Contents. I. A Simple Java Program. Topic 02 - Java Fundamentals. VIII. Conversion and type casting

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1 Tpic 02 Cntents Tpic 02 - Java Fundamentals CS2312 Prblem Slving and Prgramming I. A simple JAVA Prgram access mdifier (eg. public), static, II. III. IV. Packages and the Imprt statement, Java API (java.lang, java.util, Math,) Creating Packages and Default Package Cmments and Javadc V. Data types and Variables VIII. Cnversin and type casting IX. Parentheses, Operatr Hierarchy, Precedence levels, Assciativity X. Strings, StringBuilder XI. Input (cnsle, file, input frm string) XII. Output (System.ut.printf, String.frmat, PrinterWriter) VI. Cnstants (the final keywrd) XIII. Cntrl flw VII. Arithmetic Operatrs, Relatinal Operatrs, Blean (lgical) Operatrs, Bitwise Operatrs XIV. Arrays I. A Simple Java Prgram FirstSample.java public class FirstSample public static vid main(string[] args) System.ut.println("Hell!"); Access Mdifier: public The keywrd public is ne f the access mdifiers, that states hw ther parts can get the access. Fr example, here public is applied t class FirstSample meaning that utsiders can use the class. Except public, we als have ther mdifiers: private, prtected, etc., We will cver them in next tpic. JAVA classes and.java files Classes are the building blcks fr Java prgrams. By cnventin: start with an uppercase letter A.java file cannt have 2 r mre public classes. The name f a public class = The file name Case sensitive. FirstSample.java matches with class name FirstSample The main methd in Java main() des nt return anything, thus vid main() has t be inside a class; as a static methd (ie. A methd that des nt perate n bjects.). String[] args Arguments can be supplied t main() as an array f strings. (Ref. Tpic01) Last mdified: 15-Sep /14

$System.ut.println("Hell!"); prints Hell! + terminate the line (newline character '\n') Can be withut argument: simply a blank line.print() methd System.ut.println(); System.ut.print("Hell!$

2 Tpic 02 CS2312 Prblem Slving and Prgramming print(), println() General syntax t invke a methd: bject.methd(parameters) Use the System.ut bject and call its println methd. System.ut.println("Hell!"); prints Hell! + terminate the line (newline character '\n') Can be withut argument: simply a blank line.print() methd System.ut.println(); System.ut.print("Hell!"); nt terminating the line ( \n ) II. Packages and the imprt statement Packages are grups f classes. The standard Java library is distributed ver a number f packages e.g. java.lang, java.util, java.util (and many ther classes) java.util cntains the Scanner class We can use it like: java.util.scanner If we imprt java.util.*, then we can simply write: Scanner The imprt statement: imprt java.util.*; We can use all classes in java.util imprt java.util.scanner; We can use Scanner java.lang - Java fundamental classes N need t imprt java.lang (assumed already fr all prgrams) java.lang prvides the System class, Math class, and many mre Use f the java.lang.system class: public class FirstSample public static vid main(string[] args) System.ut.println("Hell!"); Ref: JAVA API Dcumentatin Last mdified: 15-Sep /14

Tpic 02 CS2312 Prblem Slving and Prgramming www.cs.cityu.edu.hk/~helena java.lang.math class - prvides static methds that perate n numbers. e.g. max, abs, sin, cs, pw, sqrt, lg Cnstants: Math.

*; public static vid main(string[] args) int n1, n2, n; n1 = 100; n2 = 200; n = Math.max(n1,n2); System.ut.println(n); System.ut.println(Math.

