Meet & Greet! Come hang out with your TAs and Fellow Students (& eat free insomnia cookies)

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1 Meet & Greet! Come hang out with your TAs and Fellow Students (& eat free insomnia cookies) When : Friday, Sept. 29th. 5-6 pm Where : 3rd Floor Atrium, CIT CS33 Intro to Computer Systems X 1 Copyright 2017 Thomas W. Doeppner. All rights reserved.

2 CS 33 Intro to Machine Programming CS33 Intro to Computer Systems X 2 Copyright 2017 Thomas W. Doeppner. All rights reserved.

3 Machine Model Processor (aka CPU) instructions and data data Memory (aka RAM) CS33 Intro to Computer Systems X 3 Copyright 2017 Thomas W. Doeppner. All rights reserved.

4 Memory Instructions or Instructions are Data Data CS33 Intro to Computer Systems X 4 Copyright 2017 Thomas W. Doeppner. All rights reserved.

5 Processor: Some Details Execution engine Instruction pointer Condition codes CS33 Intro to Computer Systems X 5 Copyright 2017 Thomas W. Doeppner. All rights reserved.

6 Processor: Basic Operation while (forever) { fetch instruction IP points at decode instruction fetch operands execute store results update IP and condition code } CS33 Intro to Computer Systems X 6 Copyright 2017 Thomas W. Doeppner. All rights reserved.

7 Instructions... Op code Operand1 Operand2... CS33 Intro to Computer Systems X 7 Copyright 2017 Thomas W. Doeppner. All rights reserved.

8 Operands Form immediate vs. reference» value vs. address How many? 3» add a,b,c c = a + b 2» add a,b b += a CS33 Intro to Computer Systems X 8 Copyright 2017 Thomas W. Doeppner. All rights reserved.

9 Operands (continued) Accumulator special memory in the processor» known as a register» fast access allows single-operand instructions» add a» add b acc += a acc += b CS33 Intro to Computer Systems X 9 Copyright 2017 Thomas W. Doeppner. All rights reserved.

10 From C to Assembler... a = (b + c) * d; mov b,%acc add c,%acc mul d,%acc mov %acc,a if (a<b) c = 1; else d = 1; cmp a,b jge.l1 mov $1,c jmp.l2.l1 mov $1,d.L2 immediate operand immediate operand CS33 Intro to Computer Systems X 10 Copyright 2017 Thomas W. Doeppner. All rights reserved.

11 Condition Codes Set of flags giving status of most recent operation: zero flag» result was or was not zero sign flag» for signed arithmetic interpretation: sign bit is or is not set overflow flag» for signed arithmetic interpretation carry flag (generated by carry or borrow out of mostsignificant bit)» for unsigned arithmetic interpretation Set implicitly by arithmetic instructions Set explicitly by compare instruction cmp a,b» sets flags based on result of b-a CS33 Intro to Computer Systems X 11 Copyright 2017 Thomas W. Doeppner. All rights reserved.

12 Quiz 1 Set of flags giving status of most recent operation: zero flag» result was or was not zero sign flag» for signed arithmetic interpretation: sign bit is or is not set overflow flag» for signed arithmetic interpretation carry flag (generated by carry or borrow out of most-significant bit)» for unsigned arithmetic interpretation Set explicitly by compare instruction cmp a,b» sets flags based on result of b-a Which flags are set to one by cmp 2,1? a) overflow flag only b) carry flag only c) sign and carry flags only d) sign and overflow flags only e) sign, overflow, and carry flags CS33 Intro to Computer Systems X 12 Copyright 2017 Thomas W. Doeppner. All rights reserved.

13 Jump Instructions Unconditional jump just do it Conditional jump to jump or not to jump determined by conditioncode flags field in the op code indicates how this is computed in assembler language, simply say» je jump on equal» jne jump on not equal» jgt» etc. jump on greater than CS33 Intro to Computer Systems X 13 Copyright 2017 Thomas W. Doeppner. All rights reserved.

14 Addresses int a, b, c, d; int main() { a = (b + c) * d;... } mov add mul mov b,%acc c,%acc d,%acc %acc,a mov add mul mov 1004,%acc 1008,%acc 1012,%acc %acc, : 1008: 1004: 1000: d c b a global variables Memory CS33 Intro to Computer Systems X 14 Copyright 2017 Thomas W. Doeppner. All rights reserved.

15 Addresses int b; int func(int c, int d) { } int a; a = (b + c) * d;... mov add mul mov?,%acc?,%acc?,%acc %acc,? One copy of b for duration of program s execution b s address is the same for each call to func Different copies of a, c, and d for each call to func addresses are different in each call CS33 Intro to Computer Systems X 15 Copyright 2017 Thomas W. Doeppner. All rights reserved.

16 Relative Addresses Absolute address actual location in memory Relative address offset from some other location Blob s absolute address is Datum s relative address (to Blob) is 100 its absolute address is Blob Datum Memory CS33 Intro to Computer Systems X 16 Copyright 2017 Thomas W. Doeppner. All rights reserved.

17 Base Registers mov $10000, %base mov $10, 100(%base) Blob base register Datum Memory CS33 Intro to Computer Systems X 17 Copyright 2017 Thomas W. Doeppner. All rights reserved.

18 Addresses int b; int func(int c, int d) { int a; a = (b + c) * d;... } mov 1000,%acc add c_rel(%base),%acc mul d_rel(%base),%acc mov %acc,a_rel(%base) base 1000: earlier stack frame previous stack frame c d a b func stack frame global variables Memory CS33 Intro to Computer Systems X 18 Copyright 2017 Thomas W. Doeppner. All rights reserved.

19 Quiz 2 Suppose the value in base is int b; 10,000 and c_rel is -8. What is the address of c? a) 9992 int a; b) 9996 a = (b + c) * d; c) 10, d) 10,008 int func(int c, int d) { } mov 1000,%acc add c_rel(%base),%acc mul d_rel(%base),%acc mov %acc,a_rel(%base) base 1000: earlier stack frame previous stack frame c d a b func stack frame global variables Memory CS33 Intro to Computer Systems X 19 Copyright 2017 Thomas W. Doeppner. All rights reserved.

20 Registers Execution engine Instruction pointer Accumulator Base register more interchangeable Condition codes CS33 Intro to Computer Systems X 20 Copyright 2017 Thomas W. Doeppner. All rights reserved.

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