on stack Read return address bool mem_read = icode in { IMRMOVL, IPOPL, IRET }; 18 CS:APP

19 PC Update Logic PC New PC Select next value of PC New PC icode Bch valc valm valp 19 CS:APP

20 PC Update OPl ra, rb PC valp rmmovl ra, D(rB) PC valp Update PC Update PC popl ra PC valp Update PC jxx Dest PC Bch? valc : valp Update PC call Dest PC valc Set PC to destination ret PC valm Set PC to return address int new_pc = [ icode == ICALL : valc; icode == IJXX && Bch : valc; icode == IRET : valm; 1 : valp; ]; 20 CS:APP

21 SEQ Operation State PC register Combinational Logic CC Read Read Ports Data memory Register file Ports Cond. Code register Data memory Register file All updated as clock rises Combinational Logic ALU Control logic PC 0x00c reads Instruction memory Register file Data memory 21 CS:APP

22 SEQ Operation #2 Clock Cycle 1: Cycle 2: Cycle 3: Cycle 4: Cycle 1 Cycle 2 Cycle 3 Cycle 4 0x000: irmovl $0x100,%ebx # %ebx <-- 0x100 0x006: irmovl $0x200,%edx # %edx <-- 0x200 0x00c: addl %edx,%ebx # %ebx <-- 0x300 CC < x00e: je dest # Not taken Combinational Logic CC 100 Read Read Ports Data memory Register file %ebx = 0x100 Ports state set according to second irmovl instruction combinational logic starting to react to state changes PC 0x00c 22 CS:APP

23 SEQ Operation #3 Clock Cycle 1: Cycle 2: Cycle 3: Cycle 4: Cycle 1 Cycle 2 Cycle 3 Cycle 4 0x000: irmovl $0x100,%ebx # %ebx <-- 0x100 0x006: irmovl $0x200,%edx # %edx <-- 0x200 0x00c: addl %edx,%ebx # %ebx <-- 0x300 CC < x00e: je dest # Not taken Combinational Logic CC Read Read Ports Data memory Register file %ebx = 0x100 Ports state set according to second irmovl instruction combinational logic generates results for addl instruction 0x00e PC 0x00c 23 CS:APP

24 SEQ Operation #4 Clock Cycle 1: Cycle 2: Cycle 3: Cycle 4: Cycle 1 Cycle 2 Cycle 3 Cycle 4 0x000: irmovl $0x100,%ebx # %ebx <-- 0x100 0x006: irmovl $0x200,%edx # %edx <-- 0x200 0x00c: addl %edx,%ebx # %ebx <-- 0x300 CC < x00e: je dest # Not taken Combinational Logic CC 000 Read Read Ports Data memory Register file %ebx = 0x300 Ports state set according to addl instruction combinational logic starting to react to state changes PC 0x00e 24 CS:APP

25 SEQ Operation #5 Clock Cycle 1: Cycle 2: Cycle 3: Cycle 4: Cycle 1 Cycle 2 Cycle 3 Cycle 4 0x000: irmovl $0x100,%ebx # %ebx <-- 0x100 0x006: irmovl $0x200,%edx # %edx <-- 0x200 0x00c: addl %edx,%ebx # %ebx <-- 0x300 CC < x00e: je dest # Not taken Combinational Logic CC 000 Read Data memory Read Ports Ports Register file %ebx = 0x300 state set according to addl instruction combinational logic generates results for je instruction 0x013 PC 0x00e 25 CS:APP

Systems I. Datapath Design II. Topics Control flow instructions Hardware for sequential machine (SEQ)

Systems I. Datapath Design II. Topics Control flow instructions Hardware for sequential machine (SEQ) Systems I Datapath Design II Topics Control flow instructions Hardware for sequential machine (SEQ) Executing Jumps jxx Dest 7 fn Dest fall thru: XX XX Not taken target: XX XX Taken Fetch Decode Read 5

More information

CS:APP Chapter 4 Computer Architecture Sequential Implementation

CS:APP Chapter 4 Computer Architecture Sequential Implementation CS:APP Chapter 4 Computer Architecture Sequential Implementation Randal E. Bryant Carnegie Mellon University http://csapp.cs.cmu.edu CS:APP Y86 Instruction Set Byte 0 1 2 3 4 5 nop 0 0 halt 1 0 rrmovl

More information

Computer Science 104:! Y86 & Single Cycle Processor Design!

Computer Science 104:! Y86 & Single Cycle Processor Design! Computer Science 104: Y86 & Single Cycle Processor Design Alvin R. Lebeck Slides based on those from Randy Bryant CS:APP Administrative HW #4 Due tomorrow tonight HW #5 up soon ing: 4.1-4.3 Today Review

More information

Giving credit where credit is due

Giving credit where credit is due CSCE 230J Computer Organization Processor Architecture III: Sequential Implementation Dr. Steve Goddard goddard@cse.unl.edu http://cse.unl.edu/~goddard/courses/csce230j Giving credit where credit is due

More information

CISC Fall 2009

CISC Fall 2009 Michela Taufer October 20, 2009 Powerpoint Lecture Notes for Computer Systems: A Programmer's Perspective, R. Bryant and D. O'Hallaron, Prentice Hall, 2003 Y86 Instruction Set Byte 0 1 2 3 4 5 nop 0 0

More information

Processor Architecture II! Sequential! Implementation!

