Moments and products of inertia and radii of gyration about central axes. I x ¼ I y ¼ Ix 0 ¼ a4. r x ¼ r y ¼ r 0 x ¼ 0:2887a.
|
|
- Noreen Watson
- 5 years ago
- Views:
Transcription
1
2
3 TBLE.1 Properties of sections NOTTION: ¼ re ðlengthþ 2 ; y ¼ distnce to extreme fiber (length); I ¼ moment of inerti ðlength Þ; r ¼ rdius of gyrtion (length); Z ¼ plstic section modulus ðlength 3 Þ;SF¼ shpe fctor. See Sec for pplictions of Z nd SF Form of section 1. Squre ¼ 2 2. Rectngle ¼ bd y c ¼ x c ¼ 2 y 0 c ¼ 0:707 cos p y c ¼ d 2 3. Hollow rectngle ¼ bd b i d i y c ¼ d 2 re nd distnces from centroid to extremities Moments nd products of inerti nd rdii of gyrtion bout centrl xes I x ¼ I y ¼ Ix 0 ¼ 1 12 r x ¼ r y ¼ r 0 x ¼ 0:2887 I x ¼ 1 12 bd3 I y ¼ 1 12 db3 I x > I y if d > b r x ¼ 0:2887d r y ¼ 0:2887b I x ¼ bd3 b i d 3 i 12 I y ¼ db3 d i b 3 i 12 r x ¼ x r y ¼ y Z x ¼ Z y ¼ 0:25 3 SF x ¼ SF y ¼ 1:5 Z x ¼ 0:25bd 2 Z y ¼ 0:25db 2 SF x ¼ SF y ¼ 1:5 Z x ¼ bd2 b i d 2 i SF x ¼ Z xd 2I x Z x ¼ db2 d i b 2 i SF y ¼ Z yb 2I y Plstic section moduli, shpe fctors, nd loctions of plstic neutrl xes 802 Formuls for Stress nd Strin [PP.
4 TBLE.1. Tee section ¼ tb þ t w d y c ¼ bt2 þ t w dð2t þ dþ 2ðtb þ t w dþ 5. Chnnel section ¼ tb þ 2t w d y c ¼ bt2 þ 2t w dð2t þ dþ 2ðtb þ 2t w dþ I x ¼ b 3 ðd þ tþ3 d3 3 ðb t wþ ðd þ t y c Þ 2 I y ¼ tb3 12 þ dt3 w 12 r x ¼ x r y ¼ y I x ¼ b 3 ðd þ tþ3 d3 3 ðb 2t wþ ðdþt y c Þ 2 ðd þ tþb3 I y ¼ dðb 2t wþ r x ¼ x r y ¼ y If t w d 5 bt, then Z x ¼ d2 t w b2 t 2 btðd þ tþ þ t w 2 Neutrl xis x is locted distnce ðbt=t w þ dþ=2 from the bottom. If t w d bt, then Z x ¼ t2 b þ t wdðt þ d t w d=2bþ 2 Neutrl xis x is locted distnce ðt w d=b þ tþ=2 from the top. SF x ¼ Z xðd þ t y c Þ I 1 Z y ¼ b2 t þ t 2 wd SF y ¼ Z yb 2I y If 2t w d 5 bt, then Z x ¼ d2 t w 2 b2 t 2 btðd þ tþ þ 8t w 2 Neutrl xis x is locted distnce ðbt=2t w þ dþ=2 from the bottom. If 2t w d bt, then Z x ¼ t2 b þ t wd tþ d t wd b Neutrl xis x is locted distnce t w d=b þ t=2 from the top. SF x ¼ Z xðd þ t y c Þ I x Z y ¼ b2 t þ t wdðb t w Þ SF y ¼ Z yb 2I y PP. ] Properties of Plne re 803
5 TBLE.1 Form of section 6. Wide-flnge bem with equl flnges ¼ 2bt þ t w d y c ¼ d 2 þ t 7. Equl-legged ngle ¼ tð2 tþ y c1 ¼ 0:7071ð2 þ t t 2 Þ 2 t y c2 ¼ 0: t x c ¼ 0: Unequl-legged ngle ¼ tðb þ d tþ x c ¼ b2 þ dt t 2 2ðb þ d tþ y c ¼ d2 þ bt t 2 2ðb þ d tþ re nd distnces from centroid to extremities Moments nd products of inerti nd rdii of gyrtion bout centrl xes bðd þ 2tÞ3 I x ¼ ðb t wþd I y ¼ b3 t 6 þ t3 wd 12 r x ¼ x r y ¼ y I x ¼ b 0:5t2 b 2 12 þ b I y ¼ b where b ¼ t 12 r x ¼ x r y ¼ y I x ¼ 1 3 ½bd3 ðb tþðd tþ 3 Š ðd y c Þ 2 I y ¼ 1 3 ½db3 ðd tþðb tþ 3 Š ðb x c Þ 2 I xy ¼ 1 ½b2 d 2 ðb tþ 2 ðd tþ 2 Š ðb x c Þðd y c Þ r x ¼ x r y ¼ y Z x ¼ t wd 2 þ btðd þ tþ SF x ¼ Z x y c I x Z y ¼ b2 t 2 þ t2 wd SF y ¼ Z yx c I y Plstic section moduli, shpe fctors, nd loctions of plstic neutrl xes Let y p be the verticl distnce from the top corner to the plstic neutrl xis. If t= 5 0:0, then # 1=2 y p ¼ t ðt=þ2 2 Z x ¼ ðy c1 0:6667y p Þ If t= 0:, then y p ¼ 0:3536ð þ 1:5tÞ Z x ¼ y c1 2:828y 2 pt þ 1:8856t 3 80 Formuls for Stress nd Strin [PP.
