Solids. Solids. Curriculum Ready.

Size: px
Start display at page:

Download "Solids. Solids. Curriculum Ready."

Transcription

1 Curriulum Rey

2

3 This ooklet is ll out ientifying, rwing n mesuring solis n prisms. SOM CUES The Som Cue ws invente y Dnish sientist who went y the nme of Piet Hein. It is simple 3 # 3 # 3 ue tht is split up into seven unique piees. These n e put together in mny ifferent wys to form ue n other soli shpes. The seven piees re speil euse no other omintions of 3 or 4 ues joine y their sies re possile. Even relly ool furniture hs een me using these soli omintions. Look them up to fin out more out them. lso serh out Polyominoes for the flt shpe equivlent. Q Use ruler n penil to hnge the plne shpe elow into soli, 3-imensionl rwing. Work through the ook for gret wy to o this H 14 1 SERIES TOPIC

4 How oes it work? Polyherons Polyherons re lose 3-imensionl solis forme with flt polygon fes n stright eges. Prts of polyheron: Corner/Vertex (verties plurl) Sie/Fe Ege Visile Ege (soli line) Ege not visile from this view (otte line) Polyheron? Polyheron? Polyheron? - ll fes re flt polygons - Soli is lose - Not ll fes re flt polygons - Soli is lose - ll fes re flt polygons - Not lose soli Here re just few of the mny si types of polyherons tht exist. Prisms These solis hve the sme shpe (ross-setion) ll long their length. Nme y the ross-setion shpe. Pltoni polyherons ll fes re the sme regulr polygon. n equl numer of eges meet t eh vertex. Right-Prisms The en ross-setionl shpe is perpeniulr (90⁰) to the length of the soli. Pyrmis ll eges from the verties of the se meet t point. Nme y the se polygon. Convex polyherons stright line rwn through these will only pss through two fes. Conve polyherons stright line rwn through these n pss through more thn two fes. The ifferent views elow show how stright lines n pss through Convex or Conve polyherons. Convex Conve 1 2 View from the top stright line n only pss through two fes View from the top stright line rwn through the soli n pss through more thn two fes. 2 H 14 SERIES TOPIC

5 How oes it work? Polyherons s with polygons, polyheron n e nme using Greek prefixes mthing the numer of fes it hs. Polyheron nming n lssifition hrt Fes Nme Soli Pltoni (ll eges equl length) 4 Tetrheron Forme using 4 equilterl tringles 5 Pentheron N/ 6 Hexheron Cue: forme using 6 equl squres 7 Heptheron N/ 8 Otheron Forme using 8 equilterl tringles Some solis o not hve pltoni form in the tle. In ft, there re only 5 pltoni solis in totl! The other two re: Doeherons (forme using 12 regulr pentgons) Iosherons (forme using 20 equilterl tringles) There re only 5 euse the totl internl sum of the polygon ngles whih meet t eh vertex must e no more thn 360⁰. Tetrheron Hexheron Otheron Doeheron Iosheron 60 ⁰ 60⁰ 60 ⁰ 108 ⁰ 3 # 60⁰ < 360⁰ Euler s rule for onvex polyherons Euler isovere tht for ll onvex polyherons, the sum of the ll the fes n verties, minus the numer of eges will lwys equl 2. For this ox, the totl numer of: fes (F) = 6 F + V - E = 2 verties (V) = 8 eges (E ) = 12. Fes Verties 3 # 90⁰ < 360⁰ Eges 4 # 60⁰ < 360⁰ 3 # 108⁰ < 360⁰ ` F + V - E = = 2 5 # 60⁰ < 360⁰ H SERIES 14 TOPIC 3

6 POLYHEDRONS *POLYHEDRONS *POLYHEDRONS * How oes it work? Polyherons 1 Ientify whih of these solis in rel life woul e lssifie s polyherons or not. n of rink soli house rik 12-sie ie Polyheron Polyheron Polyheron Not polyheron Not polyheron Not polyheron n Ornge tresure hest n open ox Polyheron Polyheron Polyheron Not polyheron Not polyheron Not polyheron 2 Tik ll the est-mthing properties tht eh of these polyherons hve. Convex Conve Pltoni Prism Right-Prism Pyrmi Convex Conve Pltoni Prism Right-Prism Pyrmi Convex Conve Pltoni Prism Right-Prism Pyrmi Convex Conve Pltoni Prism Right-Prism Pyrmi e Convex Conve Pltoni Prism Right-Prism Pyrmi f Convex Conve Pltoni Prism Right-Prism Pyrmi 3 Show tht Euler s rule works for eh of the polyherons elow. Tetrheron Fes = Pentgonl pyrmi Fes = Verties = Verties = Eges = Eges = + - = + - = Pentgonl Prism Otheron Doeheron e.../.../ = + - = + - = 4 H 14 SERIES TOPIC

7 How oes it work? Volume of prisms using unit ues Polyherons ll tke up spe in the rel 3-imensionl worl. The mesurement of the spe they oupy is lle the Volume (or pity for liquis). unit ue is polyheron where every fe is squre with sies one unit of mesurement long. 1 unit Little shes on eh sie men they re ll the sme length. Volume (V) = 1 ui unit = 1 unit 3 (in shorter, units form) The volume of the prism elow is foun y ounting the numer of whole unit ues use to uil it. 1 unit Volume () = 4 ui units = 4 unit 3 Here re some prisms inluing hlves n qurters of unit ue: Clulte the volume (V) of these solis (i) Volume (V) = 4 whole ues + 3 hlves of ue = 4 ui units + 3 # 2 1 ui units = ( ) ui units 1 unit = 5.5 units 3 When units of mesurement re given, they re use inste of the wor units (ii) V = 6 whole ues + 4 hlves of ue + 6 qurters of ue = 6 ui mm + 4 # 2 1 ui mm + 6 # 1 4 ui mm = ( ) ui mm 1 mm = 9.5 mm 3 H 14 5 SERIES TOPIC

8 How oes it work? Volume of prisms using unit ues.../.../ VOLUMEOFPRISMSUSINGUNITCUES * 1 Clulte the volume of these prisms forme y omining 1 unit ues: V = whole ues V = whole ues 1 unit = units 3 1 m = m 3 V = mm 3 V = m 3 1 mm 1 m e f V = units 3 V = m unit Clulte the volume of these prisms forme y omining whole n hlf unit ues: 1 m 1 mm V = whole + hlves of ue = mm # 2 mm 3 = mm 3 1 m V = whole + hlves of ue = m # 2 m 3 = m 3 1 m V = m 3 V = m 3 1 m e f V = units 3 V = mm 3 1 unit 1 mm 6 H 14 SERIES TOPIC

9 How oes it work? Volume of prisms using unit ues 3 Fin the volume of these prisms forme y omining whole, hlf n qurter unit ues: 1 unit 1 m V = whole + qurters of ue V = whole + qurters of ue = m 3 + # 1 4 m3 = units 3 + # 1 4 units3 = m 3 = units 3 V = whole + hlves of ue + qurters of ue = m 3 + # 1 2 m3 + # 1 4 m3 1 m = m 3 V = whole + hlves of ue + qurters of ue = mm 3 + # 1 2 mm3 + # 1 4 mm3 1 mm = mm 3 4 Clulte the volume of these prisms: 1 unit 1 m 1 m 1 mm V = V = V = V = 5 Clulte the volume of this prism n ern yourself n wesome pssport stmp! 1 m H 14 7 SERIES TOPIC