Processor Architecture II! Sequential! Implementation! Processor Architecture II! Sequential! Implementation! Lecture 6, April 14 th 2011 Alexandre David Slides by Randal E. Bryant! Carnegie Mellon University! Y86 Instruction Set! Byte! 0 1 2 3 4 5 nop 0 0

More information

Computer Science 104:! Y86 & Single Cycle Processor Design!

Computer Science 104:! Y86 & Single Cycle Processor Design! Computer Science 104:! Y86 & Single Cycle Processor Design! Alvin R. Lebeck! Slides based on those from Randy Bryant CS:APP! Administrative! 2! CS:APP! Y86 Instruction Set! Byte! 0 1 2 3 4 5 nop 0 0 halt

More information

Chapter 4! Processor Architecture!!

Chapter 4! Processor Architecture!! Chapter 4! Processor Architecture!! Sequential Implementation! Instructor: Dr. Hyunyoung Lee! Texas A&M University! Based on slides provided by Randal E. Bryant, CMU Topics Covered! Hardware Control Language

More information

Sequential Implementation

Sequential Implementation CS:APP Chapter 4 Computer Architecture Sequential Implementation Randal E. Bryant adapted by Jason Fritts http://csapp.cs.cmu.edu CS:APP2e Hardware Architecture - using Y86 ISA For learning aspects of

More information

CS:APP Chapter 4 Computer Architecture Sequential Implementation

CS:APP Chapter 4 Computer Architecture Sequential Implementation CS:APP Chapter 4 Computer Architecture Sequential Implementation Randal E. Bryant Carnegie Mellon University http://csapp.cs.cmu.edu CS:APP Y86 Instruction Set Byte 0 1 2 3 4 5 nop 0 0 halt 1 0 rrmovl

More information

CS:APP Chapter 4! Computer Architecture! Sequential! Implementation!

CS:APP Chapter 4! Computer Architecture! Sequential! Implementation! CS:APP Chapter 4! Computer Architecture! Sequential! Implementation! Randal E. Bryant! Carnegie Mellon University! http://csapp.cs.cmu.edu CS:APP2e! Y86 Instruction Set #1! Byte! 0 1 2 3 4 5 halt 0 0 nop

More information

God created the integers, all else is the work of man Leopold Kronecker

God created the integers, all else is the work of man Leopold Kronecker Sequential Hardware God created the integers, all else is the work of man Leopold Kronecker (He believed in the reduction of all mathematics to arguments involving only the integers and a finite number

More information

CS:APP Chapter 4 Computer Architecture Sequential Implementation

CS:APP Chapter 4 Computer Architecture Sequential Implementation CS:APP Chapter 4 Computer Architecture Sequential Implementation Randal E. Bryant Carnegie Mellon University CS:APP Y86 Instruction Set Byte ra rb ra rb V rb rb V ra D rb ra rb D D rb ra ra rb D ra rb

More information

Systems I. Datapath Design II. Topics Control flow instructions Hardware for sequential machine (SEQ)

Systems I. Datapath Design II. Topics Control flow instructions Hardware for sequential machine (SEQ) Systems I Datapath Design II Topics Control flow instructions Hardware for sequential machine (SEQ) Executing Jumps jxx Dest 7 fn Dest fall thru: XX XX Not taken target: XX XX Taken Read 5 bytes Increment

More information

Background: Sequential processor design. Computer Architecture and Systems Programming , Herbstsemester 2013 Timothy Roscoe

Background: Sequential processor design. Computer Architecture and Systems Programming , Herbstsemester 2013 Timothy Roscoe Background: Sequential processor design Computer Architecture and Systems Programming 252 0061 00, Herbstsemester 2013 Timothy Roscoe Overview Y86 instruction set architecture Processor state Instruction

More information

Giving credit where credit is due

Giving credit where credit is due JDEP 284H Foundations of Computer Systems Processor rchitecture III: Sequential Implementation Dr. Steve Goddard goddard@cse.unl.edu Giving credit where credit is due Most of slides for this lecture are

More information

Computer Science 104:! Y86 & Single Cycle Processor Design!

Computer Science 104:! Y86 & Single Cycle Processor Design! Computer Science 104: Y86 & Single Cycle Processor Design Alvin R. Lebeck Slides based on those from Randy Bryant 1 CS:APP Administrative Homework #4 My office hours today 11:30-12:30 Reading: text 4.3

More information

Computer Science 104:! Y86 & Single Cycle Processor Design!

Computer Science 104:! Y86 & Single Cycle Processor Design! Computer Science 104:! Y86 & Single Cycle Processor Design! Alvin R. Lebeck! Slides based on those from Randy Bryant 1! CS:APP! CS:APP! Administrative! 2! CS:APP! Instruction Set Architecture! Application!

More information

CS429: Computer Organization and Architecture

CS429: Computer Organization and Architecture CS429: Computer Organization and Architecture Dr Bill Young Department of Computer Sciences University of Texas at Austin Last updated: March 15, 2018 at 10:58 CS429 Slideset 13: 1 The ISA Byte 0 1 2 3

More information

Sequential CPU Implementation.