6 TBLE.1 9. Equilterl tringle ¼ 0: Isosceles tringle 11. Tringle y c ¼ 0:577 x c ¼ 0:5000 y 0 c ¼ 0:577 cos ¼ bd 2 y c ¼ 2 3 d ¼ bd 2 y c ¼ 2 3 d x c ¼ 2 3 b Prllelogrm ¼ bd y c ¼ d 2 x c ¼ 1 2 ðb þ Þ I x ¼ I y ¼ I x 0 ¼ 0:0180 r x ¼ r y ¼ r x 0 ¼ 0:201 I x ¼ 1 36 bd3 I y ¼ 1 8 db3 I x > I y if d > 0:866b r x ¼ 0:2357d r y ¼ 0:201b I x ¼ 1 36 bd3 I y ¼ 1 36 bdðb2 b þ 2 Þ I xy ¼ 1 72 bd2 ðb 2Þ y x ¼ 1 dðb 2Þ 2 tn 1 b 2 b þ 2 d 2 r x ¼ 0:2357d p r y ¼ 0:2357 ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi b 2 b þ 2 I x ¼ 1 12 bd3 I y ¼ 1 12 bdðb2 þ 2 Þ I xy ¼ 1 12 bd2 y x ¼ 1 2d 2 tn 1 b 2 þ 2 d 2 r x ¼ 0:2887d p r y ¼ 0:2887 ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi b 2 þ 2 Z x ¼ 0: ; Z y ¼ 0: SF x ¼ 2:33; SF y ¼ 2:000 Neutrl xis x is 0:2537 from the bse. Z x ¼ 0:097bd 2 ; Z y ¼ 0:0833db 2 SF x ¼ 2:33; SF y ¼ 2:000 Neutrl xis x is 0:2929d from the bse. PP. ] Properties of Plne re 805
7 TBLE.1 Form of section 13. Dimond 1. Trpezoid ¼ bd 2 y c ¼ d Solid circle ¼ pr 2 re nd distnces from centroid to extremities ¼ d ðb þ cþ 2 y c ¼ d 2b þ c 3 b þ c x c ¼ 2b2 þ 2bc b 2c c 2 3ðb þ cþ y c ¼ R Moments nd products of inerti nd rdii of gyrtion bout centrl xes I x ¼ 1 8 bd3 I y ¼ 1 8 db3 r x ¼ 0:201d r y ¼ 0:201b I x ¼ d3 b 2 þ bc þ c 2 36 b þ c d I y ¼ 36ðb þ cþ ½b þ c þ 2bcðb 2 þ c 2 Þ ðb 3 þ 3b 2 c 3bc 2 c 3 Þ þ 2 ðb 2 þ bc þ c 2 ÞŠ d 2 I xy ¼ 72ðb þ cþ ½cð3b2 3bc c 2 Þ þ b 3 ð2b 2 þ 8bc þ 2c 2 ÞŠ I x ¼ I y ¼ p R r x ¼ r y ¼ R 2 Plstic section moduli, shpe fctors, nd loctions of plstic neutrl xes Z x ¼ 0:0833bd 2 ; Z y ¼ 0:0833db 2 SF x ¼ SF y ¼ 2:000 Z x ¼ Z y ¼ 1:333R 3 SF x ¼ 1: Formuls for Stress nd Strin [PP.
8 TBLE Hollow circle ¼ pðr 2 R 2 i Þ y c ¼ R 17. Very thin nnulus ¼ 2pRt y c ¼ R 18. Sector of solid circle ¼ R 2 y c1 ¼ R 1 2 sin 3 2R sin y c2 ¼ 3 x c ¼ R sin I x ¼ I y ¼ p ðr R i Þ qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi r x ¼ r y ¼ 1 2 R 2 þ R 2 i I x ¼ I y ¼ pr 3 t r x ¼ r y ¼ 0:707R I x ¼ R! þ sin cos 16 sin2 9 I y ¼ R ð sin cos Þ ðnote: If is smll; sin cos ¼ Þ sffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi r x ¼ R sin cos 1 þ 16 sin r y ¼ R rffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi sin cos 1 2 Z x ¼ Z y ¼ 1:333ðR 3 R 3 i Þ SF x ¼ 1:698 R R 3 i R R R i Z x ¼ Z y ¼ R 2 t SF x ¼ SF y ¼ p If 5:3, then Z x ¼ 0:6667R 3 3 1=2 # sin 2 tn Neutrl xis x is locted distnce Rð0:5= tn Þ 1=2 from the vertex. If 55:3, then Z x ¼ 0:6667R 3 ð2 sin 3 1 sin Þ where the expression 2 1 sin 2 1 ¼ is solved for the vlue of 1. Neutrl xis x is locted distnce R cos 1 from the vertex. If 73:09, then SF x ¼ Z xy c2 I x If 73:09 90, then SF x ¼ Z xy c1 I x Z y ¼ 0:6667R 3 ð1 cos Þ If 90, then 1 cos SF y ¼ 2:6667 sin sin cos If 590, then 1 cos SF y ¼ 2:6667 sin cos PP. ] Properties of Plne re 807
9 TBLE.1 Form of section 19. Segment of solid circle (Note: If p=, use expressions from cse 20) 20. Segment of solid circle (Note: Do not use if > p=þ re nd distnces from centroid to extremities ¼ R 2 ð sin cos Þ # 2 sin 3 y c1 ¼ R 1 3ð sin cos Þ # 2 sin 3 y c2 ¼ R cos 3ð sin cos Þ x c ¼ R sin ¼ 2 3 R2 3 ð1 0:2 2 þ 0:019 Þ y c1 ¼ 0:3R 2 ð1 0: þ 0:0028 Þ y c2 ¼ 0:2R 2 ð1 0: þ 0:0027 Þ x c ¼ Rð1 0: þ 0:0083 Þ 21. Sector of hollow circle ¼ tð2r tþ y c1 ¼ R 1 2 sin 1 t 3 R þ 1 2 t=r 2 sin y c2 ¼ R 3ð2 t=rþ þ 1 t 2 sin 3 cos R 3 (Note: If t=r is smll, cn exceed p to form n overlpped nnulus) x c ¼ R sin Moments nd products of inerti nd rdii of gyrtion bout centrl xes # I x ¼ R sin cos þ 2 sin 3 16 sin 6 cos 9ð sin cos Þ I y ¼ R 12 ð3 3 sin cos 2 sin3 cos Þ sffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi r x ¼ R 1 þ 2 sin3 cos 2 sin cos 16 sin 6 9ð sin cos Þ 2 sffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi r y ¼ R 1 2 sin3 cos 2 3ð sin cos Þ I x ¼ 0:0113R 7 ð1 0:391 2 þ 0:050 Þ I y ¼ 0:1333R 5 ð1 0:762 2 þ 0:1111 Þ r x ¼ 0:1309R 2 ð1 0:075 2 Þ r y ¼ 0:72Rð1 0: þ 0:018 Þ I x ¼ R 3 t 1 3t 2R þ t2 t3 R2 R 3! þ sin cos 2 sin2 þ t2 sin 2 3R 2 1 t # ð2 t=rþ R þ t2 6R 2 I y ¼ R 3 t 1 3t 2R þ t2 t3 R2 R 3 ð sin cos Þ rffiffiffiffi rffiffiffiffi I r x ¼ x I y ; r y ¼ Plstic section moduli, shpe fctors, nd loctions of plstic neutrl xes 808 Formuls for Stress nd Strin [PP.