10 Where oes it work? Volume of right-prisms Prisms hve the sme polygon ross-setionl shpe throughout their height/length. Eh of these slies re the ext sme shpe. height In right-prisms, the ross-setion polygon is perpeniulr to the height of the soli. Volume (units 3 ) = re of the ross-setion shpe (units 2 ) # height of the soli (units) V = # h The lultion for the volume is me esier euse the ross-setionl re is given For this right-prism, the ross-setionl re is 25 m 2 n the height of the soli is 4 m. (i) Volume (V) = re of the ross-setionl polygon # height of the soli = 25 m = 25 m 2 # 4 m 2 = 100 m 3 4 m This next one is not tully prism s it hs urve sies, ut we lulte its volume the sme wy. (ii) = 12 m 2 Volume (V) = re of the en shpe # height 5 m = 12 m 2 # 5 m = 60 m 3 ll mesurements must e in the sme units efore lulting the volume. (iii) Volume (V) = re of the ross-setionl polygon # height of the soli = 36 m 2 # 50 mm 36 m 2 = 36 m 2 # 5 m 50 mm = 180 m 3 8 H 14 SERIES TOPIC

11 Where oes it work? Volume of right-prisms 1 Complete the volume lultions for these right-prisms: = 12 m 2 2 m 8 m m 4.5 mm 2 14 mm V = m 2 # m Cross-setion Height = m 3 V = m 2 # m Cross-setion Height = m 3 V = mm 2 # mm Cross-setion Height = mm 3 2 Complete the volume lultions for these right-solis: 10 m 2 50 m 8.25 m 2 1 m 12.5 mm 2 40 m V = m 2 # m Cross-setion Height = m 3 V = m 2 # m Cross-setion Height = m 3 V = mm 2 # mm Cross-setion Height = mm 3 3 Use the re onversion tle to help omplete the volume lultions for these right-prisms: ' 100 ' squre millimetres mm 2 squre entimetres m 2 squre metres m 2 25 m m 2 5 mm 12 m V = mm 2 # mm V = m 2 # m # 100 # 1000 Cross-setion Height = mm 3 Cross-setion Height = m 3 4 Clulte the missing mesurements of these solis: = m 3 ' m h = m 3 ' m 2 12 m Volume Height 12.6 m 2 Volume re h Volume = 84 m = m 2 3 Volume = 14 m 3 = m = m 3 ' m h = mm 3 ' mm m 2 80 m = m 2 h = mm Volume = 14.8 m 3 Volume = 31 mm 3 H SERIES 14 TOPIC 9

12 *VOLUME OF RIGHT PRISMS*VOLUME OF RIGHT PRISMS Where oes it work? Volume of right-prisms 5 Clulte the volume for these right-prisms showing ll working. 16 m 2 28 mm 2 4 m 5 mm ` V = m 3 ` V = mm m m 2 7 m 8 m ` V = m 3 ` V = m 3 e f 15 m 2 80 mm ` V = m 3 4 m m ` V = m 3 g h m 2 2 m 2 20 m 10 mm ` V = mm 3 ` V = m 3 6 This pttern ws me using pver riks. Eh rik hs height of 105 mm n ross-setionl re of 288 m 2. Wht is the totl volume of riks in m 3 use to mke this 28-rik pttern (to 2 eiml ples)? psst: 1 m 3 = m 3.../.../ H 14 SERIES TOPIC

13 Where oes it work? Volume of right-prisms Volume lultions involving fluis nee nswers using units of pity Cpity onversion hrt ' 1000 ' 1000 ' 1000 ' 1 m 3 = 1 kilolitre (kl) 1000 m 3 = 1 Litre (L) 1 m 3 = 1 millilitre (ml) mirolitre μl millilitres ml litres L kilolitres kl meglitres ML # # 1000 # 1000 # 1000 (i) How mny litres (L) woul ontiner of this shpe hol? Volume (V) = 15 m 2 # 0.85 m = 15 m 2 85 m = m 3 `Cpity = kl = L 1 m 3 = 1 kilolitre (kl) 1 kl = 1000 L (ii) Clulte the ross-setionl re of this right-prism ontiner if it n hol 210 ml. Cpity = 210 ml = 210 m 3 1 m 3 = 1 millilitre (ml) m 2 re = Volume ' height of the soli 30 m = 210 m 3 ' 30 m = 7 m 2 7 Clulte the pity of these ontiners when full. 24 m 2 3 m Volume = m 3 25 m 30 m 2 Volume = m 3 ` Cpity = kl ` Cpity = ml 45 mm 884 mm 2 Volume = mm 3 ` Cpity = L Volume = m mm m ` Cpity = L 8 Clulte the ross-setionl re () of these right-prism ontiners if they oth hol 42.5 litres mm 85 m = m 2 = m 2 H SERIES 14 TOPIC 11

14 Where oes it work? Volume of Retngulr prisms For retngulr or squre right-prisms: Volume = Length # reth # Height V = l # # h units units units units 3 = 12 units 3 Joine together the shpe forme looks like this: height length reth Volume = Length # reth # Height 3 # 2 # 2 units 3 = 12 units 3 So you simply multiply ll the imensions of retngulr prism to lulte the volume. Clulte the volume of these retngulr prisms (i) (ii) 4 m 3 m Volume (V) = length # reth # height = 1.5 m # 3 m # 4 m = 18 m 3 efore you n use the volume formul, ll mesurements must e in the sme units. 50 mm 1.5 m 1.5 m V = length # reth # height = 50 mm # 1.5 m # 1.5 m = 5 m # 1.5 m # 1.5 m = m 3 Rememer: the orer you multiply the numers y oes not mtter. hnge to e ll sme units You oul hve lso hnge 1.5 m to 15 mm inste, then the volume woul look like mm 3 12 H 14 SERIES TOPIC

15 Where oes it work? Volume of Retngulr prisms 1 Clulte the volume of these right-prisms using the formul V = l # # h 3 m 3 m 4 m 6 mm 2.5 mm 5 mm V = m # m # m = m 3 V = mm # mm # mm = mm 3 5 m 7 m 220 mm 2 m 0.06 m 6 m V = m # m # m = m 3 V = m # m # m = m 3 e f 0.5 m 0.05 m V = mm # mm # mm = mm mm 150 mm V = m # m # m = m 3 2 Clulte the volume of these right-prisms showing ll your working. 3.5 m 6 mm 5 m 6 m 4.75 mm ` V = m 3 ` V = mm mm 40 mm 140 mm 0.18 m 2 m 8.5 m ` V = m 3 ` V = m 3 H SERIES TOPIC

16 Where oes it work? Volume of Retngulr prisms 3 Hollow retngulr onrete riks hve een use to uil the tringulr wll shown here. 25 m Empty Spe 32 m 22 m rik wll 24 m Eh rik Do you think there is more onrete or hollow spe in this wll? Mrk on the numer line where you think the lne of onrete to ir is in this wll. ll ir m equl ll onrete How mny onrete riks were use to uil this wll? Wht is the totl volume of this wll if eh rik ws not hollow? Clulte the volume of the spe tken up y the hole in eh rik? e Clulte the totl volume of hollow spe in this wll. f The totl volume of onrete = the volume of the wll - the volume of hollow spe. Clulte the volume of onrete in the wll. g How mny litres of onrete re require to mke ll the riks neee for this wll? h Using the informtion you now hve from your lultions, mrk new point on the numer line where the tul nswer for question is. H 14 SERIES TOPIC