3 Tpic 02 CS2312 Prblem Slving and Prgramming java.lang.math class - prvides static methds that perate n numbers. e.g. max, abs, sin, cs, pw, sqrt, lg Cnstants: Math.PI, Math.E Withut imprt public class Testing With imprt (static is needed if we use the static methds in the imprted class) imprt static java.lang.math.*; public static vid main(string[] args) int n1, n2, n; n1 = 100; n2 = 200; n = Math.max(n1,n2); System.ut.println(n); System.ut.println(Math.PI); public class Testing public static vid main(string[] args) int n1, n2, n; n1 = 100; n2 = 200; n = max(n1,n2); System.ut.println(n); //200 System.ut.println(PI); // III. Creating Packages and Default Package We can grup ur surce files int packages A class nt gruped int package is in "default package" A class gruped int package is in the package flder and has the package statement: Eclipse prject File explrer Surce cde Calendar package cntains Day.java Package name must match flder name Add package statement t the tp f file T use the class, type Calendar.Day r add imprt Calendar.* Unluckily PASS desn t cmpile packages at this mment. IV. Cmments Three ways f marking Cmments Like C++: //, /*... */ Fr autmatic dcumentatin generatin: /**... */ /** Just print t1-1st thing t be t2-2nd thing t be dne */ static vid dtwthings(string t1, String t2) System.ut.println(t1); System.ut.println(t2); autmatic dcumentatin generatin (by the javadc prgram frm JDK) Sme IDEs add * in frnt f /** every line, fr visual style nly. * Just print them t1-1st thing t be dne t2-2nd thing t be dne */ Last mdified: 15-Sep /14

4 Tpic 02 CS2312 Prblem Slving and Prgramming V. Data Types and Variables Overview f Data types There are tw kinds f types in the Java: Primitive types and Reference types I. Primitive types: - Java has 8 primitive types: blean, byte, shrt, int, lng, flat, duble, char II. Reference types (~ pinters in C++) : - The values f a reference type are references t bjects. Recall: an bject is an instance f a class, created using the new peratr. - Examples f built-in Java classes: String, Math, Scanner Examples f user-defined classes (Lab01-03): Day, Table2dMxSumRwCl, Student We can create bjects f these classes, using the new peratr We ften use a variable t hld the bject reference; Then we can use the variable t access the bject. e.g. Table2dMxSumRlCl t = new Table2dMxSumRlCl( data.txt ); - An array is als a special kind f bject t.print(); Variables We have seen that there are 2 types f data: Primitive and Reference types. These tw kinds f data can be stred in variables: primitive values and reference values: Types f variables in JAVA Infrmatin stred Examples (i) Variables f Primitive Types primitive values int x; x = 689; (ii) Variables f Reference Types references t bjects (Like pinters in C++) Day d; d = new Day(2016,1,20); #1 int[][] arr; arr = new int[10][10]; #1: Use f a class: We use a class name as variable type, and use the class t create ("new") an bject f its kind. Data Types Integers Integer types Java has n unsigned types Lng integer numbers have a suffix L lng x; x = L; //2,223,123,123 is supprted nly as lng System.ut.println(x); T prvide numbers in Binary, we need prefix: 0b T prvide numbers in Hexadecimal, we need prefix: 0x int x; x = 0b10110; System.ut.print(x); //shws 22 x = 0xFF; System.ut.print(x); //shws 255 Last mdified: 15-Sep /14

$Tpic 02 CS2312 Prblem Slving and Prgramming www.cs.cityu.edu.hk/~helena Data Types Flating Pint Types Flating Pint Types Fr numbers with fractinal parts, (ie. nt whle numbers, e.g. 1.$ println(x1); //Shws 0.9876599 duble x2=0.98765987659876598765d; System.ut.println(x2); //Shws 0.987659876598766 duble x3=0.98765987659876598765; //'D' is ptinal System.ut.println(x3); //Shws 0.

println(x1); //Shws 0.9876599 duble x2=0.98765987659876598765d; System.ut.println(x2); //Shws 0.987659876598766 duble x3=0.98765987659876598765; //'D' is ptinal System.ut.println(x3); //Shws 0.

$8999999999999999 Reasn f Rundff errrs: cmputer uses binary number system; and there is n precise binary representatin f a lt f fractins (e.g.$

5 Tpic 02 CS2312 Prblem Slving and Prgramming Data Types Flating Pint Types Flating Pint Types Fr numbers with fractinal parts, (ie. nt whle numbers, e.g. 1.1), and Fr very large numbers (e.g. 5 x ) The precisin is limited (ie. keep a few significant digits). 2 Types: Suffix: flat - F duble D (ptinal) flat x1 = F; System.ut.println(x1); //Shws duble x2= d; System.ut.println(x2); //Shws duble x3= ; //'D' is ptinal System.ut.println(x3); //Shws duble x4= d; System.ut.println(x4); //Shws E19 Rundff errrs System.ut.println( ); // Reasn f Rundff errrs: cmputer uses binary number system; and there is n precise binary representatin f a lt f fractins (e.g. 1/10) Slutin: use the BigDecimal class (Interested students may lk fr the example in the given cde f this tpic) Data Types char and Escape Sequence Primitive type fr characters: char Escape Sequence fr special char values: Data Types Blean Blean type: true, false We cannt cnvert between integers and Blean values blean b=true; int i = 3; b = i; //Errr!! Type mismatch - cannt cnvert frm int t blean i = b; //Errr!! Type mismatch - cannt cnvert frm blean t int Last mdified: 15-Sep /14