Sequential CPU Implementation. Sequential CPU Implementation Y86 Instruction Set P259 Byte 0 1 2 3 4 5 nop 0 0 halt 1 0 rrmovl ra, rb 2 0 ra rb irmovl V, rb 3 0 8 rb V rmmovl ra, D(rB) 4 0 ra rb D mrmovl D(rB), ra 5 0 ra rb D OPl ra,

More information

Y86 Instruction Set. SEQ Hardware Structure. SEQ Stages. Sequential Implementation. Lecture 8 Computer Architecture III.

Y86 Instruction Set. SEQ Hardware Structure. SEQ Stages. Sequential Implementation. Lecture 8 Computer Architecture III. Building Blocks Combinational Logic Compute Boolean functions of inputs Continuously respond to input changes Operate on data and implement control Storage Elements Store bits Lecture 8 Computer rchitecture

More information

Where Have We Been? Logic Design in HCL. Assembly Language Instruction Set Architecture (Y86) Finite State Machines

Where Have We Been? Logic Design in HCL. Assembly Language Instruction Set Architecture (Y86) Finite State Machines Where Have We Been? Assembly Language Instruction Set Architecture (Y86) Finite State Machines States and Transitions Events Where Are We Going? Tracing Instructions at the Register Level Build a CPU!

More information

The ISA. Fetch Logic

The ISA. Fetch Logic The ISA CS429: Computer Organization and Architecture Dr Bill Young Department of Computer Science University of Texas at Austin Last updated: July 5, 2018 at 11:55 Byte 0 1 2 3 4 5 6 7 8 9 halt 0 0 nop

More information

Overview. CS429: Computer Organization and Architecture. Y86 Instruction Set. Building Blocks

Overview. CS429: Computer Organization and Architecture. Y86 Instruction Set. Building Blocks Overview CS429: Computer Organization and Architecture Dr. Bill Young Department of Computer Sciences University of Texas at Austin Last updated: March 15, 2018 at 10:54 How do we build a digital computer?

More information

CISC: Stack-intensive procedure linkage. [Early] RISC: Register-intensive procedure linkage.

CISC: Stack-intensive procedure linkage. [Early] RISC: Register-intensive procedure linkage. CISC: Stack-intensive procedure linkage. The stack is used for procedure arguments and return addresses. [Early] RISC: Register-intensive procedure linkage. Registers are used for procedure arguments and

More information

cmovxx ra, rb 2 fn ra rb irmovq V, rb 3 0 F rb V rmmovq ra, D(rB) 4 0 ra rb D mrmovq D(rB), ra 5 0 ra rb D OPq ra, rb 6 fn ra rb jxx Dest 7 fn Dest

cmovxx ra, rb 2 fn ra rb irmovq V, rb 3 0 F rb V rmmovq ra, D(rB) 4 0 ra rb D mrmovq D(rB), ra 5 0 ra rb D OPq ra, rb 6 fn ra rb jxx Dest 7 fn Dest Computer Architecture: Y86-64 Sequential Implementation CSci 2021: Machine Architecture and Organization Lecture #19, March 4th, 2016 Your instructor: Stephen McCamant Based on slides originally by: Randy

More information

Foundations of Computer Systems

Foundations of Computer Systems 18-600 Foundations of Computer Systems Lecture 7: Processor Architecture & Design John P. Shen & Gregory Kesden September 20, 2017 Lecture #7 Processor Architecture & Design Lecture #8 Pipelined Processor

More information

cmovxx ra, rb 2 fn ra rb irmovq V, rb 3 0 F rb V rmmovq ra, D(rB) 4 0 ra rb D mrmovq D(rB), ra 5 0 ra rb D OPq ra, rb 6 fn ra rb jxx Dest 7 fn Dest

cmovxx ra, rb 2 fn ra rb irmovq V, rb 3 0 F rb V rmmovq ra, D(rB) 4 0 ra rb D mrmovq D(rB), ra 5 0 ra rb D OPq ra, rb 6 fn ra rb jxx Dest 7 fn Dest Computer Architecture: Y86-64 Sequential Implementation CSci 2021: Machine Architecture and Organization October 31st, 2018 Your instructor: Stephen McCamant Based on slides originally by: Randy Bryant

More information

For Tuesday. Finish Chapter 4. Also, Project 2 starts today

For Tuesday. Finish Chapter 4. Also, Project 2 starts today For Tuesday Finish Chapter 4 Also, Project 2 starts today 1 Sequential Y86 Implementation 1. Fetch From icode (4 bits) & ifun (4 bits) [valc (4bytes)] Calc valp 2. Decode: get ra [rb] [%esp] 3. Execute

More information

CSC 252: Computer Organization Spring 2018: Lecture 11

CSC 252: Computer Organization Spring 2018: Lecture 11 CSC 252: Computer Organization Spring 2018: Lecture 11 Instructor: Yuhao Zhu Department of Computer Science University of Rochester Action Items: Assignment 3 is due March 2, midnight Announcement Programming

More information

cs281: Introduction to Computer Systems CPUlab Datapath Assigned: Oct. 29, Due: Nov. 3

cs281: Introduction to Computer Systems CPUlab Datapath Assigned: Oct. 29, Due: Nov. 3 cs281: Introduction to Computer Systems CPUlab Datapath Assigned: Oct. 29, Due: Nov. 3 The objective of this exercise is to familiarize you with the Datapath of the Y86 CPU and to introduce you to the