17 Where oes it work? Volume of Retngulr prisms 4 The glss sreen on the front n k of one rn of smrt phone hs these imensions: 11.5 m 0.08 m 5.7 m Over five yer perio, this rn sol pproximtely 240 million ( ) phones. Mrk elow wht you preit the height of squre prism ontiner with with n length of 10 m woul nee to e to hol ll this glss. < 2.5 m 2.5 m or more ut 5 m or more ut 7.5 m or more ut > 10 m less thn 5 m less thn 7.5 m less thn 10 m Clulte the volume of glss in eh phone sreen in m 3. How mny ml of glss re there in eh phone sreen? How mny ml of glss re there in 240 million ( ) phones? e If ll this glss ws poure into prism ontiner with squre se of sie length 1 m (100 m), how high woul the ontiner nee to e to hol it ll?.../.../ VOLUMEOFRECTNGULRPRISMS*VOLUMEOFRECTNGULRPRISMS* H SERIES 14 TOPIC 15

18 Wht else n you o? Different views of solis It n e iffiult to show ll the fetures of soli shpe in single igrm. For exmple is the soli rwn here me using 5 or 6 ues? Viewe from the opposite iretion we see tht this oul represent ny one of these solis elow: 6 ues 6 ues 5 ues So to ommunite whih one it is extly n esily, we rw ifferent flt views to mke it ler. The three si views re, Sie n views. Sie With these views of the soli given, we n see lerly tht it is tully the first one me with 6 ues. Sie Opposite view nother wy to help imgine the pln views is y pretening there is glss ox roun the soli refleting the view of eh sie. 16 H 14 SERIES TOPIC

19 FDIFFERENT VIEWS OF SOLIDS*DIF Wht else n you o? Different views of solis 1 Mth the pln views elow with the orret soli to fin the nswer to this question:.../.../ ERENT VIEWS OF SOLIDS* Wht is the nme given to rwings tht show the front or sies of n ojet? Sie (v) C F M U (x) (ii) G T (vi) L O S (i) H W T (vii) E (viii) (iii) V Y P E (iv) (ix) N N K (i) (ii) (iii) (iv) (v) (vi) (vii) (viii) (ix) (x) H SERIES TOPIC

20 Wht else n you o? Different views of solis 2 Eh of these solis were forme using six ues only. Drw the front, top n sie views for eh one. Sie Sie Sie Sie Sie e Sie f Sie 18 H 14 SERIES TOPIC

21 Wht else n you o? Different views of solis 3 Drw the front, top n sie views for eh of 3-D imges me using smll prisms. Sie Sie Sie Sie Sie e Sie H SERIES TOPIC

22 Wht else n you o? Different views of solis The soli view n e rwn esily from the ifferent pln views using isometri gri pper The leing ege n e inite with letters to show the ege to e use t the front. Sie Sie 4 Use the isometri gris to rw the solis represente y the front, top n sie views given. Sie Sie Sie Sie 20 H 14 SERIES TOPIC

23 Wht else n you o? Different views of solis 5 Use the isometri gris to rw the letters represente y the front, top n sie views given. Sie Sie Sie Sie e Sie H SERIES 14 TOPIC 21

24 Wht else n you o? 3D rwings using vnishing points When ojets re fr wy they pper smller thn they tully re. We n use this ft to help trnsform flt 2-imensionl polygons into prisms. For exmple, let s trnsform this squre into prism. 1. Put ot some ple to the left/right n just ove the squre. This ot is lle the Vnishing Point (VP). VP 2. Rule some stright lines in penil from eh vertex on the sme sie s the VP, pssing through it. VP 3. Drw vertil n horizontl lines s shown elow to rete the fr sie of the soli. VP 4. Complete y rwing in the other eges long the vnishing point lines. VP 22 H 14 SERIES TOPIC

25 Wht else n you o? 3D rwings using vnishing points Use the given vnishing point for eh of these polygons to mke them prisms..../.../ VP *TRNSFORMINGFLTSHPESINTO3DUSINGVNISHINGPOINTS 2 VP 3 This one will nee two horizontl n two vertil lines in step 3. VP 4 This is triky one to finish off with. e reful with the horizontl n vertil lines step. VP H SERIES TOPIC

26 Chet Sheet Here is wht you nee to rememer from this topi on solis Polyherons Close 3-imensionl solis forme with flt polygon fes n stright eges. Corner/Vertex (verties plurl) Sie/Fe Ege Visile Ege (soli line) Ege not visile from this view (otte line) Prisms These solis hve the sme shpe (ross-setion) ll long their length. Nme y the ross-setion shpe. Pltoni polyherons ll fes re the sme regulr polygon. n equl numer of eges meet t eh vertex. Right-Prisms The en ross-setionl shpe is perpeniulr (90⁰) to the length of the soli. Pyrmis ll eges from the verties of the se meet point. Nme y the se polygon. Convex polyherons stright line rwn through these will only pss through two fes. Conve polyherons stright line rwn through these n pss through more thn two fes. Euler s rule for onvex polyherons F + V - E = 2 Fes Verties Eges Volume of right-prisms Volume of retngulr right- prisms V = # h height reth height length Volume = Length # reth # Height Different Views of Pln Views (or Elevtions) Sie 24 H 14 SERIES TOPIC

27

28

5 ANGLES AND POLYGONS

5 ANGLES AND POLYGONS 5 GLES POLYGOS urling rige looks like onventionl rige when it is extene. However, it urls up to form n otgon to llow ots through. This Rolling rige is in Pington sin in Lonon, n urls up every Friy t miy.

More information

10.2 Graph Terminology and Special Types of Graphs

10.2 Graph Terminology and Special Types of Graphs 10.2 Grph Terminology n Speil Types of Grphs Definition 1. Two verties u n v in n unirete grph G re lle jent (or neighors) in G iff u n v re enpoints of n ege e of G. Suh n ege e is lle inient with the

More information

Final Exam Review F 06 M 236 Be sure to look over all of your tests, as well as over the activities you did in the activity book

Final Exam Review F 06 M 236 Be sure to look over all of your tests, as well as over the activities you did in the activity book inl xm Review 06 M 236 e sure to loo over ll of your tests, s well s over the tivities you did in the tivity oo 1 1. ind the mesures of the numered ngles nd justify your wor. Line j is prllel to line.

More information

Chapter44. Polygons and solids. Contents: A Polygons B Triangles C Quadrilaterals D Solids E Constructing solids

Chapter44. Polygons and solids. Contents: A Polygons B Triangles C Quadrilaterals D Solids E Constructing solids Chpter44 Polygons nd solids Contents: A Polygons B Tringles C Qudrilterls D Solids E Constructing solids 74 POLYGONS AND SOLIDS (Chpter 4) Opening prolem Things to think out: c Wht different shpes cn you

More information

Can Pythagoras Swim?