6 Tpic 02 CS2312 Prblem Slving and Prgramming Declaratin f Variables Every variable has a type: duble salary; int vacatindays; lng earthppulatin; blean dne; Cmmn ways t name: start with lwercase letter Bx bx; //Bx is a class type and bx is the variable. Bx abx; //using a as prefix Bx bxjewels, bxcins; Must explicit initialize befre use int x; System.ut.println(x); // ERROR--variable nt initialized int x = 12; System.ut.println(x); //12 int x; x= 28; System.ut.println(x); //28 VI. Cnstants Cnstants: Java keywrd is final final: the value is set nce and fr all. Cmmn ways t name a cnstant: all in uppercase Often given as Methd cnstants r Class cnstants public class MyApp public static vid main(string[] args) final duble CM_PER_INCH = 2.54; public class MyApp public static final duble CM_PER_INCH = 2.54; public static vid main(string[] args) VII. Operatrs: Arithmetic Operatrs, Relatinal Operatrs, Blean (lgical) Operatrs, Bitwise Operatrs (I) Arithmetic Operatrs: +, -, *, /, %, +=, -=, *=, /=, %= x/y If bth x and y are integers, dentes integer divisin, e.g. 3/4 is 0 Otherwise flating-pint divisin, eg. 3.0/4 is 0.75 x/0 If x is integer => divisin by zer exceptin (run-time errr) Otherwise, ie. x is flating pint if x is 0.0 => 0.0/0 gives NaN Nt a number, can check with Duble.isNaN() Else, eg. 12.0/0 gives Infinity Can check with Duble.isInfinite() System.ut.println(0/0); java.lang.arithmeticexceptin: / by zer System.ut.println(0%0); java.lang.arithmeticexceptin: / by zer System.ut.println(0.0/0); gives NaN System.ut.println(0.0%0); gives NaN System.ut.println(12.0/0); gives Infinity System.ut.println(12.0%0); gives NaN Last mdified: 15-Sep /14

Tpic 02 CS2312 Prblem Slving and Prgramming www.cs.cityu.edu.hk/~helena (II) Relatinal Operatrs: ==,!=, >, <, >=, <= (III) Blean (lgical) peratrs: && AND, OR Evaluated in Shrt circuit fashin I.e., The secnd argument is nt evaluated if first argument already determines the value.

7 Tpic 02 CS2312 Prblem Slving and Prgramming (II) Relatinal Operatrs: ==,!=, >, <, >=, <= (III) Blean (lgical) peratrs: && AND, OR Evaluated in Shrt circuit fashin I.e., The secnd argument is nt evaluated if first argument already determines the value. Example 1: if ((ismember==true) (calculateage()>=65)) System.ut.print("Gift"); if ismember is true, then calculateage desn't need t (will nt) run. Example 2: if (ttcurses>0 && ttalmarks/ttcurses >=90) System.ut.print("Well dne!!"); if ttcurse is 0, then ttalmark/ttcurses will nt be calculated (avid run-time errr "Divisin-by-zer ) (IV) Bitwise Operatrs: & ( AND ) ( OR ) ^ ( XOR ) ~ ( NOT ) << (left-shift) >> (right-shift) Example: int n1, n2, n3; n1 = 0xFE; (ie. 0b ) n2 = n1 ^ 0xFF; //set n2 t 0b (0b XOR 0b ) n3 = n2 << 4; //set n3 t 0b (left-shift 0b by 4 bits) VIII. Cnversin between numbers, type casting Legal cnversins: 2 bytes Case 1: Withut infrmatin lss, r 1 byte 2 bytes 4 bytes 8 bytes Case 2: Just t lse precisin duble d; flat f; int i= ; d=i; f=i; System.ut.println(f); //utput: E9 System.ut.println(d); //utput: E9 System.ut.println(i); //utput: bytes 8 bytes Case 3: Thugh legal, but may lse infrmatin. Fr these cases explicit type casting is needed: int i=97; char c; c=(char)i; System.ut.println(i); //utput: 97 System.ut.println(c); //utput: a Q: Why int->char may cause infrmatin lst? A: int is 4 bytes, can hld big range f values But char is 2 bytes nly Last mdified: 15-Sep /14

Tpic 02 CS2312 Prblem Slving and Prgramming www.cs.cityu.edu.hk/~helena IX.