More information

Computer Organization Chapter 4. Prof. Qi Tian Fall 2013

Computer Organization Chapter 4. Prof. Qi Tian Fall 2013 Computer Organization Chapter 4 Prof. Qi Tian Fall 2013 1 Topics Dec. 6 (Friday) Final Exam Review Record Check Dec. 4 (Wednesday) 5 variable Karnaugh Map Quiz 5 Dec. 2 (Monday) 3, 4 variables Karnaugh

More information

CS:APP Chapter 4 Computer Architecture Pipelined Implementation

CS:APP Chapter 4 Computer Architecture Pipelined Implementation CS:APP Chapter 4 Computer Architecture Pipelined Implementation Part II Randal. Bryant Carnegie ellon University http://csapp.cs.cmu.edu CS:APP Overview ata Hazards ake the pipelined processor work! Instruction

More information

cs281: Computer Systems CPUlab ALU and Datapath Assigned: Oct. 30, Due: Nov. 8 at 11:59 pm

cs281: Computer Systems CPUlab ALU and Datapath Assigned: Oct. 30, Due: Nov. 8 at 11:59 pm cs281: Computer Systems CPUlab ALU and Datapath Assigned: Oct. 30, Due: Nov. 8 at 11:59 pm The objective of this exercise is twofold to complete a combinational circuit for an ALU that we can use with

More information

Systems I. Pipelining II. Topics Pipelining hardware: registers and feedback paths Difficulties with pipelines: hazards Method of mitigating hazards

Systems I. Pipelining II. Topics Pipelining hardware: registers and feedback paths Difficulties with pipelines: hazards Method of mitigating hazards Systems I Pipelining II Topics Pipelining hardware: registers and feedback paths ifficulties with pipelines: hazards Method of mitigating hazards Adding Pipeline Registers val, valm _icode, _valm rite

More information

Michela Taufer CS:APP

Michela Taufer CS:APP ichela Taufer CS:APP Powerpoint Lecture Notes for Computer Systems: A Programmer's Perspective, R. Bryant and. O'Hallaron, Prentice Hall, 2003 Overview 2 CISC 360 Faʼ08 Pipeline Stages W_icode, W_val W

More information

Term-Level Verification of a Pipelined CISC Microprocessor

Term-Level Verification of a Pipelined CISC Microprocessor Term-Level Verification of a Pipelined CISC Microprocessor Randal E. Bryant December, 2005 CMU-CS-05-195 School of Computer Science Carnegie Mellon University Pittsburgh, PA 15213 This work was supported

More information

Byte. cmovle 7 1. halt 0 0 addq 6 0 nop 1 0 subq 6 1 cmovxx ra, rb 2 fn ra rb andq 6 2 irmovq V, rb 3 0 F rb V xorq 6 3. cmovl 7 2.

Byte. cmovle 7 1. halt 0 0 addq 6 0 nop 1 0 subq 6 1 cmovxx ra, rb 2 fn ra rb andq 6 2 irmovq V, rb 3 0 F rb V xorq 6 3. cmovl 7 2. Y86-6 Instruc&on Set Computer rchitecture Sequen&al Implementa&on CSCI 202: Machine rchitecture and Organiza&on Byte 0 2 3 5 6 7 8 9 2 fn r rb irmovq V, rb 3 0 F rb V 0 r rb Pen- Chung Yew epartment Computer

More information

Review. Computer Science 104 Machine Organization & Programming

Review. Computer Science 104 Machine Organization & Programming Review Computer Science 104 Machine Organization & Programming Administrative 104/16 Processor Due today Final Sunday Dec 18, 2-5pm in D106 Today Ø high-level review Ø Q&A Alex will review sometime, watch

More information

CS:APP Chapter 4 Computer Architecture Wrap-Up Randal E. Bryant Carnegie Mellon University

CS:APP Chapter 4 Computer Architecture Wrap-Up Randal E. Bryant Carnegie Mellon University CS:APP Chapter 4 Computer Architecture Wrap-Up Randal E. Bryant Carnegie Mellon University http://csapp.cs.cmu.edu CS:APP Overview Wrap-Up of PIPE Design Performance analysis Fetch stage design Exceptional

More information

CS:APP Chapter 4 Computer Architecture Wrap-Up Randal E. Bryant Carnegie Mellon University

CS:APP Chapter 4 Computer Architecture Wrap-Up Randal E. Bryant Carnegie Mellon University CS:APP Chapter 4 Computer Architecture Wrap-Up Randal E. Bryant Carnegie Mellon University http://csapp.cs.cmu.edu CS:APP2e Overview Wrap-Up of PIPE Design Exceptional conditions Performance analysis Fetch

More information

SEQ part 3 / HCLRS 1

SEQ part 3 / HCLRS 1 SEQ part 3 / HCLRS 1 Changelog 1 Changes made in this version not seen in first lecture: 21 September 2017: data memory value MUX input for call is PC + 10, not PC 21 September 2017: slide 23: add input

More information

Systems I. Pipelining IV

Systems I. Pipelining IV Systems I Pipelining IV Topics Implementing pipeline control Pipelining and performance analysis Implementing Pipeline Control W icode val val dst dst _icode icode Bch val vala dst dst e_bch Pipe control