10 TBLE Solid semicircle ¼ p 2 R2 23. Hollow semicircle Note: b ¼ R þ R i 2 t ¼ R R i Note: If is smll: sin ¼ þ 120 ; sin cos ¼ þ 2 sin 2 ; ¼ þ 2 5 cos ¼ þ 2 ; þ sin cos 2 sin2 ¼ þ 105 y c1 ¼ 0:5756R y c2 ¼ 0:2R x c ¼ R ¼ p 2 ðr2 R 2 i Þ y c2 ¼ 3p R 3 R 2 i R 2 R 2 i or y c2 ¼ 2b p y c1 ¼ R y c2 x c ¼ R 2. Solid ellipse ¼ pb y c ¼ x c ¼ b # 1 þ ðt=bþ2 12 I x ¼ 0:1098R I y ¼ p 8 R r x ¼ 0:263R r y ¼ R 2 I x ¼ p 8 ðr R i Þ 8 ðr 3 R 3 i Þ2 9p R 2 R 2 i or I x ¼ 0:2976tb 3 þ 0:1805bt 3 0:0088t5 b I y ¼ p 8 ðr R i Þ or I y ¼ 1:5708b 3 t þ 0:3927bt 3 I x ¼ p b3 I y ¼ p b3 r x ¼ 2 r y ¼ b 2 Z x ¼ 0:350R 3 ; Z y ¼ 0:6667R 3 SF x ¼ 1:856; SF y ¼ 1:698 Plstic neutrl xis x is locted distnce 0:00R from the bse. Let y p be the verticl distnce from the bottom to the plstic neutrl xis. y p ¼ð0:7071 0:2716C 0:299C 2 þ 0:3983C 3 ÞR Z x ¼ð0:828 0:910C þ 0:725C 2 0:2850C 3 ÞR 2 t where C ¼ t=r Z y ¼ 0:6667ðR 3 R 3 i Þ Z x ¼ 1:333 2 b; SF x ¼ SF y ¼ 1:698 Z y ¼ 1:333b 2 PP. ] Properties of Plne re 809
11 TBLE.1 re nd distnces from Form of section centroid to extremities 25. Hollow ellipse ¼ pðb i b i Þ y c ¼ x c ¼ b Note: For this cse the inner nd outer perimeters re both ellipses nd the wll thickness is not constnt. For cross section with constnt wll thickness see cse Hollow ellipse with constnt wll thickness t. The midthickness perimeter is n ellipse (shown dshed). 0:2 < =b < 5 See the note on mximum wll thickness in cse 27. # 2 b ¼ ptð þ bþ 1 þ K 1 þ b where K 1 ¼ 0:26 þ 0: b þ b y c ¼ þ t 2 x c ¼ b þ t 2 Moments nd products of inerti nd rdii of gyrtion bout centrl xes I x ¼ p ðb3 b i 3 i Þ I y ¼ p ðb3 i b 3 i Þ sffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi r x ¼ 1 b 3 b i 3 i 2 b i b i sffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi r y ¼ 1 b 3 i b 3 i 2 b i b i I x ¼ p # 2 b t2 ð þ 3bÞ 1 þ K 2 þ b þ p # 2 b 16 t3 ð3 þ bþ 1 þ K 3 þ b where K 2 ¼ 0:139 þ 0:1279 b 0: b K 3 ¼ 0:139 þ 0:1279 b 0:0128 b 2 For I y interchnge nd b in the expressions for I x ; K 2,ndK 3 Plstic section moduli, shpe fctors, nd loctions of plstic neutrl xes Z x ¼ 1:333ð 2 b 2 i b i Þ Z y ¼ 1:333ðb 2 b 2 i i Þ SF x ¼ 1:698 3 b 2 i b i 3 b 3 i b i SF y ¼ 1:698 b3 b 2 i ib b 3 b 3 i i # 2 b Z x ¼ 1:3333tð þ 2bÞ 1 þ K þ t3 þ b 3 where K ¼ 0:1835 þ 0:895 b 0: b For Z y interchnge nd b in the expression for Z x nd K. 810 Formuls for Stress nd Strin [PP.
12 TBLE Hollow semiellipse with constnt wll thickness t. The midthickness perimeter is n ellipse (shown dshed). 0:2 < =b < 5 Note: There is limit on the mximum wll thickness llowed in this cse. Cusps will form in the perimeter t the ends of the mjor xis if this mximum is exceeded. If b 1; then t mx ¼ 22 b If b 5 1; then t mx ¼ 2b2 ¼ p # 2 2 tð þ bþ 1 þ K b 1 þ b where K 1 ¼ 0:26 þ 0: b þ b y c2 ¼ 2 p K 2 þ t2 6p K 3 where K 2 ¼ 1 0:331C þ 0:0136C 2 þ 0:1097C 3 K 3 ¼ 1 þ 0:9929C 0:2287C 2 0:2193C 3 Using C ¼ b þ b y c1 ¼ þ t 2 y c2 x c ¼ b þ t 2 I X ¼ p # 2 b 8 t2 ð þ 3bÞ 1 þ K þ b þ p # 2 b 32 t3 ð3 þ bþ 1 þ K 5 þ b where K ¼ 0:139 þ 0:1279 b 0: b K 5 ¼ 0:139 þ 0:1279 b 0:0128 b 2 I x ¼ I X y 2 c2 For I y use one-hlf the vlue for I y in cse 26. Let y p be the verticl distnce from the bottom to the plstic neutrl xis. y p ¼ C 1 þ C 2 =b þ C 3 ð=bþ 2 þ C ð=bþ 3 where if 0:25 < =b 1, then C 1 ¼ 0:5067 0:5588D þ 1:3820D 2 C 2 ¼ 0:3731 þ 0:1938D 1:078D 2 C 3 ¼ 0:100 þ 0:0179D þ 0:885D 2 C ¼ 0:0170 0:0079D 0:0565D 2 or if 1 =b <, then C 1 ¼ 0:829 þ 0:0725D 0:1815D 2 C 2 ¼ 0:1957 0:6608D þ 1:222D 2 C 3 ¼ 0:0203 þ 1:8999D 3:356D 2 C ¼ 0:0578 1:6666D þ 2:6012D 2 where D ¼ t=t mx nd where 0:2 < D 1 Z x ¼ C 5 þ C 6 =b þ C 7 ð=bþ 2 þ C 8 ð=bþ 3 2 t where if 0:25 < =b 1, then C 5 ¼ 0:0292 þ 0:379D 1=2 þ 0:0578D C 6 ¼ 0:367 0:8531D 1=2 þ 0:3882D C 7 ¼ 0:1218 þ 0:3563D 1=2 0:1803D C 8 ¼ 0:015 0:08D 1=2 þ 0:0233D or if 1 =b <, then C 5 ¼ 0:221 0:3922D 1=2 þ 0:2960D C 6 ¼ 0:6637 þ 2:7357D 1=2 2:082D C 7 ¼ 1:5211 5:386D 1=2 þ 3:9286D C 8 ¼ 0:898 þ 2:8763D 1=2 1:887D For Z y use one-hlf the vlue for Z y in cse 26. PP. ] Properties of Plne re 811
13 TBLE.1 Form of section 28. Regulr polygon with n sides 29. Hollow regulr polygon with n sides Properties of sections Continued) re nd distnces from centroid to extremities ¼ 2 n tn r 1 ¼ 2 sin r 2 ¼ 2 tn If n is odd y 1 ¼ y 2 ¼ r 1 cos n þ 1 p 2 2 If n=2 is odd y 1 ¼ r 1 ; y 2 ¼ r 2 If n=2 is even y 1 ¼ r 2 ; y 2 ¼ r 1 ¼ nt 1 t tn r 1 ¼ 2 sin r 2 ¼ 2 tn If n is odd y 1 ¼ y 2 ¼ r 1 cos n þ 1 p 2 2 If n=2 is odd y 1 ¼ r 1 ; y 2 ¼ r 2 If n=2 is even y 1 ¼ r 2 ; y 2 ¼ r 1 Moments nd products of inerti nd rdii of gyrtion bout centrl xes I 1 ¼ I 2 ¼ 1 2 ð6r2 1 2 Þ qffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 r 1 ¼ r 2 ¼ 2 ð6r2 1 2 Þ I 1 ¼ I 2 ¼ n3 t þ 1 tn t tn þ t tn 2 2 t tn # 3 r 1 ¼ r 2 ¼ p ffiffiffi 8 vffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi 1 þ 1 t tn 3 tn þ 2 t tn # u 2 t Plstic section moduli, shpe fctors, nd loctions of plstic neutrl xes For n ¼ 3, see cse 9. For n ¼, see cses 1 nd 13. For n ¼ 5, Z 1 ¼ Z 2 ¼ 0:8825r 3 1. For n xis perpendiculr to xis 1, Z ¼ 0:8838r 3 1. The loction of this xis is from tht side which is perpendiculr to xis 1. For n 5 6, use the following expression for neutrl xis of ny inclintion: Z ¼ r 3 1 1:333 13: þ 12:528 1 # 3 n n 812 Formuls for Stress nd Strin [PP.