Can Pythagoras Swim? Overview Ativity ID: 8939 Mth Conepts Mterils Students will investigte reltionships etween sides of right tringles to understnd the Pythgoren theorem nd then use it to solve prolems. Students will simplify

More information

UNCORRECTED SAMPLE PAGES. Angle relationships and properties of 6geometrical figures 1. Online resources. What you will learn

UNCORRECTED SAMPLE PAGES. Angle relationships and properties of 6geometrical figures 1. Online resources. What you will learn Online resoures uto-mrked hpter pre-test Video demonstrtions of ll worked exmples Intertive widgets Intertive wlkthroughs Downlodle HOTsheets ess to ll HOTmths ustrlin urriulum ourses ess to the HOTmths

More information

Answer Key Lesson 6: Workshop: Angles and Lines

Answer Key Lesson 6: Workshop: Angles and Lines nswer Key esson 6: tudent Guide ngles nd ines Questions 1 3 (G p. 406) 1. 120 ; 360 2. hey re the sme. 3. 360 Here re four different ptterns tht re used to mke quilts. Work with your group. se your Power

More information

Measurement and geometry

Measurement and geometry Mesurement nd geometry 4 Geometry Geometry is everywhere. Angles, prllel lines, tringles nd qudrilterls n e found ll round us, in our homes, on trnsport, in onstrution, rt nd nture. This sene from Munih

More information

Chapter 2. Chapter 2 5. Section segments: AB, BC, BD, BE. 32. N 53 E GEOMETRY INVESTIGATION Answers will vary. 34. (a) N. sunset.

Chapter 2. Chapter 2 5. Section segments: AB, BC, BD, BE. 32. N 53 E GEOMETRY INVESTIGATION Answers will vary. 34. (a) N. sunset. Chpter 2 5 Chpter 2 32. N 53 E GEOMETRY INVESTIGATION Answers will vry. 34. () N Setion 2.1 2. 4 segments: AB, BC, BD, BE sunset sunrise 4. 2 rys: CD (or CE ), CB (or CA ) 6. ED, EC, EB W Oslo, Norwy E

More information

Order these angles from smallest to largest by wri ng 1 to 4 under each one. Put a check next to the right angle.

Order these angles from smallest to largest by wri ng 1 to 4 under each one. Put a check next to the right angle. Lines nd ngles Connect ech set of lines to the correct nme: prllel perpendiculr Order these ngles from smllest to lrgest y wri ng to 4 under ech one. Put check next to the right ngle. Complete this tle

More information

3D convex hulls. Convex Hull in 3D. convex polyhedron. convex polyhedron. The problem: Given a set P of points in 3D, compute their convex hull

3D convex hulls. Convex Hull in 3D. convex polyhedron. convex polyhedron. The problem: Given a set P of points in 3D, compute their convex hull Convex Hull in The rolem: Given set P of oints in, omute their onvex hull onvex hulls Comuttionl Geometry [si 3250] Lur Tom Bowoin College onvex olyheron 1 2 3 olygon olyheron onvex olyheron 4 5 6 Polyheron

More information

6.3 Volumes. Just as area is always positive, so is volume and our attitudes towards finding it.

6.3 Volumes. Just as area is always positive, so is volume and our attitudes towards finding it. 6.3 Volumes Just s re is lwys positive, so is volume nd our ttitudes towrds finding it. Let s review how to find the volume of regulr geometric prism, tht is, 3-dimensionl oject with two regulr fces seprted

More information

Simplifying Algebra. Simplifying Algebra. Curriculum Ready.

Simplifying Algebra. Simplifying Algebra. Curriculum Ready. Simplifying Alger Curriculum Redy www.mthletics.com This ooklet is ll out turning complex prolems into something simple. You will e le to do something like this! ( 9- # + 4 ' ) ' ( 9- + 7-) ' ' Give this

More information

V = set of vertices (vertex / node) E = set of edges (v, w) (v, w in V)

V = set of vertices (vertex / node) E = set of edges (v, w) (v, w in V) Definitions G = (V, E) V = set of verties (vertex / noe) E = set of eges (v, w) (v, w in V) (v, w) orere => irete grph (igrph) (v, w) non-orere => unirete grph igrph: w is jent to v if there is n ege from

More information

Right Angled Trigonometry. Objective: To know and be able to use trigonometric ratios in rightangled

Right Angled Trigonometry. Objective: To know and be able to use trigonometric ratios in rightangled C2 Right Angled Trigonometry Ojetive: To know nd e le to use trigonometri rtios in rightngled tringles opposite C Definition Trigonometry ws developed s method of mesuring ngles without ngulr units suh

More information

Here is an example where angles with a common arm and vertex overlap. Name all the obtuse angles adjacent to

Here is an example where angles with a common arm and vertex overlap. Name all the obtuse angles adjacent to djcent tht do not overlp shre n rm from the sme vertex point re clled djcent ngles. me the djcent cute ngles in this digrm rm is shred y + + me vertex point for + + + is djcent to + djcent simply mens

More information

Naming 3D objects. 1 Name the 3D objects labelled in these models. Use the word bank to help you.

Naming 3D objects. 1 Name the 3D objects labelled in these models. Use the word bank to help you. Nming 3D ojects 1 Nme the 3D ojects lelled in these models. Use the word nk to help you. Word nk cue prism sphere cone cylinder pyrmid D A C F A B C D cone cylinder cue cylinder E B E prism F cue G G pyrmid

More information

Grade 7/8 Math Circles Geometric Arithmetic October 31, 2012

Grade 7/8 Math Circles Geometric Arithmetic October 31, 2012 Fculty of Mthemtics Wterloo, Ontrio N2L 3G1 Grde 7/8 Mth Circles Geometric Arithmetic Octoer 31, 2012 Centre for Eduction in Mthemtics nd Computing Ancient Greece hs given irth to some of the most importnt

More information

COMMON FRACTIONS. or a / b = a b. , a is called the numerator, and b is called the denominator.

COMMON FRACTIONS. or a / b = a b. , a is called the numerator, and b is called the denominator. COMMON FRACTIONS BASIC DEFINITIONS * A frtion is n inite ivision. or / * In the frtion is lle the numertor n is lle the enomintor. * The whole is seprte into "" equl prts n we re onsiering "" of those

More information

Chapter 9. Greedy Technique. Copyright 2007 Pearson Addison-Wesley. All rights reserved.

Chapter 9. Greedy Technique. Copyright 2007 Pearson Addison-Wesley. All rights reserved. Chpter 9 Greey Tehnique Copyright 2007 Person Aison-Wesley. All rights reserve. Greey Tehnique Construts solution to n optimiztion prolem piee y piee through sequene of hoies tht re: fesile lolly optiml

More information

Area and Volume. Introduction

Area and Volume. Introduction CHAPTER 3 Are nd Volume Introduction Mn needs mesurement for mny tsks. Erly records indicte tht mn used ody prts such s his hnd nd forerm nd his nturl surroundings s mesuring instruments. Lter, the imperil

More information

PROBLEM OF APOLLONIUS

PROBLEM OF APOLLONIUS PROBLEM OF APOLLONIUS In the Jnury 010 issue of Amerin Sientist D. Mkenzie isusses the Apollonin Gsket whih involves fining the rius of the lrgest irle whih just fits into the spe etween three tngent irles

More information

Line The set of points extending in two directions without end uniquely determined by two points. The set of points on a line between two points

Line The set of points extending in two directions without end uniquely determined by two points. The set of points on a line between two points Lines Line Line segment Perpendiulr Lines Prllel Lines Opposite Angles The set of points extending in two diretions without end uniquely determined by two points. The set of points on line between two