More information

Chapter 4 Processor Architecture: Y86 (Sections 4.1 & 4.3) with material from Dr. Bin Ren, College of William & Mary

Chapter 4 Processor Architecture: Y86 (Sections 4.1 & 4.3) with material from Dr. Bin Ren, College of William & Mary Chapter 4 Processor Architecture: Y86 (Sections 4.1 & 4.3) with material from Dr. Bin Ren, College of William & Mary 1 Outline Introduction to assembly programing Introduction to Y86 Y86 instructions,

More information

Systems I. Pipelining IV

Systems I. Pipelining IV Systems I Pipelining IV Topics Implementing pipeline control Pipelining and performance analysis Implementing Pipeline Control W icode val val dst dst _icode icode Bch val vala dst dst e_bch Pipe control

More information

Giving credit where credit is due

Giving credit where credit is due CSC 230J Computer Organization Processor rchitecture V: aking the Pipelined Implementation ork r. Steve Goddard goddard@cse.unl.edu http://cse.unl.edu/~goddard/courses/csc230j Giving credit where credit

More information

CPSC 121: Models of Computation. Module 10: A Working Computer

CPSC 121: Models of Computation. Module 10: A Working Computer CPSC 121: Models of Computation Module 10: A Working Computer Module 10: A Working Computer???build a computer that is?able to 1. How can we?execute a user-defined program? We are finally able to answer

More information

Midterm Exam CSC February 2009

Midterm Exam CSC February 2009 Midterm Exam CSC 252 26 February 2009 Directions; PLEASE READ This exam has 7 questions, all of which have subparts. Each question indicates its point value. The total is 90 points. Questions 3(d) and

More information

Foundations of Computer Systems

Foundations of Computer Systems 18-600 Foundations of Computer Systems Lecture 8: Pipelined Processor Design John P. Shen & Gregory Kesden September 25, 2017 Lecture #7 Processor Architecture & Design Lecture #8 Pipelined Processor Design

More information

CPSC 313, Summer 2013 Final Exam Date: June 24, 2013; Instructor: Mike Feeley

CPSC 313, Summer 2013 Final Exam Date: June 24, 2013; Instructor: Mike Feeley CPSC 313, Summer 2013 Final Exam Date: June 24, 2013; Instructor: Mike Feeley This is a closed-book exam. No outside notes. Electronic calculators are permitted. You may remove the last two pages of the

More information

CPSC 121: Models of Computation. Module 10: A Working Computer

CPSC 121: Models of Computation. Module 10: A Working Computer CPSC 121: Models of Computation The 10th online quiz is due Tuesday, March 26 th at 17:00. Assigned reading for the quiz: Epp, 4th edition: 6.1, 7.1 Epp, 3rd edition: 5.1, 6.1 Rosen, 6th edition: 2.1,

More information

Changelog. Changes made in this version not seen in first lecture: 13 Feb 2018: add slide on constants and width

Changelog. Changes made in this version not seen in first lecture: 13 Feb 2018: add slide on constants and width HCL 1 Changelog 1 Changes made in this version not seen in first lecture: 13 Feb 2018: add slide on constants and width simple ISA 4: mov-to-register 2 irmovq $constant, %ryy rrmovq %rxx, %ryy mrmovq 10(%rXX),

More information

Reading assignment. Chapter 3.1, 3.2 Chapter 4.1, 4.3

Reading assignment. Chapter 3.1, 3.2 Chapter 4.1, 4.3 Reading assignment Chapter 3.1, 3.2 Chapter 4.1, 4.3 1 Outline Introduc5on to assembly programing Introduc5on to Y86 Y86 instruc5ons, encoding and execu5on 2 Assembly The CPU uses machine language to perform

More information

CS 3330: SEQ part September 2016

CS 3330: SEQ part September 2016 1 CS 3330: SEQ part 2 15 September 2016 Recall: Timing 2 compute new values between rising edges compute compute compute compute clock signal registers, memories change at rising edges next value register

More information

CS:APP Guide to Y86 Processor Simulators

CS:APP Guide to Y86 Processor Simulators CS:APP Guide to Y86 Processor Simulators Randal E. Bryant David R. O Hallaron November 4, 2004 Copyright c 2002, R. E. Bryant, D. R. O Hallaron. All rights reserved. 1 This document describes the processor

More information

Instruction Set Architecture

Instruction Set Architecture CS:APP Chapter 4 Computer Architecture Instruction Set Architecture Randal E. Bryant adapted by Jason Fritts http://csapp.cs.cmu.edu CS:APP2e Hardware Architecture - using Y86 ISA For learning aspects

More information

Wrap-Up. CS:APP Chapter 4 Computer Architecture. Overview. Performance Metrics. CPI for PIPE. Randal E. Bryant. Carnegie Mellon University

Wrap-Up. CS:APP Chapter 4 Computer Architecture. Overview. Performance Metrics. CPI for PIPE. Randal E. Bryant. Carnegie Mellon University CS:APP Chapter 4 Computer Architecture rap-up Overview rap-up of PIP esign Performance analysis etch stage design xceptional conditions odern High-Performance Processors Out-of-order execution Randal.