8 Tpic 02 CS2312 Prblem Slving and Prgramming IX. Parentheses and Operatr Hierarchy When ne expressin cntains 2 r mre peratrs, then The rder f Evaluatin depends n precedence level and assciativity. E.g. int x = / (4 + 5 * 7-2); - The precedence level f / and * are higher than the precedence level f + and - - T verride the abve rdering, we add () fr gruping. the precedence level f () is high precedence level Exercise: Q1. Fr each underlined expressin belw, mark the steps with, : (i). System.ut.println(1234 / 100 / 10) ; (ii) System.ut.println(1234 * 60 % 24); (nte: * and % have the same precedence) (iii). int a,b; a = b = 10; Q2. Delete the wrng items belw (*): In * (i) / (ii) / (iii), we say that the assciativity is left-t-right. In * (i) / (ii) / (iii), we say that the assciativity is right-t-left. Nte: When peratrs have the same precedence level, then the assciativity rules f the peratrs decide the rder f evaluatin. Last mdified: 15-Sep /14

9 Tpic 02 CS2312 Prblem Slving and Prgramming X. Strings & StringBuilder Strings (java.lang.string) A String bject cntains a sequence f Unicde characters (cde units in UTF-16 encding) String variables are references t string bjects String s = new String("Hell"); r String s = "Hell"; Shrthand.length methd yields number f characters "" is the empty string f length 0, different frm null if (s!= null && s.length()!= 0) Check fr nn-null and nn-empty.charat methd yields char: char c = s.charat(i);.substring methd yields substrings: String greeting = "Hell"; String s = greeting.substring(1,3); It means frm psitin 1 inclusive t psitin 3 exclusive "el" + String greeting = "Hell"; String s; s = " " + greeting; // "1000 Hell" s = ' ' + greeting; // Use.equals t cmpare string cntents: String greeting = "Hell"; String part = greeting.substring(1, 3); if (part == "el") //NO! if (part.equals("el")) //OK Cnverting Strings t Numbers: Integer.parseInt String input = "7"; int n = Integer.parseInt(input); // n gets 7 Strings are immutable: N methd can change a character in an existing string T turn greeting frm Hell t Help!, it is nt s cnvenient: greeting = greeting.substring(0,3)+"p!"; actually a new string bject Fr the riginal string bject which was previusly referred by greeting, Java has the Garbage Cllectin mechanism t recycle the unused memry. StringBuilder (java.lang.stringbuilder) If mre cncatenatin wrk is needed, using + fr string cncatenatin is inefficient reasn: it actually creates new string bjects StringBuilder sb = new StringBuilder(); sb.append("hell "); sb.append(name); //suppse name is "Peter" String result=sb.tstring(); //gives "Hell Peter" StringBuilder bject can manipulate characters within itself. Other StringBuilder methds fr handling character cntents: setcharat, insert, delete Last mdified: 15-Sep /14

10 Tpic 02 CS2312 Prblem Slving and Prgramming XI. Input (Cnsle, File, Input frm String) (1) Reading input frm Cnsle Cnstruct Scanner frm input stream (e.g. System.in) Scanner in = new Scanner(System.in);.nextInt,.nextDuble reads next int r duble int n = in.nextint();.next reads next string (delimited by whitespace: space, tab, newline; discard leading whitespace).nextline reads until newline and remves newline frm the stream. Smetimes we need.nextline t remve extra line break (Learn frm Lab03).clse clses the stream Scanner in = new Scanner(System.in); String s1,s2; s1 = in.next(); //type " Tday is a gd day." s2 = in.nextline(); System.ut.println(s1); //"Tday" System.ut.println(s2); //" is a gd day in.clse(); Tday is a gd day. Tday is a gd day. Rundwn (2) Reading input frm a file Cnstruct Scanner frm a File bject Scanner infile = new Scanner(new File("c:\\data\\case1.txt"));.hasNext() checks whether there is still next string in the file. Scanner infile = new Scanner(new File(fileName)); while (infile.hasnext()) String line = infile.nextline(); infile.clse(); (3) Reading input frm anther string Scanner indata = new Scanner(str); //where str is a String // apply.hasnext(),.next(),.clse() etc Example: Read a f wrds and shw them line by line: System.ut.print("Enter a line f wrds: "); Scanner scannercnsle = new Scanner(System.in); String str = scannercnsle.nextline(); Scanner scannerstr = new Scanner(str); while (scannerstr.hasnext()) System.ut.println(scannerStr.next()); scannerstr.clse(); scannercnsle.clse(); Output Enter a line f wrds: Have a gd day! Have a gd day! Last mdified: 15-Sep /14