More information

CS 241 Week 4 Tutorial Solutions

CS 241 Week 4 Tutorial Solutions CS 4 Week 4 Tutoril Solutions Writing n Assemler, Prt & Regulr Lnguges Prt Winter 8 Assemling instrutions utomtilly. slt $d, $s, $t. Solution: $d, $s, nd $t ll fit in -it signed integers sine they re 5-it

More information

Section 10.4 Hyperbolas

Section 10.4 Hyperbolas 66 Section 10.4 Hyperbols Objective : Definition of hyperbol & hyperbols centered t (0, 0). The third type of conic we will study is the hyperbol. It is defined in the sme mnner tht we defined the prbol

More information

Greedy Algorithm. Algorithm Fall Semester

Greedy Algorithm. Algorithm Fall Semester Greey Algorithm Algorithm 0 Fll Semester Optimiztion prolems An optimiztion prolem is one in whih you wnt to fin, not just solution, ut the est solution A greey lgorithm sometimes works well for optimiztion

More information

10.5 Graphing Quadratic Functions

10.5 Graphing Quadratic Functions 0.5 Grphing Qudrtic Functions Now tht we cn solve qudrtic equtions, we wnt to lern how to grph the function ssocited with the qudrtic eqution. We cll this the qudrtic function. Grphs of Qudrtic Functions

More information

Calculus Differentiation

Calculus Differentiation //007 Clulus Differentition Jeffrey Seguritn person in rowot miles from the nerest point on strit shoreline wishes to reh house 6 miles frther down the shore. The person n row t rte of mi/hr nd wlk t rte

More information

Angle Properties in Polygons. Part 1 Interior Angles

Angle Properties in Polygons. Part 1 Interior Angles 2.4 Angle Properties in Polygons YOU WILL NEED dynmic geometry softwre OR protrctor nd ruler EXPLORE A pentgon hs three right ngles nd four sides of equl length, s shown. Wht is the sum of the mesures

More information

WORKSHOP 9 HEX MESH USING SWEEP VECTOR

WORKSHOP 9 HEX MESH USING SWEEP VECTOR WORKSHOP 9 HEX MESH USING SWEEP VECTOR WS9-1 WS9-2 Prolem Desription This exerise involves importing urve geometry from n IGES file. The urves re use to rete other urves. From the urves trimme surfes re

More information

EXPONENTIAL & POWER GRAPHS

EXPONENTIAL & POWER GRAPHS Eponentil & Power Grphs EXPONENTIAL & POWER GRAPHS www.mthletics.com.u Eponentil EXPONENTIAL & Power & Grphs POWER GRAPHS These re grphs which result from equtions tht re not liner or qudrtic. The eponentil

More information

A23 ECR SEP2017 WW RR A24 ECR MAY2018 KD FL N#0.30

A23 ECR SEP2017 WW RR A24 ECR MAY2018 KD FL N#0.30 THIS RWING IS UNPULISHE. OPYRIGHT 0 Y RELESE FOR PULITION LL RIGHTS RESERVE. 0 LO IST ES 00 P LTR ESRIPTION TE WN PV ER0 SEP0 WW RR ER00 0MY0 K FL N#0.0 M#0.0 NOTE HOUSING HS RST OMPLINT KEYING, LTHING,

More information

Review Packet #3 Notes

Review Packet #3 Notes SCIE 40, Spring 0 Miller Review Pket # Notes Mpping Nottion We use mpping nottion to note how oordinte hnges. For exmple, if the point ( ) trnsformed under mpping nottion of ( x, y) ( x, y), then it eomes

More information

Math 4 Review for Quarter 2 Cumulative Test

Math 4 Review for Quarter 2 Cumulative Test Mth 4 Review for Qurter 2 Cumultive Test Nme: I. Right Tringle Trigonometry (3.1-3.3) Key Fcts Pythgoren Theorem - In right tringle, 2 + b 2 = c 2 where c is the hypotenuse s shown below. c b Trigonometric

More information

Angles. Angles. Curriculum Ready.

Angles. Angles. Curriculum Ready. ngles ngles urriculum Redy www.mthletics.com ngles mesure the mount of turn in degrees etween two lines tht meet t point. Mny gmes re sed on interpreting using ngles such s pool, snooker illirds. lck

More information

Stained Glass Design. Teaching Goals:

Stained Glass Design. Teaching Goals: Stined Glss Design Time required 45-90 minutes Teching Gols: 1. Students pply grphic methods to design vrious shpes on the plne.. Students pply geometric trnsformtions of grphs of functions in order to

More information

SIMPLIFYING ALGEBRA PASSPORT.

SIMPLIFYING ALGEBRA PASSPORT. SIMPLIFYING ALGEBRA PASSPORT www.mthletics.com.u This booklet is ll bout turning complex problems into something simple. You will be ble to do something like this! ( 9- # + 4 ' ) ' ( 9- + 7-) ' ' Give

More information

Practise Maths. Sarah-Anne Fernandes and Trevor Dixon. Year3

Practise Maths. Sarah-Anne Fernandes and Trevor Dixon. Year3 Prtise Mths Srh-Anne Fernndes nd Trevor Dixon Yer Every effort hs een mde to tre ll opyright holders, ut if ny hve een indvertently overlooked, the Pulishers will e plesed to mke the neessry rrngements

More information

Distance vector protocol

Distance vector protocol istne vetor protool Irene Finohi finohi@i.unirom.it Routing Routing protool Gol: etermine goo pth (sequene of routers) thru network from soure to Grph strtion for routing lgorithms: grph noes re routers

More information

TOPIC 10 THREE DIMENSIONAL GEOMETRY

TOPIC 10 THREE DIMENSIONAL GEOMETRY TOPIC THREE DIMENSIONAL GEOMETRY SCHEMATIC DIAGRAM Topi Conept Degree of importne Three Dimensionl Geometr (i Diretion Rtios n Diretion Cosines (iicrtesin n Vetor eqution of line in spe & onversion of

More information

a < a+ x < a+2 x < < a+n x = b, n A i n f(x i ) x. i=1 i=1

a < a+ x < a+2 x < < a+n x = b, n A i n f(x i ) x. i=1 i=1 Mth 33 Volume Stewrt 5.2 Geometry of integrls. In this section, we will lern how to compute volumes using integrls defined by slice nlysis. First, we recll from Clculus I how to compute res. Given the

More information

Section 2.3 Functions. Definition: Let A and B be sets. A function (mapping, map) f from A to B, denoted f :A B, is a subset of A B such that

Section 2.3 Functions. Definition: Let A and B be sets. A function (mapping, map) f from A to B, denoted f :A B, is a subset of A B such that Setion 2.3 Funtions Definition: Let n e sets. funtion (mpping, mp) f from to, enote f :, is suset of suh tht x[x y[y < x, y > f ]] n [< x, y 1 > f < x, y 2 > f ] y 1 = y 2 Note: f ssoites with eh x in

More information

Kulleġġ San Ġorġ Preca Il-Liċeo tas-subien Ħamrun. Name & Surname: A) Mark the correct answer by inserting an X in the correct box. a b c d.