More information

bitwise (finish) / SEQ part 1

bitwise (finish) / SEQ part 1 bitwise (finish) / SEQ part 1 1 Changelog 1 Changes made in this version not seen in first lecture: 14 September 2017: slide 16-17: the x86 arithmetic shift instruction is sar, not sra last time 2 bitwise

More information

CPSC 313, Winter 2016 Term 1 Sample Date: October 2016; Instructor: Mike Feeley

CPSC 313, Winter 2016 Term 1 Sample Date: October 2016; Instructor: Mike Feeley CPSC 313, Winter 2016 Term 1 Sample Date: October 2016; Instructor: Mike Feeley NOTE: This sample contains all of the question from the two CPSC 313 midterms for Summer 2015. This term s midterm will be

More information

Instruction Set Architecture

Instruction Set Architecture CS:APP Chapter 4 Computer Architecture Instruction Set Architecture Randal E. Bryant Carnegie Mellon University http://csapp.cs.cmu.edu CS:APP Instruction Set Architecture Assembly Language View Processor

More information

Instruction Set Architecture

Instruction Set Architecture CS:APP Chapter 4 Computer Architecture Instruction Set Architecture Randal E. Bryant Carnegie Mellon University http://csapp.cs.cmu.edu CS:APP Instruction Set Architecture Assembly Language View! Processor

More information

Wrap-Up. Lecture 10 Computer Architecture V. Performance Metrics. Overview. CPI for PIPE (Cont.) CPI for PIPE. Clock rate

Wrap-Up. Lecture 10 Computer Architecture V. Performance Metrics. Overview. CPI for PIPE (Cont.) CPI for PIPE. Clock rate Lecture 10 Computer Architecture V Overview rap-up of PIP esign Performance analysis etch stage design xceptional conditions rap-up Performance etrics Clock rate easured in egahertz or Gigahertz unction

More information

Computer Systems: A Programmer s Perspective Instructor s Solution Manual 1

Computer Systems: A Programmer s Perspective Instructor s Solution Manual 1 Computer Systems: A Programmer s Perspective Instructor s Solution Manual 1 Randal E. Bryant David R. O Hallaron December 4, 2003 1 Copyright c 2003, R. E. Bryant, D. R. O Hallaron. All rights reserved.

More information

Wrap-Up. Lecture 10 Computer Architecture V. Performance Metrics. Overview. CPI for PIPE (Cont.) CPI for PIPE. Clock rate

Wrap-Up. Lecture 10 Computer Architecture V. Performance Metrics. Overview. CPI for PIPE (Cont.) CPI for PIPE. Clock rate Lecture 10 Computer Architecture V Overview rap-up of PIP esign Performance analysis etch stage design xceptional conditions odern High-Performance Processors Out-of-order execution rap-up 10 1 atorarkitektur

More information

Datorarkitektur, 2009 Tentamen

Datorarkitektur, 2009 Tentamen Namn: Personnummer: Datorarkitektur, 2009 Tentamen 2009-03-13 Instructions: Make sure that your exam is not missing any sheets, then write your full name on the front. Write your answers in the space provided

More information

CPSC 121: Models of Computation Lab #9: A Working Computer

CPSC 121: Models of Computation Lab #9: A Working Computer CPSC 121: Models of Computation Lab #9: A Working Computer Objectives In this lab, we revisit the Y86 processor, which you saw components of in labs 4 and 6. Recall that in lab 4, you learned about the

More information

CS:APP3e Web Aside ARCH:HCL: HCL Descriptions of Y86-64 Processors

CS:APP3e Web Aside ARCH:HCL: HCL Descriptions of Y86-64 Processors CS:APP3e Web Aside ARCH:HCL: HCL Descriptions of Y86-64 Processors Randal E. Bryant David R. O Hallaron December 29, 2014 Notice The material in this document is supplementary material to the book Computer

More information

CPSC 313, Summer 2013 Final Exam Solution Date: June 24, 2013; Instructor: Mike Feeley

CPSC 313, Summer 2013 Final Exam Solution Date: June 24, 2013; Instructor: Mike Feeley CPSC 313, Summer 2013 Final Exam Solution Date: June 24, 2013; Instructor: Mike Feeley 1 (10 marks) This question is concerned with the general principles of pipelining, dependencies and hazards. First,

More information

CS429: Computer Organization and Architecture

CS429: Computer Organization and Architecture CS429: Computer Organization and Architecture Warren Hunt, Jr. and Bill Young Department of Computer Sciences University of Texas at Austin Last updated: October 1, 2014 at 12:03 CS429 Slideset 6: 1 Topics

More information

Giving credit where credit is due

Giving credit where credit is due CSC 230J Computer Organization Processor Architecture VI: rap-up r. Steve Goddard goddard@cse.unl.edu Giving credit where credit is due ost of slides for this lecture are based on slides created by r.

More information

Data Hazard vs. Control Hazard. CS429: Computer Organization and Architecture. How Do We Fix the Pipeline? Possibilities: How Do We Fix the Pipeline?

