proc print data=account; <insert statement here> run;

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1 Statistics 6250 Name: Fall 2012 (print: first last ) Prof. Fan NetID #: Midterm Three Instructions: This is an in-class and open book midterm. You must write your answers on the provide spaces. Give concise but detailed answers for full credit.write your SAS codes for all questions except the multiple choice questions. To generate the datasets of this test paper, first run the SAS code in the file data_test3_f12.txt posted on class webpage ( and click teaching then STAT 4910/6250; the file locates at the bottom of Exams section). Multiple Choice Questions 1. Which assignment statement will produce a value for FULLNAME with a comma between the LASTNAME and FIRSTNAME? a. FULLNAME = CATS(',', LASTNAME, FIRSTNAME); b. FULLNAME = CATX(',', LASTNAME, FIRSTNAME); c. FULLNAME = CATS(LASTNAME, FIRSTNAME, ','); d. FULLNAME = CATX(LASTNAME, FIRSTNAME, ','); b 1. The following SAS program is submitted: proc print data=account; <insert statement here> The following list report containing the character variable name and the numeric variables date and amount is generated: Obs name date amount 1 JACK 16MAY2007 $123, SUE 17JUL2006 $89, Which SAS statement created the report? a. format date date9. amount dollar11.2; b. format date ddmmyy9. amount dollar11.2; c. format date ddmmmyyyy9. amount comma11.2; d. format date date9. amount dollarcomma11.2; a 1. Which of the following is true regarding the SCAN function? 1

2 e. The SCAN function only uses two default delimiters (the blank and the comma) if a delimiter is not specified. f. The SCAN function has an optional fourth argument, which is the direction (forward or backward) to read the string. g. The SCAN function returns a missing value if the number of the word scanned is greater than the number of words in the character string. h. If the SCAN function returns a value to a variable that was not yet assigned a length, the variable length is determined by the length of the first argument. c 2. A character array that contains three variables (name1, name2, and name3) with the values of Smith, Jones, and Westinghouseis requested. Which ARRAY statement will create the desired array? a. array name{3} $ ('Smith','Jones','Westinghouse'); b. array name1-name3 $ ('Smith' 'Jones' 'Westinghouse'); c. array name{3} $ name1-name3 ('Smith' 'Jones' 'Westinghouse'); d. array name(3) $ 12 ('Smith','Jones','Westinghouse'); D 1. The PRINT Procedure Place the appropriate letter before each item. f BY Statement a ID Statement h FOOTNOTE Statement j SUM Statement i FORMAT Statement c TITLE Statement e LABEL Statement g VAR Statement b NOOBS Option d WHERE Statement a. Replaces the column obs by a certain variable b. Suppresses the column in the output that identifies each observation by number c. Specifies up to 10 lines of text at the top of output d. Subsets the input data set by specifying certain conditions that each observation must meet e. Assigns descriptive labels to variable names f. Produces a separate section of the report for each BY group g. Selects variables that appear in the report and determines the variables order h. Specifies up to 10 lines of text at the bottom of output i. Associates formats to variable values 2

3 j. Totals values of numeric variables Question One The data set college contains four variables: gender (F, M), scholarship (Y, N), Schoolsize (L, M, S) and GPA (student s current GPA). (a) Print the 68 th to 70 th observations of the dataset. PROC PRINT DATA=COLLEGE(FIRSTOBS=68 OBS=70); RUN; (b) Use PROC TABULATE to create a table as follows. School Size Missing Large Medium Small Total GPA GPA GPA GPA GPA Average Average Average Average Average Scholarship Female No NA Yes Male No Yes NA Total Scholarship No Yes proc tabulate data=college missing; title "proc tabulate example"; class gender scholarship Schoolsize; var GPA; table (gender=' ' all)*scholarship, (schoolsize all)*gpa*(mean)/misstext='na'; label schoolsize='school Size'; keylabel all='total' mean='average'; Question Three The dataset answers contains four test scores for each student in the class (plus an ID number and his/her gender). 3

4 (a) Assume that the passing score of the four tests was 60, 70, 60, and 70, respectively. Add two variables into the dataset answers(1) PASS, the number of tests that a student passed and (2) AVE, the mean score of a student. data answers; set answers; array score{4}; array pass_score{4} _temporary_ ( ); pass=0; do i=1 to 4; drop i; pass=pass+(score{i} ge pass_score{i}); end; ave=mean(of score1-score4); (b) Use PROC REPORT to create the following report: The CSUEB Statistics Department The mean of four tests for each student mean Student mean >= score ID 75? no no yes yes Make sure you do the following things: 1) Use OPTIONS to align your titles to the left 2) Sort your output for AVE and use proper format to print the first digit after decimal point for AVE 3) Use COMPUTE inside PROC REPORT to create a variable GRDB which is yes if the mean score is at least 75 and no otherwise 4) Label your variables properly. options nocenter; title1 "The CSUEB Statistics Department"; title3 "The mean of four tests for each student"; title4 " "; proc report data=answers nowd; column ave id grdb; define ave/order "mean score" width=7 format=7.1; define id/ display "Student ID" width=7; define grdb/ computed "mean >= 75?" width=10; compute grdb/ character length=10; if ave ge 75 then grdb='yes'; 4

5 else grdb='no'; endcomp; Question Four The dataset phoneall contains four variables: name, phone number and height of customers. Create a new SAS dataset using the dataset phoneall with the following changes: (a) Add the variable of the 3-digit area code (AreaCode). (b) Phone becomes only the 7 digits of the local phone number (without the area code). *Data set phoneall; data phoneall; input Name $20. Phone & $14. Height & $10.; datalines; Roger Cody (908) ft. 10in. Thomas Jefferson (315) ft. 1in. Marco Polo (800) Ft. 6in. Brian Watson (518) ft. 10in Michael DeMarco (445) ft. ; data newphone; set phoneall; phone=compress(phone,,'kd'); areacode=substr(phone,1,3); phone=substr(phone,4); 3. The following SAS program is submitted: data personnel; Phone = ; <insert statement here> proc print data=personnel; The following report is generated: Area Obs Phone Code What is the inserted SAS statement? Hint: you may need to change the type of phone in order to extract the first three digits. AreaCode=substr(put(Phone,10.),1,3); 5