9.1 apply the distance and midpoint formulas
9.1 pply the distnce nd midpoint formuls DISTANCE FORMULA MIDPOINT FORMULA To find the midpoint between two points x, y nd x y 1 1,, we Exmple 1: Find the distnce between the two points. Then, find the
More informationB. Definition: The volume of a solid of known integrable cross-section area A(x) from x = a
Mth 176 Clculus Sec. 6.: Volume I. Volume By Slicing A. Introduction We will e trying to find the volume of solid shped using the sum of cross section res times width. We will e driving towrd developing
More informationGraphing Conic Sections
Grphing Conic Sections Definition of Circle Set of ll points in plne tht re n equl distnce, clled the rdius, from fixed point in tht plne, clled the center. Grphing Circle (x h) 2 + (y k) 2 = r 2 where
More informationPythagoras theorem and trigonometry (2)
HPTR 10 Pythgors theorem nd trigonometry (2) 31 HPTR Liner equtions In hpter 19, Pythgors theorem nd trigonometry were used to find the lengths of sides nd the sizes of ngles in right-ngled tringles. These
More informationa < a+ x < a+2 x < < a+n x = b, n A i n f(x i ) x. i=1 i=1
Mth 33 Volume Stewrt 5.2 Geometry of integrls. In this section, we will lern how to compute volumes using integrls defined by slice nlysis. First, we recll from Clculus I how to compute res. Given the
More information6.3 Volumes. Just as area is always positive, so is volume and our attitudes towards finding it.
6.3 Volumes Just s re is lwys positive, so is volume nd our ttitudes towrds finding it. Let s review how to find the volume of regulr geometric prism, tht is, 3-dimensionl oject with two regulr fces seprted
More information50 AMC LECTURES Lecture 2 Analytic Geometry Distance and Lines. can be calculated by the following formula:
5 AMC LECTURES Lecture Anlytic Geometry Distnce nd Lines BASIC KNOWLEDGE. Distnce formul The distnce (d) between two points P ( x, y) nd P ( x, y) cn be clculted by the following formul: d ( x y () x )
More information9.1 PYTHAGOREAN THEOREM (right triangles)
Simplifying Rdicls: ) 1 b) 60 c) 11 d) 3 e) 7 Solve: ) x 4 9 b) 16 80 c) 9 16 9.1 PYTHAGOREAN THEOREM (right tringles) c If tringle is right tringle then b, b re the legs * c is clled the hypotenuse (side
More informationClass-XI Mathematics Conic Sections Chapter-11 Chapter Notes Key Concepts
Clss-XI Mthemtics Conic Sections Chpter-11 Chpter Notes Key Concepts 1. Let be fixed verticl line nd m be nother line intersecting it t fixed point V nd inclined to it t nd ngle On rotting the line m round
More informationConic Sections Parabola Objective: Define conic section, parabola, draw a parabola, standard equations and their graphs
Conic Sections Prol Ojective: Define conic section, prol, drw prol, stndrd equtions nd their grphs The curves creted y intersecting doule npped right circulr cone with plne re clled conic sections. If
More informationSection 10.4 Hyperbolas
66 Section 10.4 Hyperbols Objective : Definition of hyperbol & hyperbols centered t (0, 0). The third type of conic we will study is the hyperbol. It is defined in the sme mnner tht we defined the prbol
More informationArea & Volume. Chapter 6.1 & 6.2 September 25, y = 1! x 2. Back to Area:
Bck to Are: Are & Volume Chpter 6. & 6. Septemer 5, 6 We cn clculte the re etween the x-xis nd continuous function f on the intervl [,] using the definite integrl:! f x = lim$ f x * i )%x n i= Where fx
More informationMTH 146 Conics Supplement
105- Review of Conics MTH 146 Conics Supplement In this section we review conics If ou ne more detils thn re present in the notes, r through section 105 of the ook Definition: A prol is the set of points
More informationChapter44. Polygons and solids. Contents: A Polygons B Triangles C Quadrilaterals D Solids E Constructing solids
Chpter44 Polygons nd solids Contents: A Polygons B Tringles C Qudrilterls D Solids E Constructing solids 74 POLYGONS AND SOLIDS (Chpter 4) Opening prolem Things to think out: c Wht different shpes cn you
More information6.2 Volumes of Revolution: The Disk Method
mth ppliction: volumes by disks: volume prt ii 6 6 Volumes of Revolution: The Disk Method One of the simplest pplictions of integrtion (Theorem 6) nd the ccumultion process is to determine so-clled volumes
More informationFig.1. Let a source of monochromatic light be incident on a slit of finite width a, as shown in Fig. 1.