Data Hazard vs. Control Hazard. CS429: Computer Organization and Architecture. How Do We Fix the Pipeline? Possibilities: How Do We Fix the Pipeline? Data Hazard vs. Control Hazard CS429: Computer Organization and Architecture There are two types of hazards that interfere with flow through a pipeline. Dr. Bill Young Department of Computer Science University

More information

CS429: Computer Organization and Architecture

CS429: Computer Organization and Architecture CS429: Computer Organization and Architecture Dr. Bill Young Department of Computer Sciences University of Texas at Austin Last updated: April 4, 2018 at 07:36 CS429 Slideset 16: 1 Data Hazard vs. Control

More information

Assembly I: Basic Operations. Jo, Heeseung

Assembly I: Basic Operations. Jo, Heeseung Assembly I: Basic Operations Jo, Heeseung Moving Data (1) Moving data: movl source, dest Move 4-byte ("long") word Lots of these in typical code Operand types Immediate: constant integer data - Like C

More information

Processor Architecture

Processor Architecture Processor Architecture God created the integers, all else is the work of man Leopold Kronecker (He believed in the reduction of all mathematics to arguments involving only the integers and a finite number

More information

ASSEMBLY I: BASIC OPERATIONS. Jo, Heeseung

ASSEMBLY I: BASIC OPERATIONS. Jo, Heeseung ASSEMBLY I: BASIC OPERATIONS Jo, Heeseung MOVING DATA (1) Moving data: movl source, dest Move 4-byte ("long") word Lots of these in typical code Operand types Immediate: constant integer data - Like C

More information

Y86 Processor State. Instruction Example. Encoding Registers. Lecture 7A. Computer Architecture I Instruction Set Architecture Assembly Language View

Y86 Processor State. Instruction Example. Encoding Registers. Lecture 7A. Computer Architecture I Instruction Set Architecture Assembly Language View Computer Architecture I Instruction Set Architecture Assembly Language View Processor state Registers, memory, Instructions addl, movl, andl, How instructions are encoded as bytes Layer of Abstraction

More information

CISC 360 Instruction Set Architecture

CISC 360 Instruction Set Architecture CISC 360 Instruction Set Architecture Michela Taufer October 9, 2008 Powerpoint Lecture Notes for Computer Systems: A Programmer's Perspective, R. Bryant and D. O'Hallaron, Prentice Hall, 2003 Chapter

More information

Instruction Set Architecture

Instruction Set Architecture CISC 360 Instruction Set Architecture Michela Taufer October 9, 2008 Powerpoint Lecture Notes for Computer Systems: A Programmer's Perspective, R. Bryant and D. O'Hallaron, Prentice Hall, 2003 Chapter

More information

Assembly I: Basic Operations. Computer Systems Laboratory Sungkyunkwan University

Assembly I: Basic Operations. Computer Systems Laboratory Sungkyunkwan University Assembly I: Basic Operations Jin-Soo Kim (jinsookim@skku.edu) Computer Systems Laboratory Sungkyunkwan University http://csl.skku.edu Moving Data (1) Moving data: movl source, dest Move 4-byte ( long )

More information

Chapter 4! Processor Architecture!

Chapter 4! Processor Architecture! Chapter 4! Processor Architecture!! Y86 Instruction Set Architecture! Instructor: Dr. Hyunyoung Lee! Texas A&M University! Based on slides provided by Randal E. Bryant, CMU Why Learn Processor Design?!

More information

ASSEMBLY III: PROCEDURES. Jo, Heeseung

ASSEMBLY III: PROCEDURES. Jo, Heeseung ASSEMBLY III: PROCEDURES Jo, Heeseung IA-32 STACK (1) Characteristics Region of memory managed with stack discipline Grows toward lower addresses Register indicates lowest stack address - address of top

More information

Assembly III: Procedures. Jo, Heeseung

Assembly III: Procedures. Jo, Heeseung Assembly III: Procedures Jo, Heeseung IA-32 Stack (1) Characteristics Region of memory managed with stack discipline Grows toward lower addresses Register indicates lowest stack address - address of top

More information

Systems I. Machine-Level Programming V: Procedures

Systems I. Machine-Level Programming V: Procedures Systems I Machine-Level Programming V: Procedures Topics abstraction and implementation IA32 stack discipline Procedural Memory Usage void swap(int *xp, int *yp) int t0 = *xp; int t1 = *yp; *xp = t1; *yp

More information

Pipelining 3: Hazards/Forwarding/Prediction

Pipelining 3: Hazards/Forwarding/Prediction Pipelining 3: Hazards/Forwarding/Prediction 1 pipeline stages 2 fetch instruction memory, most PC computation decode reading register file execute computation, condition code read/write memory memory read/write

More information

CS213. Machine-Level Programming III: Procedures

CS213. Machine-Level Programming III: Procedures CS213 Machine-Level Programming III: Procedures Topics IA32 stack discipline Register saving conventions Creating pointers to local variables IA32 Region of memory managed with stack discipline Grows toward

More information

CS241 Computer Organization Spring 2015 IA

CS241 Computer Organization Spring 2015 IA CS241 Computer Organization Spring 2015 IA-32 2-10 2015 Outline! Review HW#3 and Quiz#1! More on Assembly (IA32) move instruction (mov) memory address computation arithmetic & logic instructions (add,

More information

Processor Architecture I. Alexandre David

Processor Architecture I. Alexandre David Processor Architecture I Alexandre David Overview n Introduction: from transistors to gates. n and from gates to circuits. n 4.1 n 4.2 n Micro+macro code. 12-04-2011 CART - Aalborg University 2 Evolution