Kulleġġ San Ġorġ Preca Il-Liċeo tas-subien Ħamrun. Name & Surname: A) Mark the correct answer by inserting an X in the correct box. a b c d. Kulleġġ Sn Ġorġ Pre Il-Liċeo ts-suien Ħmrun Hlf Yerly Exmintion 2012 Trk 3 Form 3 INFORMATION TECHNOLOGY Time : 1hr 30 mins Nme & Surnme: Clss: A) Mrk the orret nswer y inserting n X in the orret ox. 1)

More information

Pythagoras theorem and trigonometry (2)

Pythagoras theorem and trigonometry (2) HPTR 10 Pythgors theorem nd trigonometry (2) 31 HPTR Liner equtions In hpter 19, Pythgors theorem nd trigonometry were used to find the lengths of sides nd the sizes of ngles in right-ngled tringles. These

More information

ZZ - Advanced Math Review 2017

ZZ - Advanced Math Review 2017 ZZ - Advnced Mth Review Mtrix Multipliction Given! nd! find the sum of the elements of the product BA First, rewrite the mtrices in the correct order to multiply The product is BA hs order x since B is

More information

GENG2140 Modelling and Computer Analysis for Engineers

GENG2140 Modelling and Computer Analysis for Engineers GENG4 Moelling n Computer Anlysis or Engineers Letures 9 & : Gussin qurture Crete y Grn Romn Joles, PhD Shool o Mehnil Engineering, UWA GENG4 Content Deinition o Gussin qurture Computtion o weights n points

More information

50 AMC LECTURES Lecture 2 Analytic Geometry Distance and Lines. can be calculated by the following formula:

50 AMC LECTURES Lecture 2 Analytic Geometry Distance and Lines. can be calculated by the following formula: 5 AMC LECTURES Lecture Anlytic Geometry Distnce nd Lines BASIC KNOWLEDGE. Distnce formul The distnce (d) between two points P ( x, y) nd P ( x, y) cn be clculted by the following formul: d ( x y () x )

More information

Angle properties of lines and polygons

Angle properties of lines and polygons chievement Stndrd 91031 pply geometric resoning in solving problems Copy correctly Up to 3% of workbook Copying or scnning from ES workbooks is subject to the NZ Copyright ct which limits copying to 3%

More information

Lecture 8: Graph-theoretic problems (again)

Lecture 8: Graph-theoretic problems (again) COMP36111: Advned Algorithms I Leture 8: Grph-theoreti prolems (gin) In Prtt-Hrtmnn Room KB2.38: emil: iprtt@s.mn..uk 2017 18 Reding for this leture: Sipser: Chpter 7. A grph is pir G = (V, E), where V

More information

Lesson 4.4. Euler Circuits and Paths. Explore This

Lesson 4.4. Euler Circuits and Paths. Explore This Lesson 4.4 Euler Ciruits nd Pths Now tht you re fmilir with some of the onepts of grphs nd the wy grphs onvey onnetions nd reltionships, it s time to egin exploring how they n e used to model mny different

More information

Review Packet #3 Notes

Review Packet #3 Notes SCIE 40, Fll 05 Miller Review Pket # Notes Prllel Lines If two prllel lines re onneted y third line (lled the trnsversl), the resulting ngles re either ongruent or supplementry. Angle pirs re nmed s follows:

More information

Class-XI Mathematics Conic Sections Chapter-11 Chapter Notes Key Concepts

Class-XI Mathematics Conic Sections Chapter-11 Chapter Notes Key Concepts Clss-XI Mthemtics Conic Sections Chpter-11 Chpter Notes Key Concepts 1. Let be fixed verticl line nd m be nother line intersecting it t fixed point V nd inclined to it t nd ngle On rotting the line m round

More information

Geometrical reasoning 1

Geometrical reasoning 1 MODULE 5 Geometril resoning 1 OBJECTIVES This module is for study y n individul teher or group of tehers. It: looks t pprohes to developing pupils visulistion nd geometril resoning skills; onsiders progression

More information

Mathematics Background

Mathematics Background For more roust techer experience, plese visit Techer Plce t mthdshord.com/cmp3 Mthemtics Bckground Extending Understnding of Two-Dimensionl Geometry In Grde 6, re nd perimeter were introduced to develop

More information

The Math Learning Center PO Box 12929, Salem, Oregon Math Learning Center

The Math Learning Center PO Box 12929, Salem, Oregon Math Learning Center Resource Overview Quntile Mesure: Skill or Concept: 80Q Multiply two frctions or frction nd whole numer. (QT N ) Excerpted from: The Mth Lerning Center PO Box 99, Slem, Oregon 9709 099 www.mthlerningcenter.org

More information

Journal of Combinatorial Theory, Series A

Journal of Combinatorial Theory, Series A Journl of Comintoril Theory, Series A 0 (0) Contents lists ville t SiVerse SieneDiret Journl of Comintoril Theory, Series A www.elsevier.om/lote/jt Spheril tiling y ongruent pentgons Hongho Go, Nn Shi,

More information

CS 551 Computer Graphics. Hidden Surface Elimination. Z-Buffering. Basic idea: Hidden Surface Removal

CS 551 Computer Graphics. Hidden Surface Elimination. Z-Buffering. Basic idea: Hidden Surface Removal CS 55 Computer Grphis Hidden Surfe Removl Hidden Surfe Elimintion Ojet preision lgorithms: determine whih ojets re in front of others Uses the Pinter s lgorithm drw visile surfes from k (frthest) to front

More information

Class Overview. Database Design. Database Design Process. Database Design. Introduction to Data Management CSE 414

Class Overview. Database Design. Database Design Process. Database Design. Introduction to Data Management CSE 414 Introution to Dt Mngement CSE 44 Unit 6: Coneptul Design E/R Digrms Integrity Constrints BCNF Introution to Dt Mngement CSE 44 E/R Digrms ( letures) CSE 44 Autumn 08 Clss Overview Dtse Design Unit : Intro

More information

Lily Yen and Mogens Hansen

Lily Yen and Mogens Hansen SKOLID / SKOLID No. 8 Lily Yen nd Mogens Hnsen Skolid hs joined Mthemticl Myhem which is eing reformtted s stnd-lone mthemtics journl for high school students. Solutions to prolems tht ppered in the lst

More information

Introducing fractions

Introducing fractions Introduing frtions Nme Colour hlf of eh shpe: Show the following fr ons: out of out of out of Lel these fr ons: Shde these fr ons: 7 0 Represents ommon fr ons on different models Interprets the numertor

More information

Area & Volume. Chapter 6.1 & 6.2 September 25, y = 1! x 2. Back to Area:

Area & Volume. Chapter 6.1 & 6.2 September 25, y = 1! x 2. Back to Area: Bck to Are: Are & Volume Chpter 6. & 6. Septemer 5, 6 We cn clculte the re etween the x-xis nd continuous function f on the intervl [,] using the definite integrl:! f x = lim$ f x * i )%x n i= Where fx

More information

Introduction to Algebra

Introduction to Algebra INTRODUCTORY ALGEBRA Mini-Leture 1.1 Introdution to Alger Evlute lgeri expressions y sustitution. Trnslte phrses to lgeri expressions. 1. Evlute the expressions when =, =, nd = 6. ) d) 5 10. Trnslte eh

More information

9.1 apply the distance and midpoint formulas

9.1 apply the distance and midpoint formulas 9.1 pply the distnce nd midpoint formuls DISTANCE FORMULA MIDPOINT FORMULA To find the midpoint between two points x, y nd x y 1 1,, we Exmple 1: Find the distnce between the two points. Then, find the

More information

Tight triangulations: a link between combinatorics and topology

Tight triangulations: a link between combinatorics and topology Tight tringultions: link between ombintoris nd topology Jonthn Spreer Melbourne, August 15, 2016 Topologil mnifolds (Geometri) Topology is study of mnifolds (surfes) up to ontinuous deformtion Complited

