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1 AVL Trees v z 20 Goodrich, Tamassia, Goldwasser AVL Trees

2 AVL Tree Definition Adelson-Velsky and Landis binary search tree balanced each internal node v the heights of the children of v can differ by at most An example of an AVL tree where the heights are shown next to the nodes 20 Goodrich, Tamassia, Goldwasser AVL Trees 2

3 n(2) 3 Height of an AVL Tree n() Fact: The height of an AVL tree storing n keys is O(log n). Proof (by induction): n(h): the minimum number of internal nodes of an AVL tree of height h. n() = and n(2) = 2 For n > 2, an AVL tree of height h contains the root node, one AVL subtree of height n- and another of height n-2. That is, n(h) = + n(h-) + n(h-2) Knowing n(h-) > n(h-2), we get n(h) > 2n(h-2). So n(h) > 2n(h-2), n(h) > n(h-), n(h) > 8n(n-6), (by induction), n(h) > 2 i n(h-2i) Solving the base case we get: n(h) > 2 h/2 - Taking logarithms: h < 2log n(h) +2 Thus the height of an AVL tree is O(log n) 20 Goodrich, Tamassia, Goldwasser AVL Trees 3

4 Insertion Insertion is as in a binary search tree Always done by expanding an external node. Insert 5: a=y c=z b=x before insertion w 5 after insertion 20 Goodrich, Tamassia, Goldwasser AVL Trees

5 Insertion Insertion is like a binary search tree Always done by expanding an external node. Insert 5: a=y Imbalance Node z c=z b=x before insertion Insert Node w 5 w after insertion 20 Goodrich, Tamassia, Goldwasser AVL Trees 5

6 Insertion z = first unbalanced node encountered while travelling up the tree from w. y = child of z with the larger height, x = child of y with the larger height trinode restructuring to restore balance at z 20 Goodrich, Tamassia, Goldwasser AVL Trees 6

7 Overview of Cases of Trinode Restructuring Case Case 2 Case 3 Case z -> y -> x -> Goodrich, Tamassia, Goldwasser Red-Black Trees 7

8 Rotation operation Consider subtree points to y and we also have x and y. y.left = x.right 2. x.right = y 3. subtree = x With a linked structure Constant number of updates O() time 20 Goodrich, Tamassia, Goldwasser AVL Trees 8

9 Trinode Restructuring: Case Single Rotation: Keys: a < b < c Nodes: grandparent z is not balanced, y is parent, x is node a = z b = y c = x single rotation a = z b = y c = x T 0 T T 2 T 3 T 0 T T 2 T 3 Not balanced at a, the smallest key x has the largest key c Result: middle key b at the top 20 Goodrich, Tamassia, Goldwasser AVL Trees 9

10 Example for Case Case z y x T0 2 T 6 T2 T3 2 6 T0 T T2 T3 20 Goodrich, Tamassia, Goldwasser Red-Black Trees 0

11 Trinode Restructuring: Case 2 Single Rotation: Not balanced at c, the largest key x has the smallest key a Keys: a < b < c Nodes: grandparent z is not balanced, y is parent, x is node Result: middle key b at the top a = x b = y c = z single rotation a = x b = y c = z T 0 T T 3 T 2 20 Goodrich, Tamassia, Goldwasser AVL Trees T 0 T T2 T 3

12 Example for Case 2 Case 2 z y x 2 6 T2 T3 T0 T 2 6 T0 T T2 T3 20 Goodrich, Tamassia, Goldwasser Red-Black Trees 2

13 Trinode Restructuring: Case 3 double rotation: Keys: a < b < c Nodes: grandparent z is not balanced, y is parent, x is node a = z b = x c = y double rotation a = z b = x c = y T 0 T 2 T T 3 T 0 Not balanced at a, the smallest key x has the middle key b x is rotated above y x is then rotated above x Result: middle key b at the top T T 2 T 3 20 Goodrich, Tamassia, Goldwasser AVL Trees 3

14 Example for Case 3 Case 3 T0 2 T T2 6 T3 T0 2 T 6 T2 T3 z y x 2 6 T0 T T2 T3 20 Goodrich, Tamassia, Goldwasser Red-Black Trees