More information

Meltdown and Spectre: Complexity and the death of security

Meltdown and Spectre: Complexity and the death of security Meltdown and Spectre: Complexity and the death of security May 8, 2018 Meltdown and Spectre: Wait, my computer does what? May 8, 2018 Meltdown and Spectre: Whoever thought that was a good idea? May 8,

More information

Pipelining 4 / Caches 1

Pipelining 4 / Caches 1 Pipelining 4 / Caches 1 1 2 after forwarding/prediction where do we still need to stall? memory output needed in fetch ret followed by anything memory output needed in exceute mrmovq or popq + use (in

More information

cmovxx ra, rb 2 fn ra rb irmovl V, rb rb V rmmovl ra, D(rB) 4 0 ra rb D mrmovl D(rB), ra 5 0 ra rb D OPl ra, rb 6 fn ra rb jxx Dest 7 fn Dest

cmovxx ra, rb 2 fn ra rb irmovl V, rb rb V rmmovl ra, D(rB) 4 0 ra rb D mrmovl D(rB), ra 5 0 ra rb D OPl ra, rb 6 fn ra rb jxx Dest 7 fn Dest Instruction Set Architecture Instruction Set Architecture CSci 2021: Machine Architecture and Organization Lecture #16, February 25th, 2015 Your instructor: Stephen McCamant Based on slides originally

More information

3 (5 marks) RISC instruction sets do not allow an ALU operation (e.g., addl) to read from memory. 2a Why is the memory stage after the execute stage?

3 (5 marks) RISC instruction sets do not allow an ALU operation (e.g., addl) to read from memory. 2a Why is the memory stage after the execute stage? CPSC 313, Winter 2016 Term 1 Sample Solution Date: October 2016; Instructor: Mike Feeley 1 (5 marks) The classic RISC pipeline we are studying consists of 5 stages. Briefly explain the role of each stage

More information

The course that gives CMU its Zip! Machine-Level Programming III: Procedures Sept. 17, 2002

The course that gives CMU its Zip! Machine-Level Programming III: Procedures Sept. 17, 2002 15-213 The course that gives CMU its Zip! Machine-Level Programming III: Procedures Sept. 17, 2002 Topics IA32 stack discipline Register saving conventions Creating pointers to local variables class07.ppt

More information

Assembly III: Procedures. Jin-Soo Kim Computer Systems Laboratory Sungkyunkwan University

Assembly III: Procedures. Jin-Soo Kim Computer Systems Laboratory Sungkyunkwan University Assembly III: Procedures Jin-Soo Kim (jinsookim@skku.edu) Computer Systems Laboratory Sungkyunkwan University http://csl.skku.edu IA-32 (1) Characteristics Region of memory managed with stack discipline

More information

Turning C into Object Code Code in files p1.c p2.c Compile with command: gcc -O p1.c p2.c -o p Use optimizations (-O) Put resulting binary in file p

Turning C into Object Code Code in files p1.c p2.c Compile with command: gcc -O p1.c p2.c -o p Use optimizations (-O) Put resulting binary in file p Turning C into Object Code Code in files p1.c p2.c Compile with command: gcc -O p1.c p2.c -o p Use optimizations (-O) Put resulting binary in file p text C program (p1.c p2.c) Compiler (gcc -S) text Asm

More information

CS 261 Fall Mike Lam, Professor. CPU architecture

CS 261 Fall Mike Lam, Professor. CPU architecture CS 261 Fall 2017 Mike Lam, Professor CPU architecture Topics CPU stages and design Pipelining Y86 semantics CPU overview A CPU consists of Combinational circuits for computation Sequential circuits for

More information

Intel x86-64 and Y86-64 Instruction Set Architecture

Intel x86-64 and Y86-64 Instruction Set Architecture CSE 2421: Systems I Low-Level Programming and Computer Organization Intel x86-64 and Y86-64 Instruction Set Architecture Presentation J Read/Study: Bryant 3.1 3.5, 4.1 Gojko Babić 03-07-2018 Intel x86

More information

last time Exam Review on the homework on office hour locations hardware description language programming language that compiles to circuits

last time Exam Review on the homework on office hour locations hardware description language programming language that compiles to circuits last time Exam Review hardware description language programming language that compiles to circuits stages as conceptual division not the order things happen easier to figure out wiring stage-by-stage?

More information

Region of memory managed with stack discipline Grows toward lower addresses. Register %esp contains lowest stack address = address of top element

Region of memory managed with stack discipline Grows toward lower addresses. Register %esp contains lowest stack address = address of top element Machine Representa/on of Programs: Procedures Instructors: Sanjeev Se(a 1 IA32 Stack Region of memory managed with stack discipline Grows toward lower addresses Stack BoGom Increasing Addresses Register

More information

CISC 360. Machine-Level Programming I: Introduction Sept. 18, 2008

CISC 360. Machine-Level Programming I: Introduction Sept. 18, 2008 CISC 360 Machine-Level Programming I: Introduction Sept. 18, 2008 Topics Assembly Programmerʼs Execution Model Accessing Information Registers Memory Arithmetic operations IA32 Processors Totally Dominate

More information

CS241 Computer Organization Spring Addresses & Pointers

CS241 Computer Organization Spring Addresses & Pointers CS241 Computer Organization Spring 2015 Addresses & Pointers 2-24 2015 Outline! Addresses & Pointers! leal - load effective address! Condition Codes & Jumps! conditional statements: if-then-else! conditional

More information