Answer on Question #5692, Physics, Optics Stte slient fetures of single slit Frunhofer diffrction pttern. The slit is verticl nd illuminted by point source. Also, obtin n expression for intensity distribution
More informationStained Glass Design. Teaching Goals:
Stined Glss Design Time required 45-90 minutes Teching Gols: 1. Students pply grphic methods to design vrious shpes on the plne.. Students pply geometric trnsformtions of grphs of functions in order to
More informationANALYTICAL GEOMETRY. The curves obtained by slicing the cone with a plane not passing through the vertex are called conics.
ANALYTICAL GEOMETRY Definition of Conic: The curves obtined by slicing the cone with plne not pssing through the vertex re clled conics. A Conic is the locus directrix of point which moves in plne, so
More informationIf f(x, y) is a surface that lies above r(t), we can think about the area between the surface and the curve.
Line Integrls The ide of line integrl is very similr to tht of single integrls. If the function f(x) is bove the x-xis on the intervl [, b], then the integrl of f(x) over [, b] is the re under f over the
More informationUnit 5 Vocabulary. A function is a special relationship where each input has a single output.
MODULE 3 Terms Definition Picture/Exmple/Nottion 1 Function Nottion Function nottion is n efficient nd effective wy to write functions of ll types. This nottion llows you to identify the input vlue with
More informationStudy Sheet ( )
Key Terms prol circle Ellipse hyperol directrix focus focl length xis of symmetry vertex Study Sheet (11.1-11.4) Conic Section A conic section is section of cone. The ellipse, prol, nd hyperol, long with
More informationOPTICS. (b) 3 3. (d) (c) , A small piece
AQB-07-P-106 641. If the refrctive indices of crown glss for red, yellow nd violet colours re 1.5140, 1.5170 nd 1.518 respectively nd for flint glss re 1.644, 1.6499 nd 1.685 respectively, then the dispersive
More informationAlgebra II Notes Unit Ten: Conic Sections
Sllus Ojective: 0. The student will sketch the grph of conic section with centers either t or not t the origin. (PARABOLAS) Review: The Midpoint Formul The midpoint M of the line segment connecting the
More informationMATH 2530: WORKSHEET 7. x 2 y dz dy dx =
MATH 253: WORKSHT 7 () Wrm-up: () Review: polr coordintes, integrls involving polr coordintes, triple Riemnn sums, triple integrls, the pplictions of triple integrls (especilly to volume), nd cylindricl
More informationcalled the vertex. The line through the focus perpendicular to the directrix is called the axis of the parabola.
Review of conic sections Conic sections re grphs of the form REVIEW OF CONIC SECTIONS prols ellipses hperols P(, ) F(, p) O p =_p REVIEW OF CONIC SECTIONS In this section we give geometric definitions
More informationAnswer Key Lesson 6: Workshop: Angles and Lines
nswer Key esson 6: tudent Guide ngles nd ines Questions 1 3 (G p. 406) 1. 120 ; 360 2. hey re the sme. 3. 360 Here re four different ptterns tht re used to mke quilts. Work with your group. se your Power
More informationsuch that the S i cover S, or equivalently S
MATH 55 Triple Integrls Fll 16 1. Definition Given solid in spce, prtition of consists of finite set of solis = { 1,, n } such tht the i cover, or equivlently n i. Furthermore, for ech i, intersects i
More informationIterated Integrals. f (x; y) dy dx. p(x) To evaluate a type I integral, we rst evaluate the inner integral Z q(x) f (x; y) dy.
Iterted Integrls Type I Integrls In this section, we begin the study of integrls over regions in the plne. To do so, however, requires tht we exmine the importnt ide of iterted integrls, in which inde
More informationName Date Class. cot. tan. cos. 1 cot 2 csc 2
Fundmentl Trigonometric Identities To prove trigonometric identit, use the fundmentl identities to mke one side of the eqution resemle the other side. Reciprocl nd Rtio Identities csc sec sin cos Negtive-Angle
More informationZZ - Advanced Math Review 2017
ZZ - Advnced Mth Review Mtrix Multipliction Given! nd! find the sum of the elements of the product BA First, rewrite the mtrices in the correct order to multiply The product is BA hs order x since B is
More informationThirty-fourth Annual Columbus State Invitational Mathematics Tournament. Instructions
Thirty-fourth Annul Columbus Stte Invittionl Mthemtics Tournment Sponsored by Columbus Stte University Deprtment of Mthemtics Februry, 008 ************************* The Mthemtics Deprtment t Columbus Stte
More informationPOLYGON NAME UNIT # ASSIGN # 2.) STATE WHETHER THE POLYGON IS EQUILATERAL, REGULAR OR EQUIANGULAR
POLYGONS POLYGON CLOSED plane figure that is formed by three or more segments called sides. 2.) STTE WHETHER THE POLYGON IS EQUILTERL, REGULR OR EQUINGULR a.) b.) c.) VERTEXThe endpoint of each side of
More informationN-Level Math (4045) Formula List. *Formulas highlighted in yellow are found in the formula list of the exam paper. 1km 2 =1000m 1000m
*Formul highlighted in yellow re found in the formul lit of the em pper. Unit Converion Are m =cm cm km =m m = m = cm Volume m =cm cm cm 6 = cm km/h m/ itre =cm (ince mg=cm ) 6 Finncil Mth Percentge Incree
More informationRay surface intersections
Ry surfce intersections Some primitives Finite primitives: polygons spheres, cylinders, cones prts of generl qudrics Infinite primitives: plnes infinite cylinders nd cones generl qudrics A finite primitive
More informationAngle properties of lines and polygons
chievement Stndrd 91031 pply geometric resoning in solving problems Copy correctly Up to 3% of workbook Copying or scnning from ES workbooks is subject to the NZ Copyright ct which limits copying to 3%
More informationPhysics 152. Diffraction. Difrraction Gratings. Announcements. Friday, February 2, 2007
ics Fri Feb.02. Announcements Diffrction Difrrction Grtings Fridy, Februry 2, 2007 Help sessions: W 9-10 pm in NSC 118 Msteringics WU #5 due Mondy WU #6 due Wednesdy http://www.voltnet.com/ldder/ A bem
More informationMath 142, Exam 1 Information.
