Control Transfer Instructions Jump, Loop, and Call. ECE473/573 Microprocessor System Design, Dr. Shiue
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1 Control Transfer Instructions Jump, Loop, and Call 1
2 Jump Instructions JZ label ; Jump if A=0 JNZ label ; Jump if A!=0 DJNZ reg, label ; Decrement and Jump if A (or reg.)!=0 CJNE A, byte ; Compare and Jump if A!=byte CJNE reg, #data ; Compare and Jump if byte!=data JC ; Jump if Carry=1 JNC ; Jump if Carry=0 JB ; Jump if bit =1 JNB ; Jump if bit =0 JBC ; Jump if bit=1 and clear bit 2
3 DJNZ Decrement and Jump if not zero (DJNZ) DJNZ register, label Ex1: Count from 1 to 20 and sent the count to P1. Ex2: Add 3 to the ACC ten times. Ex3: What is the maximum number of times that the loop in the Ex2 can be repeated? Ex4: Write a program to (a) add the ACC with the value 55H, and (b) complement the ACC 700 times. 3
4 JZ JZ: Jump if A=0 JZ label Ex1: MOV A, R0 JZ Over ; jump if A=0 MOV A, R1 JZ Over ; jump if A=0 Over: 4
5 JNZ, JNC, and JC JNZ: Jump if A!=0 JNZ label Ex1: Write a program to determine if R5 contains the value of 0. If so, put 55H in it. JNC: Jump if C=0 JNC label JC: Jump if C=1 JC label 5
6 JNC Examples JNC: Jump if C=0 JNC label Ex1: Find the sum of the values 79H, F5H, and E2H. Put the sum in registers R0 (low byte) and R5 (high byte) 6
7 LJMP: 3-byte instruction Uncondition Jump KB ROM FFFF 7
8 Uncondition Jump SJMP: 2-byte instruction (Range: -128 (backward) ~ +127 (forward) bytes) B ROM FF 8
9 Jump Forward and Backward Ex1: Using the following list file, verify the jump forward address calculation. lines PC B Opcode Instructions ORG 0 MOV R0, #0 JZ Next INC R0 Again: INC A MOV A, #55H =0009 Jump forward! INC A Next: ADD A, #77H JNC Over Jump forward! 9
10 Jump Forward and Backward 000D+05 =0012 lines PC Opcode Instructions D E4 CLR A E F8 MOV R0, A F F9 MOV R1, A FA MOV R2, A FB MOV R3, A 0015+F2 = B 50F2 Over: ADD A, R3 JNC Again Jump backward! 0017+FE = FE Here: SJMP Here END Jump backward! 10
11 LCALL (Long Call) LCALL: 3-byte instruction When subroutine is called Control is transferred to that subroutine Processor saves the PC onto the Stack and begins to fetch instructions from new location. RET (return to caller) POP from Stack to PC 0000 FFFF 64KB ROM Ex1:Write a program to toggle all the bits of port 1 by sending to it the values 55H and AAH continuously. Put a time delay in between each issuing of data to port 1. (This program is used to test the ports of the 8051) 11
12 Main Program and Calls ORG 0 Main: LCALL Sub_1 LCALL Sub_2 LCALL Sub_3 Here: SJMP Here ; end of main Sub_1:. RET : end of Sub_1 Sub_2:. RET : end of Sub_2 Sub_3:. RET : end of Sub_3 END 12
13 ACALL (Absolute Call) ACALL: 2-byte instruction ACALL s target address must be with in a 2KB range KB ROM =2*2 10 = FF 13
14 Time Delay Generation and Calculation Crystal frequency (XTAL): 4MHz ~ 30MHz Using MHz to make the 8051 compatible with the serial port of the IBM PC. Ex1: Find the period of the machine cycle (a) MHz (b) 16MHz (c) 20MHz Ex2: For an 8051 system of MHz, find how long it takes to execute each of the following instructions MOV R3, #55H 1 DEC R3 1 DJNZ R2, target 2 LJMP 2 SJMP 2 NOP 1 MUL AB 4 14
15 Delay Calculation Ex3: Find the size of the delay in the following program if XTAL = MHz MOV A, #55H Again: MOV P1, A ACALL Delay CPL A SJMP Again Delay: MOV R3, #200 Here: DJNZ R3, Here RET 15
16 NOP NOP is used for increasing the delay Ex4: Find the time delay for the following subroutine, XTAL= MHz Delay: MOV R3, #250 Here: NOP NOP NOP NOP DJNZ R3, Here RET 16
17 Nested Loop Ex5: Find the time delay for the following subroutine Delay: MOV R2, #200 Again: MOV R3, #250 Here: NOP NOP DJNZ R3, Here DJNZ R2, Again RET 17
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