More information

Hyperbolas. Definition of Hyperbola

Hyperbolas. Definition of Hyperbola CHAT Pre-Clculus Hyperols The third type of conic is clled hyperol. For n ellipse, the sum of the distnces from the foci nd point on the ellipse is fixed numer. For hyperol, the difference of the distnces

More information

Graphing Conic Sections

Graphing Conic Sections Grphing Conic Sections Definition of Circle Set of ll points in plne tht re n equl distnce, clled the rdius, from fixed point in tht plne, clled the center. Grphing Circle (x h) 2 + (y k) 2 = r 2 where

More information

Neo-Flex Slide-out Keyboard Tray Wall Mount

Neo-Flex Slide-out Keyboard Tray Wall Mount User's Guie Neo-Flex Slie-out Keyor Try Wll Mount For the ltest User Instlltion Guie plese visit: www.ergotron.om User's Guie - English Guí el usurio - Espñol Mnuel e l utilisteur - Frnçis Geruikersgis

More information

Subtracting Fractions

Subtracting Fractions Lerning Enhncement Tem Model Answers: Adding nd Subtrcting Frctions Adding nd Subtrcting Frctions study guide. When the frctions both hve the sme denomintor (bottom) you cn do them using just simple dding

More information

MTH 146 Conics Supplement

MTH 146 Conics Supplement 105- Review of Conics MTH 146 Conics Supplement In this section we review conics If ou ne more detils thn re present in the notes, r through section 105 of the ook Definition: A prol is the set of points

More information

Chapter 2. 3/28/2004 H133 Spring

Chapter 2. 3/28/2004 H133 Spring Chpter 2 Newton believe tht light ws me up of smll prticles. This point ws ebte by scientists for mny yers n it ws not until the 1800 s when series of experiments emonstrte wve nture of light. (But be

More information

COMP 423 lecture 11 Jan. 28, 2008

COMP 423 lecture 11 Jan. 28, 2008 COMP 423 lecture 11 Jn. 28, 2008 Up to now, we hve looked t how some symols in n lphet occur more frequently thn others nd how we cn sve its y using code such tht the codewords for more frequently occuring

More information

Summer Review Packet For Algebra 2 CP/Honors

Summer Review Packet For Algebra 2 CP/Honors Summer Review Pcket For Alger CP/Honors Nme Current Course Mth Techer Introduction Alger uilds on topics studied from oth Alger nd Geometr. Certin topics re sufficientl involved tht the cll for some review

More information

In the last lecture, we discussed how valid tokens may be specified by regular expressions.

In the last lecture, we discussed how valid tokens may be specified by regular expressions. LECTURE 5 Scnning SYNTAX ANALYSIS We know from our previous lectures tht the process of verifying the syntx of the progrm is performed in two stges: Scnning: Identifying nd verifying tokens in progrm.

More information

Computational geometry

Computational geometry Leture 23 Computtionl geometry Supplementl reding in CLRS: Chpter 33 exept 33.3 There re mny importnt prolems in whih the reltionships we wish to nlyze hve geometri struture. For exmple, omputtionl geometry

More information

MA1008. Calculus and Linear Algebra for Engineers. Course Notes for Section B. Stephen Wills. Department of Mathematics. University College Cork

MA1008. Calculus and Linear Algebra for Engineers. Course Notes for Section B. Stephen Wills. Department of Mathematics. University College Cork MA1008 Clculus nd Liner Algebr for Engineers Course Notes for Section B Stephen Wills Deprtment of Mthemtics University College Cork s.wills@ucc.ie http://euclid.ucc.ie/pges/stff/wills/teching/m1008/ma1008.html

More information

Fig.1. Let a source of monochromatic light be incident on a slit of finite width a, as shown in Fig. 1.

Fig.1. Let a source of monochromatic light be incident on a slit of finite width a, as shown in Fig. 1. Answer on Question #5692, Physics, Optics Stte slient fetures of single slit Frunhofer diffrction pttern. The slit is verticl nd illuminted by point source. Also, obtin n expression for intensity distribution

More information

UNIVERSITY OF EDINBURGH COLLEGE OF SCIENCE AND ENGINEERING SCHOOL OF INFORMATICS INFORMATICS 1 COMPUTATION & LOGIC INSTRUCTIONS TO CANDIDATES

UNIVERSITY OF EDINBURGH COLLEGE OF SCIENCE AND ENGINEERING SCHOOL OF INFORMATICS INFORMATICS 1 COMPUTATION & LOGIC INSTRUCTIONS TO CANDIDATES UNIVERSITY OF EDINBURGH COLLEGE OF SCIENCE AND ENGINEERING SCHOOL OF INFORMATICS INFORMATICS COMPUTATION & LOGIC Sturdy st April 7 : to : INSTRUCTIONS TO CANDIDATES This is tke-home exercise. It will not

More information

CS 340, Fall 2016 Sep 29th Exam 1 Note: in all questions, the special symbol ɛ (epsilon) is used to indicate the empty string.

CS 340, Fall 2016 Sep 29th Exam 1 Note: in all questions, the special symbol ɛ (epsilon) is used to indicate the empty string. CS 340, Fll 2016 Sep 29th Exm 1 Nme: Note: in ll questions, the speil symol ɛ (epsilon) is used to indite the empty string. Question 1. [10 points] Speify regulr expression tht genertes the lnguge over

More information

a c = A C AD DB = BD

a c = A C AD DB = BD 1.) SIMILR TRINGLES.) Some possile proportions: Geometry Review- M.. Sntilli = = = = =.) For right tringle ut y its ltitude = = =.) Or for ll possiilities, split into 3 similr tringles: ll orresponding

More information

Pipeline Example: Cycle 1. Pipeline Example: Cycle 2. Pipeline Example: Cycle 4. Pipeline Example: Cycle 3. 3 instructions. 3 instructions.

Pipeline Example: Cycle 1. Pipeline Example: Cycle 2. Pipeline Example: Cycle 4. Pipeline Example: Cycle 3. 3 instructions. 3 instructions. ipeline Exmple: Cycle 1 ipeline Exmple: Cycle X X/ /W X X/ /W $3,$,$1 lw $,0($5) $3,$,$1 3 instructions 8 9 ipeline Exmple: Cycle 3 ipeline Exmple: Cycle X X/ /W X X/ /W sw $6,($7) lw $,0($5) $3,$,$1 sw

More information

8.2 Areas in the Plane

8.2 Areas in the Plane 39 Chpter 8 Applictions of Definite Integrls 8. Ares in the Plne Wht ou will lern out... Are Between Curves Are Enclosed Intersecting Curves Boundries with Chnging Functions Integrting with Respect to

More information

Angles. Angles and Polygons. Solutions. Curriculum Ready.