Tpic 02 CS2312 Prblem Slving and Prgramming www.cs.cityu.edu.hk/~helena XII. Output (System.ut.printf, String.frmat, PrinterWriter) Frmatted Output using System.ut.printf() Using.print,.

$Next year yu'll be %d\n", name, (age+1)); Cnversin characters (%f, %d, %s): Similar methd t create a string String msg = String.frmat( Hi %s.$

11 Tpic 02 CS2312 Prblem Slving and Prgramming XII. Output (System.ut.printf, String.frmat, PrinterWriter) Frmatted Output using System.ut.printf() Using.print,.println fr flating-pint values (prblem): duble x = / 3.0; System.ut.println(x); //prints Using.printf frmatted utput (slutin) duble x = / 3.0; System.ut.printf("%8.2f", x);//prints Field width f 8 characters Precisin f 2 characters => Result has a leading space and 7 characters Using.printf multiple parameters System.ut.printf("Hi %s. Next year yu'll be %d\n", name, (age+1)); Cnversin characters (%f, %d, %s): Similar methd t create a string String msg = String.frmat( Hi %s. Next year yu'll be %d", name, age+1); Output t a file (Create a PrinterWriter bject, then apply.print etc) PrintWriter ut = new PrintWriter("c:\\reprt\\myfile.txt"); ut.println("my GPA is 4.0"); ut.clse(); Last mdified: 15-Sep /14

Tpic 02 CS2312 Prblem Slving and Prgramming www.cs.cityu.edu.hk/~helena XIII.

main(string[] args) int n;... int k; int n; // ERROR--can't redefine n in inner blck... Declaring a variable in a fr-lp: fr (int i = 1; i <= 10; i++).

12 Tpic 02 CS2312 Prblem Slving and Prgramming XIII. Cntrl flw Cntrl structures (similar t C++): if ifelse switch-case while d-while fr Blck Scpe (cmpund statement inside ) Cannt declare identically named variables in 2 nested blcks: public static vid main(string[] args) int n;... int k; int n; // ERROR--can't redefine n in inner blck... Declaring a variable in a fr-lp: fr (int i = 1; i <= 10; i++)... // i n lnger defined here fr (int i = 11; i <= 20; i++) // OK t define anther variable named i... Using break and cntinue: break means "immediately halt executin f this lp" Cntinue means "skip t next iteratin f this lp." // Find x in an array A // read in 10 numbers // and handle nly the psitive nes bfund=false; fr (i=0; i<10; i++) fr (i=0;i<n;i++) x=scannerobj.nextint(); if (A[i]==x) if (x<0) bfund=true; System.ut.println("Wrng"); break; cntinue; // N need t use break // prcessing f x bfund=false; fr (i=0;i<n &&!bfund;i++) if (A[i]==x) bfund=true; Last mdified: 15-Sep /14