Mth 14, Exm 1 Informtion. 9/14/10, LC 41, 9:30-10:45. Exm 1 will be bsed on: Sections 7.1-7.5. The corresponding ssigned homework problems (see http://www.mth.sc.edu/ boyln/sccourses/14f10/14.html) At
More informationSection 9.2 Hyperbolas
Section 9. Hperols 597 Section 9. Hperols In the lst section, we lerned tht plnets hve pproimtel ellipticl orits round the sun. When n oject like comet is moving quickl, it is le to escpe the grvittionl
More informationMA1008. Calculus and Linear Algebra for Engineers. Course Notes for Section B. Stephen Wills. Department of Mathematics. University College Cork
MA1008 Clculus nd Liner Algebr for Engineers Course Notes for Section B Stephen Wills Deprtment of Mthemtics University College Cork s.wills@ucc.ie http://euclid.ucc.ie/pges/stff/wills/teching/m1008/ma1008.html
More information1 Drawing 3D Objects in Adobe Illustrator
Drwing 3D Objects in Adobe Illustrtor 1 1 Drwing 3D Objects in Adobe Illustrtor This Tutoril will show you how to drw simple objects with three-dimensionl ppernce. At first we will drw rrows indicting
More informationHyperbolas. Definition of Hyperbola
CHAT Pre-Clculus Hyperols The third type of conic is clled hyperol. For n ellipse, the sum of the distnces from the foci nd point on the ellipse is fixed numer. For hyperol, the difference of the distnces
More information8.2 Areas in the Plane
39 Chpter 8 Applictions of Definite Integrls 8. Ares in the Plne Wht ou will lern out... Are Between Curves Are Enclosed Intersecting Curves Boundries with Chnging Functions Integrting with Respect to
More informationLine The set of points extending in two directions without end uniquely determined by two points. The set of points on a line between two points
Lines Line Line segment Perpendiulr Lines Prllel Lines Opposite Angles The set of points extending in two diretions without end uniquely determined by two points. The set of points on line between two
More informationAngle Properties in Polygons. Part 1 Interior Angles
2.4 Angle Properties in Polygons YOU WILL NEED dynmic geometry softwre OR protrctor nd ruler EXPLORE A pentgon hs three right ngles nd four sides of equl length, s shown. Wht is the sum of the mesures
More information4-1 NAME DATE PERIOD. Study Guide. Parallel Lines and Planes P Q, O Q. Sample answers: A J, A F, and D E
4-1 NAME DATE PERIOD Pges 142 147 Prllel Lines nd Plnes When plnes do not intersect, they re sid to e prllel. Also, when lines in the sme plne do not intersect, they re prllel. But when lines re not in
More informationLily Yen and Mogens Hansen
SKOLID / SKOLID No. 8 Lily Yen nd Mogens Hnsen Skolid hs joined Mthemticl Myhem which is eing reformtted s stnd-lone mthemtics journl for high school students. Solutions to prolems tht ppered in the lst
More informationNaming 3D objects. 1 Name the 3D objects labelled in these models. Use the word bank to help you.
Nming 3D ojects 1 Nme the 3D ojects lelled in these models. Use the word nk to help you. Word nk cue prism sphere cone cylinder pyrmid D A C F A B C D cone cylinder cue cylinder E B E prism F cue G G pyrmid
More information2 Computing all Intersections of a Set of Segments Line Segment Intersection
15-451/651: Design & Anlysis of Algorithms Novemer 14, 2016 Lecture #21 Sweep-Line nd Segment Intersection lst chnged: Novemer 8, 2017 1 Preliminries The sweep-line prdigm is very powerful lgorithmic design
More informationMATHS LECTURE # 09. Plane Geometry. Angles
Mthemtics is not specttor sport! Strt prcticing. MTHS LTUR # 09 lne eometry oint, line nd plne There re three sic concepts in geometry. These concepts re the point, line nd plne. oint fine dot, mde y shrp
More informationYoplait with Areas and Volumes
Yoplit with Ares nd Volumes Yoplit yogurt comes in two differently shped continers. One is truncted cone nd the other is n ellipticl cylinder (see photos below). In this exercise, you will determine the
More informationMath 4 Review for Quarter 2 Cumulative Test
Mth 4 Review for Qurter 2 Cumultive Test Nme: I. Right Tringle Trigonometry (3.1-3.3) Key Fcts Pythgoren Theorem - In right tringle, 2 + b 2 = c 2 where c is the hypotenuse s shown below. c b Trigonometric
More informationMath 35 Review Sheet, Spring 2014
Mth 35 Review heet, pring 2014 For the finl exm, do ny 12 of the 15 questions in 3 hours. They re worth 8 points ech, mking 96, with 4 more points for netness! Put ll your work nd nswers in the provided
More informationMath Line Integrals I
Mth 213 - Line Integrls I Peter A. Perry University of Kentucky November 16, 2018 Homework Re-Red Section 16.2 for Mondy Work on Stewrt problems for 16.2: 1-21 (odd), 33-41 (odd), 49, 50 Begin Webwork
More informationGrade 7/8 Math Circles Geometric Arithmetic October 31, 2012
Fculty of Mthemtics Wterloo, Ontrio N2L 3G1 Grde 7/8 Mth Circles Geometric Arithmetic Octoer 31, 2012 Centre for Eduction in Mthemtics nd Computing Ancient Greece hs given irth to some of the most importnt
More informationTrigonometric Formulas, Identities and Equations
CHAPTER 0 Trigonometric Formulas, Identities and Equations 0. BASIC IDENTITIES. ; Dividing by roduces or cot csc. sec tan tan 5. tan cot sec 7. ð Þðtan Þ tan tan ð Þ. csc csc ð Þð Þ ð Þ ð Þ ð Þ ð Þ ð Þ
More informationRight Triangle Trigonometry
Rigt Tringle Trigonometry Trigonometry comes from te Greek trigon (tringle) nd metron (mesure) nd is te study of te reltion between side lengts nd ngles of tringles. Angles A ry is strigt lf line tt stretces
More informationSSC TIER II (MATHS) MOCK TEST - 21 (SOLUTION)
007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLIE STTION, DELHI-0009 SS TIER II (MTHS) MOK TEST - (SOLUTION). () Let, totl no. of students Totl present students 8 7 9 7 5 5 Required frction 5 5.
More informationTopics in Analytic Geometry
Nme Chpter 10 Topics in Anltic Geometr Section 10.1 Lines Objective: In this lesson ou lerned how to find the inclintion of line, the ngle between two lines, nd the distnce between point nd line. Importnt
More informationObjective: Students will understand what it means to describe, graph and write the equation of a parabola. Parabolas
Pge 1 of 8 Ojective: Students will understnd wht it mens to descrie, grph nd write the eqution of prol. Prols Prol: collection of ll points P in plne tht re the sme distnce from fixed point, the focus
More informationprisms Prisms Specifications Catalogue number BK7 Wedge, Beam Deviation, deg
Cotings Wedge Steer bems in opticl systems Cn be used in pirs for continuous ngulr djustment T Hving selected n pproprite wedge, it is esy to crete precise bem devition without ffecting other bem prmeters.