Angles. Angles and Polygons. Solutions. Curriculum Ready. Angles Angles nd Polygons Solutions Curriulum Redy www.mthletis.om How does it work? Solutions Angles nd Polygons Pge questions Angle sum of tringle K 1 +XYZ = 50 +JKL = 40 X +XZY = 50 +JLK = 60 +YXZ

More information

Width and Bounding Box of Imprecise Points

Width and Bounding Box of Imprecise Points Width nd Bounding Box of Impreise Points Vhideh Keikh Mrten Löffler Ali Mohdes Zhed Rhmti Astrt In this pper we study the following prolem: we re given set L = {l 1,..., l n } of prllel line segments,

More information

CMPUT101 Introduction to Computing - Summer 2002

CMPUT101 Introduction to Computing - Summer 2002 CMPUT Introdution to Computing - Summer 22 %XLOGLQJ&RPSXWHU&LUFXLWV Chpter 4.4 3XUSRVH We hve looked t so fr how to uild logi gtes from trnsistors. Next we will look t how to uild iruits from logi gtes,

More information

Lecture 12 : Topological Spaces

Lecture 12 : Topological Spaces Leture 12 : Topologil Spes 1 Topologil Spes Topology generlizes notion of distne nd loseness et. Definition 1.1. A topology on set X is olletion T of susets of X hving the following properties. 1. nd X

More information

Graph theory Route problems

Graph theory Route problems Bhelors thesis Grph theory Route prolems Author: Aolphe Nikwigize Dte: 986 - -5 Sujet: Mthemtis Level: First level (Bhelor) Course oe: MAE Astrt In this thesis we will review some route prolems whih re

More information

Fall 2018 Midterm 1 October 11, ˆ You may not ask questions about the exam except for language clarifications.

Fall 2018 Midterm 1 October 11, ˆ You may not ask questions about the exam except for language clarifications. 15-112 Fll 2018 Midterm 1 October 11, 2018 Nme: Andrew ID: Recittion Section: ˆ You my not use ny books, notes, extr pper, or electronic devices during this exm. There should be nothing on your desk or

More information

Doubts about how to use azimuth values from a Coordinate Object. Juan Antonio Breña Moral

Doubts about how to use azimuth values from a Coordinate Object. Juan Antonio Breña Moral Douts out how to use zimuth vlues from Coordinte Ojet Jun Antonio Breñ Morl # Definition An Azimuth is the ngle from referene vetor in referene plne to seond vetor in the sme plne, pointing towrd, (ut

More information

Lecture 13: Graphs I: Breadth First Search

Lecture 13: Graphs I: Breadth First Search Leture 13 Grphs I: BFS 6.006 Fll 2011 Leture 13: Grphs I: Bredth First Serh Leture Overview Applitions of Grph Serh Grph Representtions Bredth-First Serh Rell: Grph G = (V, E) V = set of verties (ritrry

More information

2 Computing all Intersections of a Set of Segments Line Segment Intersection

2 Computing all Intersections of a Set of Segments Line Segment Intersection 15-451/651: Design & Anlysis of Algorithms Novemer 14, 2016 Lecture #21 Sweep-Line nd Segment Intersection lst chnged: Novemer 8, 2017 1 Preliminries The sweep-line prdigm is very powerful lgorithmic design

More information

4-1 NAME DATE PERIOD. Study Guide. Parallel Lines and Planes P Q, O Q. Sample answers: A J, A F, and D E

4-1 NAME DATE PERIOD. Study Guide. Parallel Lines and Planes P Q, O Q. Sample answers: A J, A F, and D E 4-1 NAME DATE PERIOD Pges 142 147 Prllel Lines nd Plnes When plnes do not intersect, they re sid to e prllel. Also, when lines in the sme plne do not intersect, they re prllel. But when lines re not in

More information

Compilers Spring 2013 PRACTICE Midterm Exam

Compilers Spring 2013 PRACTICE Midterm Exam Compilers Spring 2013 PRACTICE Midterm Exm This is full length prctice midterm exm. If you wnt to tke it t exm pce, give yourself 7 minutes to tke the entire test. Just like the rel exm, ech question hs

More information

WORKSHOP 8B TENSION COUPON

WORKSHOP 8B TENSION COUPON WORKSHOP 8B TENSION COUPON WS8B-2 Workshop Ojetives Prtie reting n eiting geometry Prtie mesh seeing n iso meshing tehniques. WS8B-3 Suggeste Exerise Steps 1. Crete new tse. 2. Crete geometry moel of the

More information

3.5.1 Single slit diffraction

3.5.1 Single slit diffraction 3..1 Single slit diffrction ves pssing through single slit will lso diffrct nd produce n interference pttern. The reson for this is to do with the finite width of the slit. e will consider this lter. Tke

More information

9.1 PYTHAGOREAN THEOREM (right triangles)

9.1 PYTHAGOREAN THEOREM (right triangles) Simplifying Rdicls: ) 1 b) 60 c) 11 d) 3 e) 7 Solve: ) x 4 9 b) 16 80 c) 9 16 9.1 PYTHAGOREAN THEOREM (right tringles) c If tringle is right tringle then b, b re the legs * c is clled the hypotenuse (side

More information

ES 00 NTS 1 5 A7 RAST 2.5 TAB HEADER ASSY TH, VERTICAL, EXTERNAL LOCKING

ES 00 NTS 1 5 A7 RAST 2.5 TAB HEADER ASSY TH, VERTICAL, EXTERNAL LOCKING 2 THIS RWING IS UNPULISHE. OPYRIGHT 2 Y RELESE FOR PULITION LL RIGHTS RESERVE. 2 LO IST ES P LTR ESRIPTION TE WN PV ER2 JUN2 M.T YH.M.2 2. ER NOV2 GRZ T ER MY2 WW RR NOTE SEE SHEET FOR VILLE ONFIGURTIONS

More information

A & LIFT BASE INFORMATION HEIGHT DIM A MM [INCH]

A & LIFT BASE INFORMATION HEIGHT DIM A MM [INCH] 9 [ ] 9 [ ] 0 [ 9 ] [ ] 0 [ 9 ] [ ] 9 [ ] 9 [ ] LTERNTOR EN [ ] RITOR EN X 09 [ 9. ] X [ 9. ] FIXE IR INTKE LOUVER (STNR) X [ 0.0 ] OUTLET SILENER 0 [ ] [ 9 ] OOR REMOVE 0 [ 9 ] INTKE ESS 9 [ ] [ 0 ] 9

More information

3.5.1 Single slit diffraction

3.5.1 Single slit diffraction 3.5.1 Single slit diffrction Wves pssing through single slit will lso diffrct nd produce n interference pttern. The reson for this is to do with the finite width of the slit. We will consider this lter.

More information

CASS-TL4 PLAN VIEW CASS-TL4 ELEVATION VIEW (TYPICAL LAY-OUT)

CASS-TL4 PLAN VIEW CASS-TL4 ELEVATION VIEW (TYPICAL LAY-OUT) /" (-) LENGTH OF NEE SS LE TERMINL (T): (REQUIRES PROTETION SEE NOTE.) EPRTURE INSTLLTION: LON IS T POST # (S SHOWN) PPROH INSTLLTION: LON IS " PST POST # LENGTH OF NEE T SS SS LE NHOR (): PPROH INSTLLTION:

More information

MITSUBISHI ELECTRIC RESEARCH LABORATORIES Cambridge, Massachusetts. Introduction to Matroids and Applications. Srikumar Ramalingam

MITSUBISHI ELECTRIC RESEARCH LABORATORIES Cambridge, Massachusetts. Introduction to Matroids and Applications. Srikumar Ramalingam Cmrige, Msshusetts Introution to Mtrois n Applitions Srikumr Rmlingm MERL mm//yy Liner Alger (,0,0) (0,,0) Liner inepenene in vetors: v, v2,..., For ll non-trivil we hve s v s v n s, s2,..., s n 2v2...

More information