13 Tpic 02 CS2312 Prblem Slving and Prgramming XIV. Arrays An array is a cllectin f elements f the same type Index is zer-based int[] arr; // int[] is the array type; arr is the array name // int arr[]; is als kay, but nt welcme by Java fans arr = new int[5]; //create the array; arr[0] = 3; arr[1] = 25; fr (int i=0;i<arr.length;i++) //use.length t tell the array size System.ut.println(arr[i]); Output Initialized values Fr number elements : 0 Fr blean elements: false; Fr bject elements: null Once created, cannt change size If extensin is needed, make arr t refer t a new larger array and cpy the ld cntents. Array variable is a reference arr [0] = 3 [1] = 25 Styles f array declaratin: (1) int[] arr; (2) int[] arr = new int[5]; (3) arr = new int[5]; arr[0] = 3; arr[0] = 3; arr[1] = 25; arr[1] = 25; int[] arr = 3,5,0,0,0; Shrthand - Declaratin with initializers Reinitializing an array variable int[] arr = 3,5,0,0,0; arr = new int[] 1,2,3,4,5,6,7,8; a new array Fr the riginal array which was previusly referred by arr, Java has a Garbage Cllectin mechanism t recycle the unused memry. The fr each lp: Syntax: fr (variable : cllectin) statement Example: fr (int x: arr) System.ut.println(x); "fr each" lp - ges thrugh each element as x Arrays.tString Prvided by the java.util.arrays class Returns a string representatin f the array int[] arr = 3,5,0,0,0; Output System.ut.println(Arrays.tString(arr)); [3, 5, 0, 0, 0] Srting with Arrays.srt Arrays.srt(arr); Output System.ut.println(Arrays.tString(arr)); [0, 0, 0, 3, 5] Last mdified: 15-Sep /14

Tpic 02 CS2312 Prblem Slving and Prgramming www.cs.cityu.edu.

cpyOf(riginalArray, newsize); arr1 arr3 int[] arr1, arr2, arr3, arr4, arr5; arr1 = new int[] 3,25,0,0,0; // 5 elements arr2 [0] = 3 [1] = 99 [0] = 3 [1] = 25 arr2 = arr1; arr3 = Arrays.

14 Tpic 02 CS2312 Prblem Slving and Prgramming Array cpying (1) Cpying reference nt really creating new array arr1 = new int[] 3,25,0,0,0; arr2 = arr1; arr1 arr2 [0] = 3 [1] = 25 (2) Cpying as a new array: Arrays.cpyOf Syntax: Arrays.cpyOf(riginalArray, newsize); arr1 arr3 int[] arr1, arr2, arr3, arr4, arr5; arr1 = new int[] 3,25,0,0,0; // 5 elements arr2 [0] = 3 [1] = 99 [0] = 3 [1] = 25 arr2 = arr1; arr3 = Arrays.cpyOf(arr1, 4); // nly want 4 elements arr4 = Arrays.cpyOf(arr1, arr1.length); arr5 = Arrays.cpyOf(arr1, 8); // 3 additinal elements are 0 arr1[1]=99; arr4 [0] = 3 [1] = 25 arr5 [0] = 3 [1] = 25 System.ut.println(Arrays.tString(arr1)); System.ut.println(Arrays.tString(arr2)); System.ut.println(Arrays.tString(arr3)); System.ut.println(Arrays.tString(arr4)); System.ut.println(Arrays.tString(arr5)); Output [3, 99, 0, 0, 0] [3, 99, 0, 0, 0] [3, 25, 0, 0] [3, 25, 0, 0, 0] [3, 25, 0, 0, 0, 0, 0, 0] Arrays.cpyOfRange is anther useful methd. Learn it in Lab03. Multidimensinal array 2D array: - Is a 1D array f sme 1D arrays 5 rws 10 clumns int[][] table = new int[5][10]; table[3][5]=1234; // set 4th rw, 6th clumn t 1234 fr (int[] arr1d: table) System.ut.println(Arrays.tString(arr1D)); Output [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [0, 0, 0, 0, 0, 1234, 0, 0, 0, 0] [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] table = table[0]= table[4]= 1234 Ragged Array: - Different rws have different lengths It is easy t d s in Java. String[][] helpers = "Helena", "Kit", "Jasn", "Helena", "Kit", "Jasn", "Kit", "Jasn", "Helena", "Kit", "Helena" ; System.ut.println("Helpers fr T01-T05:"); System.ut.println("===================="); fr (String[] arr1d: helpers) System.ut.println(Arrays.tString(arr1D)); Output Helpers fr T01-T05: ==================== [Helena, Kit, Jasn] [Helena, Kit, Jasn] [Kit, Jasn] [Helena, Kit] [Helena] Last mdified: 15-Sep /14

CS1150 Principles of Computer Science Midterm Review

CS1150 Principles of Computer Science Midterm Review CS1150 Principles f Cmputer Science Midterm Review Yanyan Zhuang Department f Cmputer Science http://www.cs.uccs.edu/~yzhuang CS1150 UC. Clrad Springs Office hurs 10/15, Mnday, 12:05 12:50pm 10/17, Wednesday