More informationTANGENCY AMONG THREE CYLINDERS A HYPERBOLOID AND A TORUS
TANGENCY AMONG TREE CYLINDERS A YPERBOLOID AND A TORUS Pul ZSOMBOR-MURRAY McGill University, Cnd A chllenging exercise in solid modeling is exmined nd developed s n opportunity to rise students consciousness
More informationGeometric Constitution of Space Structure Based on Regular-Polyhedron Combinations
Geometric Constitution of Spce Structure Bsed on Regulr-Polyhedron Combintions Zichen Wng School of Civil Engineering nd Trnsporttion South Chin University of Technology Gungzhou, Gungdong, Chin Abstrct
More information)
Chpter Five /SOLUTIONS Since the speed ws between nd mph during this five minute period, the fuel efficienc during this period is between 5 mpg nd 8 mpg. So the fuel used during this period is between
More informationOn the Detection of Step Edges in Algorithms Based on Gradient Vector Analysis
On the Detection of Step Edges in Algorithms Bsed on Grdient Vector Anlysis A. Lrr6, E. Montseny Computer Engineering Dept. Universitt Rovir i Virgili Crreter de Slou sin 43006 Trrgon, Spin Emil: lrre@etse.urv.es
More informationNOTE 12 USB OPENING 'U' & 'UB' SERIES ONLY USB CAP NOT SHOWN NOTE 12 USB OPENING U & UB SERIES ONLY THIRD ANGLE PROJECTION DO NOT SCALE DRAWING
P80804(x) CONFIGURTIONS -S -U -UB -UBC -UBB -B -C P80804 COVER P80804 COVER w/usb OPENING P80804 COVER w/usb & BUTTON HOLE P80804 BSE P80804 BSE w/usb P80804 BUTTON P20603 CP 'UB' SERIES ONLY R E V I S
More informationAML710 CAD LECTURE 16 SURFACES. 1. Analytical Surfaces 2. Synthetic Surfaces
AML7 CAD LECTURE 6 SURFACES. Anlticl Surfces. Snthetic Surfces Surfce Representtion From CAD/CAM point of view surfces re s importnt s curves nd solids. We need to hve n ide of curves for surfce cretion.
More informationIntroduction Transformation formulae Polar graphs Standard curves Polar equations Test GRAPHS INU0114/514 (MATHS 1)
POLAR EQUATIONS AND GRAPHS GEOMETRY INU4/54 (MATHS ) Dr Adrin Jnnett MIMA CMth FRAS Polr equtions nd grphs / 6 Adrin Jnnett Objectives The purpose of this presenttion is to cover the following topics:
More informationA TRIANGULAR FINITE ELEMENT FOR PLANE ELASTICITY WITH IN- PLANE ROTATION Dr. Attia Mousa 1 and Eng. Salah M. Tayeh 2
A TRIANGLAR FINITE ELEMENT FOR PLANE ELASTICITY WITH IN- PLANE ROTATION Dr. Atti Mous nd Eng. Slh M. Teh ABSTRACT In the present pper the strin-bsed pproch is pplied to develop new tringulr finite element
More informationEECS 281: Homework #4 Due: Thursday, October 7, 2004
EECS 28: Homework #4 Due: Thursdy, October 7, 24 Nme: Emil:. Convert the 24-bit number x44243 to mime bse64: QUJD First, set is to brek 8-bit blocks into 6-bit blocks, nd then convert: x44243 b b 6 2 9
More informationa c = A C AD DB = BD
1.) SIMILR TRINGLES.) Some possile proportions: Geometry Review- M.. Sntilli = = = = =.) For right tringle ut y its ltitude = = =.) Or for ll possiilities, split into 3 similr tringles: ll orresponding
More informationSTANDARD THIRD ANGLE PROJECTION DO NOT SCALE DRAWING
NOTES: UNLESS OTHERWISE SPECIFIED. CORNERS DRWN SHRP TO BE R.005 MXIMUM. 2. EXTERIOR SURFCE TEXTURE TO BE LIGHT EDM FINISH. EQUIVLENT TO MT-020. 3. INTERIOR SURFCE TEXTURE TO BE: NONE 4. LL INSIDE RDII.00R.
More information4452 Mathematical Modeling Lecture 4: Lagrange Multipliers
Mth Modeling Lecture 4: Lgrnge Multipliers Pge 4452 Mthemticl Modeling Lecture 4: Lgrnge Multipliers Lgrnge multipliers re high powered mthemticl technique to find the mximum nd minimum of multidimensionl
More information2. What are the types of diffraction and give the differences between them? (June 2005, June 2011)
UNIT-1 b DIFFRACTION Diffrction:A) Distinction between Fresnel nd Frunhofer diffrction, B) diffrction due to single slit, N-slits,C) Diffrction grting experiment. 1 A) Distinction between Fresnel nd Frunhofer
More informationOrder these angles from smallest to largest by wri ng 1 to 4 under each one. Put a check next to the right angle.
Lines nd ngles Connect ech set of lines to the correct nme: prllel perpendiculr Order these ngles from smllest to lrgest y wri ng to 4 under ech one. Put check next to the right ngle. Complete this tle
More information1. SEQUENCES INVOLVING EXPONENTIAL GROWTH (GEOMETRIC SEQUENCES)
Numbers nd Opertions, Algebr, nd Functions 45. SEQUENCES INVOLVING EXPONENTIAL GROWTH (GEOMETRIC SEQUENCES) In sequence of terms involving eponentil growth, which the testing service lso clls geometric
More informationAVolumePreservingMapfromCubetoOctahedron
Globl Journl of Science Frontier Reserch: F Mthemtics nd Decision Sciences Volume 18 Issue 1 Version 1.0 er 018 Type: Double Blind Peer Reviewed Interntionl Reserch Journl Publisher: Globl Journls Online
More informationOptics and Optical design Problems
Optics nd Opticl design 0 Problems Sven-Görn Pettersson / Cord Arnold 0-09-06 4:3 This mteril is tken from severl sources. Some problems re from the book Våglär och Optik by Görn Jönsson nd Elisbeth Nilsson.