15 Trinode Restructuring: Case double rotation Not balanced at c, the largest key x has the middle key b x is rotated above y x is then rotated above z Keys: a < b < c Nodes: grandparent z is not balanced, y is parent, x is node Result: middle key b at the top a = y b = x c = z double rotation a = y b = x c = z T 0 T 3 T 2 T 3 T T 0 T T 3 T T 0 T T 0 T T 2 T Goodrich, Tamassia, Goldwasser AVL Trees 5 T 2

16 Example for Case Case T0 2 T 6 T2 T3 T0 2 T 6 T2 T3 z y x 2 6 T0 T T2 T3 20 Goodrich, Tamassia, Goldwasser Red-Black Trees 6

17 Insert 5 (Case 3 or?) unbalanced z y x balanced 5 T 0 T 2 T T 3 Draw the double rotation y x z 88 T 2 T 0 T T 3 20 Goodrich, Tamassia, Goldwasser AVL Trees 7

18 Trinode Restructuring summary Case imbalance/ grandparent z Node x Rotation Smallest key a Largest key c single 2 Largest key c Smallest key a single 3 Smallest key a Middle key b double Largest key c Middle key b double 20 Goodrich, Tamassia, Goldwasser AVL Trees 8

19 Trinode Restructuring Summary Case imbalance/ grandparent z Node x Rotation Smallest key a Largest key c single 2 Largest key c Smallest key a single 3 Smallest key a Middle key b double Largest key c Middle key b double The resulting balanced subtree has: middle key b at the top smallest key a as left child T0 and T are left and right subtrees of a largest key c as right child T2 and T3 are left and right subtrees of c 20 Goodrich, Tamassia, Goldwasser AVL Trees 9

20 Removal Removal begins as in a binary search tree the node removed will become an empty external node. Its parent, w, may cause an imbalance. Remove 32, imbalance at before deletion of 32 after deletion 20 Goodrich, Tamassia, Goldwasser AVL Trees 20

21 Rebalancing after a Removal z = first unbalanced node encountered while travelling up the tree from w. y = child of z with the larger height, x = child of y with the larger height trinode restructuring to restore balance at z Case in example a=z 62 w 7 62 b=y c=x Goodrich, Tamassia, Goldwasser AVL Trees 2

22 Rebalancing after a Removal this restructuring may upset the balance of another node higher in the tree continue checking for balance until the root of T is reached a=z 62 w 7 62 b=y c=x Goodrich, Tamassia, Goldwasser AVL Trees 22

23 Rebalancing after a Removal [Slide added jyp] In the case below, restructuring the subtree rooted at created a new subtree (incidentally now rooted at 62) which is has height decreased by This might cause an unbalanced situation at an ancestor of this subtree a=z 62 w 7 62 b=y c=x Goodrich, Tamassia, Goldwasser AVL Trees 23

24 Balanced tree Goodrich, Tamassia, Goldwasser AVL Trees 2

25 Delete Goodrich, Tamassia, Goldwasser AVL Trees 25

26 Not balanced at Goodrich, Tamassia, Goldwasser AVL Trees 26

27 Single rotation Goodrich, Tamassia, Goldwasser AVL Trees 27

28 Anything wrong? Goodrich, Tamassia, Goldwasser AVL Trees 28

29 Not balanced at 50! Goodrich, Tamassia, Goldwasser AVL Trees 29

30 AVL Tree Performance n entries O(n) space A single restructuring takes O() time using a linked-structure binary tree Operation Worst-case Time Complexity Get/search O(log n) Up to height log n Put/insert O(log n) O(log n): searching & restructuring Remove/delete O(log n) O(log n): searching & restructuring up to height log n 20 Goodrich, Tamassia, Goldwasser AVL Trees 30

31 AVL Trees balanced Binary Search Tree (BST) Insert/delete operations include rebalancing if needed Worst-case time complexity: O(log n) 20 Goodrich, Tamassia, Goldwasser AVL Trees 3

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