More informationDate: 9.1. Conics: Parabolas
Dte: 9. Conics: Prols Preclculus H. Notes: Unit 9 Conics Conic Sections: curves tht re formed y the intersection of plne nd doulenpped cone Syllus Ojectives:. The student will grph reltions or functions,
More informationArea and Volume. Introduction
CHAPTER 3 Are nd Volume Introduction Mn needs mesurement for mny tsks. Erly records indicte tht mn used ody prts such s his hnd nd forerm nd his nturl surroundings s mesuring instruments. Lter, the imperil
More informationMath 464 Fall 2012 Notes on Marginal and Conditional Densities October 18, 2012
Mth 464 Fll 2012 Notes on Mrginl nd Conditionl Densities klin@mth.rizon.edu October 18, 2012 Mrginl densities. Suppose you hve 3 continuous rndom vribles X, Y, nd Z, with joint density f(x,y,z. The mrginl
More informationThe Fundamental Theorem of Calculus
MATH 6 The Fundmentl Theorem of Clculus The Fundmentl Theorem of Clculus (FTC) gives method of finding the signed re etween the grph of f nd the x-xis on the intervl [, ]. The theorem is: FTC: If f is
More informationThe Basic Properties of the Integral
The Bsic Properties of the Integrl When we compute the derivtive of complicted function, like + sin, we usull use differentition rules, like d [f()+g()] d f()+ d g(), to reduce the computtion d d d to
More information3 4. Answers may vary. Sample: Reteaching Vertical s are.
Chpter 7 Answers Alterntive Activities 7-2 1 2. Check students work. 3. The imge hs length tht is 2 3 tht of the originl segment nd is prllel to the originl segment. 4. The segments pss through the endpoints
More informationOptions Dedicated Bellows Dedicated Bellows For the supported models, see the table of options by model number on
Dedicted Bellows Dedicted Bellows For the supported s, see the tle of options y numer on. For the dedicted ellows dimensions, see to. Item nme chemtic digrm / mounting loction urpose/loction of use Dedicted
More information2 b. 3 Use the chain rule to find the gradient:
Conic sections D x cos θ, y sinθ d y sinθ So tngent is y sin θ ( x cos θ) sinθ Eqution of tngent is x + y sinθ sinθ Norml grdient is sinθ So norml is y sin θ ( x cos θ) xsinθ ycos θ ( )sinθ, So eqution
More informationSIMPLIFYING ALGEBRA PASSPORT.
SIMPLIFYING ALGEBRA PASSPORT www.mthletics.com.u This booklet is ll bout turning complex problems into something simple. You will be ble to do something like this! ( 9- # + 4 ' ) ' ( 9- + 7-) ' ' Give
More informationseven rigid frames: analysis & design Rigid Frames Rigid Frames Rigid Frames composed of linear elements member geometry fixed at joints
APPLIED ARCHITECTURAL STRUCTURES: STRUCTURAL ANALYSIS AND SYSTEMS DR. ANNE NICHOLS ALL 2018 lecture seven rigid rmes: nlysis & design http:// nisee.erkeley.edu/godden Rigid rmes composed o liner elements
More informationCONSTRUCTING CONGRUENT LINE SEGMENTS
NME: 1. Given: Task: Construct a segment congruent to. CONSTRUCTING CONGRUENT LINE SEGMENTS B a) Draw a new, longer segment with your straightedge. b) Place an endpoint on the left side of the new segment
More informationHonors Geometry Chapter 5 Tentative Syllabus (Updated 11/4/2015)
Honors Geometry Chapter 5 Tentative Syllabus (Updated 11/4/2015) ll text book answers are posted on Mrs. Moreman s website YOU RE EXPECTED TO CHECK YOUR NSWERS BEFORE COMING TO CLSS. Red Day Red Date Blue
More informationBennett s linkage and the cylindroid
Mechanism and Machine Theory 37 () 45 6 www.elsevier.com/locate/mechmt Bennett s linkage and the cylindroid Alba Perez *, J.M. McCarthy * Robotics and Automation Laboratory, Department of Mechanical and
More informationInstallation manual. Daikin Altherma low temperature monobloc option box EK2CB07CAV3. Installation manual. English
Instlltion mnul Dikin Altherm low temperture monobloc option box EKCB07CAV Instlltion mnul Dikin Altherm low temperture monobloc option box English Tble of Contents Tble of Contents About the documenttion.
More informationMath 17 - Review. Review for Chapter 12
Mth 17 - eview Ying Wu eview for hpter 12 1. Given prmetric plnr curve x = f(t), y = g(t), where t b, how to eliminte the prmeter? (Use substitutions, or use trigonometry identities, etc). How to prmeterize
More informationLink 3 (A to B) b := in Offset c := 1.00 in. m 4 := 0.20 blob. a G4 := in sec 2 θ AG4 := deg
DESIGN O MACHINERY SOLUTION MANUAL -b- PROBLEM -b Stteent: Tble P- shows ketic nd geoetric dt for severl slider-crnk lkges of the type nd orienttion shown igure P-. The pot loctions re defed s described
More informationAbout the Finite Element Analysis for Beam-Hinged Frame. Duan Jin1,a, Li Yun-gui1
Advnces in Engineering Reserch (AER), volume 143 6th Interntionl Conference on Energy nd Environmentl Protection (ICEEP 2017) About the Finite Element Anlysis for Bem-Hinged Frme Dun Jin1,, Li Yun-gui1
More informationModeling and Simulation of Short Range 3D Triangulation-Based Laser Scanning System
Modeling nd Simultion of Short Rnge 3D Tringultion-Bsed Lser Scnning System Theodor Borngiu Anmri Dogr Alexndru Dumitrche April 14, 2008 Abstrct In this pper, simultion environment for short rnge 3D lser
More informationThe notation y = f(x) gives a way to denote specific values of a function. The value of f at a can be written as f( a ), read f of a.
Chpter Prerequisites for Clculus. Functions nd Grphs Wht ou will lern out... Functions Domins nd Rnges Viewing nd Interpreting Grphs Even Functions nd Odd Functions Smmetr Functions Defined in Pieces Asolute
More informationLesson 6.5A Working with Radicals
Lesson 6.5A Working with Radicals Activity 1 Equivalent Radicals We use the product and quotient rules for radicals to simplify radicals. To "simplify" a radical does not mean to find a decimal approximation
More informationLecture 5: Spatial Analysis Algorithms
Lecture 5: Sptil Algorithms GEOG 49: Advnced GIS Sptil Anlsis Algorithms Bsis of much of GIS nlsis tod Mnipultion of mp coordintes Bsed on Eucliden coordinte geometr http://stronom.swin.edu.u/~pbourke/geometr/
More informationAim: How do we find the volume of a figure with a given base? Get Ready: The region R is bounded by the curves. y = x 2 + 1
Get Ready: The region R is bounded by the curves y = x 2 + 1 y = x + 3. a. Find the area of region R. b. The region R is revolved around the horizontal line y = 1. Find the volume of the solid formed.
More information1.1 Lines AP Calculus
. Lines AP Clculus. LINES Notecrds from Section.: Rules for Rounding Round or Truncte ll finl nswers to 3 deciml plces. Do NOT round before ou rech our finl nswer. Much of Clculus focuses on the concept
More information